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Zorluk: OrtaUnit Digit and Cyclicity

Find the unit digit of the numerical expression N=(56763×23445)34337N = (567^{63} \times 234^{45}) - 343^{37}.

Cevap: 9

Cevap

9
The unit digit of 56763567^{63} is 3 and for 23445234^{45} it is 4, making their product's unit digit 2. The unit digit of 34337343^{37} is 3. Subtracting 3 from 2 with regrouping (12312 - 3) yields 9.

Adım Adım Çözüm

1
Determine the unit digit of 56763567^{63}
3
Base unit digit is 7 with cyclicity 4. Since 63(mod4)=363 \pmod 4 = 3, 737^3 gives a unit digit of 3.
2
Determine the unit digit of 23445234^{45}
4
Base unit digit is 4 with cyclicity 2. An odd exponent yields a unit digit of 4.
3
Multiply the unit digits of the first two terms
2
The unit digit of the product is (3×4)(mod10)=2(3 \times 4) \pmod{10} = 2.
4
Determine the unit digit of 34337343^{37}
3
Base unit digit is 3 with cyclicity 4. Since 37(mod4)=137 \pmod 4 = 1, 313^1 gives a unit digit of 3.
5
Subtract the unit digit of the second part from the first part
9
Subtracting 3 from 2 requires borrowing 10 (123=912 - 3 = 9) to yield a valid positive unit digit.

Anahtar Kavram

Unit Digit and Cyclicity of Powers
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