A mechanical clock is synchronized to the correct standard time at exactly 00:00 (midnight) on February 15th of a leap year. This particular clock is known to gain exactly minutes every hours of true time.
What is the acute angle (in degrees) between the hour and minute hands of this faulty clock at exactly 12:00 noon (true time) on March 2nd of the same leap year?
Cevap: 3 degrees
Cevap
The acute angle between the hands is 3 degrees.
By determining the exact time elapsed across the leap year boundary ( days), the total time gained by the clock is minutes. Adding this to the true time of 12:00 yields a faulty clock time of 13:06 (or 1:06). At 1:06, the minute hand is at () and the hour hand has moved past the 1 o'clock mark () by an additional (). The difference between and is .
Adım Adım Çözüm
Anahtar Kavram
Calculating elapsed time across leap year month boundaries combined with continuous clock drift and geometric clock angle formulas.
Tahmini Süre:2m 30s