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Zorluk: OrtaUnit Digit and Cyclicity

What is the unit digit of the expression S=284+497×354945S = 2^{84} + 4^{97} \times 3^{54} - 9^{45}?

  1. 3Cevap
  2. B
    8
  3. C
    2
  4. D
    1

Cevap

The unit digit of the expression is 3.
The unit digit of 2842^{84} is 6 (since 84 is a multiple of 4, corresponding to the 4th position in cyclicity). The product 497×3544^{97} \times 3^{54} has a unit digit of (4×9)(mod10)=6(4 \times 9) \pmod{10} = 6. The unit digit of 9459^{45} is 9. Substituting these into the original expression yields 6+69=36 + 6 - 9 = 3.

Adım Adım Çözüm

1
Find the unit digit of 2842^{84}
Unit digit is 6
The cyclicity of 22 is 44 (2,4,8,62, 4, 8, 6). Since 84÷4=2184 \div 4 = 21 with remainder 00, we take the 4th term in the cyclicity pattern, which is 66.
2
Find the unit digit of 4974^{97} and 3543^{54}
Unit digit of 4974^{97} is 4; Unit digit of 3543^{54} is 9
The cyclicity of 44 is 22 (44 for odd powers, 66 for even powers). Since 9797 is odd, 4974^{97} ends in 44. The cyclicity of 33 is 44 (3,9,7,13, 9, 7, 1). Since 54=4×13+254 = 4 \times 13 + 2, remainder is 22, giving 32=93^2 = 9.
3
Find the unit digit of the product 497×3544^{97} \times 3^{54}
Unit digit of product is 6
Multiplying the unit digits: 4×9=364 \times 9 = 36, so the unit digit is 66.
4
Find the unit digit of 9459^{45}
Unit digit is 9
The cyclicity of 99 is 22 (99 for odd powers, 11 for even powers). Since 4545 is odd, 9459^{45} ends in 99.
5
Combine the unit digits following the algebraic operations
Unit digit is 3
Evaluating 6+69=129=36 + 6 - 9 = 12 - 9 = 3.

Anahtar Kavram

Unit Digit and Cyclicity of Exponential Numbers
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