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Zorluk: OrtaNumber and Alphabet Series
Determine the value of the missing term that logically continues the given numerical sequence:
6,13,28,59,122,?6, 13, 28, 59, 122, ?

Cevap: 249

Cevap

The missing term in the sequence is 249.
The sequence follows the pattern Tn=Tn1×2+(n1)T_n = T_{n-1} \times 2 + (n-1) for n2n \ge 2. Thus, the 6th term is 122×2+5=249122 \times 2 + 5 = 249.

Adım Adım Çözüm

1
Examine the transition between consecutive numbers in the series
From 6 to 13: 6×2+1=136 \times 2 + 1 = 13
From 13 to 28: 13×2+2=2813 \times 2 + 2 = 28
Establishing the basic recursive function pattern
2
Verify the pattern across remaining terms
From 28 to 59: 28×2+3=5928 \times 2 + 3 = 59
From 59 to 122: 59×2+4=12259 \times 2 + 4 = 122
Confirming that the multiplier is constant (2) while the added constant increments by 1 at each step
3
Apply the rule to find the missing term
122×2+5=244+5=249122 \times 2 + 5 = 244 + 5 = 249
Extending the pattern by adding 5 after doubling the previous term

Anahtar Kavram

Recursive series with constant multiplier and arithmetic additive offset
Tahmini Süre:1m 0s
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