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Zorluk: ZorVenn Diagrams and Set-Based Data

In a survey of 500500 civil service aspirants preparing for State PSC examinations regarding their daily newspaper reading habits:
- 260260 aspirants read Newspaper A
- 220220 aspirants read Newspaper B
- 180180 aspirants read Newspaper C
- 9090 aspirants read both Newspaper A and Newspaper B
- 7070 aspirants read both Newspaper B and Newspaper C
- 8080 aspirants read both Newspaper A and Newspaper C
- 3030 aspirants read all three newspapers

How many aspirants read exactly one of these three newspapers?

  1. A
    180180
  2. B
    240240
  3. 270270Cevap
  4. D
    420420

Cevap

The number of aspirants who read exactly one newspaper is 270270.
The correct answer is derived by determining the number of readers exclusive to each single newspaper set. Subtracting all overlapping regions (both the exclusive two-paper readers and three-paper readers) from each newspaper's total gives 120120 for Newspaper A only, 9090 for Newspaper B only, and 6060 for Newspaper C only. Adding these exclusive values yields 270270.

Adım Adım Çözüm

1
Calculate the number of aspirants who read ONLY Newspaper A, ONLY Newspaper B, and ONLY Newspaper C by isolating two-set and three-set intersections.
Disjoint 2-set intersection counts (excluding all 3 newspapers):
- Reading A and B only: 9030=6090 - 30 = 60
- Reading B and C only: 7030=4070 - 30 = 40
- Reading A and C only: 8030=5080 - 30 = 50
The given two-newspaper intersection counts include the 3030 aspirants who read all three newspapers.
2
Subtract the exclusive two-set and three-set intersection counts from each total newspaper count to find single-newspaper readers.
- Only Newspaper A: 260(60+50+30)=120260 - (60 + 50 + 30) = 120
- Only Newspaper B: 220(60+40+30)=90220 - (60 + 40 + 30) = 90
- Only Newspaper C: 180(50+40+30)=60180 - (50 + 40 + 30) = 60
To find readers of 'only' one paper, all overlaps must be subtracted from the total set count.
3
Sum the exclusive counts for Newspaper A, Newspaper B, and Newspaper C.
Total reading exactly one newspaper = 120+90+60=270120 + 90 + 60 = 270
These three categories are mutually exclusive, so their sum gives the total count for 'exactly one'.

Anahtar Kavram

Principle of Inclusion-Exclusion for Three Sets
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