Soru

Zorluk: OrtaClassification of Numbers

Consider the numerical expression E=852327E = 8^{52} - 3^{27}. If uu represents the unit digit of the positive integer EE, which of the following correctly classifies the number uu?

  1. It is an odd composite number.Cevap
  2. B
    It is an even composite number.
  3. C
    It is a negative integer.
  4. D
    It is a unique number that is neither prime nor composite.

Cevap

The calculated unit digit is 9, which is classified as an odd composite number.
Evaluating the expression requires finding the unit digits of both exponential terms. The unit digit of 8528^{52} is 6, and the unit digit of 3273^{27} is 7. When subtracting 7 from 6 in a larger positive number, borrowing from the tens place results in 167=916 - 7 = 9. The number 9 is odd and has three distinct factors (1, 3, 9), making it an odd composite number.

Adım Adım Çözüm

1
Determine the unit digit of 8528^{52}.
The unit digit is 6.
The cyclicity pattern for powers of 8 is 4 (ending in 8, 4, 2, 6). Since 52 is a perfect multiple of 4 (remainder is 0), the unit digit matches the 4th power in the cycle, which is 6.
2
Determine the unit digit of 3273^{27}.
The unit digit is 7.
The cyclicity pattern for powers of 3 is 4 (ending in 3, 9, 7, 1). Dividing the exponent 27 by 4 leaves a remainder of 3. Therefore, the unit digit matches the 3rd power in the cycle (333^3), which ends in 7.
3
Calculate the unit digit uu of the difference EE.
u=9u = 9
Subtracting the unit digits gives 676 - 7. Because EE is a positive integer, we must borrow 10 from the next higher place value in the base-10 system, yielding 167=916 - 7 = 9.
4
Classify the resulting number 9.
9 is an odd composite number.
The integer 9 cannot be evenly divided by 2 (making it odd) and has positive divisors other than 1 and itself (1, 3, and 9), which classifies it as composite.

Anahtar Kavram

Integration of power cyclicity rules and fundamental number classification.
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