Soru

Zorluk: OrtaFractions and Decimals

A civil contractor is tasked with upgrading a rural highway. In the first month, the crew successfully upgrades 0.2750.275 of the total highway length. During the second month, they upgrade 512\frac{5}{12} of the remaining length. If the crew has exactly 10.1510.15 kilometers left to upgrade in the third month to complete the project, what is the total length of the highway in kilometers?

Cevap: 24 km

Cevap

The total length of the highway is 24 kilometers.
The correct total length is calculated by accurately determining the remaining fraction of the highway step-by-step. Converting the decimal 0.275 to a fraction (11/40) allows for clean, exact operations without repeating decimal rounding errors. By tracking the remainder accurately, we establish that the final 10.15 km represents exactly 203/480 of the total length, resulting in a total of 24 km.

Adım Adım Çözüm

1
Determine the fraction of the highway remaining after the first month.
2940\frac{29}{40} of the total length remains.
The crew upgraded 0.2750.275 of the total. Converting 0.2750.275 to a fraction gives 2751000\frac{275}{1000}, which simplifies to 1140\frac{11}{40}. Subtracting this from the whole gives 11140=29401 - \frac{11}{40} = \frac{29}{40}.
2
Calculate the fraction of the total highway upgraded in the second month.
2996\frac{29}{96} of the total length.
The crew upgraded 512\frac{5}{12} of the remaining length. Therefore, multiply the two fractions: 512×2940=1×2912×8=2996\frac{5}{12} \times \frac{29}{40} = \frac{1 \times 29}{12 \times 8} = \frac{29}{96}.
3
Calculate the total fraction of the highway remaining for the third month.
203480\frac{203}{480} of the total length.
Subtract the second month's progress from the remainder after the first month: 29402996\frac{29}{40} - \frac{29}{96}. The least common multiple of 4040 and 9696 is 480480. Converting to common denominators gives 348480145480=203480\frac{348}{480} - \frac{145}{480} = \frac{203}{480}.
4
Set up the final equation and solve for the total highway length.
2424 km
The remaining fraction equals the given physical distance of 10.1510.15 km. So, 203480×Total=10.15\frac{203}{480} \times \text{Total} = 10.15. Solving for Total yields 10.15×480203\frac{10.15 \times 480}{203}. Since 10.15÷203=0.0510.15 \div 203 = 0.05, the Total is 0.05×480=240.05 \times 480 = 24 km.

Anahtar Kavram

Solving sequential parts-of-a-whole word problems by effectively converting between decimals and fractions to find a remaining proportion.
Bu soruyu puanla