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Zorluk: OrtaHCF and LCM

An inventory analyst is auditing two specific electronic components in a warehouse. He calculates that the product of their exact unit quantities is 32,17532,175, and the Highest Common Factor (HCF) of these two quantities is 1515. If there are more than 100100 units of each component currently in stock, what is the total combined quantity of both components?

Cevap: 360 units

Cevap

The correct total combined quantity is 360 units.
By representing the numbers as 15x15x and 15y15y, we determine that 15x×15y=32,17515x \times 15y = 32,175, which simplifies to xy=143xy = 143. Factoring 143143 into co-prime pairs gives (1,143)(1, 143) and (11,13)(11, 13). Multiplying these by the HCF (1515) gives potential quantities of (15,2145)(15, 2145) and (165,195)(165, 195). Only the pair (165,195)(165, 195) satisfies the condition that both quantities must be greater than 100100. Their sum is 165+195=360165 + 195 = 360.

Adım Adım Çözüm

1
Express the two unknown quantities mathematically using their HCF.
Let the quantities be 15x15x and 15y15y, where xx and yy are co-prime integers.
Since the HCF of the two numbers is 1515, both numbers must be multiples of 1515. Their remaining factors (xx and yy) cannot share any common factors other than 11.
2
Formulate an equation using the given product of the quantities.
15x×15y=32,17515x \times 15y = 32,175
The problem states the product of the two component quantities is equal to 32,17532,175.
3
Solve the equation for the product of the co-prime variables xx and yy.
225xy=32,175xy=32,175225=143225xy = 32,175 \Rightarrow xy = \frac{32,175}{225} = 143
Isolating xyxy simplifies the problem to finding two co-prime factors that multiply to 143143.
4
Identify all co-prime factor pairs of 143143.
The co-prime pairs are (1,143)(1, 143) and (11,13)(11, 13).
We must list all integer pairs that multiply to 143143 and verify they share no common divisors.
5
Calculate the possible original quantities and apply the boundary constraints.
Pair 1 gives (15,2145)(15, 2145). Pair 2 gives (165,195)(165, 195). Because the problem states both quantities are >100>100, we must choose (165,195)(165, 195).
The constraint strictly eliminates the first pair, as 1515 is not greater than 100100.
6
Sum the valid quantities.
165+195=360165 + 195 = 360
The question asks for the total combined quantity of both components.

Anahtar Kavram

The relationship between the Highest Common Factor (HCF) and the product of two numbers, utilizing co-prime factor pairs.
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