Soru

Zorluk: OrtaDirection and Distance Test

A botanist leaves her base camp to collect soil samples in a dense forest. She first walks 35 m35\text{ m} straight East. She then turns 135135^{\circ} to her left and walks 202 m20\sqrt{2}\text{ m}. Finally, she turns 135135^{\circ} to her left again and walks 12 m12\text{ m}. What is the shortest straight-line distance, in meters, between her current position and the base camp?

Cevap: 17 m

Cevap

The shortest straight-line distance between the botanist's current position and the base camp is 17 meters.
By breaking each movement into its horizontal and vertical components on a Cartesian plane, the final position is found to be 15 meters East and 8 meters North of the origin. The shortest direct distance is the hypotenuse of the triangle formed by these coordinates: √(15² + 8²) = 17.

Adım Adım Çözüm

1
Plot the first movement on a coordinate plane.
Position 1 is at (35,0)(35, 0).
Setting the starting base camp at the origin (0,0)(0, 0), moving East means traveling along the positive x-axis.
2
Calculate the vector and position for the second movement.
Position 2 is at (15,20)(15, 20).
Facing East (0°), a left turn of 135° results in facing North-West. Moving 202 m20\sqrt{2}\text{ m} diagonally at a 45° angle to the axes translates to Δx=20 m\Delta x = -20\text{ m} (West) and Δy=+20 m\Delta y = +20\text{ m} (North). New coordinate: (3520,0+20)(35 - 20, 0 + 20).
3
Calculate the vector and position for the third movement.
Position 3 is at (15,8)(15, 8).
Facing North-West, another left turn of 135° places her facing directly South. Walking 12 m12\text{ m} South subtracts 12 from the y-coordinate. New coordinate: (15,2012)(15, 20 - 12).
4
Calculate the shortest straight-line distance to the origin.
The final distance is 17 m17\text{ m}.
The straight-line distance from (0,0)(0, 0) to (15,8)(15, 8) forms a right-angled triangle. Using Pythagoras: d=152+82=225+64=289=17d = \sqrt{15^2 + 8^2} = \sqrt{225 + 64} = \sqrt{289} = 17.

Anahtar Kavram

Calculating continuous displacement using angular turns, vector breakdown, and the Pythagorean theorem.
Tahmini Süre:1m 30s
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