General Mental Ability

303 soru

Soru 181Soru

In a standardized coding system:
1. Each consonant in a word is replaced by the letter that is NN positions ahead of it in the English alphabetical order, where NN is the total count of vowels present in that specific word.
2. Each vowel is replaced by its reverse alphabetical counterpart (where AZA \leftrightarrow Z, BYB \leftrightarrow Y, etc.), and then shifted backward by 33 positions in the English alphabet.
3. Finally, the sequence of letters obtained is written in reverse order.

If the word PRACTICE is coded as SFOFWUS using this rule, what is the code for the word DIPLOMAT?

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Cevap: WWPIOSOG; W W P I O S O G; wwpiosog

Cevap

WWPIOSOG
The correct answer is obtained by first identifying that DIPLOMAT contains 3 vowels (I, O, A), making N=3N = 3. Each consonant is shifted forward by 3 positions (D \rightarrow G, P \rightarrow S, L \rightarrow O, M \rightarrow P, T \rightarrow W). Each vowel is mapped to its reverse letter and then shifted back 3 places (I \rightarrow R \rightarrow O, O \rightarrow L \rightarrow I, A \rightarrow Z \rightarrow W). Combining these gives GOSOI PWW, which when reversed yields WWPIOSOG.

Adım Adım Çözüm

1
Count the number of vowels in the target word DIPLOMAT to determine the consonant shift parameter NN.
The vowels in DIPLOMAT are I, O, and A. The total number of vowels is N=3N = 3.
Rule 1 requires shifting consonants forward by the number of vowels in the word.
2
Apply Rule 1 to all consonants in DIPLOMAT by shifting each forward by 33 positions.
D \rightarrow G, P \rightarrow S, L \rightarrow O, M \rightarrow P, T \rightarrow W.
Consonants shift forward by N=3N=3 positions in alphabetical order.
3
Apply Rule 2 to all vowels in DIPLOMAT by finding their reverse alphabetical counterpart and shifting backward by 33 positions.
I (opposite R) \rightarrow R - 3 = O; O (opposite L) \rightarrow L - 3 = I; A (opposite Z) \rightarrow Z - 3 = W.
Vowels undergo reverse alphabetical substitution followed by a 3-position backward shift.
4
Assemble the transformed letters in original sequential order and reverse the entire string.
Forward order: G O S O I P W W. Reversed string: W W P I O S O G.
Rule 3 dictates reversing the entire transformed character sequence.

Anahtar Kavram

Multi-rule Alphanumeric Transformation and Positional Reversal
Tahmini Süre:2m 30s
Soru 182Soru
Consider the following alphanumeric sequence:
W7,T14,P26,K45,E73,W7, T14, P26, K45, E73, \dots
Which of the following options logically completes the sequence?
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Cevap: X112X112

Cevap

The correct option is X112X112, obtained by shifting the letter term backwards by 7 positions (E to X) and adding 39 to the previous numerical term (73 + 39 = 112) based on the double-difference pattern.
The correct answer is X112X112. The letter pattern subtracts increasing integer steps (-3, -4, -5, -6, -7), where E (5) minus 7 wraps to X (24). The numerical pattern relies on a double difference of consecutive odd numbers (+5, +7, +9, +11), adding 39 to 73 to yield 112.

Adım Adım Çözüm

1
Analyze the letter progression pattern.
Alphabetical positions: W(23), T(20), P(16), K(11), E(5). The differences are -3, -4, -5, -6. The next shift must be -7.
The step size subtracted from the letter positions increases by 1 at each step.
2
Calculate the next letter term.
Subtracting 7 steps backwards from E (5): 57=224(mod26)5 - 7 = -2 \equiv 24 \pmod{26}, which corresponds to the 24th letter, X.
Cyclic alphabetical wrapping applies when counting backwards past A.
3
Analyze the numerical progression using first and second differences.
First differences: 147=714 - 7 = 7, 2614=1226 - 14 = 12, 4526=1945 - 26 = 19, 7345=2873 - 45 = 28. Second differences: 127=512 - 7 = 5, 1912=719 - 12 = 7, 2819=928 - 19 = 9.
The second differences form a sequence of consecutive odd numbers (+5, +7, +9).
4
Compute the next numerical term.
The next second difference is +11+11. Thus, the next first difference is 28+11=3928 + 11 = 39. Adding this to the last term yields 73+39=11273 + 39 = 112.
Extrapolating the double-difference pattern determines the missing number.

Anahtar Kavram

Alphanumeric series completion with variable reverse positional letter shifts and double-difference numerical patterns
Soru 183Soru

Complete the given numerical series by identifying the term that logically follows.

Aşağıdaki boşlukları doldurun

In the numerical sequence 3,7,11,15,19,3, 7, 11, 15, 19, \dots, the term that completes the blank is .
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Cevap

The next term in the sequence is 23.
Each consecutive term in the given series increases by a fixed constant of 44 (3+4=73 + 4 = 7, 7+4=117 + 4 = 11, 11+4=1511 + 4 = 15, 15+4=1915 + 4 = 19). Adding 44 to 1919 gives the correct term, 2323.

Adım Adım Çözüm

1
Find the difference between consecutive terms in the sequence.
73=47 - 3 = 4, 117=411 - 7 = 4, 1511=415 - 11 = 4, and 1915=419 - 15 = 4.
Determining the common difference helps uncover the underlying arithmetic rule of the sequence.
2
Add the constant difference of 4 to the last term given (1919).
19+4=2319 + 4 = 23.
Applying the identified rule (+4) yields the logical next term of the series.

Anahtar Kavram

Arithmetic Number Series with Constant Difference
Tahmini Süre:30s
Soru 184Soru

In a certain code language, the word 'CRAFT' is coded as 'UGZSD' and the word 'BELONG' is coded as 'IPLNVD'. Based on the same logic, which of the following represents the correct code for the word 'TRUMPET'?

Cevabı ve açıklamayı göster

Cevap: VVROFTV

Cevap

VVROFTV
The correct answer 'VVROFTV' is obtained by recognizing that 'TRUMPET' contains 22 vowels ('U' and 'E'). Each consonant (T, R, M, P, T) is shifted forward by +2+2 positions, while each vowel is replaced by its reverse alphabetical counterpart (U \rightarrow F, E \rightarrow V), resulting in 'VTFORVV'. Reversing this string produces 'VVROFTV'.

Adım Adım Çözüm

1
Analyze the coding rules using the given examples 'CRAFT' and 'BELONG'
Rule 1: Count the number of vowels in the given word (e.g., 'CRAFT' has 11 vowel; 'BELONG' has 22 vowels).
Rule 2: Each consonant is shifted forward in the English alphabet by NN positions, where NN is the total count of vowels in that word.
Rule 3: Each vowel is replaced by its reverse alphabetical letter (where AZA \leftrightarrow Z, BYB \leftrightarrow Y, etc., such that reverse position = 27forward position27 - \text{forward position}).
Rule 4: The transformed sequence of letters is reversed from back to front.
Establishing the precise multi-step rule set explains both sample transformations.
2
Count vowels in the target word 'TRUMPET'
The word 'TRUMPET' contains 22 vowels ('U' and 'E'). Thus, for all consonants, N=2N = 2.
Determines the exact shift value needed for consonant transformations.
3
Apply transformations to each letter of 'TRUMPET'
• T (Consonant): 20+2=22V20 + 2 = 22 \rightarrow V
• R (Consonant): 18+2=20T18 + 2 = 20 \rightarrow T
• U (Vowel): 2721=6F27 - 21 = 6 \rightarrow F
• M (Consonant): 13+2=15O13 + 2 = 15 \rightarrow O
• P (Consonant): 16+2=18R16 + 2 = 18 \rightarrow R
• E (Vowel): 275=22V27 - 5 = 22 \rightarrow V
• T (Consonant): 20+2=22V20 + 2 = 22 \rightarrow V
Transformed string: VTFORVV
Executes positional shifts for consonants and reverse indexing for vowels.
4
Reverse the transformed letter string
Reversing 'VTFORVV' yields 'VVROFTV'.
Completes the final step of the coding algorithm.

Anahtar Kavram

Multi-Rule Alphanumeric and Reverse Alphabetical Coding
Soru 185Soru

In a certain code system, words are transformed according to the following rules:
1. Every vowel is replaced by its reverse alphabetical counterpart (where AZA \leftrightarrow Z, EVE \leftrightarrow V, IRI \leftrightarrow R, OLO \leftrightarrow L, UFU \leftrightarrow F, such that the sum of the positional values of the original and transformed letter is 2727).
2. Every consonant located at an odd-numbered position in the word (1st, 3rd, 5th...) is replaced by the letter 33 steps ahead of it in the alphabetical series (+3+3).
3. Every consonant located at an even-numbered position in the word (2nd, 4th, 6th...) is replaced by the letter 22 steps behind it in the alphabetical series (2-2).

If the word 'TRIANGLE' is coded as 'WPRZQEOV', which of the following represents the correct code for the word 'SOLUTION' in this language?

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Cevap: VLOFWRLL

Cevap

The correct code for the word 'SOLUTION' is 'VLOFWRLL'.
The correct code 'VLOFWRLL' is obtained by applying the specified rules systematically: 'S' (1st letter, consonant at odd position) becomes 'V' (+3+3); 'O' (2nd letter, vowel) becomes its reverse letter 'L' (2715=1227-15=12); 'L' (3rd letter, consonant at odd position) becomes 'O' (+3+3); 'U' (4th letter, vowel) becomes its reverse letter 'F' (2721=627-21=6); 'T' (5th letter, consonant at odd position) becomes 'W' (+3+3); 'I' (6th letter, vowel) becomes its reverse letter 'R' (279=1827-9=18); 'O' (7th letter, vowel) becomes its reverse letter 'L' (2715=1227-15=12); and 'N' (8th letter, consonant at even position) becomes 'L' (2-2).

Adım Adım Çözüm

1
Analyze the rule verification on the example word 'TRIANGLE'
Position 1 (T, Consonant, Odd) T+3=W\rightarrow T+3 = W; Position 2 (R, Consonant, Even) R2=P\rightarrow R-2 = P; Position 3 (I, Vowel) 279=18(R)\rightarrow 27-9 = 18 (R); Position 4 (A, Vowel) 271=26(Z)\rightarrow 27-1 = 26 (Z); Position 5 (N, Consonant, Odd) N+3=Q\rightarrow N+3 = Q; Position 6 (G, Consonant, Even) G2=E\rightarrow G-2 = E; Position 7 (L, Consonant, Odd) L+3=O\rightarrow L+3 = O; Position 8 (E, Vowel) 275=22(V)\rightarrow 27-5 = 22 (V). Output: 'WPRZQEOV'.
Confirms that the three-part rule set applies strictly by letter type and 1-indexed letter position.
2
Apply rules to the target word 'SOLUTION' letter by letter
1st letter 'S' (Odd pos, Consonant): S(19)+3=22(V)S (19) + 3 = 22 (V).
2nd letter 'O' (Vowel): Reverse of O(15)O (15) is 2715=12(L)27 - 15 = 12 (L).
3rd letter 'L' (Odd pos, Consonant): L(12)+3=15(O)L (12) + 3 = 15 (O).
4th letter 'U' (Vowel): Reverse of U(21)U (21) is 2721=6(F)27 - 21 = 6 (F).
5th letter 'T' (Odd pos, Consonant): T(20)+3=23(W)T (20) + 3 = 23 (W).
6th letter 'I' (Vowel): Reverse of I(9)I (9) is 279=18(R)27 - 9 = 18 (R).
7th letter 'O' (Vowel): Reverse of O(15)O (15) is 2715=12(L)27 - 15 = 12 (L).
8th letter 'N' (Even pos, Consonant): N(14)2=12(L)N (14) - 2 = 12 (L).
Evaluates each character in 'SOLUTION' according to its specific classification and position.
3
Combine transformed letters to get final coded string
'VLOFWRLL'
Concatenates individual output characters into the complete coded string.

Anahtar Kavram

Multi-rule positional letter shifting combined with reverse alphabetical indexing (27n27 - n rule).
Soru 186Soru

In a certain code system, words are transformed according to the following rules based on letter positions indexed 1,2,3,,n1, 2, 3, \dots, n from left to right:
1. Letters at odd position indices (1,3,5,1, 3, 5, \dots) are replaced by their reverse alphabetical counterparts (where AZA \leftrightarrow Z, BYB \leftrightarrow Y, CXC \leftrightarrow X, etc.).
2. Letters at even position indices (2,4,6,2, 4, 6, \dots) are replaced by the letter shifted forward in the English alphabet by a number of positions equal to their 1-based index (wrapping around from ZZ to AA if necessary).

Based on these rules, what is the correct code for the word 'JOURNEY'?

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Cevap: QQFVMKB

Cevap

QQFVMKB
The correct answer 'QQFVMKB' is obtained by applying the two positional rules step-by-step: at odd positions (1, 3, 5, 7), the reverse alphabetical positions (27rank27 - \text{rank}) yield Q, F, M, and B respectively. At even positions (2, 4, 6), adding the letter's 1-based index to its rank gives Q (15 + 2 = 17), V (18 + 4 = 22), and K (5 + 6 = 11). Combining these yields 'QQFVMKB'.

Adım Adım Çözüm

1
Identify the 1-based position index and standard alphabetical rank of each letter in 'JOURNEY'
J (pos 1, rank 10), O (pos 2, rank 15), U (pos 3, rank 21), R (pos 4, rank 18), N (pos 5, rank 14), E (pos 6, rank 5), Y (pos 7, rank 25).
Establishing letter positions and numerical ranks is required before applying positional transformation rules.
2
Apply reverse alphabetical substitution (27rank27 - \text{rank}) to letters at odd positions (1, 3, 5, 7)
Position 1: 2710=17Q27 - 10 = 17 \rightarrow \text{Q}; Position 3: 2721=6F27 - 21 = 6 \rightarrow \text{F}; Position 5: 2714=13M27 - 14 = 13 \rightarrow \text{M}; Position 7: 2725=2B27 - 25 = 2 \rightarrow \text{B}.
Letters at odd position indices must be replaced by their reverse counterparts.
3
Apply forward shift by position index (rank+index)(\text{rank} + \text{index}) to letters at even positions (2, 4, 6)
Position 2: 15+2=17Q15 + 2 = 17 \rightarrow \text{Q}; Position 4: 18+4=22V18 + 4 = 22 \rightarrow \text{V}; Position 6: 5+6=11K5 + 6 = 11 \rightarrow \text{K}.
Letters at even position indices are shifted forward by their respective 1-based index.
4
Combine the transformed letters in order from position 1 to 7
The encoded string is QQFVMKB.
Assembling the results from all letter positions yields the complete final code.

Anahtar Kavram

Positional Hybrid Coding (Reverse Indexing combined with Index-Based Forward Shift)
Tahmini Süre:1m 30s
Soru 187Soru

If P×QP \times Q means 'PP is the father of QQ', P+QP + Q means 'PP is the sister of QQ', and PQP - Q means 'PP is the mother of QQ', how is AA related to CC in the expression A+B×CA + B \times C?

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Cevap: Aunt

Cevap

Aunt
The expression A+B×CA + B \times C breaks down into two steps: A+BA + B means AA is the sister of BB, and B×CB \times C means BB is the father of CC. Because AA is the sister of CC's father, AA is CC's aunt.

Adım Adım Çözüm

1
Decode the first relation A+BA + B
AA is the sister of BB, which establishes that AA is female.
The symbol ++ represents the 'sister of' relationship.
2
Decode the second relation B×CB \times C
BB is the father of CC.
The symbol ×\times represents the 'father of' relationship.
3
Combine the relations to deduce the relation of AA to CC
AA is the sister of CC's father (BB), which means AA is the aunt of CC.
A father's sister is defined as a paternal aunt.

Anahtar Kavram

Coded Blood Relations
Soru 188Soru

In a certain code, if the word BLOCK is written as CMPDL, what is the code for the word TRAIN?

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Cevap: USBJO; usbjo

Cevap

USBJO
Each letter in the word is shifted forward by 1 position in the English alphabet (+1 rule). Applying this pattern to TRAIN yields USBJO.

Adım Adım Çözüm

1
Analyze the rule used to transform BLOCK into CMPDL.
Each letter in BLOCK is replaced by its immediate next letter in the alphabetical order (+1 position shift): B → C, L → M, O → P, C → D, K → L.
Determining the pattern is necessary to encode new words.
2
Apply the same +1 shift rule to each letter of TRAIN.
T → U, R → S, A → B, I → J, N → O.
Applying the identified pattern consistently yields the correct encoded string.

Anahtar Kavram

Forward Letter Shifting (+1 Pattern)
Soru 189Soru

Read the following coded relationship symbols carefully:
- A÷BA \div B means 'AA is the mother of BB'
- A+BA + B means 'AA is the father of BB'
- ABA - B means 'AA is the sister of BB'
- A×BA \times B means 'AA is the brother of BB'

Based on the expression M÷N+OP×QM \div N + O - P \times Q, how is QQ related to MM?

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Cevap: Cannot be determined

Cevap

Cannot be determined
Decoding the expression shows that M is the mother of N, N is the father of O, and O, P, and Q are siblings. This places Q as the grandchild of M. However, no relation symbol defines the gender of Q (whether Q is male or female). Therefore, Q could be a grandson or a granddaughter, making the exact relationship impossible to determine.

Adım Adım Çözüm

1
Analyze the first operation M÷NM \div N
MM is the mother of NN (Female, 1st Generation).
The symbol ÷\div specifies a mother-child relationship.
2
Analyze the second operation N+ON + O
NN is the father of OO (Male, 2nd Generation).
The symbol ++ specifies a father-child relationship, making MM the paternal grandmother of OO.
3
Analyze the remaining operations OP×QO - P \times Q
OO is the sister of PP, and PP is the brother of QQ. Thus, OO, PP, and QQ are siblings whose father is NN.
The symbols - and ×\times define sibling relations within the same generation.
4
Determine the relationship and gender of QQ
QQ is a grandchild of MM, but QQ's gender is not stated.
In P×QP \times Q, PP is defined as the brother of QQ, which establishes PP's gender as male but leaves QQ's gender unstated (could be male or female).

Anahtar Kavram

Coded Blood Relations and Gender Ambiguity
Tahmini Süre:1m 15s
Soru 190Soru

In a certain code language, if the word "SMART" is written as "UOCTV", how is the word "LIGHT" written in that same code language?

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Cevap: NKIJV

Cevap

The word "LIGHT" is coded as "NKIJV".
Each letter of the original word is shifted forward by 2 positions in the English alphabet: L becomes N, I becomes K, G becomes I, H becomes J, and T becomes V. Combining these gives "NKIJV".

Adım Adım Çözüm

1
Analyze the pattern from the given example pair "SMART" -> "UOCTV".
S (+2) -> U, M (+2) -> O, A (+2) -> C, R (+2) -> T, T (+2) -> V. The rule is adding 2 positions to each letter (+2 alphabetical shift).
Establishing the positional shift rule between corresponding letters.
2
Apply the identical +2 shift rule to each letter of the target word "LIGHT".
L (+2) -> N; I (+2) -> K; G (+2) -> I; H (+2) -> J; T (+2) -> V.
Executing the established shift logic to code the new word.
3
Combine the transformed letters.
The final coded word is "NKIJV".
Formulating the complete answer string.

Anahtar Kavram

Forward Positional Letter Coding
Soru 191Soru

Match each original word in List-I with its correctly coded representation in List-II based on the logical transformation rules applied.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

PATIENT
HARVEST
DOMAINS
CLIMAX

Eşleşmeler

Cevabı ve açıklamayı göster

Cevap

PATIENT matches SZWRQVW; HARVEST matches JZTEGHV; DOMAINS matches NPE1TOJ; CLIMAX matches HNEZZO.
Each word follows a specific multi-step transformation rule: PATIENT applies vowel replacement by reverse alphabet and +3+3 shift to consonants; HARVEST applies +2+2 shift to odd-positioned letters and reverse alphabet to even-positioned letters; DOMAINS reverses outer 3-letter blocks with a +1+1 shift while converting the central letter to its numeric position; CLIMAX applies consonant +2+2 and vowel 1-1 shifts within 3-letter halves before reversing each half.

Adım Adım Çözüm

1
Analyze PATIENT transformation rule
Vowels (A,I,EA, I, E) use reverse positional mapping (27position27 - \text{position}), yielding Z,R,VZ, R, V. Consonants (P,T,N,TP, T, N, T) shift +3+3, yielding S,W,Q,WS, W, Q, W. Combined: SZWRQVW.
Identify rule based on vowel vs. consonant classification.
2
Analyze HARVEST transformation rule
Odd indices (1,3,5,7H,R,E,T1, 3, 5, 7 \rightarrow H, R, E, T) shift +2J,T,G,V+2 \rightarrow J, T, G, V. Even indices (2,4,6A,V,S2, 4, 6 \rightarrow A, V, S) take reverse alphabet values Z,E,H\rightarrow Z, E, H. Combined: JZTEGHV.
Identify rule based on odd/even character indexing.
3
Analyze DOMAINS transformation rule
First half 'DOM' \rightarrow reversed 'MOD' +1\rightarrow +1 shift 'NPE'. Central letter 'A' \rightarrow numerical rank 11. Second half 'INS' \rightarrow reversed 'SNI' +1\rightarrow +1 shift 'TOJ'. Combined: NPE1TOJ.
Identify structural split, segment reversal, positional shift, and numerical conversion.
4
Analyze CLIMAX transformation rule
First half 'CLI': consonants +2+2, vowel 1-1 \rightarrow 'ENH', reversed \rightarrow 'HNE'. Second half 'MAX': consonants +2+2, vowel 1-1 \rightarrow 'OZZ', reversed \rightarrow 'ZZO'. Combined: HNEZZO.
Identify sub-string segmentation, character-type conditional shifts, and section inversion.

Anahtar Kavram

Multi-rule complex coding-decoding involving conditional letter shifts, positional indices, reverse alphabetical mapping, and string segmentation.
Soru 192Soru

Based on the family relations described below, match each person listed in List I with their correct relationship to P listed in List II:

Narrative:
- J is the paternal grandfather of P.
- L is the brother-in-law of M (where L is the son of J), and M is the mother of P.
- K is the wife of J.
- N is the daughter of M.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

J
K
L
N

Eşleşmeler

Cevabı ve açıklamayı göster

Cevap

J matches with Paternal Grandfather; K matches with Paternal Grandmother; L matches with Paternal Uncle; and N matches with Sister.
Analyzing the multi-generational family tree reveals that J is P's paternal grandfather. K, being J's wife, is P's paternal grandmother. L, as the son of J and brother-in-law to P's mother M, is P's paternal uncle. N, as the daughter of M, is P's sister.

Adım Adım Çözüm

1
Identify the direct relationship for J
J is given directly as the paternal grandfather of P.
The narrative explicitly specifies J's relationship to P.
2
Deduce the relationship for K
K is the paternal grandmother of P.
Since K is the wife of J (P's paternal grandfather), K is P's paternal grandmother.
3
Determine the lineage and relationship for L
L is the paternal uncle of P.
L is the son of J (P's paternal grandfather) and brother-in-law to M (P's mother), proving L is the brother of P's father.
4
Determine the relationship for N
N is the sister of P.
N is the daughter of M, who is the mother of P.

Anahtar Kavram

Multi-Generational Blood Relations and Lineage Deductions
Soru 193Soru

Rohit introduces Priya at a social event, stating, 'She is the mother of my father's only son.' Assuming Rohit is a male and has no brothers or sisters, what is Priya's relationship to Rohit?

Cevabı ve açıklamayı göster

Cevap: Mother; mother

Cevap

Priya is Rohit's mother.
The phrase 'my father's only son' uniquely identifies Rohit himself because Rohit is a male without siblings. Replacing this phrase into the original statement yields 'She is the mother of Rohit', establishing Priya as Rohit's mother.

Adım Adım Çözüm

1
Analyze the phrase 'my father's only son'.
Since Rohit is male and has no siblings, his father's only son must be Rohit himself.
An only son of a father with no other children refers directly to the speaker.
2
Substitute this result back into the full statement.
'Priya is the mother of Rohit.'
Replacing 'my father's only son' with 'Rohit' simplifies the relation.
3
Determine the final kinship relation of Priya to Rohit.
Priya is the mother of Rohit.
Direct relationship derived from the decoded statement.

Anahtar Kavram

Kinship Deduction via Self-Reference
Soru 194Soru

In a certain code language, the word BEACON is written as DGCEQP. How is the word MONKEY written in that same code language?

Cevabı ve açıklamayı göster

Cevap: OQPMGA

Cevap

OQPMGA
The pattern follows a constant shift of +2 positions forward in alphabetical order for every letter: B→D, E→G, A→C, C→E, O→Q, N→P. Applying the same rule to MONKEY gives M→O, O→Q, N→P, K→M, E→G, and Y→A (wrapping around after Z), resulting in OQPMGA.

Adım Adım Çözüm

1
Analyze the rule given by the pattern BEACON to DGCEQP.
B (+2) = D, E (+2) = G, A (+2) = C, C (+2) = E, O (+2) = Q, N (+2) = P. The pattern is a uniform forward shift of +2 for every letter.
Determining the transformation rule from the given pair is required to decode the target word.
2
Apply the identified +2 forward shift to each letter of MONKEY.
M (+2) = O, O (+2) = Q, N (+2) = P, K (+2) = M, E (+2) = G, Y (+2) = A.
Applying the exact pattern step-by-step gives the coded output.

Anahtar Kavram

Forward Letter Shift Coding
Tahmini Süre:45s
Soru 195Soru

If M#NM \# N means 'MM is the daughter of NN', M$NM \$ N means 'MM is the brother of NN', M%NM \% N means 'MM is the mother of NN', and M@NM @ N means 'MM is the husband of NN', then in the expression J#K@L%M$NJ \# K @ L \% M \$ N, how is NN related to JJ?

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Cevap: Either brother or sister

Cevap

Either brother or sister
Breaking down the expression shows that JJ, MM, and NN share the same parents (KK and LL). JJ is their daughter, and MM is their son. The symbol sequence M$NM \$ N establishes that MM is the brother of NN, which confirms NN is a sibling to JJ. However, because no symbol defines the gender of NN, NN could be male or female, making the exact relationship either brother or sister.

Adım Adım Çözüm

1
Decode the sub-expression M$NM \$ N
MM is the brother of NN. This implies MM is male, but the gender of NN is not specified.
The relation 'MM is the brother of NN' defines the gender of MM, not NN.
2
Decode L%M$NL \% M \$ N
LL is the mother of MM (and therefore also the mother of NN).
L%ML \% M means LL is the mother of MM, who is sibling to NN.
3
Decode K@LK @ L
KK is the husband of LL, which makes KK the father of MM and NN.
K@LK @ L means KK and LL are husband and wife.
4
Decode J#KJ \# K
JJ is the daughter of KK (and LL).
J#KJ \# K means JJ is the daughter of KK.
5
Determine the relationship between NN and JJ
Since JJ, MM, and NN are all children of the same parents (KK and LL), NN is a sibling to JJ. As NN's gender is unknown, NN is either the brother or sister of JJ.
Gender cannot be assumed without an explicit defining symbol.

Anahtar Kavram

Coded blood relations and gender determination rules
Soru 196Soru

In a certain code language, the word CENTRAL is written as AYKEGCM. Based on the same underlying transformation rule, how will the word PRUDENT be written in that code language?

Cevabı ve açıklamayı göster

Cevap: IGIUYKE

Cevap

IGIUYKE
The code is formed by replacing each letter with its reverse alphabetical position value (where A=26, B=25, ..., Z=1), then adding 3 if the value is even or subtracting 2 if it is odd, and finally mapping the resulting number back to the standard 1-26 forward alphabetical index. Applying this process to PRUDENT yields IGIUYKE.

Adım Adım Çözüm

1
Analyze the coding rule using the example word CENTRAL
Determine forward and reverse alphabetical positions for each letter: C(3→24), E(5→22), N(14→13), T(20→7), R(18→9), A(1→26), L(12→15).
Identify the positional value system being transformed.
2
Identify the conditional transformation rule applied to the reverse positional values
If reverse position is EVEN, add 3; if ODD, subtract 2. Convert back to standard forward letter: C(24+3=27≡1→A), E(22+3=25→Y), N(13-2=11→K), T(7-2=5→E), R(9-2=7→G), A(26+3=29≡3→C), L(15-2=13→M). This matches AYKEGCM.
Establish the precise pattern rules for decoding target words.
3
Apply the rule to the target word PRUDENT
P(16→11 odd: 11-2=9→I), R(18→9 odd: 9-2=7→G), U(21→6 even: 6+3=9→I), D(4→23 odd: 23-2=21→U), E(5→22 even: 22+3=25→Y), N(14→13 odd: 13-2=11→K), T(20→7 odd: 7-2=5→E).
Generate the coded string systematically letter by letter.

Anahtar Kavram

Reverse Alphabetical Indexing with Conditional Numerical Shifting
Tahmini Süre:2m 0s
Soru 197Soru
Consider the following numerical sequence:
3,11,38,102,227,3, 11, 38, 102, 227, \dots
What is the value of the next term in this sequence?
Cevabı ve açıklamayı göster

Cevap: 443

Cevap

The next term in the sequence is 443.
Each term increases by the cube of consecutive natural numbers starting from 2: +2³, +3³, +4³, +5³, and +6³. Adding 6³ (which equals 216) to the preceding term 227 yields 443.

Adım Adım Çözüm

1
Find the difference between consecutive terms in the given sequence.
The differences are 8, 27, 64, and 125.
Analyzing first-order differences reveals the rate of increase between terms.
2
Identify the logical pattern governing the sequence of differences.
The differences correspond to consecutive perfect cubes: 2³, 3³, 4³, and 5³.
Recognizing that 8 = 2³, 27 = 3³, 64 = 4³, and 125 = 5³ establishes the cubic growth rule.
3
Calculate the next term by extending the identified pattern.
Next difference = 6³ = 216, resulting in next term = 227 + 216 = 443.
Following the consecutive cubic sequence, the fifth difference must be 6³.

Anahtar Kavram

Cube-Difference Series Progression
Soru 198Soru

Match each word transformation in List-I with its correct letter-shifting rule in List-II.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

PEN → QFO
PEN → RGP
PEN → SHQ
PEN → TIR

Eşleşmeler

Cevabı ve açıklamayı göster

Cevap

PEN → QFO matches +1 shift; PEN → RGP matches +2 shift; PEN → SHQ matches +3 shift; PEN → TIR matches +4 shift.
Each transformation applies a uniform forward alphabetical shift across all letters: +1 for QFO, +2 for RGP, +3 for SHQ, and +4 for TIR.

Adım Adım Çözüm

1
Analyze PEN → QFO
P to Q (+1), E to F (+1), N to O (+1). Rule is +1 shift.
Identify the positional distance between corresponding alphabetical letters.
2
Analyze PEN → RGP
P to R (+2), E to G (+2), N to P (+2). Rule is +2 shift.
Identify the positional distance between corresponding alphabetical letters.
3
Analyze PEN → SHQ
P to S (+3), E to H (+3), N to Q (+3). Rule is +3 shift.
Identify the positional distance between corresponding alphabetical letters.
4
Analyze PEN → TIR
P to T (+4), E to I (+4), N to R (+4). Rule is +4 shift.
Identify the positional distance between corresponding alphabetical letters.

Anahtar Kavram

Constant Forward Letter Shifting
Soru 199Soru

Read the following coded blood relation definitions:
- A÷BA \div B means 'AA is the father of BB'
- A×BA \times B means 'AA is the sister of BB'
- A+BA + B means 'AA is the son of BB'

Based on the expression P÷Q×RP \div Q \times R, how is RR related to PP?

Cevabı ve açıklamayı göster

Cevap: Either Son or Daughter

Cevap

Either Son or Daughter
Analyzing P÷Q×RP \div Q \times R: P÷QP \div Q means PP is the father of QQ. Q×RQ \times R means QQ is the sister of RR. This makes QQ and RR siblings sharing the father PP. Therefore, RR is the child of PP. However, no relationship code in the expression establishes the gender of RR. As a result, RR can be either a son or a daughter of PP.

Adım Adım Çözüm

1
Decode the first relation P÷QP \div Q
PP is the father of QQ.
The division symbol defines the first person as the father of the second person.
2
Decode the second relation Q×RQ \times R
QQ is the sister of RR.
The multiplication symbol defines the first person as the sister of the second person.
3
Combine the relations to establish the lineage between PP and RR
PP is the father of both QQ and RR.
If PP is the father of QQ, and QQ and RR are siblings, then PP must also be the father of RR.
4
Determine the gender of RR
The gender of RR is unstated; thus RR is either a son or a daughter.
The code Q×RQ \times R tells us QQ is female, but does not provide gender information for RR.

Anahtar Kavram

Gender ambiguity in coded blood relations
Tahmini Süre:45s
Soru 200Soru

In a certain pattern, the letter-group FILM\text{FILM} is related to GJMN\text{GJMN} following a specific positional shift rule. Which letter-group maintains the exact same relationship with MILK\text{MILK}?

Cevabı ve açıklamayı göster

Cevap: NJML\text{NJML}

Cevap

NJML\text{NJML}
The relationship in the pair FILM:GJMN\text{FILM} : \text{GJMN} is established by moving each letter forward by 11 step in the alphabet. Applying this exact pattern to MILK\text{MILK} yields MN\text{M} \to \text{N}, IJ\text{I} \to \text{J}, LM\text{L} \to \text{M}, and KL\text{K} \to \text{L}, giving NJML\text{NJML}.

Adım Adım Çözüm

1
Analyze the rule relating the first pair FILM\text{FILM} and GJMN\text{GJMN}.
FG\text{F} \rightarrow \text{G} (+1+1), IJ\text{I} \rightarrow \text{J} (+1+1), LM\text{L} \rightarrow \text{M} (+1+1), MN\text{M} \rightarrow \text{N} (+1+1).
Each letter is shifted forward by one position in alphabetical order.
2
Apply the identified +1+1 forward shift rule to each letter of MILK\text{MILK}.
M+1=N\text{M} + 1 = \text{N}, I+1=J\text{I} + 1 = \text{J}, L+1=M\text{L} + 1 = \text{M}, K+1=L\text{K} + 1 = \text{L}.
Applying identical positional shifts maintains the analogy logic.
3
Combine the resulting letters in sequence.
NJML\text{NJML}.
The final letter-group formed is NJML\text{NJML}.

Anahtar Kavram

Alphabetical Positional Shift Analogy
Tahmini Süre:45s
ÖncekiSayfa 10 / 16Sonraki
General Mental Ability Alıştırma Soruları — State PSC Exam — Sayfa 10 | Examkin