General Mental Ability

303 soru

Soru 261Soru

On a straight railway track, a sequence of freight carriages is standing in a single line. Carriage XX is the 38th38^{\text{th}} carriage from the front end, and Carriage YY is the 47th47^{\text{th}} carriage from the rear end. Carriage ZZ is positioned exactly halfway between Carriage XX and Carriage YY. If Carriage ZZ is the 62nd62^{\text{nd}} carriage from the rear end, what is the total number of freight carriages on the track?

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Cevap: 114

Cevap

114
The positional distance between Carriage YY and Carriage ZZ from the rear is 15. Since ZZ is the midpoint, Carriage XX is another 15 positions ahead, making XX the 77th77^{\text{th}} carriage from the rear. Since XX is also 38th38^{\text{th}} from the front, the total number of carriages is calculated as 38+771=11438 + 77 - 1 = 114.

Adım Adım Çözüm

1
Calculate the positional difference between Carriage YY and Carriage ZZ from the rear.
6247=1562 - 47 = 15 positions.
To find the distance from one end of the segment to its exact midpoint.
2
Determine Carriage XX's position from the rear.
Carriage XX is the 77th77^{\text{th}} carriage from the rear.
Since ZZ is exactly halfway between XX and YY, the positional difference between ZZ and XX must also be 15. Thus, 62+15=7762 + 15 = 77.
3
Calculate the total number of carriages.
38+771=11438 + 77 - 1 = 114 carriages.
The total number of items in a row equals (Position from front) + (Position from rear) - 1.

Anahtar Kavram

Calculating total count using dual positional ranks and midpoint symmetry in a sequence.
Soru 262Soru

One evening, just before sunset, a security guard begins his patrol in an open plaza. He starts walking straight such that his shadow falls exactly to his right. He walks 20 m20\text{ m} straight, then turns 135135^\circ clockwise and walks 152 m15\sqrt{2}\text{ m}. Finally, he turns 135135^\circ counter-clockwise and walks another 15 m15\text{ m} straight.

What is the shortest distance between his final position and his starting point, and in which direction is his final position relative to the starting point?

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Cevap: 25 m25\text{ m}, North-East

Cevap

The shortest distance is 25 m25\text{ m} and the direction is North-East.
At sunset, the sun is in the West, casting shadows toward the East. Since the guard's shadow is exactly to his right, his right side faces East, meaning he begins by facing North. Walking 20 m North takes him to coordinate (0, 20). He then turns 135 degrees clockwise, which points him South-East. Moving 15√2 m in this direction shifts him 15 m East and 15 m South, placing him at (15, 5). Next, he turns 135 degrees counter-clockwise from South-East, returning him to a North-facing direction. He walks 15 m North, reaching the final coordinate of (15, 20). The shortest distance from the start (0, 0) is found using the Pythagorean theorem: √(15² + 20²) = √(225 + 400) = √625 = 25 m. Because the final position is 15 m East and 20 m North of the origin, the direction is North-East.

Adım Adım Çözüm

1
Determine the initial facing direction based on the sun and shadow.
The guard is facing North.
Since it is evening (sunset), the sun is in the West and casts shadows to the East. If the shadow is to the guard's right, his right side points East, which means he must be facing North.
2
Calculate the position after the first movement.
Current position is (0,20)(0, 20).
Walking 20 m20\text{ m} straight while facing North changes the Y-coordinate by +20+20.
3
Apply the first turn and calculate the second position.
Current position is (15,5)(15, 5).
Turning 135135^\circ clockwise from North means the guard now faces South-East. Walking 152 m15\sqrt{2}\text{ m} South-East yields a horizontal displacement of +15 m+15\text{ m} (East) and vertical displacement of 15 m-15\text{ m} (South). New coordinates: (0+15,2015)=(15,5)(0+15, 20-15) = (15, 5).
4
Apply the final turn and calculate the final position.
Final position is (15,20)(15, 20).
Turning 135135^\circ counter-clockwise from South-East means subtracting 135135^\circ, placing the guard back to facing North. Walking 15 m15\text{ m} straight (North) changes the Y-coordinate by +15+15. New coordinates: (15,5+15)=(15,20)(15, 5+15) = (15, 20).
5
Calculate the shortest distance and direction from the origin (0,0)(0,0).
Distance is 25 m25\text{ m}, Direction is North-East.
Applying the Pythagorean theorem: 152+202=225+400=625=25 m\sqrt{15^2 + 20^2} = \sqrt{225 + 400} = \sqrt{625} = 25\text{ m}. Since both X and Y coordinates are positive, the direction relative to the start is North-East.

Anahtar Kavram

Vector displacement combining angular turns, Cartesian coordinates, and shadow-based directional framing.
Soru 263Soru

An encrypted communication protocol transforms a four-letter source word into a target code using a consistent multi-step positional rule.

According to this protocol, the word FLUX\text{FLUX} is transformed into SMDA\text{SMDA}, and the word MIND\text{MIND} is transformed into LPKU\text{LPKU}.

Based on the identical cryptographic logic, what will be the resulting code for the word CURE\text{CURE}?

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Cevap: VDGT\text{VDGT}

Cevap

The correct code for the word is VDGT\text{VDGT}.
The established protocol follows a compound two-step rule: first, find the reverse alphabetical counterpart of each letter (where A=Z, B=Y, or mathematically 27Position27 - \text{Position}), and second, shift that new letter backward by 2 positions. Applying this to CURE: the reverse alphabetical sequence is XFIV. Shifting each of these letters back by 2 positions yields VDGT.

Adım Adım Çözüm

1
Analyze the positional relationship between the letters in the first example pair, FLUX and SMDA.
F(6) maps to S(19), L(12) maps to M(13), U(21) maps to D(4), and X(24) maps to A(1).
Finding the numerical alphabet positions is the required first step to decode letter-based analogies.
2
Identify the compound mathematical rule linking these letter positions.
The pattern involves two steps: first finding the Reverse Alphabetical Position (where A=Z, B=Y, or 27Position27 - \text{Position}), followed by a constant shift of -2. For example, F(6) → Reverse is U(21) → 212=1921 - 2 = 19 (S).
A single direct shift does not work consistently across all letters, indicating a multi-step positional transformation is being used.
3
Verify the identified rule using the second example pair, MIND and LPKU.
M(13) → Reverse N(14) → 142=1214 - 2 = 12 (L). I(9) → Reverse R(18) → 182=1618 - 2 = 16 (P). N(14) → Reverse M(13) → 132=1113 - 2 = 11 (K). D(4) → Reverse W(23) → 232=2123 - 2 = 21 (U). The rule holds perfectly.
Validating the hypothesized rule against a second example ensures the correct logic has been discovered.
4
Apply the verified two-step rule to the target word, CURE.
C(3) → Reverse X(24) → 242=2224 - 2 = 22 (V). U(21) → Reverse F(6) → 62=46 - 2 = 4 (D). R(18) → Reverse I(9) → 92=79 - 2 = 7 (G). E(5) → Reverse V(22) → 222=2022 - 2 = 20 (T).
Executing the established logic yields the final required code sequence: VDGT.

Anahtar Kavram

Compound Letter Analogy (Reverse Alphabetical Pairs and Constant Shift)
Tahmini Süre:1m 15s
Soru 264Soru

During a summit, a single straight row of delegates is seated facing South. Mr. Patel is seated 21st21^{\text{st}} from the right end of the row. Ms. Quinn is seated 28th28^{\text{th}} from the left end of the row. Dr. Ray is seated 7th7^{\text{th}} to the left of Mr. Patel and 5th5^{\text{th}} to the right of Ms. Quinn. What is the total number of delegates in the row?

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Cevap: 36

Cevap

The total number of delegates in the row is 36.
Because the delegates are facing South, their personal left corresponds to the right end of the row, and their personal right corresponds to the left end of the row. Dr. Ray is 77 seats to the left of Mr. Patel (21st21^{\text{st}} from the right), making him 217=14th21 - 7 = 14^{\text{th}} from the right end. Dr. Ray is 55 seats to the right of Ms. Quinn (28th28^{\text{th}} from the left), making him 285=23rd28 - 5 = 23^{\text{rd}} from the left end. The total number of delegates is the sum of Dr. Ray's position from both ends minus one (to avoid double-counting him): 23+141=3623 + 14 - 1 = 36.

Adım Adım Çözüm

1
Determine the relative left and right directions for delegates facing South.
For someone facing South, their 'Left' points toward the Right End of the row, and their 'Right' points toward the Left End of the row.
Correctly mapping personal left/right to the absolute row ends is required before applying positional offsets.
2
Calculate Dr. Ray's absolute position from the right end of the row.
Mr. Patel is 21st21^{\text{st}} from the right end. Dr. Ray is 7th7^{\text{th}} to his left (toward the right end). Dr. Ray is 217=14th21 - 7 = 14^{\text{th}} from the right end.
Because Dr. Ray is to Mr. Patel's left, and left points toward the right end, Dr. Ray is closer to the right end than Mr. Patel.
3
Calculate Dr. Ray's absolute position from the left end of the row.
Ms. Quinn is 28th28^{\text{th}} from the left end. Dr. Ray is 5th5^{\text{th}} to her right (toward the left end). Dr. Ray is 285=23rd28 - 5 = 23^{\text{rd}} from the left end.
Because Dr. Ray is to Ms. Quinn's right, and right points toward the left end, Dr. Ray is closer to the left end than Ms. Quinn.
4
Calculate the total number of delegates using Dr. Ray's known positions from both ends.
Total = (Position from Left) + (Position from Right) - 1 = 23+141=3623 + 14 - 1 = 36.
The sum of a person's rank from both ends counts that person twice, so 1 must be subtracted to find the accurate total.

Anahtar Kavram

Positional Ranking with Directional Inversion
Soru 265Soru

Six historical monuments—Alhambra, Big Ben, Colosseum, Machu Picchu, Parthenon, and Stonehenge—are scheduled for renovation over a period of six months, from January (1st) to June (6th). The renovation schedule strictly follows these conditions:

- There is exactly one monument scheduled for renovation between Machu Picchu and Alhambra.
- Big Ben is scheduled immediately before the Parthenon.
- The Colosseum is scheduled somewhere after Machu Picchu, but it is not the final monument (6th) to be renovated.
- Stonehenge is scheduled immediately before Alhambra.
- Stonehenge is scheduled somewhere before the Parthenon.

Arrange the monuments in their correct renovation sequence from January (1st) to June (6th).

Öğeleri doğru sıraya koymak için sürükleyin

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Cevap

Machu Picchu, Stonehenge, Alhambra, Colosseum, Big Ben, Parthenon
The correct sequence is logically derived by assembling fixed blocks. Stonehenge is immediately before Alhambra, creating [Stonehenge, Alhambra]. Machu Picchu has exactly one monument between it and Alhambra, which must be Stonehenge, forming the continuous block [Machu Picchu, Stonehenge, Alhambra]. Big Ben is immediately before the Parthenon, giving [Big Ben, Parthenon]. Because Stonehenge must be before the Parthenon, the [Big Ben, Parthenon] block must come later in the schedule. Placing the remaining monument (Colosseum) requires putting it after Machu Picchu but not in the 6th spot. Placing the Colosseum 4th, followed by [Big Ben, Parthenon] in 5th and 6th, perfectly satisfies all conditions.

Adım Adım Çözüm

1
Identify the definitive adjacent blocks of monuments based on the immediate sequence clues.
Two blocks are formed: [Stonehenge, Alhambra] and [Big Ben, Parthenon].
The clues explicitly state that Stonehenge is scheduled immediately before Alhambra, and Big Ben is scheduled immediately before the Parthenon.
2
Determine the relative placement of Machu Picchu in relation to the [Stonehenge, Alhambra] block.
Machu Picchu must be placed immediately before Stonehenge, forming the 3-monument block: [Machu Picchu, Stonehenge, Alhambra].
There is exactly one monument between Machu Picchu and Alhambra. Since Stonehenge is immediately before Alhambra, the sequence must be either [Machu Picchu, Stonehenge, Alhambra] or [Stonehenge, Alhambra, (gap), Machu Picchu]. If it were the latter, the gap would have to be the Colosseum. However, that sequence would put Colosseum before Machu Picchu, violating the clue that Colosseum is after Machu Picchu.
3
Position the remaining blocks to finalize the six-month sequence.
The final sequence is Machu Picchu (1), Stonehenge (2), Alhambra (3), Colosseum (4), Big Ben (5), Parthenon (6).
The [Machu Picchu, Stonehenge, Alhambra] block must precede the [Big Ben, Parthenon] block because Stonehenge is before Parthenon. This leaves spots 4, 5, and 6. The Colosseum must come after Machu Picchu but cannot be 6th. Therefore, the Colosseum is 4th, Big Ben is 5th, and the Parthenon is 6th.

Anahtar Kavram

Positional arrangement using overlapping sequence blocks and negative constraints.
Tahmini Süre:2m 0s
Soru 266Soru

A prominent industrial facility was inaugurated on March 1515, 18971897, which happened to be a Monday. The facility's operational license mandated a comprehensive structural safety inspection exactly 1010 years later on the exact same date. What day of the week was the inspection scheduled for?

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Cevap: Friday

Cevap

The inspection was scheduled for Friday.
Between 18971897 and 19071907, a span of 1010 years elapses, producing a baseline of 1010 odd days. It is critical to recognize that the year 19001900, despite being a multiple of 44, is a century year not divisible by 400400, and therefore is not a leap year. The only leap year in this timeframe is 19041904. Adding this 11 extra odd day gives a total of 1111 odd days. Dividing 1111 by 77 yields a remainder of 44. Advancing 44 days forward from Monday gives Friday.

Adım Adım Çözüm

1
Determine the total interval of years between the start and end dates.
The period from March 1515, 18971897 to March 1515, 19071907 is exactly 1010 years.
Every standard year provides 11 odd day, giving a baseline of 1010 odd days.
2
Identify the number of leap years within this specific 1010-year interval.
The only leap year crossed is 19041904. The year 19001900 is a century year not divisible by 400400, meaning it is a standard year of 365365 days.
Leap years contain 366366 days and contribute an extra odd day. Century years follow a different mathematical rule for leap year designation.
3
Calculate the total number of odd days accrued over the period.
1010 baseline odd days + 11 extra odd day (for the leap year 19041904) = 1111 total odd days.
Total odd days equal the number of years plus the number of leap years in the given interval.
4
Find the equivalent shift within a standard 77-day week.
11(mod7)=411 \pmod 7 = 4 odd days.
Because the days of the week cycle every 77 days, we only use the remainder to find the final day.
5
Add the calculated odd days to the initial day of the week.
Monday + 44 days = Friday.
Moving 44 days forward in the weekly cycle from Monday lands precisely on Friday.

Anahtar Kavram

Calculating odd days across calendar intervals containing non-leap century boundaries.
Soru 267Soru

In a certain logical classification system, the word PLANET\text{PLANET} is related to the letter-group KODMHG\text{KODMHG}. Following the same analogical pattern, which of the following letter-groups corresponds to the word MODULE\text{MODULE}?

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Cevap: NRWXOH\text{NRWXOH}

Cevap

The correct letter-group is NRWXOH\text{NRWXOH}.
The established logical rule applies two different transformations based on letter type. Consonants are replaced by their alphabetical opposites (mirror letters), while vowels are shifted forward by 3 positions. Applying this to MODULE\text{MODULE}: the consonants M, D, L mirror to N, W, O, and the vowels O, U, E shift forward by 3 to R, X, H. Combining these yields NRWXOH\text{NRWXOH}.

Adım Adım Çözüm

1
Analyze the consonants in the reference word PLANET\text{PLANET}.
The consonants P, L, N, T\text{P, L, N, T} become K, O, M, G\text{K, O, M, G}.
To identify the specific logical operation applied to consonants. Each consonant is replaced by its alphabetical mirror (e.g., the 16th letter from the start, P, becomes the 16th letter from the end, K).
2
Analyze the vowels in the reference word PLANET\text{PLANET}.
The vowels A, E\text{A, E} become D, H\text{D, H}.
To identify if vowels follow the same or a different rule. Each vowel is shifted forward by exactly 3 positions in the alphabet (A+3=D, E+3=H).
3
Separate the target word MODULE\text{MODULE} into consonants and vowels.
Consonants: M, D, L\text{M, D, L}. Vowels: O, U, E\text{O, U, E}.
To accurately apply the distinct coding rules established in the previous steps.
4
Apply the corresponding rules to the letters of MODULE\text{MODULE}.
Consonants (mirror): MN\text{M} \rightarrow \text{N}, DW\text{D} \rightarrow \text{W}, LO\text{L} \rightarrow \text{O}. Vowels (+3 shift): OR\text{O} \rightarrow \text{R}, UX\text{U} \rightarrow \text{X}, EH\text{E} \rightarrow \text{H}.
To generate the individual components of the final coded string.
5
Reassemble the transformed letters in their original order.
The sequence is N, R, W, X, O, H\text{N, R, W, X, O, H}.
To form the final answer based on the analogical framework.

Anahtar Kavram

Dual-Pattern Alphabetical Analogy
Soru 268Soru

A digital library archiving system generates tags for its collections using a specific alphabetic transformation logic. In this system, the word INDEX is coded as GQGCA, and the word BOOK is coded as EMMN.

Using the exact same logic, what is the exact code for the word SHELF?

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Cevap: VKCOI; vkcoi

Cevap

VKCOI
The established coding rule categorizes letters into consonants and vowels. Consonants are shifted forward by 3 alphabetical positions in a circular manner, while vowels are shifted backward by 2 positions. Applying this specific rule to the word SHELF: S (consonant + 3) = V, H (consonant + 3) = K, E (vowel - 2) = C, L (consonant + 3) = O, and F (consonant + 3) = I. This produces the final correct code VKCOI.

Adım Adım Çözüm

1
Analyze the first example 'INDEX' to identify the alphabetical shift pattern for each letter.
I (-2) = G, N (+3) = Q, D (+3) = G, E (-2) = C, X (+3) = A.
Determining the numerical alphabetical shift for each individual letter is the foundational step in decoding the logic.
2
Analyze the second example 'BOOK' to verify the logic and rule out position-based shifting.
B (+3) = E, O (-2) = M, O (-2) = M, K (+3) = N.
A second example confirms whether the shift depends on the letter's position in the word or its phonetic classification (vowel vs. consonant).
3
Deduce the universal coding rule from the confirmed shift patterns.
Consonants are shifted forward by 3 positions (+3), and vowels are shifted backward by 2 positions (-2).
A consistent, unified rule must be fully established before attempting to encode the target word.
4
Apply the deduced rule to the target word 'SHELF'.
S (consonant) + 3 = V, H (consonant) + 3 = K, E (vowel) - 2 = C, L (consonant) + 3 = O, F (consonant) + 3 = I.
Executing the exact transformation on the target string yields the final requested code.

Anahtar Kavram

Alphabetic transformation using conditional logic based on vowel and consonant classification.
Tahmini Süre:1m 30s
Soru 269Soru

The second letter-group is related to the first letter-group following a specific logical pattern. Based on this same pattern, which of the following letter-groups replaces the question mark?

FLUID:XRIUZ::SMART:?\text{FLUID} : \text{XRIUZ} :: \text{SMART} : \text{?}

Cevabı ve açıklamayı göster

Cevap: KQCLJ

Cevap

KQCLJ
The correct answer is derived by first replacing each letter in the word 'SMART' with its reverse alphabetical pair (S becomes H, M becomes N, A becomes Z, R becomes I, T becomes G), and then shifting each resulting letter forward by 3 positions in the alphabet to yield 'KQCLJ'.

Adım Adım Çözüm

1
Analyze the relationship between the first pair of letter-groups (FLUID and XRIUZ).
Identify the two-step transformation: finding the reverse alphabetical letter for each character, then shifting forward by 3 positions.
Establishing the exact dual-rule pattern in the complete pair is necessary to reliably apply it to the target word.
2
Apply the first step (reverse alphabetical position) to the word SMART.
S becomes H, M becomes N, A becomes Z, R becomes I, and T becomes G, resulting in the intermediate string HNZIG.
This completes the mirror pair transformation based on the established sequence of logic.
3
Apply the second step (forward shift of +3) to the intermediate result HNZIG.
H+3 = K, N+3 = Q, Z+3 = C, I+3 = L, G+3 = J. The final letter-group is KQCLJ.
This completes the full transformation rule, providing the final missing analogical term.

Anahtar Kavram

Letter Analogy and Coding Dual Transformations
Soru 270Soru

In a museum's digital archiving system, historical artifacts are tagged using a specific alphabetical transformation pattern. For example, the tag for SEAL is generated as TDBK, and the tag for IRON is generated as JQPM. Based on this established coding logic, match the following artifact materials with their correct encoded tags.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

CLAY
SILK
WOOD
JADE

Eşleşmeler

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Cevap

The correct matches are: CLAY with DKBX, SILK with THMJ, WOOD with XNPC, and JADE with KZED.
By analyzing the given examples, the coding logic follows a strict alternating sequence of shifting the first letter forward by one position (+1), the second letter backward by one position (-1), the third forward by one (+1), and the fourth backward by one (-1) according to the standard English alphabet.

Adım Adım Çözüm

1
Analyze the first example code (SEAL to TDBK) to find the position shift logic.
S to T is +1; E to D is -1; A to B is +1; L to K is -1.
Identifying the letter-by-letter transformation rule is the fundamental first step in decoding the pattern.
2
Verify the hypothesized rule with the second example (IRON to JQPM).
I(+1)=J, R(-1)=Q, O(+1)=P, N(-1)=M. The pattern is consistently an alternating +1 and -1 shift.
Confirming the rule with a second example ensures the deduced logic is universally applied and not coincidental.
3
Apply the alternating +1, -1, +1, -1 rule to each of the given artifact materials.
CLAY translates to DKBX. SILK translates to THMJ. WOOD translates to XNPC. JADE translates to KZED.
This generates the final encoded tags to pair with the original given items.

Anahtar Kavram

Alternating Alphabetical Position Shifts
Soru 271Soru

Eight researchers—Aris, Boris, Celine, Darius, Ezra, Fiona, Gemma, and Hector—are seated in a single straight row. Some of them are facing North while others are facing South. Note that 'left' and 'right' directions depend on the direction a specific person is facing.

The seating arrangement follows these conditions:
1. No three adjacent researchers face the same direction.
2. Boris sits fourth from the left end of the row and faces North.
3. Darius sits to the immediate right of Boris. Darius faces South.
4. Exactly three people sit between Darius and Hector.
5. Aris sits at one of the extreme ends of the row and faces North.
6. Ezra sits to the immediate left of Aris. Ezra faces South.
7. Gemma sits to the immediate right of Ezra.
8. Celine sits second to the left of Hector.
9. The immediate neighbors of Celine face opposite directions to each other.

Based on the final seating arrangement, arrange the following researchers in their correct sitting order from the extreme left side of the row to the right side:

Öğeleri doğru sıraya koymak için sürükleyin

Cevabı ve açıklamayı göster

Cevap

The correct left-to-right order of the specified researchers is Fiona, Celine, Gemma, and then Aris.
By systematically mapping the directional clues across 8 positions (Left/West to Right/East), we deduce the full arrangement: Hector(South) at 1, Fiona(South) at 2, Celine(North) at 3, Boris(North) at 4, Darius(South) at 5, Gemma(North) at 6, Ezra(South) at 7, and Aris(North) at 8. Extracting the requested researchers gives the left-to-right sequence: Fiona, Celine, Gemma, Aris.

Adım Adım Çözüm

1
Determine the positions of Boris, Darius, Hector, and Aris based on absolute clues.
Boris is at position 4 (North). Darius is at position 5 (South). Hector is at position 1. Aris is at position 8 (North).
Boris is 4th from left. Darius is immediate right of Boris (North), so Darius is 5th. Three people sit between Darius (5) and Hector, placing Hector at 1. Aris is at an extreme end, and since 1 is occupied, Aris must be at 8.
2
Determine the positions of Ezra and Gemma using relative directional clues.
Ezra is at position 7 (South). Gemma is at position 6.
Ezra is immediate left of Aris (facing North), placing Ezra at 7. Ezra faces South; Gemma is immediate right of Ezra, placing Gemma at position 6 (towards the West/left side).
3
Determine Hector's direction to place Celine, then place Fiona.
Hector faces South. Celine is at position 3. Fiona is at position 2.
Celine is second to the left of Hector (1). If Hector faced North, his left would be outside the row. Thus, Hector must face South, making his left point East. Position 1 + 2 = 3. Fiona takes the only remaining empty seat at position 2.
4
Deduce the remaining facing directions using the adjacency rules.
Fiona (South), Celine (North), Gemma (North).
Celine's neighbors (Fiona and Boris) face opposite directions; since Boris faces North, Fiona faces South. Hector (1) and Fiona (2) face South, so Celine (3) must face North to prevent three adjacent Souths. Similarly, Darius (5) and Ezra (7) face South, so Gemma (6) must face North.

Anahtar Kavram

Advanced Seating Arrangement with Mixed Facing Directions
Soru 272Soru

A futuristic space station log states that Commander Vika was born on Earth on Saturday, February 29, 2284. According to intergalactic law, she only officially celebrates her birthday when the exact date of February 29 occurs on the calendar. On what day of the week will Commander Vika officially celebrate her 5th birthday?

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Cevap: Sunday

Cevap

Commander Vika will celebrate her 5th birthday on a Sunday.
Commander Vika was born on February 29, 2284. Her birthdays occur only on leap years. Her first three birthdays are in 2288, 2292, and 2296. The year 2300 is a century year not divisible by 400, meaning it is not a leap year. Therefore, her 4th birthday is in 2304, and her 5th is in 2308. The span from 2284 to 2308 is 24 years. During this 24-year span, there are exactly 5 leap years (2288, 2292, 2296, 2304, 2308). The total number of odd days is the number of years plus the number of leap years: 24+5=2924 + 5 = 29. Dividing 29 by 7 gives a remainder of 1. One day after Saturday is Sunday.

Adım Adım Çözüm

1
Determine the years of the first five birthdays, keeping in mind the rules for century leap years.
Birthdays occur in 2288 (1st), 2292 (2nd), 2296 (3rd), 2304 (4th), and 2308 (5th).
The year 2300 is not divisible by 400, so it is not a leap year. There is no February 29 in 2300, forcing the 4th birthday to shift to 2304.
2
Calculate the total number of years elapsed between the birth year and the 5th birthday.
23082284=242308 - 2284 = 24 years.
Each standard year contributes 1 odd day to the calendar shift.
3
Count the exact number of leap days (February 29ths) experienced after the birth date.
There are 5 leap days experienced: in 2288, 2292, 2296, 2304, and 2308.
Each leap year contributes an additional 1 odd day on top of the standard year's 1 odd day.
4
Calculate the total odd days and determine the final day of the week.
Total odd days = 24+5=2924 + 5 = 29. Calculating 29(mod7)29 \pmod{7} gives a remainder of 11. Saturday + 11 day = Sunday.
The day of the week advances by the remainder of the total odd days divided by 7.

Anahtar Kavram

Calculating odd days across century boundaries that are not leap years.
Soru 273Soru

A global supply chain software tracks cargo shipments by encrypting destination city names to ensure data privacy. In this system, the destination "LONDON" is coded as "OLMFQP" and "BERLIN" is coded as "YVINKP". Based on this coding logic, how will the destination "MUMBAI" be coded in this tracking system?

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Cevap: NFNDCK

Cevap

NFNDCK
The coding logic splits the word into two equal halves. The letters in the first half are replaced by their reverse alphabetical counterparts (i.e., A=Z, B=Y, or position 27 - n). The letters in the second half are shifted forward by 2 positions in the alphabet. For 'MUMBAI', the first half 'MUM' becomes 'NFN' through reverse indexing, and the second half 'BAI' becomes 'DCK' through a +2 shift. Combining these yields 'NFNDCK'.

Adım Adım Çözüm

1
Analyze the first example "LONDON" -> "OLMFQP" by comparing the alphabetical positions of the letters.
The word is split into two equal halves: "LON" and "DON". 'L' becomes 'O', 'O' becomes 'L', 'N' becomes 'M'. 'D' becomes 'F', 'O' becomes 'Q', 'N' becomes 'P'.
To identify the underlying mathematical transformation rules applied to the letters.
2
Determine the specific logical rules for each half of the word.
For the first half ("LON" -> "OLM"), each letter is replaced by its reverse alphabetical counterpart (e.g., L is the 12th letter from the start, O is 12th from the end; mathematically, 27 - 12 = 15). For the second half ("DON" -> "FQP"), each letter is shifted forward by 2 positions (+2).
To establish a concrete, two-part rule that can be verified and applied.
3
Verify the extracted rules using the second example "BERLIN" -> "YVINKP".
Split into "BER" and "LIN". The reverse alphabetical index of B, E, R gives Y, V, I. Shifting L, I, N forward by 2 gives N, K, P. The rule holds perfectly.
To ensure the pattern is consistent and correct before applying it to the target word.
4
Apply the verified rules to the target word "MUMBAI".
Split into "MUM" and "BAI". Reverse index for MUM: M(13) → N(14), U(21) → F(6), M(13) → N(14). Forward +2 shift for BAI: B(2) → D(4), A(1) → C(3), I(9) → K(11). Combining these halves gives "NFNDCK".
To calculate the final encrypted code based on the established logic.

Anahtar Kavram

Identifying split-pattern coding sequences utilizing reverse alphabetical indexing and positional shifts.
Soru 274Soru

A large solid cube is constructed using 125125 smaller, identical cubic blocks. Before the large cube is painted, all 88 corner blocks are completely removed from the structure. The resulting modified structure is then completely dipped in a vat of red paint. After the paint dries, the structure is disassembled back into the remaining 117117 individual smaller blocks. How many of these 117117 smaller blocks have exactly two of their faces painted red?

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Cevap: 12

Cevap

12
In a standard 5×5×55 \times 5 \times 5 cube, the blocks with exactly two painted faces are located along the edges (excluding the corners). There are 52=35 - 2 = 3 such blocks per edge. However, when the 88 corner blocks are removed, the structural integrity changes. The edge blocks directly adjacent to the removed corners get an additional face exposed (the inner face that was previously touching the corner). This increases their painted faces from 22 to 33. Only the single block in the exact middle of each of the 1212 edges remains unaffected by the corner removal, keeping exactly 22 exposed faces. Thus, there are 12 edges×1 block/edge=1212 \text{ edges} \times 1 \text{ block/edge} = 12 such blocks.

Adım Adım Çözüm

1
Analyze the original edge composition of the 5x5x5 cube.
The cube has 12 edges. Each edge consists of 5 blocks: 2 corner blocks and 3 middle edge blocks.
To establish the baseline before the corners are removed.
2
Determine the spatial effect of removing the 8 corner blocks.
Removing a corner creates a 'dent'. The 3 edge blocks that were directly touching this corner now have an interior face exposed to the outside.
Paint will now reach surfaces that were previously hidden inside the structure.
3
Calculate the newly painted faces for the affected edge blocks.
The 2 edge blocks at the ends of each 3-block edge segment originally had 2 exposed faces. They now have 1 additional exposed face, bringing their total to 3 painted faces.
To eliminate these blocks from the target count of blocks with exactly 2 painted faces.
4
Identify the blocks that maintain exactly two exposed faces.
Only the single block in the exact center of each 5-block edge does not touch a corner. Its exposed faces remain unchanged at 2.
These are the only blocks in the entire modified structure that fit the criteria.
5
Calculate the final total.
12 edges multiplied by 1 block per edge equals 12 blocks.
To reach the final quantitative answer.

Anahtar Kavram

Spatial reasoning and dynamic visualization of modified 3D geometric structures.
Soru 275Soru

During a data encryption analysis, a student is asked to classify four specific data blocks represented by four-letter strings. Three of these strings are generated using the identical sequential shifting rule based on the standard 26-letter English alphabet. Which of the following data blocks fails to follow the established encryption rule?

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Cevap: RUFH

Cevap

The correct answer is the string RUFH.
The string RUFH is the correct answer because it deviates from the common pattern shared by the other three strings. While it correctly follows the first two steps of the pattern (a forward shift of 3, followed by its alphabetical opposite), the final step deviates. The established pattern requires a backward shift of 2 positions (-2), which from F (6) would yield D (4). However, RUFH ends with an H (8), representing an incorrect +2 shift.

Adım Adım Çözüm

1
Analyze the alphabetical position of the letters in the first group to identify a potential structural pattern.
In the string HKPN: H (8) to K (11) is a +3 shift. K (11) and P (16) form a reverse alphabetical pair (sum = 27). P (16) to N (14) is a -2 shift.
Determining the step-by-step mathematical shifts establishes the baseline logical rule for classification.
2
Apply this hypothesized rule (+3, reverse pair, -2) to the other options to verify consistency.
CFUS: C(3)+3=F(6); F(6)+U(21)=27; U(21)-2=S(19). Valid. MPKI: M(13)+3=P(16); P(16)+K(11)=27; K(11)-2=I(9). Valid.
Checking multiple strings confirms the structural rule is universally applied across the legitimate group members.
3
Evaluate the remaining string to confirm its deviation from the established pattern.
In RUFH: R(18)+3=U(21). U(21)+F(6)=27 (reverse pair). However, the final step is F(6) to H(8), which is a +2 shift instead of the expected -2 shift. The correct final letter should have been D (6 - 2 = 4).
Classification requires finding the single option that deviates from the common pattern shared by all others.

Anahtar Kavram

Letter cluster classification through sequential positional transformations and mirror pairs.
Soru 276Soru

Four athletes are training on a large flat ground. Match each athlete's movement sequence with their final direction relative to their respective starting points.

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Öğeler

Athlete P: Runs 30 m30\text{ m} North, turns right to run 40 m40\text{ m}, then turns right again and runs 30 m30\text{ m}.
Athlete Q: Runs 50 m50\text{ m} South, turns left to run 20 m20\text{ m}, then turns left again and runs 70 m70\text{ m}.
Athlete R: Runs 40 m40\text{ m} West, turns right to run 40 m40\text{ m}, then turns left and runs 20 m20\text{ m}.
Athlete S: Runs 60 m60\text{ m} East, turns right to run 50 m50\text{ m}, then turns right again and runs 80 m80\text{ m}.

Eşleşmeler

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Cevap

Athlete P matches with East, Athlete Q matches with North-East, Athlete R matches with North-West, and Athlete S matches with South-West.
By placing each athlete's starting point at an origin (0,0)(0,0) on a Cartesian plane, their movements can be translated into coordinate updates. P ends at (40,0)(40, 0) which is East. Q ends at (20,20)(20, 20) which is North-East. R ends at (60,40)(-60, 40) which is North-West. S ends at (20,50)(-20, -50) which is South-West.

Adım Adım Çözüm

1
Calculate final position of Athlete P.
Starts at (0,0)(0,0). Moves to (0,30)(0, 30) after going North, then to (40,30)(40, 30) after running East, and finally down to (40,0)(40, 0) after running South.
Tracking coordinates simplifies finding the final direction. The point (40,0)(40, 0) lies exactly on the positive x-axis, meaning the direction is East.
2
Calculate final position of Athlete Q.
Starts at (0,0)(0,0). Moves to (0,50)(0, -50) after going South. A left turn from South faces East, moving to (20,50)(20, -50). Another left turn faces North, moving 70 m70\text{ m} to (20,20)(20, 20).
The final point (20,20)(20, 20) has positive x (East) and positive y (North) components, placing it in the North-East direction from the origin.
3
Calculate final position of Athlete R.
Starts at (0,0)(0,0). Moves to (40,0)(-40, 0) after going West. A right turn from West faces North, moving to (40,40)(-40, 40). A left turn faces West, moving to (60,40)(-60, 40).
The final point (60,40)(-60, 40) has a negative x (West) and positive y (North) component, placing it in the North-West direction.
4
Calculate final position of Athlete S.
Starts at (0,0)(0,0). Moves to (60,0)(60, 0) after going East. A right turn faces South, moving to (60,50)(60, -50). Another right turn faces West, moving 80 m80\text{ m} to (20,50)(-20, -50).
The final point (20,50)(-20, -50) has a negative x (West) and negative y (South) component, placing it in the South-West direction.

Anahtar Kavram

Tracking sequential movements using cardinal directions and angular turns to determine net displacement and final relative direction.
Tahmini Süre:2m 0s
Soru 277Soru

Analyze the logical relationship between the entities in Column X. Then, pair each with the corresponding set of entities in Column Y that demonstrates the exact same analogical relationship.

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Öğeler

Scalpel : Surgeon
Parchment : Manuscript
Ignorance : Education
Prologue : Play

Eşleşmeler

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Cevap

Scalpel : Surgeon matches Awl : Cobbler; Parchment : Manuscript matches Clay : Pottery; Ignorance : Education matches Drought : Irrigation; Prologue : Play matches Preamble : Constitution.
Each pair in Column X possesses a unique, definitive logical relationship that exactly mirrors a specific pair in Column Y. The tool-to-user, material-to-product, condition-to-remedy, and introduction-to-document mappings accurately pair the items without ambiguity.

Adım Adım Çözüm

1
Analyze the relationship in 'Scalpel : Surgeon'.
Identified as a 'Tool : Professional' relationship.
This allows us to find the equivalent pair in Column Y, which is 'Awl : Cobbler'.
2
Analyze the relationship in 'Parchment : Manuscript'.
Identified as a 'Raw Material : Finished Product' relationship.
This allows us to match it with 'Clay : Pottery', where clay is the raw material shaped into pottery.
3
Analyze the relationship in 'Ignorance : Education'.
Identified as a 'Negative Condition : Remedy' relationship.
This allows us to match it with 'Drought : Irrigation', since irrigation solves the condition of drought.
4
Analyze the relationship in 'Prologue : Play'.
Identified as an 'Introduction : Main Work' relationship.
This allows us to match it with 'Preamble : Constitution', which shares the identical structural relationship.

Anahtar Kavram

Identifying underlying semantic and structural relationships between word pairs to classify and match equivalent verbal analogies.
Soru 278Soru

A maritime shipping contract was enacted on Wednesday, October 14, 1795. The agreement stipulated a mandatory review and renegotiation exactly 14 years later, on October 14, 1809. On what day of the week did the renegotiation fall?

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Cevap: Saturday

Cevap

Saturday
The interval is exactly 14 years. Within this period, there are 3 leap years: 1796, 1804, and 1808. The year 1800 is a century year not divisible by 400, so it is not a leap year. This creates a total of 14 + 3 = 17 odd days. Dividing 17 by 7 gives a remainder of 3. Advancing 3 days from Wednesday results in Saturday.

Adım Adım Çözüm

1
Calculate the total number of years elapsed between the two dates.
1809 - 1795 = 14 years.
Each normal year contributes 1 odd day, so determining the year gap gives the base number of odd days.
2
Identify the number of leap years occurring strictly within this 14-year period.
The leap years are 1796, 1804, and 1808. The year 1800 is not a leap year. Total = 3 leap years.
Century years (ending in 00) must be divisible by 400 to be leap years. Each valid leap year adds 1 additional odd day.
3
Calculate the total number of odd days.
14 (base odd days) + 3 (additional leap year days) = 17 total odd days.
Combining base year odd days with extra leap year odd days yields the complete shift in the weekly cycle.
4
Find the remainder when the total odd days are divided by 7, and add it to the starting day.
17 divided by 7 leaves a remainder of 3. Wednesday + 3 days = Saturday.
The days of the week repeat on a 7-day cycle, so only the remainder affects the final day.

Anahtar Kavram

Calculating odd days across century boundaries and identifying century leap years.
Soru 279Soru

In a certain coding language, words are translated by shifting each letter forward in the English alphabet based on its positional index within the word. The first letter is shifted by one position, the second letter by two positions, the third letter by three positions, and so on. Based on this translation rule, match the given words on the left with their correctly coded equivalents on the right.

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Öğeler

STAR
WIND
LOCK
PUMP

Eşleşmeler

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Cevap

STAR matches with TVDV, WIND matches with XKQH, LOCK matches with MQFO, and PUMP matches with QWPT.
By successfully applying a variable forward shift (+1 for the first letter, +2 for the second, +3 for the third, and +4 for the fourth) to each original word, we generate their exact coded counterparts.

Adım Adım Çözüm

1
Identify the core logic for the encryption method.
Each letter is shifted forward by its index position in the word (+1, +2, +3, +4).
This establishes the rule needed to decode or encode all the given words.
2
Apply the progressive shift to the word 'STAR'.
S(+1) = T, T(+2) = V, A(+3) = D, R(+4) = V. The encoded word is TVDV.
To accurately pair the first item.
3
Apply the progressive shift to the word 'WIND'.
W(+1) = X, I(+2) = K, N(+3) = Q, D(+4) = H. The encoded word is XKQH.
To accurately pair the second item.
4
Apply the progressive shift to the word 'LOCK'.
L(+1) = M, O(+2) = Q, C(+3) = F, K(+4) = O. The encoded word is MQFO.
To accurately pair the third item.
5
Apply the progressive shift to the word 'PUMP'.
P(+1) = Q, U(+2) = W, M(+3) = P, P(+4) = T. The encoded word is QWPT.
To accurately pair the final item.

Anahtar Kavram

Positional Letter Shifting
Soru 280Soru

Study the logical relationship between the first pair of letter-clusters. Applying the identical underlying rule, what will replace the question mark to complete the second pair?

BIRD:ERUW::FISH:?\text{BIRD} : \text{ERUW} :: \text{FISH} : \text{?}

Cevabı ve açıklamayı göster

Cevap: IRVS

Cevap

IRVS
The underlying pattern alternates between a forward alphabetical shift of 3 positions and finding the reverse alphabetical equivalent letter. Applying this strictly to the word 'FISH' yields 'I' (F+3), 'R' (reverse of I), 'V' (S+3), and 'S' (reverse of H), resulting in 'IRVS'.

Adım Adım Çözüm

1
Analyze the transformation from BIRD to ERUW position by position.
1st letter (B to E) is a +3 forward shift. 2nd letter (I to R) is the reverse alphabetical pair. 3rd letter (R to U) is a +3 forward shift. 4th letter (D to W) is the reverse alphabetical pair.
Establishing the exact sequence of logical operations applied to the first pair is necessary to solve the analogy.
2
Apply the identical transformation rule to the target word FISH.
1st letter (F) + 3 = I. 2nd letter (I) reverse = R. 3rd letter (S) + 3 = V. 4th letter (H) reverse = S.
The analogy requires the second pair to exhibit the exact same multi-step operational pattern as the first pair.

Anahtar Kavram

Alphabet/Letter Pattern Analogy using compound positional rules
ÖncekiSayfa 14 / 16Sonraki
General Mental Ability Alıştırma Soruları — State PSC Exam — Sayfa 14 | Examkin