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Zorluk: KolayNephrology

A 4545-year-old man is brought to the emergency department by his sister due to altered mental status. She states that he has a history of alcohol use disorder and was found confused in his apartment with an empty bottle of antifreeze nearby. Laboratory studies show:

LabValue
Serum sodium140 mEq/L140 \text{ mEq/L}
Serum potassium4.0 mEq/L4.0 \text{ mEq/L}
Serum chloride102 mEq/L102 \text{ mEq/L}
Serum bicarbonate12 mEq/L12 \text{ mEq/L}
Blood urea nitrogen (BUN)28 mg/dL28 \text{ mg/dL}
Serum glucose180 mg/dL180 \text{ mg/dL}
Measured serum osmolality325 mOsm/kg H2O325 \text{ mOsm/kg H}_2\text{O}

Based on these laboratory results, what is this patient's calculated osmolar gap? (Provide the exact numerical value)

Cevap: 25 mOsm/kg H2O

Cevap

The calculated osmolar gap is 25.
The patient has an elevated measured osmolality due to the ingestion of ethylene glycol (antifreeze). The calculated osmolality is 300 mOsm/kg H2O300 \text{ mOsm/kg H}_2\text{O}, derived from the formula 2×Na++Glucose18+BUN2.82 \times \text{Na}^+ + \frac{\text{Glucose}}{18} + \frac{\text{BUN}}{2.8}. Subtracting this calculated value from the measured osmolality of 325 mOsm/kg H2O325 \text{ mOsm/kg H}_2\text{O} gives an osmolar gap of 2525. An elevated osmolar gap is a hallmark of toxic alcohol ingestion.

Adım Adım Çözüm

1
Calculate the estimated serum osmolality using the standard formula.
Calculated Osmolality = 2×140+18018+282.8=280+10+10=300 mOsm/kg H2O2 \times 140 + \frac{180}{18} + \frac{28}{2.8} = 280 + 10 + 10 = 300 \text{ mOsm/kg H}_2\text{O}.
The osmolar gap is the difference between measured and calculated osmolality. To find the gap, the calculated osmolality must first be determined from serum sodium, glucose, and BUN.
2
Subtract the calculated osmolality from the measured osmolality.
325−300=25325 - 300 = 25.
This yields the osmolar gap, which represents the presence of unmeasured osmotically active substances (in this case, ethylene glycol from antifreeze).

Anahtar Kavram

The osmolar gap is calculated by subtracting the calculated serum osmolality (2×Na++Glucose18+BUN2.82 \times \text{Na}^+ + \frac{\text{Glucose}}{18} + \frac{\text{BUN}}{2.8}) from the measured serum osmolality. An elevated osmolar gap (>10 mOsm/kg H2O>10 \text{ mOsm/kg H}_2\text{O}) typically indicates the presence of toxic alcohols.
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