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Zorluk: ZorNephrology

A 54-year-old man is brought to the emergency department by emergency medical services after his wife found him unresponsive in their garage. She reports that he has a history of major depressive disorder and alcohol use disorder. An open, half-empty bottle of engine antifreeze was found nearby. Vital signs show a temperature of 36.2∘C36.2^\circ\text{C} (97.2∘F97.2^\circ\text{F}), pulse of 105105/min, blood pressure of 145/88145/88 mm Hg, and respirations of 2626/min. Physical examination reveals a comatose patient with no focal neurological deficits.

Laboratory studies reveal the following:

ParameterValue
Sodium141141 mEq/L
Potassium4.24.2 mEq/L
Chloride104104 mEq/L
Bicarbonate88 mEq/L
Blood urea nitrogen4242 mg/dL
Creatinine1.81.8 mg/dL
Glucose126126 mg/dL
EthanolUndetectable
Measured serum osmolality340340 mOsm/kg H2O\text{H}_2\text{O}

Arterial blood gas on room air:
pH: 7.187.18
pCO2\text{pCO}_2: 2020 mm Hg
pO2\text{pO}_2: 9898 mm Hg

Urinalysis reveals the presence of envelope-shaped crystals.

Based on the provided laboratory values, what is the patient's serum osmolar gap in mOsm/kg H2O\text{H}_2\text{O}?

Cevap: 36 mOsm/kg

Cevap

36
The patient's osmolar gap is 3636 mOsm/kg H2O\text{H}_2\text{O}. This is obtained by first finding the calculated serum osmolality using the formula: 2[Na+]+Glucose18+BUN2.82[\text{Na}^+] + \frac{\text{Glucose}}{18} + \frac{\text{BUN}}{2.8}. Substituting the provided values yields 2(141)+12618+422.8=282+7+15=3042(141) + \frac{126}{18} + \frac{42}{2.8} = 282 + 7 + 15 = 304 mOsm/kg H2O\text{H}_2\text{O}. Subtracting this calculated value from the measured osmolality (340340 mOsm/kg H2O\text{H}_2\text{O}) gives a gap of 3636 mOsm/kg H2O\text{H}_2\text{O}.

Adım Adım Çözüm

1
Determine the formula for calculated serum osmolality.
Calculated Osmolality=2[Na+]+Glucose18+BUN2.8\text{Calculated Osmolality} = 2[\text{Na}^+] + \frac{\text{Glucose}}{18} + \frac{\text{BUN}}{2.8}.
This standard calculation is required when assessing a patient for suspected toxic alcohol ingestion.
2
Input the patient's laboratory values into the formula.
Calculated Osmolality=2(141)+12618+422.8=282+7+15=304\text{Calculated Osmolality} = 2(141) + \frac{126}{18} + \frac{42}{2.8} = 282 + 7 + 15 = 304 mOsm/kg H2O\text{H}_2\text{O}.
Dividing glucose by 18 and BUN by 2.8 correctly converts these values from mg/dL to mOsm/L so they can be summed with sodium.
3
Calculate the serum osmolar gap.
Osmolar Gap=Measured Osmolality−Calculated Osmolality=340−304=36\text{Osmolar Gap} = \text{Measured Osmolality} - \text{Calculated Osmolality} = 340 - 304 = 36 mOsm/kg H2O\text{H}_2\text{O}.
The difference between measured and calculated osmolality reveals the concentration of unmeasured osmotically active substances (e.g., ethylene glycol).

Anahtar Kavram

The serum osmolar gap is calculated by subtracting the calculated serum osmolality (2[Na+]+Glucose18+BUN2.82[\text{Na}^+] + \frac{\text{Glucose}}{18} + \frac{\text{BUN}}{2.8}) from the measured serum osmolality. A gap >10>10 mOsm/kg H2O\text{H}_2\text{O} suggests the presence of unmeasured osmotically active agents such as toxic alcohols (e.g., ethylene glycol, methanol).
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