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Zorluk: ZorNephrology

A 54-year-old man is evaluated in the hospital for decreased urine output. He was admitted 7 days ago for infective endocarditis and has been receiving intravenous vancomycin and gentamicin. Over the past 24 hours, his urine output has dropped to 300 mL. His vital signs are within normal limits and he appears euvolemic on examination. Laboratory studies show the following:

Laboratory ParameterSerumUrine
Sodium140 mEq/L70 mEq/L
Potassium5.2 mEq/L25 mEq/L
Creatinine4.0 mg/dL50 mg/dL
Urea nitrogen (BUN)40 mg/dL-
Osmolality290 mOsm/kg H₂O310 mOsm/kg H₂O

Microscopic urinalysis reveals muddy brown granular casts.

Based on the provided laboratory findings, what is this patient's fractional excretion of sodium (FeNaFe_{Na})? (Express your answer as a percentage)

Cevap: 4 %

Cevap

4.0
The fractional excretion of sodium (FeNaFe_{Na}) measures the percentage of filtered sodium that is ultimately excreted in the urine. It is calculated using the formula: FeNa=UNa×PCrPNa×UCr×100Fe_{Na} = \frac{U_{Na} \times P_{Cr}}{P_{Na} \times U_{Cr}} \times 100. Plugging in the correctly extracted values from the table (UNa=70U_{Na} = 70, PCr=4.0P_{Cr} = 4.0, PNa=140P_{Na} = 140, UCr=50U_{Cr} = 50) yields 2807000×100=4.0%\frac{280}{7000} \times 100 = 4.0\%. A value greater than 2% in the setting of oliguria is highly suggestive of intrinsic acute kidney injury, specifically acute tubular necrosis (ATN). This correlates perfectly with the patient's history of aminoglycoside (gentamicin) use, isotonic urine (osmolality ~300 mOsm/kg), and the pathognomonic finding of muddy brown granular casts on urinalysis.

Adım Adım Çözüm

1
Recall the Fractional Excretion of Sodium (FeNa) formula.
FeNa=UNa×PCrPNa×UCr×100Fe_{Na} = \frac{U_{Na} \times P_{Cr}}{P_{Na} \times U_{Cr}} \times 100
This formula normalizes sodium excretion to the glomerular filtration rate, helping differentiate the etiology of acute kidney injury.
2
Identify the correct serum and urine values from the vignette's data table.
UNaU_{Na} = 70 mEq/L, PCrP_{Cr} = 4.0 mg/dL, PNaP_{Na} = 140 mEq/L, UCrU_{Cr} = 50 mg/dL.
Careful extraction prevents using incorrect parameters such as BUN or potassium, which act as distractors.
3
Perform the multiplication for the numerator and denominator.
Numerator = 280, Denominator = 7000.
70×4.0=28070 \times 4.0 = 280 and 140×50=7000140 \times 50 = 7000.
4
Divide the numerator by the denominator and convert to a percentage.
280/7000=0.04280 / 7000 = 0.04, which translates to 4.0%.
This yields the final diagnostic percentage, which is > 2%, consistent with acute tubular necrosis.

Anahtar Kavram

The Fractional Excretion of Sodium (FeNa) is calculated to differentiate prerenal azotemia (FeNa < 1%) from intrinsic acute kidney injury (FeNa > 2%).
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