Nephrology

337 soru

Soru 1Soru →

Match each clinical presentation and laboratory finding with the most likely underlying nephrological diagnosis.

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Öğeler

A 58-year-old man treated with high-dose intravenous acyclovir for herpes simplex encephalitis develops an abrupt rise in serum creatinine within 48 hours. Urinalysis shows needle-shaped crystals and hematuria.
A 62-year-old woman with a history of poorly controlled rheumatoid arthritis presents with nephrotic-range proteinuria. Renal biopsy reveals amorphous extracellular deposits in the mesangium that show apple-green birefringence under polarized light after Congo red staining.
A 71-year-old man undergoes coronary angiography. Five days later, he develops acute kidney injury, a reticular, erythematous skin rash on his lower extremities, and peripheral eosinophilia. Urinalysis is bland.
A 45-year-old woman with bipolar disorder on long-term lithium therapy presents with polyuria. Water deprivation testing results in a urine osmolality of 150 mOsm/kg, which remains unchanged following the administration of exogenous desmopressin.
A 38-year-old man with HIV on a highly active antiretroviral therapy regimen including tenofovir presents with hypokalemia, non-anion gap metabolic acidosis, hypophosphatemia, and glycosuria with a normal blood glucose level.

Eşleşmeler

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Cevap

The correct matches are: Acyclovir use with needle-shaped crystals correlates to Crystal-induced acute kidney injury. Rheumatoid arthritis with apple-green birefringence correlates to AA Amyloidosis. Post-angiography AKI with livedo reticularis correlates to Atheroembolic renal disease. Lithium use with lack of ADH response correlates to Nephrogenic diabetes insipidus. Tenofovir use with glycosuria and hypophosphatemia correlates to Proximal (Type 2) renal tubular acidosis.
Each vignette provides pathognomonic clues for a specific renal pathology. Acyclovir is notorious for precipitating in renal tubules. Chronic inflammatory conditions drive serum amyloid A overproduction leading to AA amyloidosis. Invasive vascular procedures can dislodge cholesterol crystals causing atheroembolic disease with systemic features. Lithium commonly impairs the collecting duct's response to ADH. Finally, tenofovir is a known cause of Fanconi syndrome, manifesting as a generalized proximal tubular dysfunction.

Adım Adım Çözüm

1
Analyze the first clinical vignette involving intravenous acyclovir.
Identify the rapid onset of acute kidney injury accompanied by needle-shaped crystals.
Recognizing the crystalluria points directly to crystal-induced intratubular obstruction caused by the drug.
2
Evaluate the second vignette detailing rheumatoid arthritis and nephrotic syndrome.
Identify the pathognomonic finding of apple-green birefringence with Congo red stain.
This specific histological finding, combined with a chronic inflammatory state, confirms AA Amyloidosis.
3
Examine the third vignette describing acute kidney injury following coronary angiography.
Identify the delayed onset, livedo reticularis, and eosinophilia.
These are the classic systemic signs of cholesterol embolization (atheroembolic renal disease), distinguishing it from contrast-induced nephropathy.
4
Assess the fourth vignette involving lithium therapy and polyuria.
Recognize the lack of urinary concentration following both water deprivation and desmopressin administration.
This establishes resistance to ADH at the renal level, confirming nephrogenic diabetes insipidus rather than central diabetes insipidus.
5
Review the fifth vignette detailing tenofovir use and multiple metabolic derangements.
Identify the combination of normoglycemic glycosuria, hypophosphatemia, and non-anion gap metabolic acidosis.
This combination indicates a generalized proximal tubule defect (Fanconi syndrome), leading to Proximal (Type 2) RTA.

Anahtar Kavram

Differentiation of complex nephrological syndromes based on specific medication toxicities, systemic disease manifestations, and pathognomonic biopsy or urinary findings.
Soru 2Soru →

A 32-year-old woman is brought to the emergency department by her partner due to 5 days of severe, voluminous diarrhea and abdominal cramping. She has a history of ulcerative colitis and panic disorder. In the waiting room, she experienced a severe panic attack and was noted to have visibly rapid, deep breathing. Physical examination reveals dry mucous membranes, decreased skin turgor, a heart rate of 115/min115/\text{min}, a respiratory rate of 28/min28/\text{min}, and a blood pressure of 105/65 mm Hg105/65\text{ mm Hg}.

Laboratory results are as follows:

Laboratory TestResultReference Range
Sodium136 mEq/L136 \text{ mEq/L}136−145 mEq/L136-145 \text{ mEq/L}
Potassium3.2 mEq/L3.2 \text{ mEq/L}3.5−5.0 mEq/L3.5-5.0 \text{ mEq/L}
Chloride115 mEq/L115 \text{ mEq/L}95−105 mEq/L95-105 \text{ mEq/L}
Bicarbonate12 mEq/L12 \text{ mEq/L}22−28 mEq/L22-28 \text{ mEq/L}
Blood urea nitrogen34 mg/dL34 \text{ mg/dL}7−18 mg/dL7-18 \text{ mg/dL}
Creatinine1.2 mg/dL1.2 \text{ mg/dL}0.6−1.2 mg/dL0.6-1.2 \text{ mg/dL}

Arterial blood gas (room air):

Arterial Blood GasResultReference Range
pH7.407.407.35−7.457.35-7.45
pCO2\text{pCO}_220 mm Hg20 \text{ mm Hg}35−45 mm Hg35-45 \text{ mm Hg}
pO2\text{pO}_298 mm Hg98 \text{ mm Hg}80−100 mm Hg80-100 \text{ mm Hg}

Which of the following best describes this patient's acid-base status?

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Cevap: Mixed normal anion gap metabolic acidosis and respiratory alkalosis

Cevap

Mixed normal anion gap metabolic acidosis and respiratory alkalosis
The patient's initial insult is severe diarrhea, which causes profound gastrointestinal loss of bicarbonate, resulting in a normal anion gap metabolic acidosis (NAGMA). This is confirmed by an anion gap of 9 mEq/L9 \text{ mEq/L} (136−115−12=9136 - 115 - 12 = 9). To evaluate if respiratory compensation is appropriate, Winter's formula is applied: Expected pCO2=(1.5×12)+8±2=26±2 mm Hg\text{Expected pCO}_2 = (1.5 \times 12) + 8 \pm 2 = 26 \pm 2 \text{ mm Hg}. Because the patient's actual pCO2\text{pCO}_2 (20 mm Hg20 \text{ mm Hg}) is significantly lower than the expected range (24−28 mm Hg24-28 \text{ mm Hg}), she is 'blowing off' more CO2\text{CO}_2 than expected. This indicates a coexisting primary respiratory alkalosis, clinically correlating with her panic attack and hyperventilation in the waiting room. The two opposing disorders (acidosis and alkalosis) offset each other, resulting in a seemingly normal pH of 7.407.40.

Adım Adım Çözüm

1
Calculate the anion gap to identify the primary metabolic disturbance.
Anion Gap=Na+−(Cl−+HCO3−)=136−(115+12)=9 mEq/L\text{Anion Gap} = \text{Na}^+ - (\text{Cl}^- + \text{HCO}_3^-) = 136 - (115 + 12) = 9 \text{ mEq/L}.
Since the anion gap is within the normal range (8−12 mEq/L8-12 \text{ mEq/L}), the patient has a normal anion gap metabolic acidosis (NAGMA), consistent with bicarbonate loss from severe diarrhea.
2
Apply Winter's formula to determine the expected respiratory compensation.
Expected pCO2=1.5×[HCO3−]+8±2=(1.5×12)+8±2=26±2 mm Hg\text{Expected pCO}_2 = 1.5 \times [\text{HCO}_3^-] + 8 \pm 2 = (1.5 \times 12) + 8 \pm 2 = 26 \pm 2 \text{ mm Hg}. The expected range is 24−28 mm Hg24-28 \text{ mm Hg}.
Winter's formula determines if the lungs are appropriately compensating for a metabolic acidosis by decreasing pCO2\text{pCO}_2.
3
Compare the actual measured pCO2\text{pCO}_2 with the expected pCO2\text{pCO}_2 range.
The patient's actual pCO2\text{pCO}_2 is 20 mm Hg20 \text{ mm Hg}, which is lower than the expected range of 24−28 mm Hg24-28 \text{ mm Hg}.
Because the pCO2\text{pCO}_2 is lower than what pure metabolic compensation would dictate, there is an additional process driving CO2 down—a primary respiratory alkalosis (due to hyperventilation from her panic attack).

Anahtar Kavram

In patients with metabolic acidosis, Winter's formula (1.5×[HCO3−]+8±21.5 \times [\text{HCO}_3^-] + 8 \pm 2) must be used to calculate expected pCO2\text{pCO}_2. An actual pCO2\text{pCO}_2 lower than the expected range indicates a superimposed primary respiratory alkalosis.
Soru 3Soru →

An emergency medical services team brings a 6262-year-old man to the hospital following 44 days of profuse, nonbloody diarrhea. His past medical history is significant for severe chronic obstructive pulmonary disease (COPD) managed with a daily inhaled tiotropium. Upon arrival, he reports profound fatigue and lightheadedness.

Vital signs include a heart rate of 108/min108/\text{min}, blood pressure of 105/65 mm Hg105/65\text{ mm Hg}, respiratory rate of 24/min24/\text{min}, and temperature of 37.2∘C37.2^\circ\text{C} (99.0∘F99.0^\circ\text{F}). Physical examination reveals dry oral mucosa and diminished skin turgor. The lungs have diffuse expiratory wheezes bilaterally.

Initial laboratory investigations reveal the following:

Laboratory TestResult
Sodium138 mEq/L138\text{ mEq/L}
Potassium3.4 mEq/L3.4\text{ mEq/L}
Chloride111 mEq/L111\text{ mEq/L}
Bicarbonate14 mEq/L14\text{ mEq/L}
Blood urea nitrogen32 mg/dL32\text{ mg/dL}
Creatinine1.4 mg/dL1.4\text{ mg/dL}

Arterial blood gas (on room air):

Arterial Blood GasResult
pH7.227.22
pCO2\text{pCO}_236 mm Hg36\text{ mm Hg}
pO2\text{pO}_262 mm Hg62\text{ mm Hg}

Based on the laboratory results, which of the following is the most accurate characterization of this patient's acid-base status?

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Cevap: Mixed metabolic acidosis and respiratory acidosis

Cevap

Mixed metabolic acidosis and respiratory acidosis
This patient has a low pH (7.227.22) and a low serum bicarbonate (14 mEq/L14\text{ mEq/L}), which establishes the presence of a primary metabolic acidosis (non-anion gap, given the gap of 1313, which is consistent with severe diarrhea). To determine if the respiratory compensation is appropriate, Winter's formula must be applied: Expected pCO2=(1.5×HCO3−)+8±2\text{pCO}_2 = (1.5 \times \text{HCO}_3^-) + 8 \pm 2. For this patient, the expected pCO2\text{pCO}_2 is (1.5×14)+8=21+8=29±2(1.5 \times 14) + 8 = 21 + 8 = 29 \pm 2 (range: 27−31 mm Hg27-31\text{ mm Hg}). The patient's actual pCO2\text{pCO}_2 is 36 mm Hg36\text{ mm Hg}. Because the actual pCO2\text{pCO}_2 is greater than the expected range, there is a concomitant primary respiratory acidosis. This is a common finding in patients with advanced COPD who cannot adequately increase their minute ventilation in response to acidemia.

Adım Adım Çözüm

1
Identify the primary acid-base disorder by evaluating the pH and serum bicarbonate.
The pH is 7.227.22 (acidemia) and the bicarbonate is 14 mEq/L14\text{ mEq/L} (low). This indicates a primary metabolic acidosis.
The pH determines the primary direction of the derangement, and the concordant change in bicarbonate confirms a metabolic etiology.
2
Calculate the expected pCO2\text{pCO}_2 using Winter's formula to assess for mixed disorders.
Expected pCO2=(1.5×14)+8=29±2 mm Hg\text{pCO}_2 = (1.5 \times 14) + 8 = 29 \pm 2\text{ mm Hg} (range 27−31 mm Hg27-31\text{ mm Hg}).
Winter's formula determines if the respiratory response (hyperventilation) to a metabolic acidosis is appropriate.
3
Compare the actual pCO2\text{pCO}_2 to the expected pCO2\text{pCO}_2.
The actual pCO2\text{pCO}_2 (36 mm Hg36\text{ mm Hg}) is higher than the expected range (27−31 mm Hg27-31\text{ mm Hg}).
A higher-than-expected pCO2\text{pCO}_2 indicates inadequate ventilation, meaning a superimposed respiratory acidosis is present, likely secondary to the patient's severe COPD.

Anahtar Kavram

Patients with a primary metabolic acidosis must be evaluated with Winter's formula to determine if respiratory compensation is adequate; a pCO2 higher than expected indicates a concomitant respiratory acidosis.
Soru 4Soru →

An 81-year-old man is brought to the emergency department by emergency medical services due to progressively worsening shortness of breath, altered mental status, and a high fever over the past two days. His past medical history is significant for severe chronic obstructive pulmonary disease (COPD). Upon arrival, he is lethargic and utilizing accessory muscles for respiration. Vital signs show a temperature of 38.9°C (102°F), heart rate of 122/min, blood pressure of 86/52 mmHg, and respiratory rate of 28/min. Oxygen saturation is 84% on room air.

Initial laboratory results are as follows:

Laboratory TestResultReference Range
Sodium140 mEq/L136–145 mEq/L
Potassium4.2 mEq/L3.5–5.0 mEq/L
Chloride98 mEq/L98–106 mEq/L
Bicarbonate12 mEq/L22–28 mEq/L
Blood urea nitrogen38 mg/dL8–20 mg/dL
Creatinine1.7 mg/dL0.7–1.3 mg/dL
Lactate7.1 mmol/L0.5–1.0 mmol/L
Arterial blood gas on room air:
ParameterResultReference Range
pHpH7.127.35–7.45
pCO2pCO_238 mm Hg35–45 mm Hg
pO2pO_252 mm Hg75–105 mm Hg

Based on the laboratory data provided, which of the following best describes this patient's acid-base status?

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Cevap: Mixed high anion gap metabolic acidosis and respiratory acidosis

Cevap

Mixed high anion gap metabolic acidosis and respiratory acidosis
The correct answer accurately identifies two concurrent acid-base disturbances. First, the patient has a high anion gap metabolic acidosis (HAGMA) driven by lactic acidosis secondary to sepsis. The anion gap is calculated as 140−(98+12)=30140 - (98 + 12) = 30 mEq/L. Next, respiratory compensation for a metabolic acidosis must be verified using Winter's formula: Expected pCO2=1.5×[HCO3−]+8±2pCO_2 = 1.5 \times [HCO_3^-] + 8 \pm 2. For this patient, the expected pCO2=1.5×12+8=26±2pCO_2 = 1.5 \times 12 + 8 = 26 \pm 2 mm Hg. The patient's actual pCO2pCO_2 is 38 mm Hg. Because the measured pCO2pCO_2 is significantly higher than the expected compensated value, there is a concurrent respiratory acidosis. This commonly occurs when a patient with underlying COPD develops sepsis and respiratory muscle fatigue, rendering them unable to mount the massive minute ventilation required to compensate for a severe metabolic acidosis.

Adım Adım Çözüm

1
Identify the primary acid-base disorder by looking at the pHpH and bicarbonate levels.
The patient is acidemic (pHpH = 7.12) with a low bicarbonate (1212 mEq/L), indicating a primary metabolic acidosis.
Both pHpH and HCO3−HCO_3^- are shifted in the same direction (downward), which is the hallmark of a metabolic process.
2
Calculate the serum anion gap to determine the etiology of the metabolic acidosis.
Anion Gap = Na+−(Cl−+HCO3−)=140−(98+12)=30Na^+ - (Cl^- + HCO_3^-) = 140 - (98 + 12) = 30 mEq/L.
An anion gap > 12 mEq/L confirms the presence of a high anion gap metabolic acidosis (HAGMA), consistent with this patient's elevated lactate from septic shock.
3
Calculate the expected respiratory compensation using Winter's formula.
Expected pCO2=1.5×[HCO3−]+8=1.5×12+8=18+8=26±2pCO_2 = 1.5 \times [HCO_3^-] + 8 = 1.5 \times 12 + 8 = 18 + 8 = 26 \pm 2 mm Hg.
Winter's formula determines if the lungs are appropriately blowing off CO2CO_2 to compensate for the metabolic acidemia.
4
Compare the expected pCO2pCO_2 with the patient's actual pCO2pCO_2.
The actual pCO2pCO_2 is 38 mm Hg, which is significantly greater than the expected range of 24-28 mm Hg.
Because the actual CO2CO_2 is higher than expected, the patient is retaining CO2CO_2. This establishes the presence of a second, concurrent disorder: a respiratory acidosis.

Anahtar Kavram

Acid-base disorders with calculation of anion gap and respiratory compensation using Winter's formula.

Alternatif Yöntem

Once HAGMA is established, you can optionally calculate the Delta-Delta ratio (Δ\Delta Anion Gap / ΔHCO3−\Delta HCO_3^-) to check for a third disorder. Here, Δ\Delta AG = 30−12=1830 - 12 = 18, and ΔHCO3−\Delta HCO_3^- = 24−12=1224 - 12 = 12. The ratio is 18/12=1.518 / 12 = 1.5. A ratio between 1.0 and 2.0 suggests an uncomplicated HAGMA without an underlying concurrent normal AG metabolic acidosis or metabolic alkalosis.
Tahmini Süre:1m 0s
Soru 5Soru →

A 32-year-old woman is evaluated in the emergency department for severe, watery diarrhea occurring over the past 5 days after returning from a trip abroad. She reports weakness and dry mouth. Vital signs show a blood pressure of 100/60 mm Hg and a heart rate of 110/min.

Laboratory studies show:
Serum sodium: 140 mEq/L140 \text{ mEq/L}
Serum chloride: 115 mEq/L115 \text{ mEq/L}
Serum bicarbonate: 16 mEq/L16 \text{ mEq/L}
Serum potassium: 3.2 mEq/L3.2 \text{ mEq/L}

Arterial blood gas analysis on room air shows a pH of 7.30.

Assuming appropriate respiratory compensation has occurred, which of the following is the expected arterial partial pressure of carbon dioxide (PaCO2) in this patient?

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Cevap: 32 mm Hg32 \text{ mm Hg}

Cevap

32 mm Hg32 \text{ mm Hg}
This patient presents with a primary metabolic acidosis due to gastrointestinal bicarbonate losses (severe diarrhea). In the presence of metabolic acidosis, the physiological respiratory compensation is hyperventilation, which decreases the carbon dioxide level. The exact expected PaCO2 can be calculated using Winter's formula: Expected PaCO2=(1.5×[HCO3−])+8±2\text{Expected } PaCO_2 = (1.5 \times [HCO_3^-]) + 8 \pm 2. Using the patient's bicarbonate of 16 mEq/L16 \text{ mEq/L}, the calculation is (1.5×16)+8=24+8=32 mm Hg(1.5 \times 16) + 8 = 24 + 8 = 32 \text{ mm Hg}.

Adım Adım Çözüm

1
Identify the primary acid-base disorder based on the provided laboratory values.
The patient has a low pH (7.30) and low bicarbonate (16 mEq/L16 \text{ mEq/L}), indicating a primary metabolic acidosis.
Severe diarrhea causes loss of bicarbonate in the stool, leading to a normal anion gap metabolic acidosis.
2
Select the appropriate formula to calculate respiratory compensation for metabolic acidosis.
Use Winter's formula: Expected PaCO2=(1.5×[HCO3−])+8±2\text{Expected } PaCO_2 = (1.5 \times [HCO_3^-]) + 8 \pm 2.
Winter's formula is the standard physiological calculation to determine if respiratory compensation for metabolic acidosis is adequate.
3
Perform the calculation using the patient's serum bicarbonate level.
(1.5×16)+8=24+8=32 mm Hg(1.5 \times 16) + 8 = 24 + 8 = 32 \text{ mm Hg}.
Inserting the given bicarbonate value of 16 mEq/L16 \text{ mEq/L} yields the precise expected target for PaCO2.

Anahtar Kavram

Respiratory compensation in primary metabolic acidosis (Winter's formula)
Soru 6Soru →

A 62-year-old man is admitted to the intensive care unit with septic shock secondary to severe pneumonia. He remains hypotensive despite adequate intravenous fluid resuscitation and requires vasopressor support. Laboratory studies are obtained to evaluate his acid-base status.

Laboratory ParameterValue
Sodium (Na+Na^+)138 mEq/L138 \text{ mEq/L}
Potassium (K+K^+)4.2 mEq/L4.2 \text{ mEq/L}
Chloride (Cl−Cl^-)98 mEq/L98 \text{ mEq/L}
Bicarbonate (HCO3−HCO_3^-)12 mEq/L12 \text{ mEq/L}

Based on the provided laboratory results, what is the patient's calculated serum anion gap?

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Cevap: 28

Cevap

28
The serum anion gap is calculated using the formula AG=Na+−(Cl−+HCO3−)AG = Na^+ - (Cl^- + HCO_3^-). Substituting the patient's values yields 138−(98+12)=138−110=28 mEq/L138 - (98 + 12) = 138 - 110 = 28 \text{ mEq/L}. An elevated anion gap (normal is typically 8-12 mEq/L) in this patient with septic shock suggests a high anion gap metabolic acidosis, most likely due to lactic acidosis from poor tissue perfusion.

Adım Adım Çözüm

1
Identify the formula for serum anion gap.
AG=Na+−(Cl−+HCO3−)AG = Na^+ - (Cl^- + HCO_3^-)
The anion gap is essential for determining the presence and etiology of a metabolic acidosis.
2
Substitute the patient's laboratory values into the formula.
AG=138−(98+12)AG = 138 - (98 + 12)
Sodium is the primary measured extracellular cation, while chloride and bicarbonate are the primary measured extracellular anions.
3
Calculate the sum of the measured anions and subtract from the measured cation.
138−110=28138 - 110 = 28
This yields the concentration of unmeasured anions in the serum.

Anahtar Kavram

Calculation of the serum anion gap
Soru 7Soru →

A 5454-year-old man is admitted to the intensive care unit directly from the medical triage area due to high fever and altered mental status. His wife reports that he has been complaining of painful urination and flank discomfort for three days. His temperature is 39.2∘C39.2^\circ\text{C} (102.6∘F102.6^\circ\text{F}), blood pressure is 82/48 mm Hg82/48 \text{ mm Hg}, heart rate is 130/min130\text{/min}, and respiratory rate is 30/min30\text{/min}. Physical examination shows a lethargic man with mottling of the lower extremities and marked suprapubic tenderness.

Laboratory results:
Serum sodium: 140 mEq/L140 \text{ mEq/L}
Serum potassium: 4.5 mEq/L4.5 \text{ mEq/L}
Serum chloride: 104 mEq/L104 \text{ mEq/L}
Serum bicarbonate: 16 mEq/L16 \text{ mEq/L}
Blood urea nitrogen: 32 mg/dL32 \text{ mg/dL}
Serum creatinine: 1.6 mg/dL1.6 \text{ mg/dL}

Arterial blood gas (room air):
pH: 7.457.45
pCO 2_2: 24 mm Hg24 \text{ mm Hg}
pO 2_2: 88 mm Hg88 \text{ mm Hg}

What is the most accurate description of this patient's acid-base disorder?

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Cevap: High anion gap metabolic acidosis and primary respiratory alkalosis

Cevap

The correct answer is a mixed high anion gap metabolic acidosis and primary respiratory alkalosis.
The patient's laboratory values reveal a mixed acid-base disorder consisting of a high anion gap metabolic acidosis (HAGMA) and a primary respiratory alkalosis. First, the elevated anion gap of 20 mEq/L20 \text{ mEq/L} (140−[104+16]140 - [104 + 16]) definitively identifies a HAGMA, which in this clinical context is likely lactic acidosis secondary to septic shock. Second, applying Winter's formula [(1.5×16)+8=32±2 mm Hg(1.5 \times 16) + 8 = 32 \pm 2 \text{ mm Hg}] establishes the expected respiratory compensation. Because the patient's actual pCO 2_2 (24 mm Hg24 \text{ mm Hg}) is significantly lower than the expected range, there is excessive hyperventilation indicating a superimposed primary respiratory alkalosis. This combination of HAGMA and respiratory alkalosis is a hallmark of early sepsis.

Adım Adım Çözüm

1
Analyze the pH to determine the overall acid-base state.
The pH is 7.457.45, which indicates alkalemia.
A pH greater than 7.407.40 establishes an alkalemic state, meaning a primary alkalosis must be present as a driving disorder.
2
Calculate the serum anion gap to evaluate for a hidden metabolic acidosis.
Anion gap =140−(104+16)=20 mEq/L= 140 - (104 + 16) = 20 \text{ mEq/L}.
An anion gap greater than 12 mEq/L12 \text{ mEq/L} confirms the presence of a primary high anion gap metabolic acidosis (HAGMA), regardless of the overall pH. This is likely due to lactic acidosis from septic shock.
3
Calculate the expected respiratory compensation for the metabolic acidosis using Winter's formula.
Expected pCO 2_2 =(1.5×16)+8=32±2 mm Hg= (1.5 \times 16) + 8 = 32 \pm 2 \text{ mm Hg}.
This calculation determines if the patient's pCO 2_2 level is purely compensatory for the acidosis or if an additional primary respiratory disorder is present.
4
Compare the actual pCO 2_2 to the expected pCO 2_2.
The actual pCO 2_2 (24 mm Hg24 \text{ mm Hg}) is less than the expected range (30−34 mm Hg30-34 \text{ mm Hg}).
Because the pCO 2_2 is significantly lower than expected, there is excessive respiratory drive, indicating a superimposed primary respiratory alkalosis (common in early sepsis).

Anahtar Kavram

Acid-base analysis requires calculating the anion gap in all patients, as a high anion gap metabolic acidosis can exist concurrently with an opposing primary acid-base disorder (such as respiratory alkalosis in early sepsis), resulting in a normal or alkalemic pH.
Tahmini Süre:1m 30s
Soru 8Soru →

Match each primary acid-base disorder to its corresponding expected physiological compensatory response.

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Öğeler

Primary metabolic acidosis
Primary metabolic alkalosis
Acute primary respiratory acidosis
Chronic primary respiratory acidosis

Eşleşmeler

Cevabı ve açıklamayı göster

Cevap

Metabolic acidosis matches Winters' formula; metabolic alkalosis matches a 0.7 mmHg0.7 \text{ mmHg} PaCO2\text{PaCO}_2 increase per 1 mEq/L1 \text{ mEq/L} HCO3−\text{HCO}_3^- increase; acute respiratory acidosis matches a 1 mEq/L1 \text{ mEq/L} HCO3−\text{HCO}_3^- increase per 10 mmHg10 \text{ mmHg} PaCO2\text{PaCO}_2 increase; and chronic respiratory acidosis matches a 3 to 4 mEq/L3 \text{ to } 4 \text{ mEq/L} HCO3−\text{HCO}_3^- increase per 10 mmHg10 \text{ mmHg} PaCO2\text{PaCO}_2 increase.
Each primary acid-base disorder triggers a predictable and calculable compensatory response. Metabolic acidosis is compensated by hyperventilation, calculated via Winters' formula. Metabolic alkalosis is compensated by hypoventilation, where PaCO2\text{PaCO}_2 rises 0.7 mmHg0.7 \text{ mmHg} per 1 mEq/L1 \text{ mEq/L} rise in HCO3−\text{HCO}_3^-. Acute respiratory acidosis is buffered acutely by cells, raising HCO3−\text{HCO}_3^- by 1 mEq/L1 \text{ mEq/L} per 10 mmHg10 \text{ mmHg} PaCO2\text{PaCO}_2 rise. Chronic respiratory acidosis allows for full renal compensation, raising HCO3−\text{HCO}_3^- by 3 to 4 mEq/L3 \text{ to } 4 \text{ mEq/L} per 10 mmHg10 \text{ mmHg} PaCO2\text{PaCO}_2 rise.

Adım Adım Çözüm

1
Identify the primary disturbance and the physiological organ system responsible for compensation.
Metabolic disorders are compensated by the respiratory system (altering PaCO2\text{PaCO}_2), while respiratory disorders are compensated by the renal system (altering HCO3−\text{HCO}_3^-).
Understanding the fundamental physiological mechanism is the first step in applying the correct numerical formula.
2
Correlate metabolic disorders with their specific respiratory compensation rules.
Metabolic acidosis requires evaluation using Winters' formula. Metabolic alkalosis is evaluated using the 0.7 rule.
These established formulas are required to determine if a superimposed secondary acid-base disorder is present.
3
Correlate respiratory disorders with their specific acute versus chronic renal compensation rules.
Acute respiratory acidosis causes a minor HCO3−\text{HCO}_3^- shift (1 for 10), while chronic respiratory acidosis allows for robust renal HCO3−\text{HCO}_3^- retention (3 to 4 for 10).
Renal metabolic compensation takes several days to reach maximal efficacy, creating distinctly different expected values for acute versus chronic respiratory conditions.

Anahtar Kavram

Acid-base compensation formulas and expected physiological responses.
Tahmini Süre:1m 0s
Soru 9Soru →

A 32-year-old woman is evaluated in the urgent care clinic due to severe nausea, diffuse abdominal discomfort, and a persistent "ringing" sensation in her ears for the past day. She reports a history of chronic lower back pain and admits to taking a large handful of over-the-counter analgesic tablets recently to manage a severe flare-up.

Vital signs show a temperature of 38.1°C (100.6°F), blood pressure of 114/72 mm Hg, pulse of 116/min, and respiratory rate of 28/min. She appears flushed and diaphoretic. Lungs are clear to auscultation.

Laboratory results are as follows:

TestResult
Arterial Blood Gas (room air)
pH7.44
PaCO₂19 mm Hg
PaO₂96 mm Hg
Serum Chemistry
Sodium141 mEq/L
Potassium3.6 mEq/L
Chloride104 mEq/L
Bicarbonate12 mEq/L
Creatinine0.8 mg/dL

Which of the following best characterizes this patient's current acid-base disturbance?

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Cevap: Mixed primary metabolic acidosis and primary respiratory alkalosis

Cevap

Mixed primary metabolic acidosis and primary respiratory alkalosis
The patient's presentation (tinnitus, tachypnea, fever, nausea) following an overdose of an over-the-counter analgesic is highly suspicious for salicylate (aspirin) toxicity. Salicylate toxicity characteristically causes a mixed acid-base disorder. First, calculate the anion gap: 141−(104+12)=25141 - (104 + 12) = 25 mEq/L. This is elevated, confirming a primary high anion gap metabolic acidosis (due to uncoupling of oxidative phosphorylation and accumulation of organic acids). Next, determine if the respiratory response is purely compensatory by applying Winter's formula: Expected PaCO2=1.5×12+8=26±2PaCO_2 = 1.5 \times 12 + 8 = 26 \pm 2 mm Hg (range 24-28 mm Hg). The patient's actual PaCO2PaCO_2 is 19 mm Hg. Because the actual PaCO2PaCO_2 is lower than the expected compensatory range, there is a concurrent primary respiratory alkalosis (due to direct stimulation of the medullary respiratory center by salicylates). These two opposing primary disorders explain why the pH (7.44) is remarkably close to normal.

Adım Adım Çözüm

1
Calculate the anion gap to assess the metabolic component.
AG = Na+−(Cl−+HCO3−)Na^+ - (Cl^- + HCO_3^-) = 141−(104+12)141 - (104 + 12) = 2525 mEq/L.
An elevated anion gap (>12 mEq/L) definitively identifies the presence of a primary high anion gap metabolic acidosis.
2
Apply Winter's formula to determine the expected respiratory compensation for the metabolic acidosis.
Expected PaCO2=1.5×HCO3−+8±2PaCO_2 = 1.5 \times HCO_3^- + 8 \pm 2 = 1.5×12+8±21.5 \times 12 + 8 \pm 2 = 26±226 \pm 2 (range 24-28 mm Hg).
Winter's formula determines if the respiratory response is purely compensatory or if an independent respiratory disorder exists.
3
Compare the actual PaCO2 to the expected PaCO2 range.
Actual PaCO2PaCO_2 is 19 mm Hg, which is significantly lower than the expected 24-28 mm Hg.
A PaCO2PaCO_2 lower than expected indicates an additional primary respiratory alkalosis.
4
Synthesize the laboratory findings with the clinical presentation.
The patient has both a high anion gap metabolic acidosis and a primary respiratory alkalosis, classic for salicylate toxicity.
Salicylates directly stimulate the medullary respiratory center (respiratory alkalosis) and uncouple oxidative phosphorylation (metabolic acidosis), often resulting in a near-normal pH due to opposing forces.

Anahtar Kavram

Evaluation of mixed acid-base disorders using the anion gap and Winter's formula.
Tahmini Süre:1m 30s
Soru 10Soru →

A 72-year-old man is brought to the emergency department from a long-term care facility due to a 4-day history of profuse, watery diarrhea and progressive lethargy. His medical history includes hypertension, benign prostatic hyperplasia, and moderate chronic obstructive pulmonary disease. His medications include amlodipine, tamsulosin, and an albuterol inhaler as needed. Temperature is 37.1∘C37.1^\circ\text{C} (98.8∘F98.8^\circ\text{F}), blood pressure is 98/62 mm Hg, pulse is 114/min, and respirations are 24/min. Physical examination shows dry mucous membranes, delayed capillary refill, and decreased skin turgor. Lungs are clear to auscultation bilaterally.

Laboratory studies show:
ParameterValueReference Range
Serum sodium136 mEq/L136 \text{ mEq/L}136−145 mEq/L136-145 \text{ mEq/L}
Serum potassium3.1 mEq/L3.1 \text{ mEq/L}3.5−5.0 mEq/L3.5-5.0 \text{ mEq/L}
Serum chloride115 mEq/L115 \text{ mEq/L}98−106 mEq/L98-106 \text{ mEq/L}
Serum bicarbonate10 mEq/L10 \text{ mEq/L}22−28 mEq/L22-28 \text{ mEq/L}
Blood urea nitrogen52 mg/dL52 \text{ mg/dL}7−18 mg/dL7-18 \text{ mg/dL}
Serum creatinine2.3 mg/dL2.3 \text{ mg/dL}0.6−1.2 mg/dL0.6-1.2 \text{ mg/dL}
Arterial blood gas (room air):
ParameterValueReference Range
pH7.207.35-7.45
pCO2\text{pCO}_232 mm Hg32 \text{ mm Hg}35−45 mm Hg35-45 \text{ mm Hg}
pO2\text{pO}_288 mm Hg88 \text{ mm Hg}75−105 mm Hg75-105 \text{ mm Hg}

Which of the following best describes this patient's acid-base status?

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Cevap: Normal anion gap metabolic acidosis with concurrent respiratory acidosis

Cevap

Normal anion gap metabolic acidosis with concurrent respiratory acidosis
The patient has acidemia (pH = 7.20) with a low bicarbonate (10 mEq/L), indicating a primary metabolic acidosis. The next step is to calculate the serum anion gap to determine the etiology. The anion gap is calculated as Na+−(Cl−+HCO3−)\text{Na}^+ - (\text{Cl}^- + \text{HCO}_3^-). For this patient, the anion gap is 136−(115+10)=11 mEq/L136 - (115 + 10) = 11 \text{ mEq/L}, which is within the normal reference range (8−12 mEq/L8-12 \text{ mEq/L}). This normal anion gap metabolic acidosis is consistent with severe bicarbonate loss from his profuse diarrhea. To assess for a mixed acid-base disorder, Winter's formula is used to calculate the expected respiratory compensation: Expected pCO2=(1.5×HCO3−)+8±2\text{Expected pCO}_2 = (1.5 \times \text{HCO}_3^-) + 8 \pm 2. For this patient, the expected pCO2=(1.5×10)+8=23±2 mm Hg\text{pCO}_2 = (1.5 \times 10) + 8 = 23 \pm 2 \text{ mm Hg}. The patient's measured pCO2\text{pCO}_2 is 32 mm Hg, which is significantly higher than the expected range of 21-25 mm Hg. This inadequate respiratory compensation indicates a concurrent primary respiratory acidosis, which is likely secondary to respiratory muscle fatigue and his underlying chronic obstructive pulmonary disease (COPD).

Adım Adım Çözüm

1
Identify the primary acid-base disturbance.
The low pH (7.20) and low bicarbonate (10 mEq/L) indicate a primary metabolic acidosis.
Acidemia driven by a primary decrease in bicarbonate is the hallmark of metabolic acidosis.
2
Calculate the serum anion gap to determine the etiology of the metabolic acidosis.
Anion Gap = Na - (Cl + HCO3) = 136 - (115 + 10) = 11 mEq/L.
An anion gap of 11 mEq/L is within the normal range (8-12 mEq/L), confirming a normal anion gap metabolic acidosis, which is consistent with severe bicarbonate loss from diarrhea.
3
Calculate the expected respiratory compensation using Winter's formula.
Expected pCO2 = (1.5 * 10) + 8 +/- 2 = 23 +/- 2 mm Hg (range 21-25 mm Hg).
This formula determines if the respiratory system is adequately compensating for the metabolic acidosis.
4
Compare the measured pCO2 to the expected pCO2 to identify any secondary disturbances.
The measured pCO2 of 32 mm Hg is higher than the expected range of 21-25 mm Hg.
An inappropriately elevated pCO2 in the setting of metabolic acidosis indicates relative hypoventilation, revealing a superimposed primary respiratory acidosis.

Anahtar Kavram

Mixed acid-base disorders are identified by determining the primary disturbance, calculating the anion gap, and using compensatory formulas such as Winter's formula to assess for secondary disturbances.
Soru 11Soru →

A 72-year-old man is evaluated in the intensive care unit for progressive lethargy and labored breathing. He was admitted 3 days ago for presumed urosepsis and is receiving broad-spectrum intravenous antibiotics. His temperature is 38.4∘C38.4^\circ\text{C} (101.1∘F101.1^\circ\text{F}), blood pressure is 82/50 mm Hg, pulse is 122/min, and respirations are 28/min. Physical examination shows a somnolent patient using accessory muscles of respiration.

Laboratory studies show the following:

ComponentValue
Serum sodium140 mEq/L
Serum potassium4.8 mEq/L
Serum chloride102 mEq/L
Serum bicarbonate14 mEq/L
Blood urea nitrogen52 mg/dL
Serum creatinine2.4 mg/dL
Serum lactate5.8 mmol/L
Arterial blood gas analysis on room air:
ComponentValue
pH7.21
PaCO2PaCO_236 mm Hg
PaO2PaO_260 mm Hg

Which of the following best describes this patient's acid-base disorder?

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Cevap: Elevated anion gap metabolic acidosis and concomitant respiratory acidosis

Cevap

Elevated anion gap metabolic acidosis and concomitant respiratory acidosis
The correct answer accurately identifies both the primary metabolic acidosis (elevated anion gap due to lactic acidosis from septic shock) and the superimposed respiratory acidosis. The respiratory acidosis is evident because the patient's measured PaCO2PaCO_2 of 36 mm Hg is significantly higher than the expected PaCO2PaCO_2 range of 27-31 mm Hg calculated by Winter's formula, reflecting respiratory muscle fatigue.

Adım Adım Çözüm

1
Determine the primary disturbance.
pH is 7.21 (acidemia) and HCO3−HCO_3^- is 14 mEq/L (low). This establishes a primary metabolic acidosis.
Identifying the primary derangement directs the choice of compensation formulas.
2
Calculate the Anion Gap (AG).
AG=Na+−(Cl−+HCO3−)=140−(102+14)=24AG = Na^+ - (Cl^- + HCO_3^-) = 140 - (102 + 14) = 24. The normal AG is approximately 12. Thus, there is an elevated anion gap metabolic acidosis, consistent with lactic acidosis in sepsis.
Metabolic acidosis must be differentiated into normal vs. elevated anion gap etiologies.
3
Apply Winter's formula to determine expected respiratory compensation.
Expected PaCO2=(1.5×[HCO3−])+8±2=(1.5×14)+8±2=29±2Expected\ PaCO_2 = (1.5 \times [HCO_3^-]) + 8 \pm 2 = (1.5 \times 14) + 8 \pm 2 = 29 \pm 2 mm Hg. The expected range is 27 to 31 mm Hg.
Metabolic acidosis should trigger a predictable hyperventilatory response. Winter's formula defines this target.
4
Compare measured PaCO2PaCO_2 with expected PaCO2PaCO_2.
The measured PaCO2PaCO_2 is 36 mm Hg, which is higher than the maximum expected value of 31 mm Hg. This indicates a secondary respiratory acidosis.
If actual PaCO2PaCO_2 exceeds expected PaCO2PaCO_2, the lungs are hypoventilating relative to the systemic acid load (in this case, due to respiratory muscle fatigue).
5
Check the delta ratio for hidden metabolic disorders.
ΔRatio=AG−1224−HCO3−=24−1224−14=1210=1.2\Delta Ratio = \frac{AG - 12}{24 - HCO_3^-} = \frac{24 - 12}{24 - 14} = \frac{12}{10} = 1.2. This confirms a pure high anion gap metabolic acidosis.
To ensure no tertiary metabolic disorder (like concomitant metabolic alkalosis) is present.

Anahtar Kavram

In metabolic acidosis, adequate respiratory compensation must be verified using Winter's formula: Expected PaCO2=1.5×[HCO3−]+8±2Expected\ PaCO_2 = 1.5 \times [HCO_3^-] + 8 \pm 2. If the measured PaCO2PaCO_2 is higher than expected, there is a concomitant respiratory acidosis, which often signals impending respiratory failure in a critically ill patient.
Tahmini Süre:1m 30s
Soru 12Soru →

A 45-year-old man is brought to the emergency department by his wife due to acute-onset confusion, slurred speech, and an unsteady gait. His symptoms began earlier in the day and have progressively worsened. The patient has a history of severe Crohn's disease that necessitated multiple extensive small bowel resections three years ago, leaving him with short bowel syndrome. He does not consume alcohol and has no history of substance use. His temperature is 37.1°C (98.8°F), blood pressure is 110/70 mm Hg, heart rate is 88/min, and respiratory rate is 22/min. Physical examination reveals a confused man with an ataxic gait. His lungs are clear to auscultation. The abdomen is soft with well-healed surgical scars.

Laboratory studies show:

Laboratory TestResult
Sodium140 mEq/L
Potassium4.0 mEq/L
Chloride104 mEq/L
Bicarbonate12 mEq/L
Blood urea nitrogen14 mg/dL
Creatinine0.9 mg/dL
Glucose90 mg/dL
L-lactate1.1 mmol/L (Normal: 0.5–2.2 mmol/L)
Osmolality (measured)290 mOsm/kg H2OH_2O
Urine ketonesNegative

Arterial blood gas analysis on room air:

ParameterResult
pH7.24
pCO2pCO_226 mm Hg
pO2pO_295 mm Hg

Which of the following best describes the primary underlying mechanism for this patient's current condition?

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Cevap: Bacterial fermentation of unabsorbed dietary carbohydrates

Cevap

The correct underlying mechanism is the bacterial fermentation of unabsorbed dietary carbohydrates.
The correct answer identifies bacterial fermentation of unabsorbed dietary carbohydrates as the mechanism for D-lactic acidosis. This patient has a high anion gap metabolic acidosis (AG = 24 mEq/L) with appropriate respiratory compensation (pCO2pCO_2 = 26 mm Hg). After ruling out toxic alcohols (normal osmolar gap), diabetic ketoacidosis (normal glucose, negative ketones), and uremia (normal BUN/Cr), the differential narrows. In a patient with short bowel syndrome presenting with acute neurologic symptoms (confusion, ataxia), D-lactic acidosis is the classic diagnosis. Unabsorbed carbohydrates reach the colon and are fermented by bacteria (e.g., Lactobacillus) into D-lactate. Humans lack the enzyme D-lactate dehydrogenase, leading to systemic accumulation. Crucially, standard laboratory assays use L-lactate dehydrogenase and only detect the L-lactate isomer, resulting in a 'normal' serum lactate report despite profound acidosis.

Adım Adım Çözüm

1
Calculate the serum anion gap.
Anion Gap = Na+−(Cl−+HCO3−)=140−(104+12)=24Na^+ - (Cl^- + HCO_3^-) = 140 - (104 + 12) = 24 mEq/L.
To determine the primary etiology of the metabolic acidosis.
2
Evaluate for respiratory compensation using Winter's formula.
Expected pCO2=1.5×[HCO3−]+8±2=1.5×12+8±2=26±2pCO_2 = 1.5 \times [HCO_3^-] + 8 \pm 2 = 1.5 \times 12 + 8 \pm 2 = 26 \pm 2 mm Hg. Since actual pCO2pCO_2 is 26 mm Hg, compensation is appropriate.
To rule out a concurrent mixed respiratory disorder.
3
Calculate the serum osmolar gap.
Calculated Osmolality = 2×Na++Glucose18+BUN2.8=280+5+5=2902 \times Na^+ + \frac{\text{Glucose}}{18} + \frac{\text{BUN}}{2.8} = 280 + 5 + 5 = 290 mOsm/kg. Measured = 290 mOsm/kg. Osmolar Gap = 0.
To rule out toxic alcohol ingestion, which is a common cause of unexplained high anion gap metabolic acidosis.
4
Analyze the remaining MUDPILES differential given the patient's specific laboratory results and history.
Standard L-lactate is normal, glucose is normal, ketones are negative, and renal function is normal. The patient has short bowel syndrome and neurologic symptoms.
To identify D-lactic acidosis, which occurs when unabsorbed carbohydrates in short bowel syndrome are fermented by colonic bacteria into D-lactate. Standard hospital assays only detect L-lactate.

Anahtar Kavram

Patients with short bowel syndrome can develop D-lactic acidosis due to bacterial fermentation of malabsorbed carbohydrates. This presents as a high anion gap metabolic acidosis with neurologic symptoms and a falsely normal L-lactate level.
Soru 13Soru →

Match each patient's clinical presentation with the most likely corresponding urinalysis sediment finding.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

A 62-year-old man who develops acute kidney injury 48 hours after prolonged hypotension during an emergency abdominal aortic aneurysm repair.
A 24-year-old woman with recent onset of a malar rash, photosensitivity, and new hematuria with mild renal insufficiency.
A 45-year-old man presenting with severe generalized edema, a serum albumin of 2.1 g/dL, and a 24-hour urine protein excretion of 5.2 g.
A 58-year-old woman presenting with high fever, right-sided costovertebral angle tenderness, dysuria, and acute kidney injury.
A 72-year-old man with longstanding, poorly controlled hypertension and diabetes mellitus, presenting with small, echogenic kidneys on ultrasound.

Eşleşmeler

Cevabı ve açıklamayı göster

Cevap

The correct matches pair acute tubular necrosis with muddy brown casts, glomerulonephritis with red blood cell casts, nephrotic syndrome with fatty casts, acute pyelonephritis with white blood cell casts, and advanced chronic kidney disease with broad waxy casts.
Each clinical vignette presents classic hallmark features for a distinct renal pathology. The underlying mechanism of injury directly dictates the type of cells or substances that precipitate within the renal tubules to form casts: necrotic epithelial cells (ATN), red blood cells (glomerulonephritis), lipids (nephrotic syndrome), neutrophils (pyelonephritis), or degenerate proteins in dilated tubules (advanced CKD).

Adım Adım Çözüm

1
Analyze the first patient's presentation involving hypotension and surgery.
Identify ischemia-induced acute tubular necrosis (ATN).
ATN is the most common cause of intrinsic acute kidney injury following severe hypoperfusion.
2
Evaluate the second patient's systemic symptoms and hematuria.
Identify acute glomerulonephritis, likely secondary to systemic lupus erythematosus.
Glomerular inflammation leads to the passage of red blood cells through the damaged basement membrane.
3
Assess the third patient's severe edema, hypoalbuminemia, and massive proteinuria.
Identify nephrotic syndrome.
Proteinuria greater than 3.5 g/day defines nephrotic syndrome, which profoundly alters lipid metabolism.
4
Examine the fourth patient's fever and costovertebral angle tenderness.
Identify acute pyelonephritis.
These are hallmark signs of an upper urinary tract infection involving the renal interstitium.
5
Review the fifth patient's chronic comorbidities and small kidneys on ultrasound.
Identify advanced chronic kidney disease (CKD).
Chronic irreversible scarring leads to loss of renal mass and compensatory hypertrophy of remaining tubules.

Anahtar Kavram

Urinalysis sediment and cast differentiation in renal disease
Tahmini Süre:2m 0s
Soru 14Soru →

Review the following clinical presentations and arterial blood gas results. Which primary acid-base disorder best matches each clinical vignette?

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

A 22-year-old woman with type 1 diabetes presents with rapid breathing. Arterial blood gas shows pH 7.28, pCO2 28 mmHg, and HCO3 12 mEq/L.
A 68-year-old man with severe COPD presents with worsened dyspnea. Arterial blood gas shows pH 7.26, pCO2 65 mmHg, and HCO3 28 mEq/L.
A 19-year-old woman presents with carpopedal spasm during a panic attack. Arterial blood gas shows pH 7.52, pCO2 22 mmHg, and HCO3 20 mEq/L.
A 55-year-old man with peptic ulcer disease presents with 3 days of intractable vomiting. Arterial blood gas shows pH 7.54, pCO2 48 mmHg, and HCO3 40 mEq/L.
A 45-year-old woman presents with 4 days of severe watery diarrhea. Arterial blood gas shows pH 7.31, pCO2 32 mmHg, and HCO3 16 mEq/L. Serum sodium is 140 mEq/L, and chloride is 114 mEq/L.

Eşleşmeler

Cevabı ve açıklamayı göster

Cevap

The correct matches pair each clinical scenario with its hallmark primary acid-base disturbance: DKA with High anion gap metabolic acidosis; COPD exacerbation with Acute respiratory acidosis; panic attack with Acute respiratory alkalosis; vomiting with Metabolic alkalosis; and diarrhea with Normal anion gap metabolic acidosis.
Each vignette represents a classic primary acid-base disorder. Diabetic ketoacidosis causes a high anion gap metabolic acidosis. Acute COPD exacerbation causes CO2 retention and acute respiratory acidosis. Panic attacks cause hyperventilation and acute respiratory alkalosis. Intractable vomiting causes loss of gastric acid, resulting in metabolic alkalosis. Severe diarrhea causes direct loss of bicarbonate, resulting in a normal anion gap metabolic acidosis.

Adım Adım Çözüm

1
Analyze the pH to determine acidemia (pH < 7.35) or alkalemia (pH > 7.45).
Vignettes 1, 2, and 5 have acidemia. Vignettes 3 and 4 have alkalemia.
Establishing the primary direction of the pH change is the first step in acid-base interpretation.
2
Evaluate the pCO2 and HCO3 to identify the primary disorder causing the pH shift.
Vignettes 1 and 5 have primary decreases in HCO3 (metabolic acidosis). Vignette 2 has a primary increase in pCO2 (respiratory acidosis). Vignette 3 has a primary decrease in pCO2 (respiratory alkalosis). Vignette 4 has a primary increase in HCO3 (metabolic alkalosis).
The parameter that shifts in the same direction as the pH defines the primary disorder.
3
Calculate the serum anion gap for the cases of metabolic acidosis.
In vignette 5 (diarrhea), the anion gap is normal: 140 - (114 + 16) = 10 mEq/L. Vignette 1 (DKA) is a classic cause of high anion gap metabolic acidosis.
Differentiating normal from high anion gap metabolic acidosis is essential for identifying the correct etiology.

Anahtar Kavram

Interpretation of primary acid-base disorders based on arterial blood gas and clinical context.
Soru 15Soru →

During a routine follow-up, a 28-year-old female patient complains of new-onset fatigue and profound muscle weakness. She has a notable past medical history of recurrent nephrolithiasis. Her vital signs are within normal limits.

Laboratory testing reveals the following values:

Serum ParameterValue
Sodium (Na+Na^+)138 mEq/L
Potassium (K+K^+)2.8 mEq/L
Chloride (Cl−Cl^-)112 mEq/L
Bicarbonate (HCO3−HCO_3^-)14 mEq/L
Urine ParameterValue
Sodium (Na+Na^+)65 mEq/L
Potassium (K+K^+)25 mEq/L
Chloride (Cl−Cl^-)55 mEq/L
pH6.8

To help differentiate the cause of her normal anion gap metabolic acidosis, the attending physician requests calculation of the urine anion gap.

What is this patient's urine anion gap (in mEq/L)?

Cevabı ve açıklamayı göster

Cevap: 35

Cevap

35
The patient presents with a normal anion gap metabolic acidosis (NAGMA), likely secondary to type 1 (distal) renal tubular acidosis given her severe hypokalemia, nephrolithiasis, and alkaline urine pH. To confirm the renal etiology, the urine anion gap is calculated using the formula UNa+UK−UClU_{Na} + U_{K} - U_{Cl}. Plugging in the patient's urine electrolyte values yields 65+25−55=3565 + 25 - 55 = 35 mEq/L. A positive urine anion gap indicates impaired renal ammonium excretion, which points toward a renal tubular acidosis rather than gastrointestinal bicarbonate loss (where the UAG would typically be negative).

Adım Adım Çözüm

1
Identify the standard formula used for calculating the urine anion gap.
UAG=UNa+UK−UClUAG = U_{Na} + U_{K} - U_{Cl}
The urine anion gap is used to indirectly estimate urinary ammonium excretion when evaluating a normal anion gap metabolic acidosis.
2
Select the correct values from the laboratory data table.
Urine Na+=65Na^+ = 65 mEq/L, Urine K+=25K^+ = 25 mEq/L, Urine Cl−=55Cl^- = 55 mEq/L.
It is crucial to use urine electrolytes, not serum electrolytes, for this specific calculation.
3
Calculate the final result by plugging the values into the formula.
65+25−55=3565 + 25 - 55 = 35
Performing the arithmetic determines whether the gap is positive or negative, which aids in narrowing the differential diagnosis.

Anahtar Kavram

The urine anion gap (UAG) is calculated as UNa+UK−UClU_{Na} + U_{K} - U_{Cl} and provides an indirect measurement of urinary ammonium excretion to help distinguish between renal and gastrointestinal causes of a normal anion gap metabolic acidosis.
Soru 16Soru →

A 7878-year-old woman is evaluated in the hospital for worsening renal function. She was admitted 44 days ago for acute decompensated heart failure and has been receiving aggressive intravenous bumetanide therapy. Over the past 2424 hours, her urine output has decreased to 300 mL300\text{ mL}. On physical examination, her blood pressure is 105/65 mmHg105/65\text{ mmHg} and pulse is 92/min92/\text{min}. Jugular venous pressure is undetectable, and her lungs are clear to auscultation. Laboratory studies are obtained:

TestResult
Serum
Sodium140 mEq/L140\text{ mEq/L}
Blood urea nitrogen50 mg/dL50\text{ mg/dL}
Creatinine2.5 mg/dL2.5\text{ mg/dL} (baseline 1.1 mg/dL1.1\text{ mg/dL})
Urine
Sodium112 mEq/L112\text{ mEq/L}
Urea nitrogen500 mg/dL500\text{ mg/dL}
Creatinine100 mg/dL100\text{ mg/dL}

Based on the laboratory values, calculate the fractional excretion of urea (FEUreaFE_{Urea}) as a percentage to help determine the etiology of her acute kidney injury.

Cevabı ve açıklamayı göster

Cevap: 25

Cevap

25
The fractional excretion of urea (FEUrea) is calculated using the formula: FEUrea=UUrea×PCrPUrea×UCr×100FE_{Urea} = \frac{U_{Urea} \times P_{Cr}}{P_{Urea} \times U_{Cr}} \times 100. Substituting the patient's laboratory values yields: 500×2.550×100×100=12505000×100=25%\frac{500 \times 2.5}{50 \times 100} \times 100 = \frac{1250}{5000} \times 100 = 25\%. In patients receiving loop or thiazide diuretics, FEUrea is the preferred diagnostic metric over FeNa. Diuretics directly inhibit sodium reabsorption in the loop of Henle or distal convoluted tubule, artificially elevating urinary sodium and falsely increasing FeNa (in this patient, FeNa is calculated to be 2%2\%). However, urea reabsorption occurs primarily in the proximal tubule and is largely unaffected by these diuretics. An FEUrea<35%FE_{Urea} < 35\% strongly suggests prerenal AKI, which perfectly aligns with this patient's clinical picture of over-diuresis (undetectable jugular venous pressure, cleared lungs, and relative hypotension).

Adım Adım Çözüm

1
Assess the clinical scenario to choose the correct diagnostic calculation.
Determine that FEUrea should be used instead of FeNa.
The patient is actively receiving a loop diuretic (bumetanide), which artificially increases urinary sodium excretion and renders FeNa unreliable for diagnosing prerenal AKI.
2
Set up the Fractional Excretion of Urea (FEUrea) formula.
FEUrea=UUrea×PCrPUrea×UCr×100FE_{Urea} = \frac{U_{Urea} \times P_{Cr}}{P_{Urea} \times U_{Cr}} \times 100
This formula compares the clearance of urea to the clearance of creatinine to assess proximal tubular reabsorption.
3
Substitute the patient's laboratory values into the formula.
FEUrea=500×2.550×100×100FE_{Urea} = \frac{500 \times 2.5}{50 \times 100} \times 100
Accurate placement of serum and urine values is necessary to perform the calculation.
4
Perform the arithmetic calculation.
FEUrea=12505000×100=0.25×100=25%FE_{Urea} = \frac{1250}{5000} \times 100 = 0.25 \times 100 = 25\%
To obtain the final percentage required by the question format.

Anahtar Kavram

In patients receiving loop diuretics, the Fractional Excretion of Urea (FEUrea) is a more reliable indicator than FeNa for distinguishing between prerenal AKI and intrinsic AKI. An FEUrea < 35% indicates a prerenal etiology.
Tahmini Süre:1m 30s
Soru 17Soru →

A triage nurse urgently calls a physician to evaluate an 8080-year-old man who was just brought to the hospital by his son. The son reports that the patient suddenly developed excruciating abdominal pain two hours ago but now appears extremely lethargic and confused. The patient has a history of medication nonadherence for his paroxysmal atrial fibrillation. On physical examination, the abdomen is soft and non-tender to deep palpation. He is tachypneic with deep, rapid respirations.

Initial laboratory studies show:
Serum Na+\text{Na}^+: 140 mEq/L140 \text{ mEq/L}
Serum Cl−\text{Cl}^-: 100 mEq/L100 \text{ mEq/L}
Serum HCO3−\text{HCO}_3^-: 10 mEq/L10 \text{ mEq/L}

Arterial blood gas analysis on room air reveals a pH of 7.227.22 and a pCO2\text{pCO}_2 of 23 mm Hg23 \text{ mm Hg}.

Based on these findings, which of the following is the most accurate description of this patient's acid-base status?

Cevabı ve açıklamayı göster

Cevap: High anion gap metabolic acidosis with appropriate respiratory compensation

Cevap

High anion gap metabolic acidosis with appropriate respiratory compensation
This patient presents with a primary metabolic acidosis, evidenced by a pH of 7.22 and a low serum bicarbonate of 10 mEq/L. The next step in any metabolic acidosis is to calculate the anion gap: 140−(100+10)=30 mEq/L140 - (100 + 10) = 30 \text{ mEq/L}. An anion gap greater than 12 indicates a high anion gap metabolic acidosis (HAGMA), which in this patient's clinical context (pain out of proportion to exam, atrial fibrillation off anticoagulation) is highly suspicious for lactic acidosis secondary to acute mesenteric ischemia. Finally, Winter's formula (Expected pCO2=1.5×[HCO3−]+8±2\text{Expected pCO}_2 = 1.5 \times [\text{HCO}_3^-] + 8 \pm 2) is applied to check for a mixed disorder. Calculating (1.5×10)+8(1.5 \times 10) + 8 yields an expected pCO2\text{pCO}_2 of 23 mm Hg23 \text{ mm Hg}. Because the patient's measured pCO2\text{pCO}_2 is exactly 23 mm Hg23 \text{ mm Hg}, the respiratory compensation is appropriate, meaning there is no superimposed secondary respiratory disorder.

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1
Determine the primary acid-base disorder by looking at the pH and bicarbonate.
The pH is 7.22 (acidemia) and the serum bicarbonate is low at 10 mEq/L, confirming a primary metabolic acidosis.
Acidemia (pH < 7.35) combined with a matched drop in bicarbonate defines a primary metabolic acidosis.
2
Calculate the serum anion gap.
Anion Gap=Na+−(Cl−+HCO3−)=140−(100+10)=30 mEq/L\text{Anion Gap} = \text{Na}^+ - (\text{Cl}^- + \text{HCO}_3^-) = 140 - (100 + 10) = 30 \text{ mEq/L}.
Determining if the anion gap is normal (8-12 mEq/L) or elevated (>12 mEq/L) restricts the differential diagnosis. Here, the gap is highly elevated, indicating the presence of unmeasured anions (likely lactate due to acute mesenteric ischemia).
3
Calculate the expected respiratory compensation using Winter's formula.
Expected pCO2=(1.5×HCO3−)+8±2=(1.5×10)+8=23±2 mm Hg\text{Expected pCO}_2 = (1.5 \times \text{HCO}_3^-) + 8 \pm 2 = (1.5 \times 10) + 8 = 23 \pm 2 \text{ mm Hg}.
Winter's formula evaluates whether the patient's respiratory response (hyperventilation) is adequate for the degree of metabolic acidosis.
4
Compare the measured pCO2 to the expected pCO2.
The measured pCO2\text{pCO}_2 is 23 mm Hg23 \text{ mm Hg}, which falls perfectly within the expected range (21−25 mm Hg21-25 \text{ mm Hg}).
Because the measured value matches the expected value, there is no superimposed secondary respiratory disorder (neither concurrent respiratory acidosis nor alkalosis).

Anahtar Kavram

Evaluation of acid-base disorders using the anion gap calculation and Winter's formula.
Soru 18Soru →

A 24-year-old man is brought to the emergency department by paramedics after being found unresponsive in his garage. An open bottle of antifreeze was found nearby. His temperature is 36.5∘C36.5^\circ\text{C} (97.7∘F97.7^\circ\text{F}), blood pressure is 110/70 mm Hg110/70\text{ mm Hg}, pulse is 112/min112\text{/min}, and respirations are 28/min28\text{/min} and deep. Physical examination reveals a comatose patient with no focal neurologic deficits.

Laboratory studies show the following:
Serum sodium: 138 mEq/L138\text{ mEq/L}
Serum potassium: 5.0 mEq/L5.0\text{ mEq/L}
Serum chloride: 104 mEq/L104\text{ mEq/L}
Serum bicarbonate: 10 mEq/L10\text{ mEq/L}
Blood urea nitrogen: 14 mg/dL14\text{ mg/dL}
Serum creatinine: 1.2 mg/dL1.2\text{ mg/dL}
Serum glucose: 90 mg/dL90\text{ mg/dL}
Measured serum osmolality: 315 mOsm/kg H2O315\text{ mOsm/kg H}_2\text{O}

Arterial blood gas on room air:
pH: 7.207.20
pCO 2_2: 24 mm Hg24\text{ mm Hg}
pO 2_2: 95 mm Hg95\text{ mm Hg}

What is this patient's serum osmolar gap? (Enter the value only)

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Cevap: 29

Cevap

The patient's serum osmolar gap is 29 mOsm/kg.
The serum osmolar gap is calculated by subtracting the calculated serum osmolality from the measured serum osmolality. The calculated serum osmolality is 2×[Na+]+[Glucose]18+[BUN]2.82 \times [Na^+] + \frac{[Glucose]}{18} + \frac{[BUN]}{2.8}. For this patient, the calculated osmolality is 2×138+9018+142.8=286 mOsm/kg2 \times 138 + \frac{90}{18} + \frac{14}{2.8} = 286 \text{ mOsm/kg}. The osmolar gap is 315−286=29 mOsm/kg315 - 286 = 29 \text{ mOsm/kg}. A normal osmolar gap is typically less than 10 mOsm/kg. An elevated osmolar gap in the setting of a high anion gap metabolic acidosis is highly suggestive of toxic alcohol ingestion (e.g., ethylene glycol or methanol).

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1
Identify the need to calculate the osmolar gap.
The patient has a high anion gap metabolic acidosis and suspected toxic alcohol ingestion, which requires calculation of the osmolar gap to support the diagnosis.
Ethylene glycol and methanol are unmeasured osmotically active substances that increase the osmolar gap.
2
Calculate the expected serum osmolality.
Expected Osmolality = 2×138+9018+142.8=276+5+5=286 mOsm/kg H2O2 \times 138 + \frac{90}{18} + \frac{14}{2.8} = 276 + 5 + 5 = 286 \text{ mOsm/kg H}_2\text{O}.
The calculated serum osmolality accounts for the primary normal osmotically active solutes in the blood: sodium, glucose, and urea.
3
Calculate the osmolar gap.
Osmolar Gap = Measured Osmolality - Calculated Osmolality = 315−286=29 mOsm/kg315 - 286 = 29 \text{ mOsm/kg}.
The difference between measured and calculated osmolality represents the concentration of unmeasured osmoles (e.g., ethylene glycol).

Anahtar Kavram

The serum osmolar gap is used to detect the presence of unmeasured osmotically active substances (such as toxic alcohols) in the blood. It is calculated as the difference between the measured serum osmolality and the calculated serum osmolality.
Tahmini Süre:1m 30s
Soru 19Soru →

A 7272-year-old woman is evaluated on hospital day 44 for worsening renal function. She was admitted for acute decompensated heart failure and has been receiving intravenous furosemide. Over the past 4848 hours, her weight has decreased by 4.5 kg4.5\text{ kg}, but her urine output has dropped to 300 mL300\text{ mL} over the last 1212 hours. Her blood pressure is 95/60 mmHg95/60\text{ mmHg} and heart rate is 102/min102\text{/min}. Laboratory studies show:

LabValue
Serum sodium136 mEq/L136\text{ mEq/L}
Serum blood urea nitrogen (BUN)75 mg/dL75\text{ mg/dL}
Serum creatinine2.5 mg/dL2.5\text{ mg/dL} (baseline 1.1 mg/dL1.1\text{ mg/dL})
Urine sodium110 mEq/L110\text{ mEq/L}
Urine urea nitrogen450 mg/dL450\text{ mg/dL}
Urine creatinine100 mg/dL100\text{ mg/dL}

What is this patient's fractional excretion of urea (FEUreaFE_{Urea})? (Express the answer as a percentage).

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Cevap: 15

Cevap

15
The correct answer is 15%15\%. This patient presents with acute kidney injury (AKI) in the setting of aggressive diuresis for heart failure. Distinguishing between prerenal azotemia (hypovolemia) and intrinsic renal disease (such as acute tubular necrosis) is critical for her ongoing management. While the fractional excretion of sodium (FENaFE_{Na}) is typically less than 1%1\% in prerenal AKI, loop diuretics directly inhibit sodium reabsorption, causing a falsely elevated FENaFE_{Na} (in this patient's case, it would be calculated as roughly 2.02%2.02\%). In patients on active diuretic therapy, the fractional excretion of urea (FEUreaFE_{Urea}) is a much more accurate diagnostic marker because urea reabsorption is closely linked to proximal tubule water reabsorption and is significantly less affected by loop diuretics. An FEUreaFE_{Urea} of less than 35%35\% strongly suggests prerenal azotemia. The calculation is performed as follows: FEUrea=UUrea×PCrPUrea×UCr×100=450×2.575×100×100=11257500×100=15%FE_{Urea} = \frac{U_{Urea} \times P_{Cr}}{P_{Urea} \times U_{Cr}} \times 100 = \frac{450 \times 2.5}{75 \times 100} \times 100 = \frac{1125}{7500} \times 100 = 15\%.

Adım Adım Çözüm

1
Evaluate the clinical scenario and the limitation of standard AKI diagnostic indices.
Identify that the patient's active furosemide use falsely elevates sodium excretion, making FE_Na inaccurate (calculated here as 2.02%).
Loop diuretics inhibit sodium reabsorption in the thick ascending limb of the loop of Henle, invalidating FE_Na as a marker for volume status.
2
Select the appropriate diagnostic calculation for patients on diuretics.
Use the Fractional Excretion of Urea (FE_Urea).
Urea reabsorption occurs primarily in the proximal tubule and is less affected by loop diuretics. An FE_Urea < 35% reliably indicates a prerenal state.
3
Apply the FE_Urea formula.
FE_Urea = (Urine Urea_nitrogen * Serum Creatinine) / (Serum BUN * Urine Creatinine) * 100
This formula compares the clearance of urea to the clearance of creatinine to determine the fraction of filtered urea that is ultimately excreted.
4
Substitute the provided laboratory values into the formula.
(450 * 2.5) / (75 * 100) * 100 = 1125 / 7500 * 100
Accurate substitution of variables is required to solve the clearance ratio.
5
Perform the final calculation.
0.15 * 100 = 15%
To express the fractional excretion as a percentage.

Anahtar Kavram

In patients receiving active diuretic therapy, the fractional excretion of urea (FE_Urea) is a more reliable indicator of prerenal azotemia than the fractional excretion of sodium (FE_Na).
Soru 20Soru →

Correlate the following patient presentations with their most characteristic histopathologic finding on renal biopsy.

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Öğeler

A 24-year-old female with a malar rash developing acute-onset hypertension, oliguria, and red blood cell casts.
A 62-year-old male with a history of colon cancer presenting with anasarca, normal serum creatinine, and heavy proteinuria.
A 28-year-old male with recurrent, transient episodes of gross hematuria occurring contemporaneously with viral upper respiratory tract infections.
A 10-year-old boy presenting with periorbital edema and cola-colored urine two weeks after resolution of a skin infection.
A 58-year-old female with chronic untreated hepatitis C presenting with palpable purpura, joint pain, and mixed nephritic-nephrotic syndrome.

Eşleşmeler

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Cevap

Lupus nephritis matches with 'wire loops'; malignancy-associated nephrotic syndrome matches with 'spike and dome'; synpharyngitic hematuria matches with mesangial IgA deposition; post-impetigo nephritic syndrome matches with subepithelial 'humps'; and Hepatitis C-associated renal disease matches with 'tram-track' appearance.
Each clinical vignette provides classic demographic and historical clues for specific glomerular diseases. Identifying the underlying etiology allows for direct correlation with its pathognomonic renal biopsy findings.

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1
Identify the underlying glomerular disease for each clinical vignette.
The vignettes describe Diffuse Proliferative Glomerulonephritis (DPGN), Membranous Nephropathy, IgA Nephropathy, Poststreptococcal Glomerulonephritis (PSGN), and Membranoproliferative Glomerulonephritis (MPGN), respectively.
Accurately diagnosing the clinical syndrome based on timing, patient demographics, and associated systemic symptoms is a prerequisite to predicting the biopsy findings.
2
Correlate each identified glomerular disease with its characteristic light, immunofluorescence, or electron microscopy findings.
DPGN -> wire loops; Membranous -> spike and dome; IgA -> mesangial IgA deposits; PSGN -> subepithelial humps; MPGN -> tram-track appearance.
USMLE Step 2 CK expects integration of clinical presentations with classic pathophysiologic and histopathologic anchors.

Anahtar Kavram

Glomerular Disease Histopathology and Clinical Correlations
Sayfa 1 / 17Sonraki
Nephrology Alıştırma Soruları — USMLE Step 2 CK | Examkin