A 62-year-old woman with a history of severe protein-calorie malnutrition and chronic diar… — USMLE Step 3

A 62-year-old woman with a history of severe protein-calorie malnutrition and chronic diarrhea is admitted to the hospital with generalized weakness and lethargy. Vital signs are within normal limits. An arterial blood gas analysis reveals a $pH$ of $7.31$ and a $PaCO_2$ of $32\text{ mmHg}$ .

Serum laboratory studies report the following:

Laboratory Test	Result	Reference Range
Sodium ( $Na^+$ )	$138\text{ mEq/L}$	$136-145\text{ mEq/L}$
Potassium ( $K^+$ )	$3.4\text{ mEq/L}$	$3.5-5.0\text{ mEq/L}$
Chloride ( $Cl^-$ )	$111\text{ mEq/L}$	$95-105\text{ mEq/L}$
Bicarbonate ( $HCO_3^-$ )	$16\text{ mEq/L}$	$22-28\text{ mEq/L}$
Blood urea nitrogen	$32\text{ mg/dL}$	$7-18\text{ mg/dL}$
Creatinine	$1.4\text{ mg/dL}$	$0.6-1.2\text{ mg/dL}$
Albumin	$1.6\text{ g/dL}$	$3.5-5.0\text{ g/dL}$
Lactate	$3.8\text{ mmol/L}$	$0.5-1.0\text{ mmol/L}$

What is the patient's albumin-corrected serum anion gap in $\text{mEq/L}$ ? (Assume a standard reference serum albumin concentration of $4.0\text{ g/dL}$ ).

Cevap: 17 mEq/L

Cevap

The patient's albumin-corrected serum anion gap is 17 mEq/L.

The correct albumin-adjusted anion gap is

17\text{ mEq/L}

. Albumin is a major unmeasured negatively charged protein in the blood. When albumin levels drop significantly, as in severe malnutrition, the baseline 'normal' anion gap shrinks. A standard uncorrected calculation in this patient yields an anion gap of

11\text{ mEq/L}

, which falsely appears normal. Applying the standard correction factor (

2.5\text{ mEq/L}

added for every

1.0\text{ g/dL}

deficit of albumin below the norm of

4.0\text{ g/dL}

) reveals a true anion gap of

17\text{ mEq/L}

. This appropriately unmasks an underlying high anion gap metabolic acidosis, which is highly consistent with the patient's elevated serum lactate of

3.8\text{ mmol/L}

Adım Adım Çözüm

Calculate the uncorrected serum anion gap.

11\text{ mEq/L}

Using the formula

Na^+ - (Cl^- + HCO_3^-)

, the calculation is

138 - (111 + 16) = 11

. This establishes the baseline apparent anion gap.

Determine the patient's albumin deficit.

2.4\text{ g/dL}

Subtracting the patient's measured albumin (

1.6\text{ g/dL}

) from the standard reference normal (

4.0\text{ g/dL}

) quantifies the lack of unmeasured anions (

4.0 - 1.6 = 2.4

Calculate the correction value for the anion gap.

6\text{ mEq/L}

For every

1.0\text{ g/dL}

decrease in serum albumin, the anion gap is falsely lowered by approximately

2.5\text{ mEq/L}

. Multiplying the deficit (

2.4

) by

2.5

yields

6

Calculate the final albumin-corrected anion gap.

17\text{ mEq/L}

Adding the correction value (

6

) to the uncorrected anion gap (

11

) reveals the true anion gap (

17

), uncovering an occult high anion gap metabolic acidosis.

Anahtar Kavram

In patients with significant hypoalbuminemia, the calculated serum anion gap must be mathematically corrected (adding

2.5\text{ mEq/L}

for every

1.0\text{ g/dL}

decrease in albumin below

4.0\text{ g/dL}

) to accurately interpret acid-base status and avoid missing a hidden high anion gap metabolic acidosis.

Alternatif Yöntem

An alternative and clinically common rough estimate is to simply expect the 'normal' anion gap threshold to decrease by

2.5

for every

1\text{ g/dL}

drop in albumin. In this patient, the expected normal upper limit anion gap would drop from

12

down to

6

. Since the patient's uncorrected measured gap is

11

, it significantly exceeds the newly adjusted threshold of

6

, confirming the presence of a high anion gap disorder.

Tahmini Süre:1m 30s

Soru

Cevap

Adım Adım Çözüm

Anahtar Kavram

Sık Yapılan Hatalar

Alternatif Yöntem

Konular

Bu konudan daha fazla soru