Question

Difficulty: HardLinear Equations and Graphing

A linear function contains the points shown in the table below:

xxyy
k2k - 255
k+1k + 11414
2k+32k + 33535

What is the yy-intercept of the line representing this function?

Answer: -4

Answer

The yy-intercept of the line representing this function is 4-4.
By using the first two coordinates, the constant slope of the linear function is determined to be 33. Equating the slope between the second and third coordinates to 33 yields the parameter k=5k = 5. Substituting this back into the coordinate expressions gives the points (3,5)(3, 5) and (6,14)(6, 14). Using the point-slope form, the equation of the line is y=3x4y = 3x - 4, meaning the yy-intercept is 4-4.

Step-by-Step Solution

1
Calculate the slope of the line using the first two points: (k2,5)(k-2, 5) and (k+1,14)(k+1, 14).
m=145(k+1)(k2)=93=3m = \frac{14 - 5}{(k+1) - (k-2)} = \frac{9}{3} = 3
Since the function is linear, the rate of change (slope) remains constant between any two points.
2
Express the slope using the second and third points, (k+1,14)(k+1, 14) and (2k+3,35)(2k+3, 35), set it equal to 33, and solve for kk.
3514(2k+3)(k+1)=3    21k+2=3    3(k+2)=21    k+2=7    k=5\frac{35 - 14}{(2k+3) - (k+1)} = 3 \implies \frac{21}{k+2} = 3 \implies 3(k+2) = 21 \implies k+2 = 7 \implies k = 5
The slope between the second and third points must also equal the constant slope of 33.
3
Substitute k=5k = 5 back into the coordinates to determine the actual points on the line.
The points are (3,5)(3, 5), (6,14)(6, 14), and (13,35)(13, 35).
This provides concrete coordinates that can be used to write the equation of the line.
4
Use the point-slope form with the point (3,5)(3, 5) and slope m=3m = 3 to write the equation of the line, then convert to slope-intercept form.
y5=3(x3)    y5=3x9    y=3x4y - 5 = 3(x - 3) \implies y - 5 = 3x - 9 \implies y = 3x - 4
Converting to slope-intercept form (y=mx+by = mx + b) directly gives the yy-intercept as the constant term bb.

Key Concept

Determining the equation and intercepts of a line using the constant slope property of linear functions.

Alternative Method

Once the slope m=3m = 3 and a point such as (3,5)(3, 5) are established, substitute these values directly into the slope-intercept equation y=mx+by = mx + b to solve for bb. This gives 5=3(3)+b    5=9+b    b=45 = 3(3) + b \implies 5 = 9 + b \implies b = -4.
Estimated Time:2m 30s
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