Question

Difficulty: MediumLogarithmic and Exponential Expressions and Equations

For all positive real numbers xx and yy, which of the following expressions is equivalent to log⁡3(9x4y−2)\log_3(9x^4 y^{-2})?

  1. A
    9+4log⁡3(x)−2log⁡3(y)9 + 4\log_3(x) - 2\log_3(y)
  2. B
    2+4log⁡3(x)+2log⁡3(y)2 + 4\log_3(x) + 2\log_3(y)
  3. 2+4log⁡3(x)−2log⁡3(y)2 + 4\log_3(x) - 2\log_3(y)Answer
  4. D
    2+4log⁡3(x)2log⁡3(y)\frac{2 + 4\log_3(x)}{2\log_3(y)}
  5. E
    2+log⁡3(4x)−log⁡3(2y)2 + \log_3(4x) - \log_3(2y)

Answer

2+4log⁡3(x)−2log⁡3(y)2 + 4\log_3(x) - 2\log_3(y)
The correct answer is correct because applying the product and power properties of logarithms allows us to expand the argument 9x4y−29x^4 y^{-2}. Specifically, the expression can be written as log⁡3(9)+log⁡3(x4)+log⁡3(y−2)\log_3(9) + \log_3(x^4) + \log_3(y^{-2}). Since 32=93^2 = 9, the term log⁡3(9)\log_3(9) evaluates to 22. Applying the power rule log⁡b(Mk)=klog⁡b(M)\log_b(M^k) = k\log_b(M) to the remaining terms yields 4log⁡3(x)4\log_3(x) and −2log⁡3(y)-2\log_3(y). Combining these terms results in the equivalent expression.

Step-by-Step Solution

1
Use the product rule of logarithms, log⁡b(MN)=log⁡b(M)+log⁡b(N)\log_b(MN) = \log_b(M) + \log_b(N), to separate the factors in the argument.
log⁡3(9x4y−2)=log⁡3(9)+log⁡3(x4)+log⁡3(y−2)\log_3(9x^4 y^{-2}) = \log_3(9) + \log_3(x^4) + \log_3(y^{-2})
This allows the expression to be broken down into individual terms for each base and variable.
2
Evaluate the constant logarithm log⁡3(9)\log_3(9). Since 32=93^2 = 9, this simplifies to 22.
log⁡3(9)=2\log_3(9) = 2
To simplify the numerical term to its integer value.
3
Use the power rule of logarithms, log⁡b(Mk)=klog⁡b(M)\log_b(M^k) = k\log_b(M), to bring the exponents of the variables to the front of each logarithm.
log⁡3(x4)=4log⁡3(x)\log_3(x^4) = 4\log_3(x) and log⁡3(y−2)=−2log⁡3(y)\log_3(y^{-2}) = -2\log_3(y)
To isolate the variable terms inside simpler logarithmic expressions.
4
Combine all the simplified parts into a single expression.
2+4log⁡3(x)−2log⁡3(y)2 + 4\log_3(x) - 2\log_3(y)
To write the final expanded equivalent expression.

Key Concept

Logarithmic properties, including product, power, and evaluation of basic log terms.

Alternative Method

Substitute test values for the variables. For example, let x=3x = 3 and y=3y = 3. The original expression evaluates to log⁡3(9⋅34⋅3−2)=log⁡3(81)=4\log_3(9 \cdot 3^4 \cdot 3^{-2}) = \log_3(81) = 4. Substituting x=3x = 3 and y=3y = 3 into the correct expression yields 2+4log⁡3(3)−2log⁡3(3)=2+4(1)−2(1)=42 + 4\log_3(3) - 2\log_3(3) = 2 + 4(1) - 2(1) = 4, which matches the original expression's value.
Estimated Time:1m 0s
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