Question

Difficulty: MediumEvaluating Algebraic Expressions

If a=−2a = -2, b=3b = 3, and c=−12c = -\frac{1}{2}, what is the value of the algebraic expression a3b+4ca2−2b\frac{a^3 b + 4c}{a^2 - 2b}?

Answer:If a=−2a = -2, b=3b = 3, and c=−12c = -\frac{1}{2}, the value of the algebraic expression a3b+4ca2−2b\frac{a^3 b + 4c}{a^2 - 2b} is 【13】.

Answer

13
Substituting a=−2a = -2, b=3b = 3, and c=−12c = -\frac{1}{2} into the given expression yields a numerator of (−2)3(3)+4(−12)=−24−2=−26(-2)^3(3) + 4(-\frac{1}{2}) = -24 - 2 = -26 and a denominator of (−2)2−2(3)=4−6=−2(-2)^2 - 2(3) = 4 - 6 = -2. Dividing the numerator by the denominator gives −26−2=13\frac{-26}{-2} = 13.

Step-by-Step Solution

1
Evaluate the terms in the numerator individually.
a3b=(−2)3⋅3=−8⋅3=−24a^3 b = (-2)^3 \cdot 3 = -8 \cdot 3 = -24 and 4c=4(−12)=−24c = 4\left(-\frac{1}{2}\right) = -2.
Exponents take precedence before multiplication, and multiplying a positive by a negative yields a negative number.
2
Combine the terms to calculate the numerator.
Numerator =−24+(−2)=−26= -24 + (-2) = -26.
Adding two negative numbers sums their magnitudes with a negative sign.
3
Evaluate the terms in the denominator.
a2=(−2)2=4a^2 = (-2)^2 = 4 and 2b=2(3)=62b = 2(3) = 6.
Squaring a negative base results in a positive value.
4
Calculate the denominator.
Denominator =4−6=−2= 4 - 6 = -2.
Subtracting a larger number from a smaller number produces a negative result.
5
Divide the numerator by the denominator to find the final value.
−26−2=13\frac{-26}{-2} = 13.
Dividing a negative number by a negative number yields a positive quotient.

Key Concept

Evaluating Algebraic Expressions
Estimated Time:1m 30s
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