Question

Difficulty: HardFactors, Multiples, and Prime Factorization

To complete a project, Alice works in shifts that last 34\frac{3}{4} of an hour, and Bob works in shifts that last 56\frac{5}{6} of an hour. If they both begin their first shift at the exact same time, after how many hours will they next begin a shift at the same time?

  1. A
    58\frac{5}{8}
  2. B
    45\frac{4}{5}
  3. C
    54\frac{5}{4}
  4. D
    1912\frac{19}{12}
  5. 152\frac{15}{2}Answer

Answer

The two workers will next begin a shift at the same time after 152\frac{15}{2} hours.
To find when both Alice and Bob will next start their shifts at the same time, we need to find the Least Common Multiple (LCM) of their shift durations, 34\frac{3}{4} and 56\frac{5}{6} hours. One way to do this is to convert the durations into minutes: 34×60=45\frac{3}{4} \times 60 = 45 minutes, and 56×60=50\frac{5}{6} \times 60 = 50 minutes. The prime factorizations are 45=32×545 = 3^2 \times 5 and 50=2×5250 = 2 \times 5^2. The LCM of 4545 and 5050 is 2×32×52=4502 \times 3^2 \times 5^2 = 450 minutes. Converting this back to hours gives 45060=152\frac{450}{60} = \frac{15}{2} hours. Alternatively, using the formula for the LCM of fractions: LCM(ab,cd)=LCM(a,c)GCD(b,d)\text{LCM}\left(\frac{a}{b}, \frac{c}{d}\right) = \frac{\text{LCM}(a, c)}{\text{GCD}(b, d)}, we get LCM(3,5)GCD(4,6)=152\frac{\text{LCM}(3, 5)}{\text{GCD}(4, 6)} = \frac{15}{2} hours.

Step-by-Step Solution

1
Identify the mathematical concept needed to solve the simultaneous starting times.
The next simultaneous starting time is the Least Common Multiple (LCM) of the two shift durations, 34\frac{3}{4} and 56\frac{5}{6} hours.
Because both shifts start at multiples of their respective durations, the first time they start together again must be a common multiple of both intervals.
2
Calculate the LCM of the fractions 34\frac{3}{4} and 56\frac{5}{6}.
Using the fraction LCM formula, LCM(ab,cd)=LCM(a,c)GCD(b,d)\text{LCM}(\frac{a}{b}, \frac{c}{d}) = \frac{\text{LCM}(a, c)}{\text{GCD}(b, d)}, we find LCM(3,5)=15\text{LCM}(3, 5) = 15 and GCD(4,6)=2\text{GCD}(4, 6) = 2, yielding 152\frac{15}{2} hours.
This formula correctly scales the numerator multiples while accounting for the common division in the denominators.

Key Concept

Finding the Least Common Multiple (LCM) of fractional values or using unit conversion to find the LCM of integers.

Alternative Method

Convert the fractional hours into minutes first. Alice's shifts are 34\frac{3}{4} of an hour, which is 4545 minutes. Bob's shifts are 56\frac{5}{6} of an hour, which is 5050 minutes. Find the LCM of 4545 and 5050 by listing their multiples or using their prime factorizations: 45=32×545 = 3^2 \times 5 and 50=2×5250 = 2 \times 5^2, so their LCM is 2×32×52=4502 \times 3^2 \times 5^2 = 450 minutes. Finally, convert 450450 minutes back to hours by dividing by 6060, which simplifies to 45060=152\frac{450}{60} = \frac{15}{2} hours.
Estimated Time:2m 0s
Rate this question