Question

Difficulty: EasyMatrices and Matrix Operations

A sporting goods chain has two locations. Location 1 sells 10 soccer balls and 15 basketballs. Location 2 sells 8 soccer balls and 20 basketballs. This is represented by the sales matrix A = \begin{bmatrix} 10 & 15 \\ 8 & 20 \\end{bmatrix}. Soccer balls cost 15eachandbasketballscost15 each and basketballs cost 25 each, represented by the price matrix B = \begin{bmatrix} 15 \\ 25 \\end{bmatrix}. What is the product ABAB, which represents the total revenue generated by each location?

  1. A
    \begin{bmatrix} 150 \\ 500 \\end{bmatrix}
  2. B
    \begin{bmatrix} 350 \\ 725 \\end{bmatrix}
  3. C
    \begin{bmatrix} 525 \\ 520 \\end{bmatrix}
  4. \begin{bmatrix} 525 \\ 620 \\end{bmatrix}Answer
  5. E
    \begin{bmatrix} 525 & 620 \\end{bmatrix}

Answer

The column matrix with elements 525 in the first row and 620 in the second row
The correct answer is the column matrix containing 525 and 620. This is found by multiplying each row of the sales matrix (representing each location) by the column of the price matrix (representing prices of the items): 10(15)+15(25)=52510(15) + 15(25) = 525 for the first row, and 8(15)+20(25)=6208(15) + 20(25) = 620 for the second row.

Step-by-Step Solution

1
Set up the matrix multiplication of the 2×22 \times 2 sales matrix AA and the 2×12 \times 1 price matrix BB.
AB = \begin{bmatrix} 10 & 15 \\ 8 & 20 \\end{bmatrix} \begin{bmatrix} 15 \\ 25 \\end{bmatrix}
To find the total revenue for each location, we multiply the sales of each item by its corresponding price.
2
Multiply the first row of AA by the column of BB to find the element in the first row of the product matrix (revenue for Location 1).
10(15)+15(25)=150+375=52510(15) + 15(25) = 150 + 375 = 525
This calculates the total revenue for Location 1 by summing the revenue from soccer balls (10×1510 \times 15) and basketballs (15×2515 \times 25).
3
Multiply the second row of AA by the column of BB to find the element in the second row of the product matrix (revenue for Location 2).
8(15)+20(25)=120+500=6208(15) + 20(25) = 120 + 500 = 620
This calculates the total revenue for Location 2 by summing the revenue from soccer balls (8×158 \times 15) and basketballs (20×2520 \times 25).
4
Combine the results into a 2×12 \times 1 resulting matrix.
\begin{bmatrix} 525 \\ 620 \\end{bmatrix}
Since matrix AA has dimensions 2×22 \times 2 and matrix BB has dimensions 2×12 \times 1, their product ABAB must have dimensions 2×12 \times 1.

Key Concept

Matrix multiplication involves multiplying the rows of the first matrix by the columns of the second matrix, matching corresponding elements and adding the products.

Alternative Method

Instead of matrix multiplication, the revenue can be computed using standard arithmetic: Location 1 revenue is 10×$15+15×$25=$52510 \times \$15 + 15 \times \$25 = \$525 and Location 2 revenue is 8×$15+20×$25=$6208 \times \$15 + 20 \times \$25 = \$620. The resulting column matrix is \begin{bmatrix} 525 \\ 620 \\end{bmatrix}.
Estimated Time:1m 0s
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