A sporting goods chain has two locations. Location 1 sells 10 soccer balls and 15 basketballs. Location 2 sells 8 soccer balls and 20 basketballs. This is represented by the sales matrix A = \begin{bmatrix} 10 & 15 \\ 8 & 20 \\end{bmatrix}. Soccer balls cost 25 each, represented by the price matrix B = \begin{bmatrix} 15 \\ 25 \\end{bmatrix}. What is the product , which represents the total revenue generated by each location?
- A\begin{bmatrix} 150 \\ 500 \\end{bmatrix}
- B\begin{bmatrix} 350 \\ 725 \\end{bmatrix}
- C\begin{bmatrix} 525 \\ 520 \\end{bmatrix}
- \begin{bmatrix} 525 \\ 620 \\end{bmatrix}Answer
- E\begin{bmatrix} 525 & 620 \\end{bmatrix}
Answer
The column matrix with elements 525 in the first row and 620 in the second row
The correct answer is the column matrix containing 525 and 620. This is found by multiplying each row of the sales matrix (representing each location) by the column of the price matrix (representing prices of the items): for the first row, and for the second row.
Step-by-Step Solution
Key Concept
Matrix multiplication involves multiplying the rows of the first matrix by the columns of the second matrix, matching corresponding elements and adding the products.
Alternative Method
Instead of matrix multiplication, the revenue can be computed using standard arithmetic: Location 1 revenue is and Location 2 revenue is . The resulting column matrix is \begin{bmatrix} 525 \\ 620 \\end{bmatrix}.
Estimated Time:1m 0s