Question

Difficulty: MediumGraphs of Trigonometric Functions

What is the period of the trigonometric function f(x)=3cos(π5x+π2)4f(x) = 3 \cos\left(\frac{\pi}{5}x + \frac{\pi}{2}\right) - 4?

  1. 1010Answer
  2. B
    55
  3. C
    2π2\pi
  4. D
    π5\frac{\pi}{5}
  5. E
    25\frac{2}{5}

Answer

10
The period of a function of the form f(x)=Acos(Bx+C)+Df(x) = A \cos(Bx + C) + D is given by T=2πBT = \frac{2\pi}{|B|}. Substituting B=π5B = \frac{\pi}{5} yields T=2ππ5=2π5π=10T = \frac{2\pi}{\frac{\pi}{5}} = 2\pi \cdot \frac{5}{\pi} = 10.

Step-by-Step Solution

1
Identify the coefficient of xx (BB) in the given trigonometric function.
B=π5B = \frac{\pi}{5}
The standard form for a transformed cosine function is f(x)=Acos(Bx+C)+Df(x) = A \cos(Bx + C) + D, where BB controls the horizontal stretch or compression.
2
Apply the period formula for cosine, T=2πBT = \frac{2\pi}{|B|}.
T=2ππ5T = \frac{2\pi}{\frac{\pi}{5}}
The fundamental period of cos(x)\cos(x) is 2π2\pi, which is scaled inversely by B|B|.
3
Simplify the fraction by multiplying by the reciprocal.
T=2π5π=10T = 2\pi \cdot \frac{5}{\pi} = 10
Dividing by a fraction is equivalent to multiplying by its reciprocal, and the factor of π\pi cancels out.

Key Concept

Period of Transformed Cosine Functions
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