Question

Difficulty: MediumFunction Evaluation, Composition, and Properties

Let the functions ff and gg be defined by f(x)=x4f(x) = |x - 4| and g(x)=2x+1g(x) = 2x + 1 for all real numbers. For what values of xx does the composition f(g(x))=5f(g(x)) = 5?

  1. x=1x = -1 and x=4x = 4Answer
  2. B
    x=4x = 4 only
  3. C
    x=2x = 2 and x=6x = 6
  4. D
    x=2x = -2 and x=2x = 2
  5. E
    x=4x = -4 and x=4x = 4

Answer

x=1x = -1 and x=4x = 4
To find the values of xx for which f(g(x))=5f(g(x)) = 5, we substitute the expression for g(x)g(x) into f(x)f(x), yielding (2x+1)4=5|(2x + 1) - 4| = 5, which simplifies to 2x3=5|2x - 3| = 5. Setting up the two possible cases for the absolute value gives 2x3=52x - 3 = 5 (which solves to x=4x = 4) and 2x3=52x - 3 = -5 (which solves to x=1x = -1). Both values of xx satisfy the original composition equation.

Step-by-Step Solution

1
Substitute the inner function g(x)=2x+1g(x) = 2x + 1 into the outer function f(x)=x4f(x) = |x - 4| to find the composite function f(g(x))f(g(x)).
f(g(x))=(2x+1)4=2x3f(g(x)) = |(2x + 1) - 4| = |2x - 3|
Function composition requires evaluating the outer function at the output of the inner function.
2
Set the composite expression equal to 55.
2x3=5|2x - 3| = 5
We are solving for the values of xx where the output of the composite function is 55.
3
Split the absolute value equation into its positive and negative cases and solve each linear equation for xx.
Case 1: 2x3=5    2x=8    x=42x - 3 = 5 \implies 2x = 8 \implies x = 4. Case 2: 2x3=5    2x=2    x=12x - 3 = -5 \implies 2x = -2 \implies x = -1.
An absolute value equation u=c|u| = c (with c>0c > 0) is equivalent to u=cu = c or u=cu = -c.

Key Concept

Evaluating a composite function with an absolute value and solving the resulting equations by considering both positive and negative cases.
Estimated Time:1m 30s
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