Function Evaluation, Composition, and Properties

38 questions

Question 1Question

Let the functions ff and gg be defined by f(x)=2x5f(x) = |2x - 5| and g(x)=x+7g(x) = \sqrt{x + 7} for all real numbers in their respective domains. If aa is a real number such that (fg)(a)=3(f \circ g)(a) = 3, what is the sum of all possible values of aa?

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Answer: 3

Answer

The sum of all possible values of aa is 33.
The correct answer is 33. The composition (fg)(a)=3(f \circ g)(a) = 3 translates to f(g(a))=2a+75=3f(g(a)) = |2\sqrt{a + 7} - 5| = 3. This absolute value relation splits into two equations: 2a+75=32\sqrt{a + 7} - 5 = 3 and 2a+75=32\sqrt{a + 7} - 5 = -3. Solving the first equation yields a+7=4a=9\sqrt{a + 7} = 4 \Rightarrow a = 9. Solving the second equation yields a+7=1a=6\sqrt{a + 7} = 1 \Rightarrow a = -6. Since both 99 and 6-6 are greater than or equal to 7-7, they are within the domain of the radical function. The sum of these values is 9+(6)=39 + (-6) = 3.

Step-by-Step Solution

1
Express the composition (fg)(a)(f \circ g)(a) in terms of aa.
2a+75=3|2\sqrt{a + 7} - 5| = 3
By definition of function composition, (fg)(a)=f(g(a))(f \circ g)(a) = f(g(a)). Substituting g(a)=a+7g(a) = \sqrt{a + 7} into the expression for f(x)f(x) yields f(g(a))=2g(a)5=2a+75f(g(a)) = |2g(a) - 5| = |2\sqrt{a + 7} - 5|.
2
Set up the two algebraic cases to eliminate the absolute value.
2a+75=32\sqrt{a + 7} - 5 = 3 or 2a+75=32\sqrt{a + 7} - 5 = -3
An absolute value equation of the form u=c|u| = c (where c0c \geq 0) has two possible cases: u=cu = c or u=cu = -c.
3
Solve the first equation case for aa.
a=9a = 9
Adding 55 to both sides of 2a+75=32\sqrt{a + 7} - 5 = 3 gives 2a+7=82\sqrt{a + 7} = 8. Dividing by 22 gives a+7=4\sqrt{a + 7} = 4. Squaring both sides yields a+7=16a + 7 = 16, which gives a=9a = 9.
4
Solve the second equation case for aa.
a=6a = -6
Adding 55 to both sides of 2a+75=32\sqrt{a + 7} - 5 = -3 gives 2a+7=22\sqrt{a + 7} = 2. Dividing by 22 gives a+7=1\sqrt{a + 7} = 1. Squaring both sides yields a+7=1a + 7 = 1, which gives a=6a = -6.
5
Verify domain constraints and sum the valid solutions.
33
Both a=9a = 9 and a=6a = -6 satisfy the domain requirement for g(x)=x+7g(x) = \sqrt{x+7}, which is x7x \geq -7. The sum of these two valid values is 9+(6)=39 + (-6) = 3.

Key Concept

Evaluating and solving equations containing composite functions, absolute values, and radical functions.

Alternative Method

Instead of expanding the composition immediately, substitute a temporary variable u=g(a)=a+7u = g(a) = \sqrt{a+7}. The equation becomes f(u)=32u5=3f(u) = 3 \Rightarrow |2u - 5| = 3. Solve this simplified absolute value equation to get 2u5=3u=42u - 5 = 3 \Rightarrow u = 4, and 2u5=3u=12u - 5 = -3 \Rightarrow u = 1. Next, substitute back a+7\sqrt{a+7} for uu: solving a+7=4\sqrt{a+7} = 4 yields a=9a = 9, and solving a+7=1\sqrt{a+7} = 1 yields a=6a = -6. Summing these two solutions gives 9+(6)=39 + (-6) = 3.
Estimated Time:2m 0s
Question 2Question

Let the functions ff and gg be defined for all real numbers by f(x)=2x3f(x) = 2x - 3 and g(x)=x+5g(x) = x + 5. What is the value of f(g(4))f(g(4))?

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Answer: 15

Answer

The value of f(g(4))f(g(4)) is 1515.
To evaluate the composite function f(g(4))f(g(4)), the inner function must be evaluated first. Substituting 44 into g(x)=x+5g(x) = x + 5 gives g(4)=9g(4) = 9. Next, substitute this output of 99 into the outer function f(x)=2x3f(x) = 2x - 3, which gives f(9)=2(9)3=15f(9) = 2(9) - 3 = 15.

Step-by-Step Solution

1
Evaluate the inner function g(4)g(4)
g(4)=9g(4) = 9
Substitute 44 for xx in the definition of g(x)=x+5g(x) = x + 5.
2
Evaluate the outer function f(x)f(x) at the output of the inner function
f(9)=15f(9) = 15
Substitute 99 (the value of g(4)g(4)) for xx in the definition of f(x)=2x3f(x) = 2x - 3.

Key Concept

Function Composition and Evaluation
Estimated Time:45s
Question 3Question

The table below gives values for the functions ff and gg at selected values of xx:

xxf(x)f(x)g(x)g(x)
135
254
321
412
543

Based on the table, what is the value of f(g(3))f(g(3))?

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Answer: 3

Answer

3
To evaluate the composite function f(g(3))f(g(3)), we first evaluate the inner function, g(3)g(3). Looking at the table, when x=3x = 3, g(3)=1g(3) = 1. We then substitute this output into the outer function to evaluate f(1)f(1). According to the table, when x=1x = 1, f(1)=3f(1) = 3. Therefore, the value of the composite function is 3.

Step-by-Step Solution

1
Locate the input value of 3 in the table to evaluate the inner function g(3)g(3).
g(3)=1g(3) = 1
We must evaluate the inner function first in the composition f(g(x))f(g(x)).
2
Substitute the result of g(3)g(3) into the outer function, giving f(1)f(1), and find its value in the table.
f(1)=3f(1) = 3
Evaluating f(x)f(x) at x=1x = 1 completes the composition f(g(3))f(g(3)).

Key Concept

Evaluating a composite function from a table of values by finding the output of the inner function and using it as the input for the outer function.
Estimated Time:45s
Question 4Question

For the functions f(x)=(x3)24f(x) = (x - 3)^2 - 4 and g(x)=x+1g(x) = |x + 1|, what is the sum of all real values of xx for which f(g(x))=5f(g(x)) = 5?

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Answer: 3-3

Answer

The sum of all real values of xx for which f(g(x))=5f(g(x)) = 5 is 3-3.
To find the sum of all real values of xx for which f(g(x))=5f(g(x)) = 5, we set up the composite function: (g(x)3)24=5(g(x) - 3)^2 - 4 = 5. Adding 44 to both sides gives (g(x)3)2=9(g(x) - 3)^2 = 9. Taking the square root yields two possible cases: g(x)3=3g(x) - 3 = 3 (which means g(x)=6g(x) = 6) or g(x)3=3g(x) - 3 = -3 (which means g(x)=0g(x) = 0). Next, we substitute g(x)=x+1g(x) = |x + 1|. For the first case, x+1=6|x + 1| = 6 gives x+1=6    x=5x + 1 = 6 \implies x = 5 or x+1=6    x=7x + 1 = -6 \implies x = -7. For the second case, x+1=0|x + 1| = 0 gives x+1=0    x=1x + 1 = 0 \implies x = -1. Summing these three real solutions gives 5+(7)+(1)=35 + (-7) + (-1) = -3.

Step-by-Step Solution

1
Substitute g(x)g(x) into f(x)f(x) and set the expression equal to 55.
f(g(x))=(g(x)3)24=5f(g(x)) = (g(x) - 3)^2 - 4 = 5
This sets up the composition equation to be solved.
2
Isolate the squared term and solve for g(x)g(x) by taking the square root of both sides.
(g(x)3)2=9(g(x) - 3)^2 = 9, which gives two cases: g(x)3=3    g(x)=6g(x) - 3 = 3 \implies g(x) = 6 or g(x)3=3    g(x)=0g(x) - 3 = -3 \implies g(x) = 0
Solving a quadratic equation of the form u2=ku^2 = k yields two possibilities: u=±ku = \pm\sqrt{k}.
3
Substitute the expression for g(x)=x+1g(x) = |x + 1| into both cases and solve for xx.
For g(x)=6g(x) = 6, x+1=6    x+1=6|x + 1| = 6 \implies x + 1 = 6 or x+1=6x + 1 = -6, yielding x=5x = 5 or x=7x = -7. For g(x)=0g(x) = 0, x+1=0    x+1=0|x + 1| = 0 \implies x + 1 = 0, yielding x=1x = -1.
Absolute value equations of the form v=c|v| = c yield v=±cv = \pm c if c>0c > 0, and v=0v = 0 if c=0c = 0.
4
Calculate the sum of all the real solutions.
5+(7)+(1)=35 + (-7) + (-1) = -3
The question asks for the sum of all real values of xx that satisfy the equation.

Key Concept

Function composition involves substituting one function into another, and solving the resulting equation requires accounting for multiple cases when dealing with quadratic and absolute value expressions.
Question 5Question

If f(x)=3x2f(x) = 3x - 2 and g(x)=x2+1g(x) = x^2 + 1, what is the value of g(f(2))g(f(2))?

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Answer: 17

Answer

The value of g(f(2))g(f(2)) is 17.
To evaluate the composite function g(f(2))g(f(2)), we first find the value of the inner function f(2)=3(2)2=4f(2) = 3(2) - 2 = 4. Then, we substitute this output as the input for the outer function to get g(4)=42+1=17g(4) = 4^2 + 1 = 17.

Step-by-Step Solution

1
Substitute x=2x = 2 into the expression for f(x)f(x) to evaluate the inner function.
f(2)=4f(2) = 4
In the composition g(f(2))g(f(2)), the inner function f(x)f(x) must be evaluated first at the input value of 2.
2
Substitute the result from Step 1, which is 4, into the expression for g(x)g(x).
g(4)=17g(4) = 17
The output of the inner function becomes the input for the outer function, so g(f(2))=g(4)=42+1=17g(f(2)) = g(4) = 4^2 + 1 = 17.

Key Concept

Function Composition
Estimated Time:45s
Question 6Question

A company's daily profit is modeled by the function P(x)=3x50P(x) = 3x - 50, where xx represents the number of items sold. The number of items sold depends on the number of hours the store is open, hh, according to the function x(h)=5hx(h) = 5h. What is the daily profit, in dollars, when the store is open for 88 hours?

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Answer: 70

Answer

70
Evaluating the composite function in the correct order, P(x(8))P(x(8)), yields 7070. First, find the number of items sold when the store is open for 8 hours: x(8)=5(8)=40x(8) = 5(8) = 40. Then, calculate the daily profit by substituting this output into the profit function: P(40)=3(40)50=12050=70P(40) = 3(40) - 50 = 120 - 50 = 70.

Step-by-Step Solution

1
Determine the number of items sold, xx, when the store is open for 88 hours by evaluating the function x(h)=5hx(h) = 5h at h=8h = 8.
x(8)=5×8=40x(8) = 5 \times 8 = 40 items.
The number of items sold is the input for the profit function.
2
Substitute the number of items sold (x=40x = 40) into the profit function P(x)=3x50P(x) = 3x - 50.
P(40)=3(40)50=12050=70P(40) = 3(40) - 50 = 120 - 50 = 70 dollars.
Evaluating the profit function at the given number of items sold determines the final daily profit.

Key Concept

Evaluating a composite function by finding the output of the inner function and using it as the input for the outer function.
Estimated Time:1m 0s
Question 7Question

For the functions f(x)=x23x1f(x) = x^2 - 3x - 1 and g(x)=x1g(x) = |x - 1|, what is the product of all real values of xx for which f(g(x))=3f(g(x)) = 3?

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Answer: -15

Answer

The product of all real values of xx is 15-15.
The correct answer is 15-15. By substituting g(x)=x1g(x) = |x - 1| into f(x)=x23x1f(x) = x^2 - 3x - 1, we get x123x11=3|x - 1|^2 - 3|x - 1| - 1 = 3. Letting u=x1u = |x - 1| yields the quadratic u23u4=0u^2 - 3u - 4 = 0, which factors into (u4)(u+1)=0(u - 4)(u + 1) = 0. Since u0u \geq 0, we have u=4u = 4. Solving x1=4|x - 1| = 4 yields x=5x = 5 and x=3x = -3. The product of these solutions is 5×(3)=155 \times (-3) = -15.

Step-by-Step Solution

1
Substitute the function g(x)=x1g(x) = |x - 1| into f(x)=x23x1f(x) = x^2 - 3x - 1 to form the composite function f(g(x))f(g(x)).
f(g(x))=x123x11f(g(x)) = |x - 1|^2 - 3|x - 1| - 1
To evaluate the composite function before setting it equal to 33.
2
Set the composite function equal to 33 and substitute u=x1u = |x - 1| (where u0u \geq 0) to rewrite the equation as a quadratic in terms of uu.
u23u1=3u23u4=0u^2 - 3u - 1 = 3 \Rightarrow u^2 - 3u - 4 = 0
Using substitution simplifies the absolute value equation into a standard quadratic equation.
3
Factor the quadratic equation (u4)(u+1)=0(u - 4)(u + 1) = 0 to solve for uu, and discard the extraneous solution.
u=4u = 4 or u=1u = -1. Since u=x10u = |x - 1| \geq 0, we discard u=1u = -1, leaving u=4u = 4.
The absolute value of a real expression must be non-negative, so uu cannot be 1-1.
4
Solve the absolute value equation x1=4|x - 1| = 4 for all possible real values of xx.
x1=4x=5x - 1 = 4 \Rightarrow x = 5, and x1=4x=3x - 1 = -4 \Rightarrow x = -3.
An absolute value equation A=B|A| = B (where B>0B > 0) yields two scenarios: A=BA = B and A=BA = -B.
5
Calculate the product of the two real solutions found.
5×(3)=155 \times (-3) = -15
To find the final product of all real values of xx that satisfy the equation.

Key Concept

Function composition and solving absolute value equations using quadratic substitution
Estimated Time:2m 0s
Question 8Question

Let the function ff be defined by f(x)=x1x+1f(x) = \frac{x - 1}{x + 1} for all real numbers x1x \neq -1. Let f1(x)=f(x)f^1(x) = f(x), and let fn(x)=f(fn1(x))f^n(x) = f(f^{n-1}(x)) for all integers n2n \geq 2. What is the value of 30f2026(3)30 \cdot f^{2026}(3)?

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Answer: -10

Answer

The value of the expression is -10.
Evaluating successive iterations of f(3)f(3) reveals a repeating sequence: f1(3)=1/2f^1(3) = 1/2, f2(3)=1/3f^2(3) = -1/3, f3(3)=2f^3(3) = -2, f4(3)=3f^4(3) = 3, and then f5(3)=1/2f^5(3) = 1/2. This indicates a cycle of period 4. Dividing the power 2026 by the period 4 gives a remainder of 2, meaning f2026(3)f^{2026}(3) is equal to f2(3)=1/3f^2(3) = -1/3. Multiplying this by 30 yields the final answer of -10.

Step-by-Step Solution

1
Calculate the first few compositions of the function evaluated at the given input x=3x = 3.
f1(3)=1/2f^1(3) = 1/2, f2(3)=1/3f^2(3) = -1/3, f3(3)=2f^3(3) = -2, and f4(3)=3f^4(3) = 3.
To look for a repeating pattern or periodic behavior in the iterated function composition.
2
Identify the period of the repeating cycle.
The cycle has a length of 4, repeating the values [1/2,1/3,2,3][1/2, -1/3, -2, 3].
Since f4(3)=3f^4(3) = 3, evaluating further iterations will yield the same sequence of values.
3
Use modular arithmetic to find the value of the 2026th composition.
20262(mod4)2026 \equiv 2 \pmod 4, meaning f2026(3)=f2(3)=1/3f^{2026}(3) = f^2(3) = -1/3.
Since the cycle repeats every 4 iterations, dividing 2026 by 4 yields a remainder of 2, indicating the second value in the sequence.
4
Multiply the computed composition value by the given coefficient.
30(1/3)=1030 \cdot (-1/3) = -10.
To find the final value of the expression 30f2026(3)30 \cdot f^{2026}(3).

Key Concept

Evaluating repeated function compositions using periodicity and modular arithmetic.
Question 9Question

A weather balloon's altitude in meters after tt minutes is given by the function A(t)=100+50tA(t) = 100 + 50t. The air temperature in degrees Celsius at an altitude of aa meters is modeled by the function T(a)=250.02aT(a) = 25 - 0.02a. What is the temperature of the air surrounding the balloon, in degrees Celsius, after 22 minutes?

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Answer: 21

Answer

The temperature of the air surrounding the balloon after 2 minutes is 21 degrees Celsius.
The temperature of the air surrounding the balloon after 2 minutes is found by first calculating the balloon's altitude, A(2)=100+50(2)=200A(2) = 100 + 50(2) = 200 meters, and then using this altitude to evaluate the temperature function, T(200)=250.02(200)=21T(200) = 25 - 0.02(200) = 21.

Step-by-Step Solution

1
Calculate the altitude of the weather balloon at t=2t = 2 minutes using the function A(t)A(t).
A(2)=200A(2) = 200 meters
To find the temperature surrounding the balloon, we must first determine its altitude at the given time of 2 minutes.
2
Substitute the altitude of 200 meters into the temperature function T(a)T(a).
T(200)=21T(200) = 21 degrees Celsius
The temperature function depends on the altitude, so evaluating T(200)T(200) yields the temperature at that height.

Key Concept

Evaluating composite functions in a real-world context.
Question 10Question

Let the functions ff and gg be defined by f(x)=25x2f(x) = \sqrt{25 - x^2} and g(x)=1x29g(x) = \frac{1}{\sqrt{x^2 - 9}} for all real numbers xx where the expressions are defined. What is the number of integers in the domain of the composite function h(x)=g(f(x))h(x) = g(f(x))?

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Answer: 7

Answer

The number of integers in the domain of the composite function h(x)=g(f(x))h(x) = g(f(x)) is 7.
The composite function h(x)=g(f(x))h(x) = g(f(x)) is defined when xx is in the domain of ff and f(x)f(x) is in the domain of gg. The domain of f(x)=25x2f(x) = \sqrt{25 - x^2} is [5,5][-5, 5]. The domain of g(u)=1u29g(u) = \frac{1}{\sqrt{u^2 - 9}} is u>3u > 3 or u<3u < -3. Substituting f(x)f(x) for uu gives 25x2>3\sqrt{25 - x^2} > 3, which simplifies to x2<16x^2 < 16 or 4<x<4-4 < x < 4. The intersection of [5,5][-5, 5] and (4,4)(-4, 4) is (4,4)(-4, 4). The integers in this interval are 3,2,1,0,1,2,3-3, -2, -1, 0, 1, 2, 3, which total 7 integers.

Step-by-Step Solution

1
Determine the domain of the inner function f(x)=25x2f(x) = \sqrt{25 - x^2}.
The domain is [5,5][-5, 5].
The term inside the square root must be greater than or equal to zero for the function to yield real values: 25x2025 - x^2 \ge 0.
2
Determine the domain of the outer function g(u)=1u29g(u) = \frac{1}{\sqrt{u^2 - 9}}.
The domain is (,3)(3,)(-\infty, -3) \cup (3, \infty).
The expression inside the square root in the denominator must be strictly positive: u29>0u^2 - 9 > 0.
3
Apply the domain constraint of the outer function to the outputs of the inner function.
4<x<4-4 < x < 4.
We require f(x)>3f(x) > 3 or f(x)<3f(x) < -3. Since the range of f(x)f(x) is non-negative, f(x)<3f(x) < -3 has no solutions. Thus, we solve 25x2>3\sqrt{25 - x^2} > 3, which squares to 25x2>925 - x^2 > 9, or x2<16x^2 < 16.
4
Find the intersection of the inner function's domain and the composite constraint.
The composite domain is (4,4)(-4, 4).
The input xx must satisfy both the domain of ff (5x5-5 \le x \le 5) and the composition constraint (4<x<4-4 < x < 4).
5
List and count the integers within the composite domain (4,4)(-4, 4).
There are 7 integers.
The integers strictly between 4-4 and 44 are 3,2,1,0,1,2,3-3, -2, -1, 0, 1, 2, 3.

Key Concept

Domain of a composite function
Estimated Time:2m 0s
Question 11Question

For the function h(x)=53xh(x) = 5 - 3x, what is the value of h(h(2))h(h(2))?

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Answer: 8

Answer

8
To find h(h(2))h(h(2)), we first calculate the value of the inner function, h(2)=53(2)=56=1h(2) = 5 - 3(2) = 5 - 6 = -1. We then substitute this result back into the function to evaluate the outer function: h(1)=53(1)=5+3=8h(-1) = 5 - 3(-1) = 5 + 3 = 8. Therefore, the correct value is 8.

Step-by-Step Solution

1
Evaluate the inner function h(2)h(2)
h(2)=1h(2) = -1
To evaluate a nested function composition of the form h(h(x))h(h(x)), first calculate the value of the inner function at the given input.
2
Evaluate the outer function h(1)h(-1) using the result from Step 1
h(h(2))=h(1)=8h(h(2)) = h(-1) = 8
Substitute the output of the inner function, 1-1, as the new input for the outer function h(x)h(x).

Key Concept

Evaluating the composition of a function with itself
Question 12Question

If f(x)=3x5f(x) = 3x - 5 and g(x)=(x1)2g(x) = (x - 1)^2, what is the value of f(g(4))f(g(4))?

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Answer: 22

Answer

22
To find f(g(4))f(g(4)), we evaluate the inner function first: g(4)=(41)2=32=9g(4) = (4 - 1)^2 = 3^2 = 9. We then evaluate the outer function at this result: f(9)=3(9)5=275=22f(9) = 3(9) - 5 = 27 - 5 = 22.

Step-by-Step Solution

1
Evaluate the inner function g(x)g(x) at x=4x = 4
g(4)=(41)2=32=9g(4) = (4 - 1)^2 = 3^2 = 9
In function composition f(g(x))f(g(x)), the inner function must be evaluated first.
2
Substitute the result from the first step into the outer function f(x)f(x)
f(9)=3(9)5f(9) = 3(9) - 5
The output of the inner function becomes the input of the outer function.
3
Calculate the final value of f(9)f(9) following the order of operations
f(9)=275=22f(9) = 27 - 5 = 22
Multiplication must be performed before subtraction.

Key Concept

Function Evaluation and Composition
Question 13Question

For all real numbers x5x \geq -5, the functions ff and gg are defined by f(x)=x24xf(x) = x^2 - 4x and g(x)=x+5g(x) = \sqrt{x + 5}. If f(g(k))=12f(g(k)) = 12, what is the real value of kk?

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Answer: 31

Answer

The correct answer is 31.
Substituting g(k)=k+5g(k) = \sqrt{k+5} into f(x)=x24xf(x) = x^2 - 4x gives the equation (k+5)24k+5=12(\sqrt{k+5})^2 - 4\sqrt{k+5} = 12. Simplifying and isolating the radical yields k7=4k+5k - 7 = 4\sqrt{k+5}. Squaring both sides results in (k7)2=16(k+5)(k-7)^2 = 16(k+5), which simplifies to k230k31=0k^2 - 30k - 31 = 0. Factoring this equation gives (k31)(k+1)=0(k-31)(k+1) = 0, yielding potential solutions of k=31k = 31 and k=1k = -1. Checking these solutions reveals that k=1k = -1 is extraneous because f(g(1))=412f(g(-1)) = -4 \neq 12. Therefore, the only valid real solution is k=31k = 31.

Step-by-Step Solution

1
Express the composition f(g(k))f(g(k)) using the given functions.
f(g(k))=(g(k))24(g(k))f(g(k)) = (g(k))^2 - 4(g(k))
To evaluate a composite function, substitute the inner function g(k)g(k) as the input into the outer function ff.
2
Substitute g(k)=k+5g(k) = \sqrt{k+5} and set the composite expression equal to 12.
(k+5)24k+5=12(\sqrt{k+5})^2 - 4\sqrt{k+5} = 12
This sets up the equation to solve for the unknown variable kk.
3
Isolate the radical term on one side of the equation.
k7=4k+5k - 7 = 4\sqrt{k+5}
Simplifying (k+5)2(\sqrt{k+5})^2 to k+5k+5 and moving terms helps isolate the radical before squaring.
4
Square both sides of the equation to eliminate the square root.
(k7)2=16(k+5)(k-7)^2 = 16(k+5)
Squaring is the inverse operation of the square root, which removes the radical.
5
Expand both sides and rewrite the equation in standard quadratic form.
k230k31=0k^2 - 30k - 31 = 0
Expanding (k7)2(k-7)^2 to k214k+49k^2 - 14k + 49 and 16(k+5)16(k+5) to 16k+8016k + 80, then moving all terms to one side, allows us to solve the resulting quadratic equation.
6
Factor the quadratic equation.
(k31)(k+1)=0(k-31)(k+1) = 0
Factoring allows us to find the potential roots easily.
7
Solve for the potential values of kk.
k=31k = 31 or k=1k = -1
Setting each factor to zero gives the candidate solutions.
8
Verify both potential values in the original equation to check for extraneous solutions.
k=31k = 31 is valid; k=1k = -1 is extraneous.
Squaring both sides can introduce extraneous solutions. Evaluating f(g(1))f(g(-1)) yields 4-4, not 1212, while evaluating f(g(31))f(g(31)) yields 1212.

Key Concept

Function composition involves substituting one function into another, and solving equations with radicals requires checking for extraneous solutions.
Question 14Question

The table below shows some values for the functions ff and gg.

xxf(x)f(x)g(x)g(x)
1-12233
00111-1
113-322
220011
332-200

What is the value of g(f(2))g(f(2))?

Show answer & explanation

Answer: 1-1

Answer

The correct answer is 1-1.
To find the value of g(f(2))g(f(2)), we begin with the inner function f(2)f(2). Looking at the table, when x=2x = 2, the value of f(x)f(x) is 00. This means f(2)=0f(2) = 0. We then substitute this value into the outer function, giving us g(0)g(0). Looking at the table again, when x=0x = 0, the value of g(x)g(x) is 1-1. Therefore, g(f(2))=1g(f(2)) = -1.

Step-by-Step Solution

1
Find the value of the inner function f(2)f(2) from the table.
f(2)=0f(2) = 0
For the composed function g(f(2))g(f(2)), the inner function ff must be evaluated first at the input 22.
2
Substitute this result into the outer function to evaluate g(0)g(0) using the table.
g(0)=1g(0) = -1
The output of the inner function becomes the input for the outer function gg.

Key Concept

Evaluating composite functions using a table of values
Estimated Time:45s
Question 15Question

Let the functions ff and gg be defined by f(x)=3x+4f(x) = \sqrt{3x + 4} and g(x)=x22g(x) = x^2 - 2. What is the positive value of xx for which the composite function value f(g(x))=5f(g(x)) = 5?

Show answer & explanation

Answer: 3

Answer

3
The correct answer is 3. We set f(g(x))=5f(g(x)) = 5, which translates to 3g(x)+4=5\sqrt{3g(x) + 4} = 5. Squaring both sides yields 3g(x)+4=253g(x) + 4 = 25. Solving for g(x)g(x) gives 3g(x)=213g(x) = 21, which simplifies to g(x)=7g(x) = 7. Substituting g(x)=x22g(x) = x^2 - 2 into this equation gives x22=7x^2 - 2 = 7, which simplifies to x2=9x^2 = 9. Taking the square root of both sides gives x=3x = 3 or x=3x = -3. Since the question specifies the positive value of xx, the correct answer is 3.

Step-by-Step Solution

1
Substitute the inner function g(x)g(x) into the outer function f(x)f(x) to express f(g(x))=5f(g(x)) = 5
3g(x)+4=5\sqrt{3g(x) + 4} = 5
Setting up the initial composite equation to isolate the inner function g(x)g(x)
2
Square both sides of the equation and isolate g(x)g(x)
3g(x)+4=25    3g(x)=21    g(x)=73g(x) + 4 = 25 \implies 3g(x) = 21 \implies g(x) = 7
Eliminating the radical allows us to determine the required output value of g(x)g(x)
3
Substitute the formula for g(x)g(x) into the equation and solve for xx
x22=7    x2=9    x=3x^2 - 2 = 7 \implies x^2 = 9 \implies x = 3 or x=3x = -3
Finding the input values of xx that satisfy the condition for g(x)g(x)
4
Select the positive value from the solution set
x=3x = 3
The question specifically requests the positive value of xx

Key Concept

Evaluating and solving composite function equations by working from the outside function inward

Alternative Method

Instead of solving from the outside in, we can first construct the symbolic expression for f(g(x))f(g(x)) by substituting g(x)g(x) directly: f(g(x))=3(x22)+4=3x26+4=3x22f(g(x)) = \sqrt{3(x^2 - 2) + 4} = \sqrt{3x^2 - 6 + 4} = \sqrt{3x^2 - 2}. Setting this equal to 5 yields 3x22=5\sqrt{3x^2 - 2} = 5. Squaring both sides gives 3x22=25    3x2=27    x2=9    x=±33x^2 - 2 = 25 \implies 3x^2 = 27 \implies x^2 = 9 \implies x = \pm 3. The positive solution is 3.
Estimated Time:1m 30s
Question 16Question

For the functions f(x)=x23f(x) = |x - 2| - 3 and g(x)=x22xg(x) = x^2 - 2x, what is the sum of all real values of xx for which g(f(x))=0g(f(x)) = 0?

Show answer & explanation

Answer: 8

Answer

The sum of all real values of xx is 8.
To solve g(f(x))=0g(f(x)) = 0, we substitute f(x)f(x) as the variable in g(x)g(x), obtaining (f(x))22f(x)=0(f(x))^2 - 2f(x) = 0. Factoring this equation yields f(x)(f(x)2)=0f(x)(f(x) - 2) = 0, giving two cases: f(x)=0f(x) = 0 or f(x)=2f(x) = 2. For the first case, x23=0|x - 2| - 3 = 0 simplifies to x2=3|x - 2| = 3, which has solutions x=5x = 5 and x=1x = -1. For the second case, x23=2|x - 2| - 3 = 2 simplifies to x2=5|x - 2| = 5, which has solutions x=7x = 7 and x=3x = -3. Summing these four solutions gives 5+(1)+7+(3)=85 + (-1) + 7 + (-3) = 8.

Step-by-Step Solution

1
Substitute f(x)f(x) into g(x)g(x) to set up the composite equation g(f(x))=0g(f(x)) = 0.
g(f(x))=(f(x))22f(x)=0g(f(x)) = (f(x))^2 - 2f(x) = 0
To evaluate a function composition, the output of the inner function f(x)f(x) becomes the input of the outer function g(x)g(x).
2
Factor the quadratic equation in terms of f(x)f(x).
f(x)(f(x)2)=0f(x)(f(x) - 2) = 0, which means f(x)=0f(x) = 0 or f(x)=2f(x) = 2.
Factoring allows us to split the quadratic equation into two separate linear cases.
3
Substitute f(x)=x23f(x) = |x - 2| - 3 into the first case, f(x)=0f(x) = 0, and solve for xx.
x23=0x2=3x2=3|x - 2| - 3 = 0 \Rightarrow |x - 2| = 3 \Rightarrow x - 2 = 3 or x2=3x - 2 = -3, yielding x=5x = 5 and x=1x = -1.
An absolute value equation u=c|u| = c has two cases: u=cu = c and u=cu = -c when c0c \geq 0.
4
Substitute f(x)=x23f(x) = |x - 2| - 3 into the second case, f(x)=2f(x) = 2, and solve for xx.
x23=2x2=5x2=5|x - 2| - 3 = 2 \Rightarrow |x - 2| = 5 \Rightarrow x - 2 = 5 or x2=5x - 2 = -5, yielding x=7x = 7 and x=3x = -3.
We must solve the second case using both positive and negative scenarios for the absolute value.
5
Calculate the sum of all four real solutions.
5+(1)+7+(3)=85 + (-1) + 7 + (-3) = 8
The question asks for the sum of all real values of xx that satisfy the composite equation.

Key Concept

Function Composition and Absolute Value Equations

Alternative Method

Instead of expanding the algebraic expressions, substitute a temporary variable u=f(x)u = f(x) into g(u)=0g(u) = 0 to get u22u=0u^2 - 2u = 0, which easily factors to u=0u = 0 or u=2u = 2. Then, substitute f(x)f(x) back to solve x23=0|x - 2| - 3 = 0 and x23=2|x - 2| - 3 = 2.
Estimated Time:1m 30s
Question 17Question

Let the functions ff and gg be defined for all real numbers by f(x)=x26x+7f(x) = x^2 - 6x + 7 and g(x)=2x5g(x) = |2x - 5|. What is the sum of all real values of xx for which f(g(x))=14f(g(x)) = 14?

Show answer & explanation

Answer: 5

Answer

The sum of all possible real values of xx is 55.
The correct answer is 55. Setting f(g(x))=14f(g(x)) = 14 yields (g(x))26g(x)+7=14(g(x))^2 - 6g(x) + 7 = 14, which simplifies to (g(x))26g(x)7=0(g(x))^2 - 6g(x) - 7 = 0. Factoring this quadratic gives g(x)=7g(x) = 7 or g(x)=1g(x) = -1. Because g(x)=2x5g(x) = |2x - 5| cannot be negative, we discard the negative case. Solving 2x5=7|2x - 5| = 7 gives 2x5=7x=62x - 5 = 7 \Rightarrow x = 6 and 2x5=7x=12x - 5 = -7 \Rightarrow x = -1. The sum of these values is 6+(1)=56 + (-1) = 5.

Step-by-Step Solution

1
Set up the composite equation f(g(x))=14f(g(x)) = 14 by substituting g(x)g(x) into f(x)f(x).
(g(x))26g(x)+7=14(g(x))^2 - 6g(x) + 7 = 14
This defines the relation between g(x)g(x) and the target output value.
2
Rearrange the equation into a standard quadratic form and solve for g(x)g(x).
(g(x))26g(x)7=0(g(x)7)(g(x)+1)=0(g(x))^2 - 6g(x) - 7 = 0 \Rightarrow (g(x) - 7)(g(x) + 1) = 0, so g(x)=7g(x) = 7 or g(x)=1g(x) = -1.
Factoring the quadratic equation gives the possible values for the inner function g(x)g(x).
3
Apply the definition of g(x)g(x) to solve for xx and discard invalid cases.
Since g(x)=2x5g(x) = |2x - 5| must be non-negative, the case g(x)=1g(x) = -1 has no real solutions. For the case g(x)=7g(x) = 7, we have 2x5=7|2x - 5| = 7.
The range of an absolute value function is [0,)[0, \infty), making negative outputs impossible.
4
Solve the absolute value equation 2x5=7|2x - 5| = 7 by setting up both positive and negative cases.
Either 2x5=72x=12x=62x - 5 = 7 \Rightarrow 2x = 12 \Rightarrow x = 6, or 2x5=72x=2x=12x - 5 = -7 \Rightarrow 2x = -2 \Rightarrow x = -1.
An absolute value equation u=c|u| = c splits into u=cu = c and u=cu = -c.
5
Sum the valid solutions for xx.
6+(1)=56 + (-1) = 5
The question asks for the sum of all real values of xx that satisfy the equation.

Key Concept

Solving equations involving composite functions and absolute values
Estimated Time:2m 0s
Question 18Question

For the functions f(x)=18x2f(x) = \frac{18}{x - 2} and g(x)=x21g(x) = x^2 - 1, what is the value of f(g(3))f(g(3))?

Show answer & explanation

Answer: 3

Answer

The value of the composite function f(g(3))f(g(3)) is 3.
To evaluate the composite function f(g(3))f(g(3)), we start by evaluating the inner function g(3)=321=8g(3) = 3^2 - 1 = 8. We then substitute this result into the outer function, giving f(8)=1882=186=3f(8) = \frac{18}{8 - 2} = \frac{18}{6} = 3.

Step-by-Step Solution

1
Evaluate the inner function g(3)g(3)
8
For any composite function of the form f(g(x))f(g(x)), the inner function g(x)g(x) must be evaluated first at the given input value.
2
Evaluate the outer function f(8)f(8)
3
Substitute the output value of the inner function as the input for the outer function f(x)f(x).

Key Concept

Function Composition and Evaluation
Estimated Time:1m 0s
Question 19Question

The functions ff and gg are defined for all real numbers by f(x)=2x5f(x) = 2x - 5 and g(x)=(x+3)2g(x) = (x + 3)^2. What is the value of f(g(1))f(g(-1))?

Show answer & explanation

Answer: 3

Answer

3
To evaluate the composite function f(g(1))f(g(-1)), first evaluate the inner function g(1)=(1+3)2=4g(-1) = (-1 + 3)^2 = 4. Then, substitute this result into the outer function to get f(4)=2(4)5=3f(4) = 2(4) - 5 = 3.

Step-by-Step Solution

1
Evaluate the inner function g(x)g(x) at x=1x = -1.
g(1)=4g(-1) = 4
In the composition f(g(1))f(g(-1)), the inner function must be evaluated first. Substituting 1-1 into g(x)=(x+3)2g(x) = (x + 3)^2 gives g(1)=(1+3)2=22=4g(-1) = (-1 + 3)^2 = 2^2 = 4.
2
Evaluate the outer function f(x)f(x) at the output of the inner function.
f(4)=3f(4) = 3
Substitute the output g(1)=4g(-1) = 4 into f(x)=2x5f(x) = 2x - 5, which yields f(4)=2(4)5=85=3f(4) = 2(4) - 5 = 8 - 5 = 3.

Key Concept

Function Composition and Evaluation
Estimated Time:1m 0s
Question 20Question

Consider the function ff defined on the domain [23,)[\frac{2}{3}, \infty) by the equation f(x)=2+3x2f(x) = 2 + \sqrt{3x - 2}. If f1f^{-1} represents the inverse of ff, what is the only real value of xx for which f(x)=f1(x)f(x) = f^{-1}(x)?

Show answer & explanation

Answer: 6

Answer

The only real value of xx for which f(x)=f1(x)f(x) = f^{-1}(x) is 6.
For a strictly increasing function, the intersection of f(x)f(x) and f1(x)f^{-1}(x) must occur on the line y=xy = x. Equating f(x)=xf(x) = x gives 2+3x2=x2 + \sqrt{3x - 2} = x. Isolating the radical term yields 3x2=x2\sqrt{3x - 2} = x - 2. Squaring both sides produces 3x2=x24x+43x - 2 = x^2 - 4x + 4, which simplifies to the quadratic equation x27x+6=0x^2 - 7x + 6 = 0. Factoring this equation gives (x6)(x1)=0(x - 6)(x - 1) = 0, yielding the solutions x=6x = 6 and x=1x = 1. Substituting these back into the original equation shows that x=6x = 6 is a valid solution (2+16=62 + \sqrt{16} = 6), whereas x=1x = 1 is extraneous because it results in 2+1=312 + 1 = 3 \neq 1. Furthermore, the domain of f1f^{-1} is the range of ff, which is [2,)[2, \infty), meaning f1(1)f^{-1}(1) is undefined. Thus, the only real solution is 6.

Step-by-Step Solution

1
Equate the function to xx using properties of increasing functions and their inverses.
Since f(x)f(x) is strictly increasing on its domain [23,)[\frac{2}{3}, \infty), the graph of f(x)f(x) and the graph of its inverse f1(x)f^{-1}(x) can only intersect on the line of symmetry y=xy = x. Therefore, the equation f(x)=f1(x)f(x) = f^{-1}(x) is equivalent to f(x)=xf(x) = x.
This simplifies the relation by eliminating the need to solve a high-degree polynomial equation derived from direct composition or substitution.
2
Set up the equation f(x)=xf(x) = x and isolate the radical term.
2+3x2=x    3x2=x22 + \sqrt{3x - 2} = x \implies \sqrt{3x - 2} = x - 2
Isolating the square root term is a necessary prerequisite step before squaring both sides.
3
Square both sides and rewrite the equation as a standard quadratic equation.
3x2=(x2)2    3x2=x24x+4    x27x+6=03x - 2 = (x - 2)^2 \implies 3x - 2 = x^2 - 4x + 4 \implies x^2 - 7x + 6 = 0
Squaring eliminates the radical to yield a standard quadratic equation that can be solved analytically.
4
Solve the quadratic equation by factoring.
(x6)(x1)=0    x=6 or x=1(x - 6)(x - 1) = 0 \implies x = 6 \text{ or } x = 1
Factoring the quadratic trinomial yields the two candidate values for xx.
5
Check the candidate solutions in the original equation to eliminate extraneous roots.
For x=1x = 1: 2+3(1)2=312 + \sqrt{3(1)-2} = 3 \neq 1 (extraneous). For x=6x = 6: 2+3(6)2=2+4=62 + \sqrt{3(6)-2} = 2 + 4 = 6 (valid). Also, the domain of f1f^{-1} is the range of ff, which is [2,)[2, \infty), thus excluding x=1x = 1.
Squaring both sides can introduce extraneous roots. We must verify that the solutions satisfy the original radical equation and fall within the domains of both ff and f1f^{-1}.

Key Concept

Applying the symmetry of inverse functions about the line y=xy=x to solve composition-based equations, while rigorously accounting for domain restrictions and extraneous roots.

Alternative Method

Find the algebraic formula for f1(x)f^{-1}(x) by setting y=2+3x2y = 2 + \sqrt{3x-2}. Subtracting 2 and squaring both sides gives (y2)2=3x2(y - 2)^2 = 3x - 2 for y2y \geq 2. Solving for xx yields f1(x)=(x2)2+23f^{-1}(x) = \frac{(x - 2)^2 + 2}{3} for x2x \geq 2. Equating f(x)=f1(x)f(x) = f^{-1}(x) results in 2+3x2=(x2)2+232 + \sqrt{3x - 2} = \frac{(x - 2)^2 + 2}{3}. Multiplying by 3 and isolating the radical term gives 33x2=x24x3\sqrt{3x - 2} = x^2 - 4x. Squaring both sides results in a fourth-degree polynomial equation: 9(3x2)=(x24x)2    x48x3+16x227x+18=09(3x - 2) = (x^2 - 4x)^2 \implies x^4 - 8x^3 + 16x^2 - 27x + 18 = 0. This factors into (x6)(x1)(x2x+3)=0(x - 6)(x - 1)(x^2 - x + 3) = 0. Since the domain of f1(x)f^{-1}(x) is restricted to x2x \geq 2, the root x=1x = 1 is rejected, and the quadratic factor x2x+3=0x^2 - x + 3 = 0 has no real roots, leaving x=6x = 6 as the unique real solution.
Estimated Time:3m 0s
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