Question

Difficulty: MediumGraphs of Trigonometric Functions

In the standard (x,y)(x,y) coordinate plane, what is the distance along the xx-axis between any two consecutive maximum points on the graph of the function f(x)=5cos(3xπ2)+4f(x) = 5 \cos\left(3x - \frac{\pi}{2}\right) + 4?

  1. A
    π3\frac{\pi}{3}
  2. B
    π2\frac{\pi}{2}
  3. 2π3\frac{2\pi}{3}Answer
  4. D
    2π2\pi
  5. E
    6π6\pi

Answer

The distance between any two consecutive maximum points is 2π3\frac{2\pi}{3}.
The distance along the xx-axis between consecutive peaks of a cosine wave represents one full period. For the function f(x)=5cos(3xπ2)+4f(x) = 5 \cos\left(3x - \frac{\pi}{2}\right) + 4, the coefficient of xx is 3. The period formula for cosine is 2πB\frac{2\pi}{|B|}, which evaluates to 2π3\frac{2\pi}{3}.

Step-by-Step Solution

1
Relate consecutive maximum points to the function's period
The distance along the xx-axis between consecutive maximum points of a periodic trigonometric function equals one period length, TT.
Cosine graphs repeat their peak values once per complete wave cycle.
2
Identify the coefficient BB of the variable xx
In f(x)=5cos(3xπ2)+4f(x) = 5 \cos\left(3x - \frac{\pi}{2}\right) + 4, the coefficient of xx is B=3B = 3.
The standard transformation model is y=Acos(BxC)+Dy = A \cos(Bx - C) + D.
3
Calculate the period using T=2πBT = \frac{2\pi}{|B|}
T=2π3T = \frac{2\pi}{3}.
Dividing the base cosine period of 2π2\pi by B=3|B| = 3 gives the period of the transformed function.

Key Concept

The period of a transformed cosine function y=Acos(BxC)+Dy = A \cos(Bx - C) + D is 2πB\frac{2\pi}{|B|}, which measures the horizontal distance between consecutive peak values.
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