Question

Difficulty: Very hardSimplifying Expressions and Combining Like Terms

When the expression 2x(x23xy+2y2)(x2y)3y(x25xy+4y2)2x(x^2 - 3xy + 2y^2) - (x - 2y)^3 - y(x^2 - 5xy + 4y^2) is fully simplified by combining like terms, what is the coefficient of the xy2xy^2 term?

Answer: -3

Answer

The coefficient of the xy2xy^2 term is 3-3.
Expanding the terms of the expression yields 2x36x2y+4xy22x^3 - 6x^2y + 4xy^2, x3+6x2y12xy2+8y3-x^3 + 6x^2y - 12xy^2 + 8y^3, and x2y+5xy24y3-x^2y + 5xy^2 - 4y^3. Summing the coefficients of the xy2xy^2 terms gives 412+5=34 - 12 + 5 = -3. Thus, the coefficient of xy2xy^2 is 3-3.

Step-by-Step Solution

1
Expand the first term of the expression: 2x(x23xy+2y2)2x(x^2 - 3xy + 2y^2)
2x36x2y+4xy22x^3 - 6x^2y + 4xy^2
Distribute the monomial 2x2x to each term inside the parentheses: 2xx2=2x32x \cdot x^2 = 2x^3, 2x(3xy)=6x2y2x \cdot (-3xy) = -6x^2y, and 2x2y2=4xy22x \cdot 2y^2 = 4xy^2.
2
Expand the cubed binomial (x2y)3(x - 2y)^3 and distribute the negative sign
x3+6x2y12xy2+8y3-x^3 + 6x^2y - 12xy^2 + 8y^3
First, expand the binomial (x2y)3=x33(x2)(2y)+3(x)(2y)2(2y)3=x36x2y+12xy28y3(x - 2y)^3 = x^3 - 3(x^2)(2y) + 3(x)(2y)^2 - (2y)^3 = x^3 - 6x^2y + 12xy^2 - 8y^3. Then, distribute the negative sign to all terms inside the parentheses.
3
Expand the third term: y(x25xy+4y2)-y(x^2 - 5xy + 4y^2)
x2y+5xy24y3-x^2y + 5xy^2 - 4y^3
Distribute the negative monomial y-y to each term inside the parentheses: yx2=x2y-y \cdot x^2 = -x^2y, y(5xy)=5xy2-y \cdot (-5xy) = 5xy^2, and y4y2=4y3-y \cdot 4y^2 = -4y^3.
4
Group and combine all like terms
x3x2y3xy2+4y3x^3 - x^2y - 3xy^2 + 4y^3
Combine the coefficients of the corresponding terms: (2x3x3)+(6x2y+6x2yx2y)+(4xy212xy2+5xy2)+(8y34y3)=x3x2y3xy2+4y3(2x^3 - x^3) + (-6x^2y + 6x^2y - x^2y) + (4xy^2 - 12xy^2 + 5xy^2) + (8y^3 - 4y^3) = x^3 - x^2y - 3xy^2 + 4y^3.

Key Concept

Simplifying Expressions and Combining Like Terms
Estimated Time:3m 0s
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