Question

Difficulty: EasyArithmetic and Geometric Sequences and Series

For a certain geometric sequence, the first term is 232^3 and the common ratio is 222^2. Which of the following expressions represents the 3rd term of this sequence?

  1. A
    252^5
  2. B
    292^9
  3. 272^7Answer
  4. D
    2102^{10}
  5. E
    2122^{12}

Answer

The 3rd term of the sequence is 272^7.
The correct answer is 272^7. The nn-th term of a geometric sequence is given by an=a1rn1a_n = a_1 \cdot r^{n-1}. For a first term a1=23a_1 = 2^3 and a common ratio r=22r = 2^2, the 3rd term is a3=23(22)31=2324a_3 = 2^3 \cdot (2^2)^{3-1} = 2^3 \cdot 2^4. Applying the exponent addition rule for multiplying bases of the same value yields 23+4=272^{3+4} = 2^7.

Step-by-Step Solution

1
Identify the formula for the nn-th term of a geometric sequence.
an=a1rn1a_n = a_1 \cdot r^{n-1}
To find any specific term in a geometric sequence, the general term formula is used.
2
Substitute the given values (a1=23a_1 = 2^3, r=22r = 2^2, and n=3n = 3) into the formula.
a3=23(22)31=23(22)2a_3 = 2^3 \cdot (2^2)^{3-1} = 2^3 \cdot (2^2)^2
This sets up the calculation for the 3rd term of the sequence.
3
Simplify the expression using exponent rules: first compute (22)2(2^2)^2, then multiply by 232^3.
a3=2324=23+4=27a_3 = 2^3 \cdot 2^4 = 2^{3+4} = 2^7
Power of a power rule states (xa)b=xab(x^a)^b = x^{ab}, and product of powers rule states xaxb=xa+bx^a \cdot x^b = x^{a+b}.

Key Concept

Finding a specific term of a geometric sequence using the general term formula an=a1rn1a_n = a_1 \cdot r^{n-1} and applying laws of exponents.
Estimated Time:45s
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