Question

Difficulty: HardArithmetic and Geometric Sequences and Series

The first three terms of a geometric sequence of positive numbers are xx, yy, and zz, in that order. An arithmetic sequence has first three terms xx, yy, and z4z - 4, in that order. If x=4x = 4, what is the value of yy?

  1. A
    2
  2. B
    4
  3. C
    6
  4. 8Answer
  5. E
    16

Answer

8
The correct answer is 8. By defining the geometric sequence terms as 4,y,z4, y, z, we have the property y2=4zy^2 = 4z. For the arithmetic sequence 4,y,z44, y, z-4, the common difference property gives y4=z4yy - 4 = z - 4 - y, which simplifies to 2y=z2y = z. Substituting z=2yz = 2y into the first equation yields y2=8yy^2 = 8y. Since all terms must be positive, dividing by yy gives y=8y = 8.

Step-by-Step Solution

1
Set up the equation for the geometric sequence.
y2=4zy^2 = 4z
Since 4,y,z4, y, z is a geometric sequence, the ratio of consecutive terms must be equal: y4=zy\frac{y}{4} = \frac{z}{y}, which simplifies to y2=4zy^2 = 4z.
2
Set up the equation for the arithmetic sequence.
2y=z2y = z
Since 4,y,z44, y, z - 4 is an arithmetic sequence, the difference between consecutive terms must be equal: y4=(z4)yy - 4 = (z - 4) - y. Simplifying this gives 2y=z2y = z.
3
Substitute the arithmetic equation into the geometric equation.
y2=8yy^2 = 8y
Substituting z=2yz = 2y into y2=4zy^2 = 4z yields y2=4(2y)=8yy^2 = 4(2y) = 8y.
4
Solve for the variable yy.
y=8y = 8
Rearranging the equation gives y28y=0y^2 - 8y = 0, which factors as y(y8)=0y(y - 8) = 0. Since the sequence consists of positive numbers, yy must be positive, so y=8y = 8.

Key Concept

Relating arithmetic and geometric sequence properties to solve a system of non-linear equations
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