Question

Difficulty: HardDetermining Control Groups and Baseline Conditions

### Passage

To study the biodegradation of a synthetic polymer, polyethylene terephthalate (PET), by a newly isolated bacterium (*Thermobacillus petrolei*), researchers conducted two experiments.

In Experiment 1, five test tubes were prepared with 10 mL10\text{ mL} of a liquid nutrient medium, 50 mg50\text{ mg} of PET film, and 1.0 mL1.0\text{ mL} of an active *T. petrolei* suspension. The pH and temperature were kept constant. A different concentration of a synthetic surfactant, Surfactant X, was added to Tubes 1–4. Tube 5 did not receive Surfactant X. After 7 days, the remaining mass of PET was measured to evaluate degradation.

In Experiment 2, to determine whether the PET degradation observed in Experiment 1 was due to active bacterial metabolic activity rather than non-biological chemical hydrolysis or passive physical absorption onto the bacterial biomass, the researchers prepared four additional test tubes (Tubes 6–9) under the same environmental conditions as Experiment 1, but modified the tube contents as shown below:

TubeLiquid Nutrient MediumPET Film*T. petrolei* SuspensionSurfactant X
6YesYesNo (sterile water added instead)None
7YesNoYes (active cells)None
8No (sterile water added instead)YesYes (active cells)None
9YesYesYes (heat-killed cells instead)None

To demonstrate that the degradation of PET film in Experiment 1 was specifically caused by the active metabolism of living *T. petrolei* cells rather than passive physical absorption of the polymer by the bacterial biomass, which of the following tubes from Experiment 2 serves as the most appropriate control when compared to Tube 5?

  1. A
    Tube 6, because it contains no *T. petrolei* cells, allowing researchers to measure the rate of non-biological chemical hydrolysis of PET.
  2. B
    Tube 7, because it contains no PET film, allowing researchers to measure the baseline cell density of *T. petrolei* in the liquid medium.
  3. C
    Tube 8, because it contains no liquid nutrient medium, allowing researchers to determine if the bacteria can degrade PET in the absence of other nutrients.
  4. Tube 9, because it contains heat-killed *T. petrolei* cells, allowing researchers to isolate the effect of active bacterial metabolism from passive polymer absorption by the bacterial biomass.Answer

Answer

The option designating Tube 9, because it contains heat-killed cells which control for passive physical absorption by the bacterial biomass.
To demonstrate that polymer degradation is caused by active bacterial metabolism rather than passive physical adsorption or binding of the polymer to the cell walls, researchers must test a control group containing dead (heat-killed) cells. Comparing Tube 5 (with active cells) to Tube 9 (with heat-killed cells) allows researchers to subtract the passive binding component, thereby isolating the contribution of active metabolism.

Step-by-Step Solution

1
Analyze the components of the experimental baseline group (Tube 5).
Tube 5 contains liquid nutrient medium, PET film, and active *T. petrolei* cells without Surfactant X.
This establishes the biological reference condition to evaluate PET degradation without the chemical agent (Surfactant X).
2
Determine the confounding factor that needs to be isolated.
Passive physical absorption (binding of the PET polymer to the cell structure) must be separated from active biological metabolism.
Both active cells and dead cells can physically bind substances, but only active cells perform metabolic degradation.
3
Select the tube from Experiment 2 that isolates this factor.
Tube 9, which contains inactive (heat-killed) cells, keeping the biomass quantity the same while stopping metabolism.
Comparing Tube 5 (active cells) to Tube 9 (inactive cells) reveals the portion of PET loss caused specifically by metabolic processes.

Key Concept

Identifying control groups to isolate specific biological mechanisms from physical artifacts (metabolic activity vs. physical absorption).
Estimated Time:1m 30s
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