Question

Difficulty: EasyFunction Evaluation, Composition, and Properties

For the function h(x)=5−3xh(x) = 5 - 3x, what is the value of h(h(2))h(h(2))?

Answer: 8

Answer

8
To find h(h(2))h(h(2)), we first calculate the value of the inner function, h(2)=5−3(2)=5−6=−1h(2) = 5 - 3(2) = 5 - 6 = -1. We then substitute this result back into the function to evaluate the outer function: h(−1)=5−3(−1)=5+3=8h(-1) = 5 - 3(-1) = 5 + 3 = 8. Therefore, the correct value is 8.

Step-by-Step Solution

1
Evaluate the inner function h(2)h(2)
h(2)=−1h(2) = -1
To evaluate a nested function composition of the form h(h(x))h(h(x)), first calculate the value of the inner function at the given input.
2
Evaluate the outer function h(−1)h(-1) using the result from Step 1
h(h(2))=h(−1)=8h(h(2)) = h(-1) = 8
Substitute the output of the inner function, −1-1, as the new input for the outer function h(x)h(x).

Key Concept

Evaluating the composition of a function with itself
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