Question

Difficulty: MediumEvaluating Algebraic Expressions

An engineering formula used to calculate a structural load index is given by L=a3b−2−c3/4a2+12bL = \frac{a^3 b^{-2} - c^{3/4}}{a^2 + 12b}. What is the value of LL when a=−2a = -2, b=13b = \frac{1}{3}, and c=16c = 16?

Answer: -10

Answer

The value of the expression is -10.
Substituting the values into the formula gives L=(−2)3⋅(1/3)−2−163/4(−2)2+12(1/3)=−8⋅9−84+4=−72−88=−808=−10L = \frac{(-2)^3 \cdot (1/3)^{-2} - 16^{3/4}}{(-2)^2 + 12(1/3)} = \frac{-8 \cdot 9 - 8}{4 + 4} = \frac{-72 - 8}{8} = \frac{-80}{8} = -10.

Step-by-Step Solution

1
Evaluate the terms in the numerator containing powers and negative exponents
a3=−8a^3 = -8, b−2=9b^{-2} = 9, and c3/4=8c^{3/4} = 8
Negative bases raised to odd powers remain negative: (−2)3=−8(-2)^3 = -8. A negative exponent represents the reciprocal raised to a positive exponent: (1/3)−2=32=9(1/3)^{-2} = 3^2 = 9. Fractional exponent c3/4=(164)3=23=8c^{3/4} = (\sqrt[4]{16})^3 = 2^3 = 8.
2
Compute the full numerator
−72−8=−80-72 - 8 = -80
Multiply a3a^3 and b−2b^{-2} to get (−8)(9)=−72(-8)(9) = -72, then subtract c3/4=8c^{3/4} = 8.
3
Evaluate the denominator
(−2)2+12(13)=4+4=8(-2)^2 + 12\left(\frac{1}{3}\right) = 4 + 4 = 8
Squaring a negative number yields a positive value: (−2)2=4(-2)^2 = 4. Multiplying 12⋅13=412 \cdot \frac{1}{3} = 4.
4
Divide the numerator by the denominator
−808=−10\frac{-80}{8} = -10
Dividing a negative integer by a positive integer yields a negative result.

Key Concept

Evaluating algebraic expressions involving negative numbers, negative exponents, and rational exponents
Estimated Time:1m 15s
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