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Difficulty: EasyResistors and Potentiometers

An electronics technician is assembling a circuit that requires a 10 kΩ10\text{ k}\Omega fixed resistor. If the first two color bands on the resistor are Brown (1) and Black (0), which color must the third (multiplier) band be?

  1. A
    Red
  2. OrangeAnswer
  3. C
    Yellow
  4. D
    Brown

Answer

Orange
Orange represents a decimal multiplier of 10310^3 (10001{}000). Multiplying the significant digits 10 (from Brown and Black) by 10001{}000 yields 10000 Ω10{}000\ \Omega, which equals 10 kΩ10\text{ k}\Omega.

Step-by-Step Solution

1
Convert the target resistance from kilohms to ohms.
10 kΩ=10000 Ω10\text{ k}\Omega = 10{}000\ \Omega
Standard color code multipliers apply directly to resistance values expressed in ohms.
2
Determine the two-digit base number from the first two color bands.
Brown (1) and Black (0) form the significant digits 10.
In a 4-band resistor, the first two bands represent the leading significant digits.
3
Calculate the necessary multiplier value and identify its corresponding color.
10×103=10000 Ω10 \times 10^3 = 10{}000\ \Omega; 10310^3 (10001{}000) corresponds to Orange.
The third band indicates the power of ten (number of trailing zeros) to multiply by the significant digits.

Key Concept

Four-Band Resistor Color Code Multipliers
Estimated Time:30s
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Topics

Resistors and Potentiometers

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