Resistors and Potentiometers

36 questions

Question 1Question →

A technician servicing a radio receiver needs to verify a fixed carbon-film resistor with four color bands: Brown, Black, Yellow, and Silver. Calculate the nominal resistance and the minimum allowable resistance under its tolerance rating, and complete the statement below.

Fill in the blanks below

The nominal resistance of the resistor is kΩ\text{k}\Omega, and its minimum allowable resistance within tolerance is kΩ\text{k}\Omega.
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Answer

The nominal resistance is 100 kΩ100\text{ k}\Omega and the minimum allowable resistance is 90 kΩ90\text{ k}\Omega.
According to the electronic color code system, Brown represents 1 and Black represents 0, forming the base number 10. The third band, Yellow, represents a multiplier of 10410^4 (1000010{}000), giving a nominal resistance of 10×10000=100000 Ω=100 kΩ10 \times 10{}000 = 100{}000\ \Omega = 100\text{ k}\Omega. The fourth band, Silver, designates a ±10%\pm 10\% tolerance. Ten percent of 100 kΩ100\text{ k}\Omega is 10 kΩ10\text{ k}\Omega, meaning the minimum allowable resistance under tolerance is 100 kΩ−10 kΩ=90 kΩ100\text{ k}\Omega - 10\text{ k}\Omega = 90\text{ k}\Omega (and the maximum is 110 kΩ110\text{ k}\Omega).

Step-by-Step Solution

1
Decode the significant digits from the first two color bands.
Band 1 (Brown) = 11, Band 2 (Black) = 00, giving significant digits 1010.
In standard 4-band EIA color coding, the first two bands represent the first two significant figures of the resistance value.
2
Apply the multiplier from the third color band and convert to kilohms.
Band 3 (Yellow) = multiplier 10410^4 (1000010{}000). Nominal resistance =10×10000=100000 Ω=100 kΩ= 10 \times 10{}000 = 100{}000\ \Omega = 100\text{ k}\Omega.
The third band determines the power of ten by which the significant digits are multiplied.
3
Determine the tolerance percentage from the fourth color band.
Band 4 (Silver) = ±10%\pm 10\% tolerance.
Silver indicates a manufacturing variation of plus or minus ten percent from nominal value.
4
Calculate the minimum allowable resistance limit.
Tolerance amount =100 kΩ×0.10=10 kΩ= 100\text{ k}\Omega \times 0.10 = 10\text{ k}\Omega. Minimum resistance =100 kΩ−10 kΩ=90 kΩ= 100\text{ k}\Omega - 10\text{ k}\Omega = 90\text{ k}\Omega.
Subtracting the tolerance deviation from the nominal value establishes the lower acceptable boundary.

Key Concept

Standard 4-band resistor color decoding and tolerance range calculation
Estimated Time:45s
Question 2Question →

A 100 kΩ100\text{ k}\Omega linear potentiometer is connected across a 12 V12\text{ V} DC power supply, with terminal 1 connected to +12 V+12\text{ V}, terminal 3 connected to ground (0 V0\text{ V}), and terminal 2 serving as the adjustable wiper. If the wiper is set to 40%40\% of its total travel distance away from terminal 3 toward terminal 1, what is the output voltage measured at terminal 2 relative to ground, and what is the resistance between terminal 1 and terminal 2?

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Answer: 4.8 V4.8\text{ V} and 60 kΩ60\text{ k}\Omega

Answer

4.8 V4.8\text{ V} output voltage and 60 kΩ60\text{ k}\Omega resistance between terminal 1 and terminal 2
A linear potentiometer configured across a DC voltage source acts as a continuous voltage divider. With terminal 3 connected to ground (0 V0\text{ V}) and the wiper at 40%40\% travel from ground, the lower resistance segment R2−3R_{2-3} is 40 kΩ40\text{ k}\Omega, yielding an output voltage of Vout=12 V×(40 kΩ/100 kΩ)=4.8 VV_{\text{out}} = 12\text{ V} \times (40\text{ k}\Omega / 100\text{ k}\Omega) = 4.8\text{ V}. The upper resistance segment between terminal 1 (+12 V+12\text{ V}) and terminal 2 (wiper) is the remaining portion: 100 kΩ−40 kΩ=60 kΩ100\text{ k}\Omega - 40\text{ k}\Omega = 60\text{ k}\Omega.

Step-by-Step Solution

1
Calculate the resistance of the lower track section between terminal 2 (wiper) and terminal 3 (ground).
R2−3=0.40×100 kΩ=40 kΩR_{2-3} = 0.40 \times 100\text{ k}\Omega = 40\text{ k}\Omega
The wiper is positioned at 40%40\% of total travel measured from the ground terminal.
2
Calculate the output voltage VoutV_{\text{out}} at terminal 2 relative to ground using the voltage divider relationship.
Vout=Vin×(R2−3Rtotal)=12 V×(40 kΩ100 kΩ)=4.8 VV_{\text{out}} = V_{\text{in}} \times \left(\frac{R_{2-3}}{R_{\text{total}}}\right) = 12\text{ V} \times \left(\frac{40\text{ k}\Omega}{100\text{ k}\Omega}\right) = 4.8\text{ V}
A potentiometer connected across a voltage source functions as an adjustable voltage divider.
3
Determine the remaining resistance between terminal 1 (+12 V+12\text{ V}) and terminal 2 (wiper).
R1−2=Rtotal−R2−3=100 kΩ−40 kΩ=60 kΩR_{1-2} = R_{\text{total}} - R_{2-3} = 100\text{ k}\Omega - 40\text{ k}\Omega = 60\text{ k}\Omega
The total resistance is divided into two series segments by the wiper contact.

Key Concept

Potentiometer voltage division and wiper segment resistance distribution
Estimated Time:45s
Question 3Question →

A technician is troubleshooting a test circuit connected to a 32V32\text{V} DC power supply. The circuit consists of a fixed resistor R1R_1 in series with a parallel block. The parallel block contains a 12 kΩ12\text{ k}\Omega fixed resistor and a variable resistor (rheostat) RvR_v. The resistor R1R_1 has four color bands: Green, Blue, Red, and Gold. The technician adjusts the rheostat RvR_v until the total current drawn from the power supply is exactly 4 mA4\text{ mA}.

What is the resistance setting of the rheostat RvR_v in kilohms (k Ω\Omega)?

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Answer: 3

Answer

3
The total resistance required by the circuit to draw 4 mA4\text{ mA} from a 32V32\text{V} source is 8 kΩ8\text{ k}\Omega. The series resistor R1R_1 (Green, Blue, Red) contributes 5.6 kΩ5.6\text{ k}\Omega. This leaves exactly 2.4 kΩ2.4\text{ k}\Omega required for the parallel section. For a 12 kΩ12\text{ k}\Omega resistor in parallel with an unknown RvR_v to yield an equivalent resistance of 2.4 kΩ2.4\text{ k}\Omega, RvR_v must be set to 3 kΩ3\text{ k}\Omega.

Step-by-Step Solution

1
Decode the color code of resistor R1R_1.
R1=5.6 kΩR_1 = 5.6\text{ k}\Omega
The color bands are Green (5), Blue (6), and Red (multiplier of 10210^2 or 100). Thus, 56×100=5,600 Ω56 \times 100 = 5,600\ \Omega, which is 5.6 kΩ5.6\text{ k}\Omega. The Gold band indicates a 5% tolerance, which applies to real-world variance but does not alter our nominal calculation.
2
Calculate the total equivalent resistance (ReqR_{eq}) of the circuit.
Req=8 kΩR_{eq} = 8\text{ k}\Omega
Using Ohm's Law (R=VIR = \frac{V}{I}), divide the source voltage (32V32\text{V}) by the total current (4 mA4\text{ mA} or 0.004 A0.004\text{ A}) to find the total resistance required to draw that current.
3
Determine the required equivalent resistance of the parallel block.
Rparallel=2.4 kΩR_{parallel} = 2.4\text{ k}\Omega
Since R1R_1 is in series with the parallel block, subtract R1R_1 from the total circuit resistance to find the resistance of the parallel segment: 8 kΩ−5.6 kΩ=2.4 kΩ8\text{ k}\Omega - 5.6\text{ k}\Omega = 2.4\text{ k}\Omega.
4
Solve for the rheostat's resistance (RvR_v).
Rv=3 kΩR_v = 3\text{ k}\Omega
The parallel block contains a 12 kΩ12\text{ k}\Omega resistor and RvR_v. Using the parallel resistance formula 1Rp=1Ra+1Rb\frac{1}{R_p} = \frac{1}{R_a} + \frac{1}{R_b}, we get 12.4=112+1Rv\frac{1}{2.4} = \frac{1}{12} + \frac{1}{R_v}. Rearranging gives 1Rv=12.4−112=1024−224=824=13\frac{1}{R_v} = \frac{1}{2.4} - \frac{1}{12} = \frac{10}{24} - \frac{2}{24} = \frac{8}{24} = \frac{1}{3}, meaning Rv=3 kΩR_v = 3\text{ k}\Omega.

Key Concept

Integrating Ohm's law with series-parallel equivalent resistance and resistor color code decoding.
Estimated Time:3m 0s
Question 4Question →

Match each resistor configuration or color-coded component on the left with its corresponding electrical characteristic and operating principle on the right.

Click a left item, then click its matching right item

Items

Three-terminal potentiometer wired across a DC supply voltage (VinV_{\text{in}}) with output taken from the wiper
Variable resistor wired as a rheostat with the wiper connected to one end terminal
Four-band fixed resistor with color sequence Yellow, Violet, Orange, Gold
Four-band fixed resistor with color sequence Brown, Gray, Green, Silver

Matches

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Answer

The three-terminal potentiometer matches the voltage divider function; the rheostat matches the series current limiter with wiper-to-end protection; the Yellow-Violet-Orange-Gold resistor matches 47 kΩ±5%47\text{ k}\Omega \pm 5\%; and the Brown-Gray-Green-Silver resistor matches 1.8 MΩ±10%1.8\text{ M}\Omega \pm 10\%.
Each item correctly links the component physical description or color code to its precise electrical definition: potentiometers provide variable potential division, rheostats adjust circuit current, Yellow-Violet-Orange-Gold evaluates to 47 kΩ±5%47\text{ k}\Omega \pm 5\%, and Brown-Gray-Green-Silver evaluates to 1.8 MΩ±10%1.8\text{ M}\Omega \pm 10\%.

Step-by-Step Solution

1
Analyze the three-terminal potentiometer and rheostat wiring configurations
A potentiometer connected across a power source acts as a continuous voltage divider (0 V0\text{ V} to VinV_{\text{in}}) at the wiper terminal. A rheostat uses a variable two-terminal configuration in series with the load to regulate current.
Variable resistors differ in circuit function based on whether they are wired as three-terminal potential dividers or two-terminal current adjusters.
2
Decode the four-band color code for Yellow-Violet-Orange-Gold
Yellow = 4, Violet = 7, Orange = multiplier 103=1,00010^3 = 1,000, Gold = ±5%\pm 5\%. Value =47×1,000 Ω=47 kΩ±5%= 47 \times 1,000\ \Omega = 47\text{ k}\Omega \pm 5\%.
Standard EIA 4-band color coding assigns significant digits to the first two bands, a decimal multiplier to the third band, and tolerance percentage to the fourth band.
3
Decode the four-band color code for Brown-Gray-Green-Silver
Brown = 1, Gray = 8, Green = multiplier 105=100,00010^5 = 100,000, Silver = ±10%\pm 10\%. Value =18×100,000 Ω=1.8 MΩ±10%= 18 \times 100,000\ \Omega = 1.8\text{ M}\Omega \pm 10\%.
Standard EIA 4-band color coding converts 1,800,000 Ω1,800,000\ \Omega using standard metric prefixes to 1.8 MΩ1.8\text{ M}\Omega with a silver tolerance of ±10%\pm 10\%.

Key Concept

Operating principles and terminal configurations of fixed and variable resistors (potentiometers, rheostats, and standard color codes)

Alternative Method

To quickly decode 4-band resistors, write down the two digits (e.g., 47 for Yellow-Violet or 18 for Brown-Gray), append the number of zeros indicated by the multiplier color (3 zeros for Orange = 47,000, 5 zeros for Green = 1,800,000), and simplify to metric units (kilo or mega).
Estimated Time:1m 0s
Question 5Question →

A 10 kΩ10\text{ k}\Omega linear potentiometer is wired as a variable rheostat by tying the center wiper (terminal 2) directly to outside terminal 3. If the control shaft is set to 25%25\% of its total travel starting from terminal 1 toward terminal 3, what is the effective resistance measured between terminal 1 and the combined terminal 2/3 connection?

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Answer: 2.5 kΩ2.5\text{ k}\Omega

Answer

2.5 kΩ2.5\text{ k}\Omega
A potentiometer wired with its wiper connected to one outer terminal functions as a two-terminal variable resistor (rheostat). Setting the shaft to 25%25\% rotation from terminal 1 creates a 2.5 kΩ2.5\text{ k}\Omega resistance path between terminal 1 and terminal 2. Because terminal 2 is strapped to terminal 3, the remaining 7.5 kΩ7.5\text{ k}\Omega section of the resistive element is completely bypassed by the short, leaving an effective resistance of 2.5 kΩ2.5\text{ k}\Omega.

Step-by-Step Solution

1
Determine the resistance of the active resistive track between terminal 1 and the wiper (terminal 2).
R1−2=0.25×10 kΩ=2.5 kΩR_{1-2} = 0.25 \times 10\text{ k}\Omega = 2.5\text{ k}\Omega
Linear potentiometers divide resistance directly in proportion to shaft travel percentage from the reference end.
2
Analyze the state of the remaining track segment between the wiper (terminal 2) and terminal 3.
R2−3=7.5 kΩR_{2-3} = 7.5\text{ k}\Omega is short-circuited.
Connecting terminal 2 directly to terminal 3 creates a zero-resistance path across this section, bypassing it entirely.
3
Calculate the total effective resistance between terminal 1 and the joined 2/3 terminal.
Reff=2.5 kΩR_{\text{eff}} = 2.5\text{ k}\Omega
Current flows through the unshorted R1−2R_{1-2} segment and exits via the combined wiper/terminal 3 connection.

Key Concept

Rheostat Wiring and Potentiometer Track Division
Estimated Time:45s
Question 6Question →

A quality assurance technician is inspecting a four-band carbon-composition resistor with the color bands in order: Yellow, Violet, Red, and Silver. To meet quality standards, the resistor must operate within its specified manufacturer tolerance. What is the minimum acceptable resistance value, in ohms (Ω\Omega), for this component?

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Answer: 4230

Answer

The minimum acceptable resistance value is 4230 Ω4230\text{ }\Omega.
The first two bands (Yellow = 4, Violet = 7) establish the significant figures of 47. The third band (Red) indicates a multiplier of 102=10010^2 = 100, giving a nominal rating of 4700 Ω4700\text{ }\Omega. The fourth band (Silver) specifies a ±10%\pm 10\% tolerance. Subtracting 10%10\% of 4700 Ω4700\text{ }\Omega (470 Ω470\text{ }\Omega) from the nominal rating gives the minimum allowable threshold of 4230 Ω4230\text{ }\Omega.

Step-by-Step Solution

1
Decode the first two color bands to obtain the significant numerical digits.
Yellow represents the digit 44, and Violet represents the digit 77, forming the base value of 4747.
Standard EIA four-band resistor color coding assigns the first two bands as significant figures of the resistance value.
2
Multiply the base significant figures by the power of ten indicated by the third band.
Red indicates a multiplier of 10210^2 (100100), so the nominal resistance is 47×100=4700 Ω47 \times 100 = 4700\text{ }\Omega.
The third band functions as the decimal multiplier for four-band fixed resistors.
3
Identify the tolerance rating from the fourth band.
Silver represents a tolerance of ±10%\pm 10\%.
The fourth band specifies the allowable deviation range from the nominal resistance value.
4
Calculate the lower allowable resistance threshold.
Tolerance amount is 4700 Ω×0.10=470 Ω4700\text{ }\Omega \times 0.10 = 470\text{ }\Omega. Minimum acceptable value is 4700 Ω−470 Ω=4230 Ω4700\text{ }\Omega - 470\text{ }\Omega = 4230\text{ }\Omega.
The minimum acceptable value represents the nominal value minus the total tolerance deviation.

Key Concept

Four-Band Resistor Color Code Decoding and Tolerance Range Calculation

Alternative Method

Multiply the nominal resistance directly by the minimum percentage factor: 4700 Ω×(1.00−0.10)=4700 Ω×0.90=4230 Ω4700\text{ }\Omega \times (1.00 - 0.10) = 4700\text{ }\Omega \times 0.90 = 4230\text{ }\Omega.
Estimated Time:45s
Question 7Question →

An electronics technician selects a four-band carbon-film resistor with the color sequence Brown, Green, Red, and Gold. What is the nominal resistance and tolerance of this resistor?

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Answer: 1.5 kΩ with ±5% tolerance1.5\text{ k}\Omega\text{ with } \pm 5\%\text{ tolerance}

Answer

1.5 kΩ with ±5% tolerance1.5\text{ k}\Omega\text{ with } \pm 5\%\text{ tolerance} (1,500 Ω±5%1,500\ \Omega \pm 5\%)
Decoding the four color bands in standard order gives: Brown = 1 (first digit), Green = 5 (second digit), Red = 10210^2 or ×100\times 100 (multiplier), and Gold = ±5%\pm 5\% (tolerance). Calculating 15×100 Ω15 \times 100\ \Omega yields 1,500 Ω1,500\ \Omega, which converts to 1.5 kΩ1.5\text{ k}\Omega with a ±5%\pm 5\% tolerance.

Step-by-Step Solution

1
Identify the first two significant digit color bands.
Brown represents the digit 1, and Green represents the digit 5, forming the number 15.
In a standard four-band resistor, the first two bands establish the base significant figures.
2
Determine the multiplier from the third band.
Red represents a multiplier of 10210^2 (100100).
The third band indicates the power of ten by which the significant digits are multiplied.
3
Calculate the nominal resistance value.
15×100=1,500 Ω=1.5 kΩ15 \times 100 = 1,500\ \Omega = 1.5\text{ k}\Omega.
Multiplying the base digits by the multiplier yields the total nominal resistance.
4
Identify the tolerance from the fourth band.
Gold indicates a tolerance of ±5%\pm 5\%.
The fourth band specifies the acceptable manufacturing variation percentage.

Key Concept

Four-band resistor color code decoding and tolerance identification
Estimated Time:35s
Question 8Question →

Match each electronic component or resistor specification on the left with its correct circuit function or definition on the right.

Click a left item, then click its matching right item

Items

Potentiometer
Rheostat
Fixed Resistor
Tolerance Band

Matches

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Answer

Potentiometer matches with the three-terminal variable resistor used as an adjustable voltage divider; Rheostat matches with the two-terminal variable resistor used to adjust current flow; Fixed Resistor matches with the component providing a single, constant resistance value; Tolerance Band matches with the color-coded marking indicating allowable percentage variation from nominal resistance.
Each item is correctly matched to its standard electrical engineering and ASVAB definition: potentiometers provide variable three-terminal voltage division, rheostats provide two-terminal variable current control, fixed resistors supply a steady ohmic value, and tolerance bands indicate the precision percentage.

Step-by-Step Solution

1
Identify the distinction between the two variable resistor types based on terminal count and primary function.
A potentiometer has 3 terminals and functions as a voltage divider; a rheostat has 2 active terminals in series to regulate current.
Variable resistors differ in wiring configuration: voltage division requires three connections across a potential difference, whereas current regulation requires two inline connections.
2
Identify the definition of a fixed resistor.
A fixed resistor provides a constant, unchangeable ohmic value.
Unlike potentiometers or rheostats, fixed resistors have no moving wiper mechanism.
3
Identify the purpose of the resistor tolerance band.
The tolerance band gives the allowable percentage deviation from the nominal value.
Manufacturing variations mean actual resistance lies within a percentage range defined by the 4th band.

Key Concept

Classification, terminal configurations, and functional specifications of fixed and variable resistors.
Estimated Time:40s
Question 9Question →

A four-band carbon-film resistor has the color bands in the following sequence: Blue, Gray, Brown, and Gold. What is the nominal resistance value and tolerance rating of this resistor?

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Answer: 680 Ω with ±5% tolerance680\ \Omega\text{ with } \pm 5\%\text{ tolerance}

Answer

680 Ω with ±5% tolerance680\ \Omega\text{ with } \pm 5\%\text{ tolerance}
Decoding the four color bands in order yields: first band (Blue) = 6, second band (Gray) = 8, third band (Brown) = ×101\times 10^1 (1010), and fourth band (Gold) = ±5%\pm 5\%. Calculating 68×1068 \times 10 gives a nominal resistance of 680 Ω680\ \Omega with ±5%\pm 5\% tolerance.

Step-by-Step Solution

1
Identify the significant digits from the first two color bands
Blue corresponds to the digit 6 and Gray corresponds to the digit 8, forming the significant number 68.
In a standard four-band resistor, the first two bands represent the first and second significant digits of the resistance value.
2
Determine the multiplier from the third color band and calculate the nominal resistance
Brown corresponds to a multiplier of 10110^1 (1010). Multiplying 68×10=680 Ω68 \times 10 = 680\ \Omega.
The third band indicates the power of ten by which the significant digits are multiplied.
3
Identify the tolerance percentage from the fourth color band
Gold corresponds to a tolerance of ±5%\pm 5\%.
The fourth band indicates the manufacturing tolerance of the resistor.

Key Concept

Four-band resistor color code decoding
Estimated Time:35s
Question 10Question →

A linear potentiometer has a total resistance of 20 kΩ20\text{ k}\Omega between its two outer terminals (Terminal 1 and Terminal 3). If the center wiper (Terminal 2) is adjusted so that the resistance between Terminal 1 and Terminal 2 is 6.5 kΩ6.5\text{ k}\Omega, what is the resistance in kilohms (kΩ\text{k}\Omega) between Terminal 2 and Terminal 3?

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Answer: 13.5

Answer

The resistance between Terminal 2 and Terminal 3 is 13.5 kΩ13.5\text{ k}\Omega.
In a three-terminal potentiometer, the resistive element connects between the two outer terminals (1 and 3), providing a fixed total resistance of 20 kΩ20\text{ k}\Omega. The adjustable wiper (terminal 2) contacts this element and divides it into two series portions such that R1−2+R2−3=R1−3R_{1-2} + R_{2-3} = R_{1-3}. Subtracting the known section (6.5 kΩ6.5\text{ k}\Omega) from the total (20 kΩ20\text{ k}\Omega) gives 13.5 kΩ13.5\text{ k}\Omega for the remaining section between Terminal 2 and Terminal 3.

Step-by-Step Solution

1
Set up the resistance relationship for the three terminals of a potentiometer.
Rtotal=R1−2+R2−3R_{\text{total}} = R_{1-2} + R_{2-3}
The wiper divides the continuous internal resistive strip into two series sections whose resistances add up to the total end-to-end resistance.
2
Subtract the resistance of the first section from the total end-to-end resistance.
R2−3=20 kΩ−6.5 kΩ=13.5 kΩR_{2-3} = 20\text{ k}\Omega - 6.5\text{ k}\Omega = 13.5\text{ k}\Omega
Isolating the unknown segment gives the remaining resistance along the track to the opposite outer terminal.

Key Concept

Potentiometer Terminal Resistance Division
Estimated Time:30s
Question 11Question →

An electronics technician is assembling a circuit that requires a 10 kΩ10\text{ k}\Omega fixed resistor. If the first two color bands on the resistor are Brown (1) and Black (0), which color must the third (multiplier) band be?

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Answer: Orange

Answer

Orange
Orange represents a decimal multiplier of 10310^3 (10001{}000). Multiplying the significant digits 10 (from Brown and Black) by 10001{}000 yields 10000 Ω10{}000\ \Omega, which equals 10 kΩ10\text{ k}\Omega.

Step-by-Step Solution

1
Convert the target resistance from kilohms to ohms.
10 kΩ=10000 Ω10\text{ k}\Omega = 10{}000\ \Omega
Standard color code multipliers apply directly to resistance values expressed in ohms.
2
Determine the two-digit base number from the first two color bands.
Brown (1) and Black (0) form the significant digits 10.
In a 4-band resistor, the first two bands represent the leading significant digits.
3
Calculate the necessary multiplier value and identify its corresponding color.
10×103=10000 Ω10 \times 10^3 = 10{}000\ \Omega; 10310^3 (10001{}000) corresponds to Orange.
The third band indicates the power of ten (number of trailing zeros) to multiply by the significant digits.

Key Concept

Four-Band Resistor Color Code Multipliers
Estimated Time:30s
Question 12Question →

Fill in the blanks to complete the statement describing variable resistor terminology.

Fill in the blanks below

A three-terminal variable resistor commonly used to create an adjustable voltage divider is called a , and the internal adjustable contact that moves across the resistive track is called the .
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Answer

blank_1: potentiometer; blank_2: wiper
A potentiometer is a three-terminal variable resistor widely used to provide an adjustable voltage division in electronic circuits. The two outer terminals connect across the full resistive element, while the center movable contact, called the wiper, adjusts the output voltage based on its mechanical position.

Step-by-Step Solution

1
Identify the standard three-terminal variable resistor component
A potentiometer (often abbreviated 'pot') is a three-terminal variable resistor configured to divide voltage across its resistive track.
By definition in basic electronics, a three-terminal variable resistor used for voltage division is designated as a potentiometer.
2
Identify the movable mechanical contact mechanism
The sliding contact that traverses the resistive material to tap off a portion of the total resistance is called the wiper.
The standard technical term for the adjustable middle contact of a potentiometer or rheostat is the wiper.

Key Concept

Potentiometer structure and terminology
Estimated Time:30s
Question 13Question →

When inspecting a circuit board, a technician observes a four-band resistor with the color sequence Red, Red, Orange, and Gold. What is the rated resistance value and tolerance of this resistor?

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Answer: 22 kΩ±5%22\text{ k}\Omega \pm 5\%

Answer

22 kΩ±5%22\text{ k}\Omega \pm 5\%
According to standard electronic color code rules, the first band (Red = 2) and second band (Red = 2) give the two significant digits 22. The third band (Orange = 10310^3) multiplies this base number by 10001{}000, resulting in 22000 Ω22{}000\ \Omega (22 kΩ22\text{ k}\Omega). The fourth band (Gold) indicates a tolerance rating of ±5%\pm 5\%.

Step-by-Step Solution

1
Determine the first two significant digits from the first and second color bands.
Band 1 (Red) = 2, Band 2 (Red) = 2. Combined digits = 22.
In standard four-band EIA color coding, the first two bands establish the base significant figures.
2
Determine the multiplier from the third band.
Band 3 (Orange) = multiplier of 10310^3 (10001{}000).
Orange corresponds to 3 zeros, or multiplying by 10001{}000.
3
Calculate nominal resistance and append the tolerance from the fourth band.
22×1000=22000 Ω=22 kΩ22 \times 1{}000 = 22{}000\ \Omega = 22\text{ k}\Omega, with Band 4 (Gold) = ±5%\pm 5\%.
Combining the base value with the metric prefix gives 22 kΩ22\text{ k}\Omega with a rated tolerance of ±5%\pm 5\%.

Key Concept

Four-Band Resistor Color Code Decoding
Estimated Time:35s
Question 14Question →

Four-band resistors use standardized color bands to indicate numerical resistance values. Match each resistor color band with its correct numerical digit value.

Click a left item, then click its matching right item

Items

Brown
Orange
Blue
Gray

Matches

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Answer

Brown matches with digit value of 11, Orange matches with digit value of 33, Blue matches with digit value of 66, and Gray matches with digit value of 88.
According to the standard EIA resistor color code: Brown represents 1, Orange represents 3, Blue represents 6, and Gray represents 8.

Step-by-Step Solution

1
Recall the standard electronic color code sequence from 0 through 9.
The standardized sequence is Black (0), Brown (1), Red (2), Orange (3), Yellow (4), Green (5), Blue (6), Violet (7), Gray (8), and White (9).
Each color band on a fixed resistor corresponds to an exact base-10 numerical value.
2
Pair each given color band to its corresponding numerical digit.
Brown = 1, Orange = 3, Blue = 6, and Gray = 8.
Direct mapping using the standard EIA color code chart.

Key Concept

Standard Resistor Color Code Digit Values
Estimated Time:35s
Question 15Question →

A four-band carbon resistor displays the color bands Orange, Orange, Brown, and Gold in sequence from left to right. What is the nominal resistance value of this component?

Show answer & explanation

Answer: 330 Ω330\ \Omega

Answer

330 Ω330\ \Omega
The first band (Orange) represents the digit 3, the second band (Orange) represents the digit 3, and the third band (Brown) represents a multiplier of 10110^1 (10). Multiplying the significant digits by the multiplier yields 33×10=330 Ω33 \times 10 = 330\ \Omega.

Step-by-Step Solution

1
Decode the first two significant color bands.
Orange corresponds to 3, and the second Orange corresponds to 3, giving the two-digit number 33.
In a 4-band resistor code, the first two bands represent the base significant digits.
2
Determine the multiplier from the third color band.
Brown corresponds to a multiplier of 10110^1 (or 1010).
The third band indicates the power of ten by which the significant digits are multiplied.
3
Multiply the significant digits by the multiplier value.
33×10=330 Ω33 \times 10 = 330\ \Omega.
Combining the base digits and multiplier gives the nominal resistance rating.

Key Concept

Four-Band Resistor Color Code Decoding
Estimated Time:35s
Question 16Question →

An electronic circuit uses a standard four-band resistor with the color bands Yellow, Violet, Brown, and Gold reading from left to right. What is the nominal resistance value of this resistor in ohms (Ω\Omega)?

Show answer & explanation

Answer: 470

Answer

The nominal resistance value is 470 Ω470\ \Omega.
In the standard electronic color code system, Yellow represents 4, Violet represents 7, Brown represents a multiplier of 10 (10110^1), and Gold indicates a tolerance of ±5%\pm 5\%. Combining the digits gives 47, and multiplying by 10 produces 470 Ω470\ \Omega.

Step-by-Step Solution

1
Decode the first two color bands into the first two digits
Yellow corresponds to 4 and Violet corresponds to 7, giving the base number 47
The first two bands on a four-band resistor represent the first and second significant figures of the resistance value
2
Decode the third band into the decimal multiplier
Brown corresponds to a multiplier of 10110^1 (1010)
The third band indicates the power of ten by which the base number must be multiplied
3
Calculate the total nominal resistance
47×10=470 Ω47 \times 10 = 470\ \Omega
Multiplying the base digits by the multiplier gives the rated nominal resistance in ohms

Key Concept

Four-band resistor color code decoding
Estimated Time:30s
Question 17Question →

A technician tests a four-band carbon resistor marked with the color sequence Green, Blue, Red, and Gold from left to right. What is the rated resistance and tolerance of this resistor?

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Answer: 5.6 kΩ±5%5.6\text{ k}\Omega \pm 5\%

Answer

5.6 kΩ±5%5.6\text{ k}\Omega \pm 5\% (5,600 Ω±5%5,600\ \Omega \pm 5\%)
According to the standard EIA four-band color code, Green represents the digit 5, Blue represents the digit 6, Red indicates a multiplier of 10210^2 (100100), and Gold represents a tolerance of ±5%\pm 5\%. Combining these values yields 56×100=5,600 Ω56 \times 100 = 5,600\ \Omega (5.6 kΩ5.6\text{ k}\Omega) with a tolerance of ±5%\pm 5\%.

Step-by-Step Solution

1
Determine the first and second significant digits from the first two color bands.
Green corresponds to 5 and Blue corresponds to 6, giving the significant digits 56.
In standard four-band EIA color coding, the first two bands represent the first two significant figures.
2
Determine the multiplier from the third color band and calculate nominal resistance.
Red indicates a multiplier of 10210^2 (100100). Multiplying 56×100=5,600 Ω=5.6 kΩ56 \times 100 = 5,600\ \Omega = 5.6\text{ k}\Omega.
The third band determines the power of ten by which the significant digits are multiplied.
3
Determine the tolerance percentage from the fourth color band.
Gold indicates a tolerance of ±5%\pm 5\%.
The fourth band specifies the manufacturing tolerance rating of the component.

Key Concept

Four-band resistor color code decoding
Estimated Time:35s
Question 18Question →

When examining fixed through-hole resistors, what electrical property is directly governed by the component's physical dimensions, and what unit is used to express this capability? Complete the technical statement below.

Fill in the blanks below

Although the printed color bands on a standard carbon-composition resistor indicate its electrical resistance and tolerance, the physical size of the resistor body determines its rating, which is measured in .
Show answer & explanation

Answer

power (or wattage) and watts (W)
In electronic components, the physical package size of an axial-lead fixed resistor determines its ability to radiate heat into the surrounding air. Consequently, larger resistors have higher power (wattage) ratings, which are quantified in watts (W). The actual resistance value in ohms and the manufacturing tolerance percentage are represented by the color-coded bands printed on the component body.

Step-by-Step Solution

1
Identify the electrical property determined by a resistor's physical dimensions and surface area.
Power rating (or wattage / power dissipation capacity)
A larger physical package provides more surface area to safely dissipate thermal energy generated by current flow without overheating or damaging the component.
2
Identify the standard unit of measurement for electrical power dissipation.
Watts (W)
Resistor power ratings are specified in watts, with common standard through-hole ratings including 1/8 W1/8\text{ W}, 1/4 W1/4\text{ W}, 1/2 W1/2\text{ W}, 1 W1\text{ W}, and 2 W2\text{ W}.

Key Concept

Resistor physical package size correlates directly to power dissipation rating in watts rather than resistance value in ohms.
Estimated Time:45s
Question 19Question →

During a quality control inspection, a technician measures a resistor marked with the color bands Brown, Gray, Red, and Gold. For this resistor to meet its manufactured specification, what is the acceptable range of measured resistance?

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Answer: 1,710 Ω to 1,890 Ω1,710\ \Omega\text{ to } 1,890\ \Omega

Answer

1,710 Ω to 1,890 Ω1,710\ \Omega\text{ to } 1,890\ \Omega
A four-band resistor with colors Brown (1), Gray (8), Red (102=10010^2 = 100), and Gold (±5%\pm 5\%) has a nominal value of 1,800 Ω1,800\ \Omega. With a ±5%\pm 5\% tolerance, the allowable variance is 1,800×0.05=90 Ω1,800 \times 0.05 = 90\ \Omega. Subtracting and adding 90 Ω90\ \Omega gives the acceptable operational range of 1,710 Ω1,710\ \Omega to 1,890 Ω1,890\ \Omega.

Step-by-Step Solution

1
Determine the nominal resistance from the first three color bands.
Brown = 1, Gray = 8, Red = multiplier of 10210^2 (100100). The nominal value is 18×100=1,800 Ω18 \times 100 = 1,800\ \Omega.
In a standard four-band resistor, the first two bands represent significant digits and the third band represents the power-of-ten multiplier.
2
Identify the tolerance percentage from the fourth band.
Gold band = ±5%\pm 5\%.
The fourth band specifies the manufacturing tolerance rating.
3
Calculate the acceptable tolerance deviation in ohms.
1,800 Ω×0.05=90 Ω1,800\ \Omega \times 0.05 = 90\ \Omega.
The allowable deviation is found by multiplying the nominal resistance by the tolerance percentage.
4
Calculate the minimum and maximum acceptable resistance boundaries.
Minimum: 1,800−90=1,710 Ω1,800 - 90 = 1,710\ \Omega; Maximum: 1,800+90=1,890 Ω1,800 + 90 = 1,890\ \Omega.
The acceptable range spans from nominal minus tolerance to nominal plus tolerance.

Key Concept

Decoding four-band resistor color codes and calculating nominal tolerance boundaries
Estimated Time:45s
Question 20Question →

Electronic circuits utilize various fixed and variable resistive components to control voltage, limit current, and calibrate operating points. Match each resistor type on the left with its primary functional description or application on the right. Which pairs correctly match each component to its function?

Click a left item, then click its matching right item

Items

Potentiometer
Rheostat
Trimmer Resistor (Trimpot)
Wirewound Resistor

Matches

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Answer

Potentiometer matches the three-terminal voltage divider description; Rheostat matches the two-terminal series current regulator description; Trimmer Resistor matches the miniature calibration component description; Wirewound Resistor matches the high-power coiled-wire construction description.
Each component is mapped directly according to its terminal count, internal construction, and operational role: Potentiometers are three-terminal voltage dividers; Rheostats are two-terminal series current controllers; Trimmers (trimpots) are compact PCB calibration resistors; Wirewound resistors are heavy-duty components constructed with wire coils around a ceramic core for high-power dissipation.

Step-by-Step Solution

1
Differentiate between three-terminal and two-terminal variable resistor operations.
Identify the potentiometer as the three-terminal voltage divider and the rheostat as the two-terminal current limiter.
Potentiometers divide voltage across three terminals, whereas rheostats vary resistance in series using two active terminals.
2
Identify the distinct mechanical and physical packaging of precision alignment components versus power components.
Match the trimmer resistor (trimpot) to calibration/alignment and the wirewound resistor to high-power ceramic-core construction.
Trimpots are miniature preset controls adjusted during calibration, while wirewound resistors are constructed to handle significant thermal dissipation.

Key Concept

Classification, terminal configuration, and circuit applications of fixed and variable resistors.
Estimated Time:1m 0s
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