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Difficulty: MediumWork, Energy, and Power

An electric winch applies a constant horizontal pulling force of 220 N220\text{ N} to drag a heavy storage crate across a level concrete floor for a distance of 15 meters15\text{ meters} in 6 seconds6\text{ seconds}. What is the average power output delivered by the winch in watts?

Answer: 550 W

Answer

The average power output of the winch is 550 W550\text{ W}.
Work equals force multiplied by distance (220 N×15 m=3300 J220\text{ N} \times 15\text{ m} = 3300\text{ J}). Power is the rate of work done per second (3300 J/6 s=550 W3300\text{ J} / 6\text{ s} = 550\text{ W}).

Step-by-Step Solution

1
Calculate the work done by multiplying force by distance
W=220 N×15 m=3300 JW = 220\text{ N} \times 15\text{ m} = 3300\text{ J}
Work measures the energy transferred by a force acting over a displacement in the direction of the force (W=FdW = Fd).
2
Calculate the power output by dividing work done by elapsed time
P=3300 J6 s=550 WP = \frac{3300\text{ J}}{6\text{ s}} = 550\text{ W}
Power represents the rate at which work is done over time (P=WtP = \frac{W}{t}).

Key Concept

Work is calculated as the product of force and displacement (W=FdW = Fd), and power is the rate of doing work over time (P=WtP = \frac{W}{t}).
Estimated Time:1m 0s
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Topics

Work, Energy, and Power

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