A military supply truck has a fuel tank capacity of 45 \text{ gallons}. The truck operates… — Armed Services Vocational Aptitude Battery (ASVAB)

A military supply truck has a fuel tank capacity of $45 \text{ gallons}$ . The truck operates with a fuel efficiency of $8 \text{ kilometers per liter}$ . Assuming the truck starts with a full tank of fuel, what is its maximum driving range in miles? (Use $1 \text{ gallon} = 3.8 \text{ liters}$ and $1 \text{ mile} = 1.6 \text{ kilometers}$ )

A
85.5
855Answer
C
1,368
D
2,188.8

Answer

855

To find the range in miles, first convert the tank capacity to liters by multiplying 45 gallons by 3.8 liters/gallon to get 171 liters. Then, find the range in kilometers by multiplying 171 liters by 8 kilometers/liter, which equals 1,368 kilometers. Finally, convert the distance from kilometers to miles by dividing 1,368 by 1.6, resulting in exactly 855 miles.

Step-by-Step Solution

Convert the fuel tank capacity from gallons to liters.

45 \text{ gallons} \times 3.8 \text{ liters/gallon} = 171 \text{ liters}

The fuel efficiency is given in kilometers per liter, so the total fuel volume must be in liters to find the total distance.

Calculate the maximum driving range in kilometers.

171 \text{ liters} \times 8 \text{ km/liter} = 1,368 \text{ kilometers}

Multiplying the total volume of fuel by the fuel efficiency yields the total distance the truck can travel in kilometers.

Convert the maximum driving range from kilometers to miles.

1,368 \text{ kilometers} \div 1.6 \text{ km/mile} = 855 \text{ miles}

The question asks for the final distance in miles, requiring division by the conversion factor.

Key Concept

Inter-System Unit Conversions with Compound Rates

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