Question

Difficulty: EasyWork, Energy, and Power

An electric motor performs 4500 J4{}500\text{ J} of mechanical work in 15 seconds15\text{ seconds}. What is the power output of the motor, in watts?

Answer: 300 W

Answer

The power output of the motor is 300 W300\text{ W}.
Power is calculated by dividing work by time (P=WtP = \frac{W}{t}). Dividing 4500 J4{}500\text{ J} by 15 s15\text{ s} yields 300 W300\text{ W}.

Step-by-Step Solution

1
Identify the relationship between power, work, and time.
P=WtP = \frac{W}{t}
Power is defined scientifically as the rate of doing work or transferring energy per unit time.
2
Substitute the given work (4500 J4{}500\text{ J}) and time (15 s15\text{ s}) into the power equation.
P=4500 J15 s=300 WP = \frac{4{}500\text{ J}}{15\text{ s}} = 300\text{ W}
Dividing total work in joules by elapsed time in seconds yields the power in watts (1 W=1 J/s1\text{ W} = 1\text{ J/s}).

Key Concept

Power is the rate at which work is performed over time (P=WtP = \frac{W}{t}).
Estimated Time:45s
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