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Difficulty: EasyResistors and Potentiometers

When inspecting a circuit board, a technician observes a four-band resistor with the color sequence Red, Red, Orange, and Gold. What is the rated resistance value and tolerance of this resistor?

  1. A
    2.2 kΩ±5%2.2\text{ k}\Omega \pm 5\%
  2. 22 kΩ±5%22\text{ k}\Omega \pm 5\%Answer
  3. C
    220 Ω±5%220\ \Omega \pm 5\%
  4. D
    223 Ω±5%223\ \Omega \pm 5\%

Answer

22 kΩ±5%22\text{ k}\Omega \pm 5\%
According to standard electronic color code rules, the first band (Red = 2) and second band (Red = 2) give the two significant digits 22. The third band (Orange = 10310^3) multiplies this base number by 10001{}000, resulting in 22000 Ω22{}000\ \Omega (22 kΩ22\text{ k}\Omega). The fourth band (Gold) indicates a tolerance rating of ±5%\pm 5\%.

Step-by-Step Solution

1
Determine the first two significant digits from the first and second color bands.
Band 1 (Red) = 2, Band 2 (Red) = 2. Combined digits = 22.
In standard four-band EIA color coding, the first two bands establish the base significant figures.
2
Determine the multiplier from the third band.
Band 3 (Orange) = multiplier of 10310^3 (10001{}000).
Orange corresponds to 3 zeros, or multiplying by 10001{}000.
3
Calculate nominal resistance and append the tolerance from the fourth band.
22×1000=22000 Ω=22 kΩ22 \times 1{}000 = 22{}000\ \Omega = 22\text{ k}\Omega, with Band 4 (Gold) = ±5%\pm 5\%.
Combining the base value with the metric prefix gives 22 kΩ22\text{ k}\Omega with a rated tolerance of ±5%\pm 5\%.

Key Concept

Four-Band Resistor Color Code Decoding
Estimated Time:35s
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Topics

Resistors and Potentiometers

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