Examkin

Question

Difficulty: MediumResistors and Potentiometers

A four-band resistor has color bands in the following sequence: Orange, White, Red, and Silver. Based on this color code, what is the maximum acceptable resistance value for this component in ohms (Ω\Omega)?

Answer: 4290 Ω

Answer

The maximum acceptable resistance value for the resistor is 4290 Ω4290\ \Omega.
The first band (Orange) equals 3, the second band (White) equals 9, and the third band (Red) represents a multiplier of 100 (10210^2), giving a nominal resistance of 3900 Ω3900\ \Omega. The fourth band (Silver) specifies a ±10%\pm 10\% tolerance. Ten percent of 3900 Ω3900\ \Omega is 390 Ω390\ \Omega, so the maximum acceptable resistance value is 3900+390=4290 Ω3900 + 390 = 4290\ \Omega.

Step-by-Step Solution

1
Decode the first two significant digit color bands.
Orange = 3, White = 9, giving base digits 39.
Standard four-band resistors use the first two bands to establish the two most significant digits.
2
Apply the multiplier from the third color band.
Red = 102=10010^2 = 100, so Rnominal=39×100=3900 ΩR_{\text{nominal}} = 39 \times 100 = 3900\ \Omega.
The third band indicates the power of ten multiplier applied to the significant digits.
3
Calculate the upper limit of the resistance range using the tolerance band.
Silver = ±10%\pm 10\%. Maximum limit =3900+(0.10×3900)=3900+390=4290 Ω= 3900 + (0.10 \times 3900) = 3900 + 390 = 4290\ \Omega.
The fourth band specifies the allowable percentage deviation from nominal resistance, and the maximum limit requires adding the tolerance value.

Key Concept

Standard four-band resistor color code decoding and percentage tolerance range calculation.
Estimated Time:45s
Rate this question

Topics

Resistors and Potentiometers

More questions from this topic