Complete the statement regarding the electrical parameters of the DC circuit by calculatin… — Armed Services Vocational Aptitude Battery (ASVAB)

Complete the statement regarding the electrical parameters of the DC circuit by calculating the missing resistance and current values.

Answer:An indicator lamp with a constant resistance draws

150\text{ mA}

when connected to a

24\text{ V}

direct current source. The internal resistance of the lamp is 【160】

\Omega

, and if the supply voltage is increased to

36\text{ V}

, the current drawn by the lamp will increase to 【225】

\text{mA}

The internal resistance of the lamp is 160 Ω, and the new current at 36 V is 225 mA.

Converting

150\text{ mA}

to standard amperes yields

0.15\text{ A}

. Using Ohm's law (

R = V / I

), the internal resistance is

24\text{ V} / 0.15\text{ A} = 160\ \Omega

. When the voltage rises to

36\text{ V}

, applying

I = V / R

produces

36\text{ V} / 160\ \Omega = 0.225\text{ A}

, which corresponds to

225\text{ mA}

Convert the nominal current from milliamperes to base amperes

I_1 = 150\text{ mA} = 0.15\text{ A}

Ohm's law requires base SI units (amperes, volts, ohms) for direct calculation.

Calculate the constant internal resistance using Ohm's law

R = \frac{V_1}{I_1} = \frac{24\text{ V}}{0.15\text{ A}} = 160\ \Omega

Resistance equals voltage divided by current.

Calculate the new current at the elevated voltage level

I_2 = \frac{V_2}{R} = \frac{36\text{ V}}{160\ \Omega} = 0.225\text{ A} = 225\text{ mA}

Current across a fixed resistance is directly proportional to applied voltage (

I = V / R

Ohm's Law (

V = I \times R

) and Direct Proportionality in DC Circuits

Estimated Time:45s

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