An auxiliary electric bilge pump operates on a 12\text{ V} DC power supply. If the interna… — Armed Services Vocational Aptitude Battery (ASVAB)

An auxiliary electric bilge pump operates on a $12\text{ V}$ DC power supply. If the internal electrical resistance of the pump motor is $6\ \Omega$ , what is the steady-state current drawn by the pump during operation?

A
$0.5\text{ A}$
$2\text{ A}$ Answer
C
$6\text{ A}$
D
$72\text{ A}$

Answer

The current drawn by the pump is

2\text{ A}

According to Ohm's Law, current (

I

) equals voltage (

V

) divided by resistance (

R

). Dividing the

12\text{ V}

supply by the

6\ \Omega

load resistance yields exactly

2\text{ A}

Step-by-Step Solution

Identify the given circuit parameters and the formula to solve for unknown current.

Given: Voltage

V = 12\text{ V}

, Resistance

R = 6\ \Omega

. Ohm's Law states

V = I \times R

, which rearranges to

I = \frac{V}{R}

Ohm's Law defines the fundamental mathematical relationship between voltage, current, and resistance in a direct current circuit.

Substitute the given values into the rearranged formula and compute the current.

I = \frac{12\text{ V}}{6\ \Omega} = 2\text{ A}

Carrying out the division provides the magnitude of electron flow (amperage) through the load.

Key Concept

Ohm's Law formula for calculating current:

I = \frac{V}{R}

Estimated Time:40s

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