Question

Difficulty: MediumPrecision Measurement Instruments

A technician uses a standard vernier caliper with 0.001-inch resolution to measure the outside diameter of a transmission output shaft. On the main beam, the zero mark on the vernier plate has moved past the 2-inch mark, past the major graduation 3 (representing 0.300 inch), and past two 0.025-inch subdivision lines. On the 25-division vernier plate, the line marked 18 aligns precisely with a graduation line on the main beam. What is the total measured diameter of the shaft in inches?

Answer: 2.368 in

Answer

The total measured diameter of the transmission output shaft is 2.368 inches.
To read a standard inch vernier caliper, sum the whole inches (2.000 in2.000\text{ in}), the exposed tenths on the main beam (0.300 in0.300\text{ in}), the exposed 0.025-inch0.025\text{-inch} subdivisions (2×0.025 in=0.050 in2 \times 0.025\text{ in} = 0.050\text{ in}), and the aligning vernier division (18×0.001 in=0.018 in18 \times 0.001\text{ in} = 0.018\text{ in}). Adding these together gives 2.000+0.300+0.050+0.018=2.368 inches2.000 + 0.300 + 0.050 + 0.018 = 2.368\text{ inches}.

Step-by-Step Solution

1
Determine the whole inch and tenths-of-an-inch value from the main beam
2.300 inches
The vernier zero index mark has passed the 2-inch mark and the numbered 3 division, representing 2.300 inches.
2
Add the value of the exposed 0.025-inch beam subdivisions
0.050 inch (running total: 2.350 inches)
Two subdivision marks are visible past the 3, and each mark represents 0.025 inch (2 × 0.025 in = 0.050 in).
3
Add the vernier plate reading based on the aligned graduation mark
0.018 inch (final total: 2.368 inches)
The 18th mark on the vernier plate aligns with a beam line, representing 18 × 0.001 in = 0.018 inch.

Key Concept

Reading a 0.001-inch vernier caliper by combining the main beam whole inches, tenths, 0.025-inch subdivisions, and the aligning vernier plate division.

Alternative Method

Convert each scale value into thousandths of an inch before summing: 2000 thousandths (whole inches) + 300 thousandths (major mark 3) + 50 thousandths (two 0.025-inch increments) + 18 thousandths (vernier alignment) = 2368 thousandths, which equals 2.368 inches.
Estimated Time:1m 0s
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