Question

Difficulty: MediumPneumatics and Gas Laws

A heavy-duty vehicle's pneumatic braking system relies on an accumulator tank to store potential energy. Initially, a volume of 150 in3150 \text{ in}^3 of air is compressed at an absolute pressure of 90 psi90 \text{ psi} inside the accumulator. When the operator engages the brakes, the air expands isothermally (at a constant temperature) into the connected brake chambers, causing the system's absolute pressure to drop to 30 psi30 \text{ psi}. What is the total volume that the air now occupies, in cubic inches?

Answer: 450 in^3

Answer

450
According to Boyle's Law, the pressure and volume of a confined gas are inversely proportional when the temperature is held constant. The initial state is 90 psi90 \text{ psi} and 150 in3150 \text{ in}^3. The final pressure drops to 30 psi30 \text{ psi}, which is one-third of the original pressure. Therefore, to balance the equation and conserve the quantity of gas, the volume must expand to three times its original size. 150×3=450 in3150 \times 3 = 450 \text{ in}^3.

Step-by-Step Solution

1
Identify the known variables from the scenario.
P1=90 psiP_1 = 90 \text{ psi}, V1=150 in3V_1 = 150 \text{ in}^3, P2=30 psiP_2 = 30 \text{ psi}.
Establishing the initial and final states of the gas is necessary to select the correct formula.
2
Select the appropriate gas law.
Use Boyle's Law: P1V1=P2V2P_1V_1 = P_2V_2.
The problem states the expansion happens isothermally (constant temperature) and involves inversely proportional pressure and volume changes.
3
Substitute the values and solve for V2V_2.
90×150=30×V290 \times 150 = 30 \times V_2, so V2=13500/30=450 in3V_2 = 13500 / 30 = 450 \text{ in}^3.
Mathematical calculation is required to find the unknown final volume.

Key Concept

Boyle's Law (Pressure-Volume relationship at constant temperature)

Alternative Method

Instead of using the formula P1V1=P2V2P_1V_1 = P_2V_2 algebraically, you can use proportional reasoning. The pressure drops from 90 psi90 \text{ psi} to 30 psi30 \text{ psi}, which is a reduction by a factor of 3 (90/30=390 / 30 = 3). Because pressure and volume are inversely proportional at a constant temperature, the volume must increase by that exact same factor. Therefore, simply multiply the initial volume by 3: 150×3=450 in3150 \times 3 = 450 \text{ in}^3.
Estimated Time:1m 0s
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