Question

Difficulty: Very hardCapacitors

During the maintenance of an aerospace navigation system, an avionics technician isolates a filtering network to verify its total capacitance. The network is configured as follows: a 20μF20 \mu\text{F} capacitor and a 5μF5 \mu\text{F} capacitor are wired in series. This series combination is placed in parallel across a 36μF36 \mu\text{F} capacitor. Finally, this entire grouped section is wired in series with a 120μF120 \mu\text{F} capacitor. What is the total equivalent capacitance of this filtering network? Enter your answer as a number.

Answer: 30 \mu\text{F}

Answer

30
To find the total equivalent capacitance, you must simplify the circuit step-by-step applying the specific rules for capacitors, which are the exact reverse of resistors. First, the 20μF20 \mu\text{F} and 5μF5 \mu\text{F} series capacitors are combined using the product-over-sum method to yield 4μF4 \mu\text{F}. Next, this 4μF4 \mu\text{F} equivalent is added directly to the 36μF36 \mu\text{F} parallel capacitor, resulting in 40μF40 \mu\text{F} for the entire parallel section. Finally, this 40μF40 \mu\text{F} equivalent block is in series with the final 120μF120 \mu\text{F} capacitor. Using the product-over-sum method once more (40×120160\frac{40 \times 120}{160}), the final total equivalent capacitance equals 30μF30 \mu\text{F}.

Step-by-Step Solution

1
Calculate the equivalent capacitance of the 20μF20 \mu\text{F} and 5μF5 \mu\text{F} series pair.
4μF4 \mu\text{F}
Capacitors in series are calculated using the reciprocal formula or product-over-sum rule: 20×520+5=4\frac{20 \times 5}{20 + 5} = 4.
2
Calculate the equivalent capacitance of the parallel section.
40μF40 \mu\text{F}
The 4μF4 \mu\text{F} series equivalent is in parallel with the 36μF36 \mu\text{F} capacitor. Capacitors in parallel simply add together: 4+36=404 + 36 = 40.
3
Calculate the final total capacitance of the entire network.
30μF30 \mu\text{F}
The 40μF40 \mu\text{F} equivalent section is in series with the 120μF120 \mu\text{F} capacitor. Using the product-over-sum rule again: 40×12040+120=30\frac{40 \times 120}{40 + 120} = 30.

Key Concept

Calculating equivalent capacitance in compound series-parallel networks
Estimated Time:3m 0s
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