Question

Difficulty: MediumWork, Energy, and Power

Four different objects are moving horizontally across a testing facility floor. Arrange these objects in order of their kinetic energy, from least kinetic energy to greatest kinetic energy.

  1. 1A 4 kg4\text{ kg} bowling ball rolling at 2 m/s2\text{ m/s}
  2. 2A 1 kg1\text{ kg} surveillance drone flying at 6 m/s6\text{ m/s}
  3. 3A 2 kg2\text{ kg} robotic vehicle traveling at 5 m/s5\text{ m/s}
  4. 4An 8 kg8\text{ kg} utility cart pushed at 3 m/s3\text{ m/s}

Answer

The correct sequence from least to greatest kinetic energy is: the 4 kg4\text{ kg} bowling ball at 2 m/s2\text{ m/s} (8 J8\text{ J}), the 1 kg1\text{ kg} drone at 6 m/s6\text{ m/s} (18 J18\text{ J}), the 2 kg2\text{ kg} robotic vehicle at 5 m/s5\text{ m/s} (25 J25\text{ J}), and the 8 kg8\text{ kg} utility cart at 3 m/s3\text{ m/s} (36 J36\text{ J}).
Kinetic energy is calculated using the formula KE=12mv2KE = \frac{1}{2}mv^2. Computing each value yields 8 J8\text{ J} for the bowling ball, 18 J18\text{ J} for the drone, 25 J25\text{ J} for the robotic vehicle, and 36 J36\text{ J} for the utility cart. Arranging these values in ascending order produces the correct sequence.

Step-by-Step Solution

1
Recall the formula for kinetic energy
KE=12mv2KE = \frac{1}{2}mv^2, where mm is mass in kilograms and vv is velocity in meters per second.
Kinetic energy depends directly on mass and the square of velocity.
2
Calculate the kinetic energy of each moving object
Bowling ball: 12(4)(22)=8 J\frac{1}{2}(4)(2^2) = 8\text{ J}; Drone: 12(1)(62)=18 J\frac{1}{2}(1)(6^2) = 18\text{ J}; Robotic vehicle: 12(2)(52)=25 J\frac{1}{2}(2)(5^2) = 25\text{ J}; Utility cart: 12(8)(32)=36 J\frac{1}{2}(8)(3^2) = 36\text{ J}.
Determine the exact numerical energy value for each scenario.
3
Order the computed values from smallest to largest
8 J<18 J<25 J<36 J8\text{ J} < 18\text{ J} < 25\text{ J} < 36\text{ J}
Satisfies the stem requirement to arrange from lowest to highest kinetic energy.

Key Concept

Kinetic Energy Calculation (KE=12mv2KE = \frac{1}{2}mv^2)
Estimated Time:1m 0s
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