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Difficulty: EasyResistors and Potentiometers

A four-band carbon resistor displays the color bands Orange, Orange, Brown, and Gold in sequence from left to right. What is the nominal resistance value of this component?

  1. A
    331 Ω331\ \Omega
  2. B
    33 Ω33\ \Omega
  3. 330 Ω330\ \OmegaAnswer
  4. D
    3.3 kΩ3.3\text{ k}\Omega

Answer

330 Ω330\ \Omega
The first band (Orange) represents the digit 3, the second band (Orange) represents the digit 3, and the third band (Brown) represents a multiplier of 10110^1 (10). Multiplying the significant digits by the multiplier yields 33×10=330 Ω33 \times 10 = 330\ \Omega.

Step-by-Step Solution

1
Decode the first two significant color bands.
Orange corresponds to 3, and the second Orange corresponds to 3, giving the two-digit number 33.
In a 4-band resistor code, the first two bands represent the base significant digits.
2
Determine the multiplier from the third color band.
Brown corresponds to a multiplier of 10110^1 (or 1010).
The third band indicates the power of ten by which the significant digits are multiplied.
3
Multiply the significant digits by the multiplier value.
33×10=330 Ω33 \times 10 = 330\ \Omega.
Combining the base digits and multiplier gives the nominal resistance rating.

Key Concept

Four-Band Resistor Color Code Decoding
Estimated Time:35s
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Topics

Resistors and Potentiometers

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