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Question 481Question →

An airport authority is installing a security barrier around a new rectangular radar facility. The facility measures 4040 yards in length and 3232 yards in width. The design for the security barrier requires a heavy-duty steel post at each of the four corners, with additional posts placed exactly every 88 feet along all four sides. How many steel posts are required in total to enclose the facility?

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Answer: 54

Answer

54 posts are required in total.
The correct answer is found by first ensuring all units match. Converting the dimensions to feet gives a length of 120 feet and a width of 96 feet. The total perimeter is 432 feet. Dividing this continuous perimeter by the 8-foot spacing requirement yields exactly 54 posts.

Step-by-Step Solution

1
Convert the given dimensions from yards to feet.
Length = 40 * 3 = 120 feet. Width = 32 * 3 = 96 feet.
The post spacing is provided in feet, so all measurements must be converted to the same unit before calculating the perimeter.
2
Calculate the total perimeter of the rectangular facility.
Perimeter = 2 * (120 + 96) = 2 * 216 = 432 feet.
The security barrier encloses the entire outer boundary of the facility, which corresponds to its perimeter.
3
Determine the total number of posts required.
Total posts = 432 / 8 = 54.
For any closed loop, the total number of equally spaced posts equals the total perimeter divided by the distance between the posts.

Key Concept

Calculating perimeter of a rectangle, unit conversions, and dividing a perimeter into equal segments.
Question 482Question →
What value of mm makes the equation 12m−7=41 12m - 7 = 41 true?
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Answer: 4

Answer

4
Applying the correct sequence of inverse operations (first adding 7, then dividing by 12) yields exactly 4.

Step-by-Step Solution

1
Add 7 to both sides of the equation.
12m=48 12m = 48
This is the first inverse operation needed to isolate the variable term.
2
Divide both sides by 12.
m=4 m = 4
This inverse operation isolates mm, giving the final solution.

Key Concept

Solving two-step linear equations using inverse operations
Estimated Time:30s
Question 483Question →

A rectangular microchip has a length of 8.0×10−38.0 \times 10^{-3} meters and a width of 4.5×10−34.5 \times 10^{-3} meters. Calculate the area of the microchip in square meters and express the result in proper scientific notation as a×10na \times 10^n (where 1≤a<101 \le a < 10). What is the value of the coefficient aa?

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Answer: 3.6

Answer

The coefficient aa is 3.6.
The correct answer is derived by multiplying the coefficients (8.0 × 4.5 = 36), adding the exponents (-3 + -3 = -6), and normalizing the preliminary result of 36 × 10^-6 by moving the decimal left by one place. This creates a proper coefficient of 3.6 and changes the exponent to -5.

Step-by-Step Solution

1
Set up the multiplication for area
Area = (8.0×10−3)×(4.5×10−3)(8.0 \times 10^{-3}) \times (4.5 \times 10^{-3})
The area of a rectangle is found by multiplying its length by its width.
2
Multiply the coefficients
8.0×4.5=368.0 \times 4.5 = 36
When multiplying terms in scientific notation, the numerical coefficients are multiplied together.
3
Multiply the powers of 10
10−3×10−3=10−610^{-3} \times 10^{-3} = 10^{-6}
When multiplying identical bases, their exponents are added: −3+(−3)=−6-3 + (-3) = -6.
4
Combine into preliminary result
36×10−636 \times 10^{-6}
Bring the multiplied coefficient and combined power of 10 together.
5
Normalize to proper scientific notation
3.6×10−53.6 \times 10^{-5}
Proper scientific notation requires the coefficient aa to satisfy 1≤a<101 \le a < 10. Moving the decimal one place left on 36 increases the exponent by 1 (−6+1=−5-6 + 1 = -5).
6
Extract the coefficient aa
3.6
The question specifically asks for the value of the coefficient aa in the final a×10na \times 10^n format.

Key Concept

Multiplying and Normalizing Values in Scientific Notation
Question 484Question →

The expression (2y−7)2(2y - 7)^2 is expanded into the standard polynomial form ay2+by+cay^2 + by + c. What is the value of the coefficient bb?

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Answer: -28

Answer

-28
Expanding the perfect square binomial (2y−7)2(2y - 7)^2 requires multiplying (2y−7)(2y - 7) by itself. Using the distributive property, the outer product is (2y)(−7)=−14y(2y)(-7) = -14y and the inner product is (−7)(2y)=−14y(-7)(2y) = -14y. Combining these like terms gives a total middle term of −28y-28y. Because the required polynomial form is ay2+by+cay^2 + by + c, the value of the coefficient bb is exactly -28.

Step-by-Step Solution

1
Rewrite the expression as a product of two binomials.
(2y−7)(2y−7)(2y - 7)(2y - 7)
Writing the binomial twice makes it easier to correctly apply the distributive property (FOIL method) and avoid missing the middle terms.
2
Distribute the terms.
4y2−14y−14y+494y^2 - 14y - 14y + 49
Multiplying the First terms, Outer terms, Inner terms, and Last terms ensures that every term in the first binomial is multiplied by every term in the second binomial.
3
Combine the like terms.
4y2−28y+494y^2 - 28y + 49
The middle terms, −14y-14y and −14y-14y, have the same variable raised to the same power, so their coefficients can be added together.
4
Identify the target coefficient.
−28-28
The standard polynomial form is given as ay2+by+cay^2 + by + c. The value of bb corresponds to the coefficient of the yy term.

Key Concept

Expanding Perfect Square Binomials
Question 485Question →

A plumber has a copper pipe that is 14.514.5 inches long. She cuts off a piece that is 3.753.75 inches long. What is the length of the remaining pipe in inches?

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Answer: 10.75

Answer

10.75
Subtracting the cut piece (3.753.75 inches) from the total length (14.514.5 inches) gives the remaining length. Aligning the decimals properly as 14.50−3.7514.50 - 3.75 results in exactly 10.7510.75.

Step-by-Step Solution

1
Identify the operation needed
Subtraction: 14.5−3.7514.5 - 3.75
Cutting a piece off means reducing the total length of the pipe.
2
Align the decimals for subtraction
14.50−3.7514.50 - 3.75
To subtract decimals correctly, align the place values by lining up the decimal points. Add a placeholder zero to 14.514.5 to make it 14.5014.50.
3
Perform the subtraction
10.7510.75
Subtracting 3.753.75 from 14.5014.50 yields 10.7510.75.

Key Concept

Decimal Subtraction and Alignment
Estimated Time:45s
Question 486Question →

Given the expression 7x−2y27x - 2y^2, what is its numerical value when x=5x = 5 and y=3y = 3?

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Answer: 17

Answer

17
The expression evaluates to 17 by successfully substituting the values into the variables and properly applying the order of operations.

Step-by-Step Solution

1
Substitute the values x=5x = 5 and y=3y = 3 into the algebraic expression.
7(5)−2(3)27(5) - 2(3)^2
Variables must be replaced with their numerical values before evaluating.
2
Calculate the exponent.
7(5)−2(9)7(5) - 2(9)
According to the order of operations (PEMDAS), exponents must be evaluated before multiplication.
3
Perform the multiplication operations.
35−1835 - 18
Multiplication is evaluated before subtraction.
4
Subtract the resulting numbers.
17
This final arithmetic step yields the evaluated expression.

Key Concept

Evaluating Algebraic Expressions
Question 487Question →

An industrial bakery has a large container holding 103810\frac{3}{8} gallons of vegetable oil. On Monday morning, a baker uses 3123\frac{1}{2} gallons for a batch of muffins. In the afternoon, they use an additional 2342\frac{3}{4} gallons for bread dough. How many gallons of vegetable oil remain in the container? (Enter your answer as a decimal.)

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Answer: 4.125

Answer

4.125
Converting all fractions to a common denominator of 8 yields 103810\frac{3}{8} total, 3483\frac{4}{8} used first, and 2682\frac{6}{8} used second. Total used is 6286\frac{2}{8}. Subtracting this from 103810\frac{3}{8} leaves 4184\frac{1}{8}. Converting 18\frac{1}{8} to a decimal yields 0.125, making the final answer 4.125.

Step-by-Step Solution

1
Find a common denominator for all the fractions involved.
The common denominator for 8, 2, and 4 is 8.
Fractions must have the same denominator before they can be added or subtracted.
2
Convert the amounts of oil used into mixed numbers with the common denominator of 8.
312=3483\frac{1}{2} = 3\frac{4}{8} and 234=2682\frac{3}{4} = 2\frac{6}{8}.
This prepares the values for addition.
3
Add the amounts used together to find the total amount of oil removed.
348+268=5108=6283\frac{4}{8} + 2\frac{6}{8} = 5\frac{10}{8} = 6\frac{2}{8}
We must consolidate the used portions before subtracting from the total.
4
Subtract the total oil used from the original amount in the container.
1038−628=41810\frac{3}{8} - 6\frac{2}{8} = 4\frac{1}{8}
Subtracting the total used gives the remaining oil.
5
Convert the final mixed number to a decimal format.
418=4+(1÷8)=4.1254\frac{1}{8} = 4 + (1 \div 8) = 4.125
The question explicitly requires the answer to be entered as a decimal.

Key Concept

Adding and subtracting mixed numbers with unlike denominators
Question 488Question →

Calculate the precise value of kk that makes the following algebraic equation true:

5(2k−3)=3k+13 5(2k - 3) = 3k + 13
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Answer: 4

Answer

4
The correct value is found by distributing the 5, gathering all variable terms on one side and constants on the other, and finally dividing by the variable's coefficient.

Step-by-Step Solution

1
Apply the distributive property on the left side of the equation.
10k−15=3k+1310k - 15 = 3k + 13
To eliminate the parentheses and expose the variable terms for grouping.
2
Subtract 3k3k from both sides.
7k−15=137k - 15 = 13
To collect all terms containing the variable kk on one side of the equation.
3
Add 1515 to both sides.
7k=287k = 28
To isolate the variable term by moving constants to the opposite side.
4
Divide both sides by 77.
k=4k = 4
To solve for the final value of kk.

Key Concept

Solving linear equations with variables on both sides using the distributive property.
Question 489Question →

Given x=−4x = -4 and y=3y = 3, what is the exact value of the expression 3∣x−y∣−∣y2−x2∣3|x - y| - |y^2 - x^2|?

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Answer: 14

Answer

14
By correctly substituting the variables, following the order of operations, and applying the definition of absolute value, the expression simplifies to 3(7)−73(7) - 7, which evaluates precisely to 1414.

Step-by-Step Solution

1
Substitute the given values for xx and yy into the expression.
3∣−4−3∣−∣(3)2−(−4)2∣3|-4 - 3| - |(3)^2 - (-4)^2|
Variable substitution is the first step in evaluating an algebraic expression.
2
Simplify the expression inside the first absolute value bars.
∣−4−3∣=∣−7∣|-4 - 3| = |-7|
Absolute value bars act as grouping symbols, so operations inside them must be performed first.
3
Evaluate the exponents inside the second absolute value bars.
∣(3)2−(−4)2∣=∣9−16∣|(3)^2 - (-4)^2| = |9 - 16|
Following the order of operations, exponents are evaluated before subtraction.
4
Simplify the expression inside the second absolute value bars.
∣9−16∣=∣−7∣|9 - 16| = |-7|
Complete the subtraction inside the grouping symbols.
5
Apply the absolute value function to both simplified terms.
3(7)−73(7) - 7
The absolute value of any non-zero real number is its positive counterpart: ∣−7∣=7|-7| = 7.
6
Perform the final multiplication and subtraction.
21−7=1421 - 7 = 14
Multiplication is performed before subtraction according to the standard order of operations.

Key Concept

Evaluating algebraic expressions involving absolute value, exponents, and signed numbers.
Estimated Time:1m 30s
Question 490Question →

A hiker plans to complete a trail that is 153415\frac{3}{4} miles long. If she hikes at a consistent average speed of 3123\frac{1}{2} miles per hour, how many hours will it take her to complete the entire trail?

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Answer: 4.5

Answer

4.5
The correct answer is found by converting the total distance (153415\frac{3}{4}) and the speed (3123\frac{1}{2}) into improper fractions (634\frac{63}{4} and 72\frac{7}{2}), and then dividing the distance by the speed. This translates to 634×27\frac{63}{4} \times \frac{2}{7}, which cross-simplifies perfectly to 92\frac{9}{2} or 4.54.5 hours.

Step-by-Step Solution

1
Convert the mixed numbers into improper fractions.
1534=63415\frac{3}{4} = \frac{63}{4} and 312=723\frac{1}{2} = \frac{7}{2}
Fraction arithmetic requires mixed numbers to be in improper fraction form before dividing.
2
Set up the division equation to solve for time.
Time = 634÷72\frac{63}{4} \div \frac{7}{2}
Time is calculated by dividing total distance by the average speed.
3
Change the division to multiplication by using the reciprocal of the divisor.
634×27\frac{63}{4} \times \frac{2}{7}
Dividing by a fraction is mathematically equivalent to multiplying by its reciprocal.
4
Multiply the fractions and simplify the result.
63×24×7=12628=92=4.5\frac{63 \times 2}{4 \times 7} = \frac{126}{28} = \frac{9}{2} = 4.5
Simplifying the fraction yields the exact number of hours.

Key Concept

Dividing mixed numbers by converting to improper fractions and multiplying by the reciprocal.
Estimated Time:1m 0s
Question 491Question →

When the algebraic expression (4x−3)(2x2+5x−1)(4x - 3)(2x^2 + 5x - 1) is fully expanded and simplified into standard polynomial form, what is the value of the coefficient of the xx term?

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Answer: -19

Answer

-19
The correct answer is −19-19 because the xx term is exclusively formed by the sum of the products (4x)(−1)(4x)(-1) and (−3)(5x)(-3)(5x), which equals −4x−15x=−19x-4x - 15x = -19x.

Step-by-Step Solution

1
Identify the goal.
We need to find the coefficient of the xx term in the product of (4x−3)(4x - 3) and (2x2+5x−1)(2x^2 + 5x - 1).
Focusing only on the terms that produce an xx term saves time compared to expanding the entire polynomial expression.
2
Find the first partial product that results in an xx term.
Multiply the xx term from the binomial (4x4x) by the constant term from the trinomial (−1-1) to get −4x-4x.
An xx term multiplied by a constant results in an xx term.
3
Find the second partial product that results in an xx term.
Multiply the constant term from the binomial (−3-3) by the xx term from the trinomial (5x5x) to get −15x-15x.
A constant multiplied by an xx term results in an xx term.
4
Combine the partial products.
−4x+(−15x)=−19x-4x + (-15x) = -19x
To find the total xx term in the expanded polynomial, all like terms must be combined.
5
Identify the final coefficient.
The coefficient of −19x-19x is −19-19.
The coefficient is the numerical multiplier of the variable.

Key Concept

Multiplying Polynomials and Combining Like Terms
Question 492Question →

A pottery studio has a storage bin containing 151415\frac{1}{4} pounds of dry clay. An instructor removes 4584\frac{5}{8} pounds of the clay for a beginner class and another 3123\frac{1}{2} pounds for an advanced class. Later that day, a new shipment arrives, and 5785\frac{7}{8} pounds of clay are added to the bin. How many pounds of clay are in the bin now?

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Answer: 13

Answer

13
The correct answer is found by establishing a common denominator for all fractions, correctly borrowing a whole number to subtract the first amount of clay, subtracting the second amount, and then adding the final shipment to yield exactly 13 pounds.

Step-by-Step Solution

1
Find a common denominator for all fractions.
1514=152815\frac{1}{4} = 15\frac{2}{8} and 312=3483\frac{1}{2} = 3\frac{4}{8}.
Fractions must have the same denominator before they can be added or subtracted.
2
Subtract the amount of clay used for the beginner class from the total.
1528−458=14108−458=105815\frac{2}{8} - 4\frac{5}{8} = 14\frac{10}{8} - 4\frac{5}{8} = 10\frac{5}{8} pounds.
Since 28\frac{2}{8} is smaller than 58\frac{5}{8}, we borrow 1 from 15 to properly execute the subtraction.
3
Subtract the amount of clay used for the advanced class from the new total.
1058−348=71810\frac{5}{8} - 3\frac{4}{8} = 7\frac{1}{8} pounds.
This accounts for the second removal of clay.
4
Add the newly shipped clay to the remaining amount.
718+578=12887\frac{1}{8} + 5\frac{7}{8} = 12\frac{8}{8} pounds.
The new shipment increases the total inventory.
5
Simplify the final mixed number.
1313 pounds.
88\frac{8}{8} is equal to 1 whole, so 12+1=1312 + 1 = 13.

Key Concept

Addition and subtraction of mixed numbers with unlike denominators, requiring whole-number borrowing.
Estimated Time:1m 15s
Question 493Question →

When the expression (3x−4)(2x+5)−x(x−2)(3x - 4)(2x + 5) - x(x - 2) is fully expanded and simplified into standard polynomial form, what is the value of the coefficient of xx?

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Answer: 9

Answer

9
Expanding the binomials gives 6x2+7x−206x^2 + 7x - 20. Distributing −x-x gives −x2+2x-x^2 + 2x. Combining like terms results in 5x2+9x−205x^2 + 9x - 20. The question asks for the coefficient of xx, which is the number multiplying the xx term: 9.

Step-by-Step Solution

1
Multiply the binomials (3x−4)(3x - 4) and (2x+5)(2x + 5).
6x2+15x−8x−206x^2 + 15x - 8x - 20, which simplifies to 6x2+7x−206x^2 + 7x - 20.
To expand the first part of the expression using the distributive property (FOIL).
2
Distribute −x-x across the binomial (x−2)(x - 2).
−x2+2x-x^2 + 2x.
To expand the second part of the expression, ensuring the negative sign is applied to both terms inside the parentheses.
3
Combine the expanded parts.
(6x2+7x−20)+(−x2+2x)=5x2+9x−20(6x^2 + 7x - 20) + (-x^2 + 2x) = 5x^2 + 9x - 20.
To simplify the full expression into standard polynomial form by grouping like terms.
4
Identify the coefficient of xx.
The coefficient of xx in 5x2+9x−205x^2 + 9x - 20 is 99.
This answers the specific question asked.

Key Concept

Multiplying polynomials and combining like terms
Question 494Question →

A machinist needs to drill a hole completely through a steel block that is 3343\frac{3}{4} inches thick. The drill bit advances through the steel at a constant rate of 316\frac{3}{16} of an inch per second. How many seconds will it take to drill completely through the block?

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Answer: 20

Answer

It will take 20 seconds to drill completely through the block.
To find the time required, the total thickness of the block must be divided by the distance the drill advances per second. Converting 3343\frac{3}{4} to 154\frac{15}{4} and dividing by 316\frac{3}{16} is calculated by multiplying by the reciprocal: 154×163=20\frac{15}{4} \times \frac{16}{3} = 20.

Step-by-Step Solution

1
Convert the mixed number to an improper fraction.
334=1543\frac{3}{4} = \frac{15}{4}
Fraction multiplication and division are performed using improper fractions rather than mixed numbers.
2
Set up the division equation to solve for time.
Time = Distance ÷\div Rate = 154÷316\frac{15}{4} \div \frac{3}{16}
The time required is equal to the total distance (thickness) divided by the rate of progress.
3
Rewrite the division problem as multiplication by the reciprocal.
154×163\frac{15}{4} \times \frac{16}{3}
Dividing by a fraction is mathematically equivalent to multiplying by its reciprocal.
4
Simplify the fractions by cross-canceling, then multiply.
5×4=205 \times 4 = 20
Cross-canceling common factors (15 and 3, 16 and 4) before multiplying makes the final calculation simpler.

Key Concept

Fraction Division and Applied Rates
Estimated Time:50s
Question 495Question →

Given the values x=12x = \frac{1}{2}, y=−4y = -4, and z=−2z = -2, determine the value of the expression 4x2y−yz34x^2y - yz^3.

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Answer: -36

Answer

-36
The correct answer is derived by substituting the variables accurately, applying the exponents (especially noting that a negative base to an odd power remains negative), and strictly following the order of operations to multiply and then subtract.

Step-by-Step Solution

1
Substitute x=12x = \frac{1}{2}, y=−4y = -4, and z=−2z = -2 into the expression.
4(12)2(−4)−(−4)(−2)34(\frac{1}{2})^2(-4) - (-4)(-2)^3
Variable substitution must be done exactly as given to prepare for evaluation.
2
Evaluate the terms with exponents.
(12)2=14(\frac{1}{2})^2 = \frac{1}{4} and (−2)3=−8(-2)^3 = -8. The expression becomes 4(14)(−4)−(−4)(−8)4(\frac{1}{4})(-4) - (-4)(-8).
According to the order of operations (PEMDAS), exponents must be resolved before multiplication.
3
Perform the multiplication operations from left to right.
4(14)(−4)=1(−4)=−44(\frac{1}{4})(-4) = 1(-4) = -4 and (−4)(−8)=32(-4)(-8) = 32. The expression is now −4−32-4 - 32.
Multiplication is the next step in the order of operations. Note that multiplying two negative numbers results in a positive product.
4
Perform the final subtraction.
−4−32=−36-4 - 32 = -36
Subtracting a positive number from a negative number moves further left on the number line.

Key Concept

Evaluating algebraic expressions using rational numbers, negative bases, and the correct order of operations.
Estimated Time:1m 0s
Question 496Question →

If the polynomial expression (3x−5)(3x - 5) is multiplied by the expression (Ax2+2x−7)(Ax^2 + 2x - 7), the resulting simplified polynomial has an x2x^2 coefficient of −19-19. What is the value of the constant AA?

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Answer: 5

Answer

5
The x2x^2 terms in the product of (3x−5)(3x - 5) and (Ax2+2x−7)(Ax^2 + 2x - 7) are generated by multiplying the xx terms together (3x⋅2x=6x2)(3x \cdot 2x = 6x^2) and by multiplying the constant by the x2x^2 term (−5⋅Ax2=−5Ax2)(-5 \cdot Ax^2 = -5Ax^2). Setting their sum equal to −19x2-19x^2 gives the equation 6−5A=−196 - 5A = -19. Solving for AA yields A=5A = 5.

Step-by-Step Solution

1
Identify combinations that yield an x2x^2 term
The x2x^2 terms come from multiplying (3x)(3x) by (2x)(2x) and (−5)(-5) by (Ax2)(Ax^2).
To find the coefficient of a specific term without expanding the entire polynomial, only multiply the terms whose exponents sum to the target power.
2
Calculate the partial products
(3x)(2x)=6x2(3x)(2x) = 6x^2 and (−5)(Ax2)=−5Ax2(-5)(Ax^2) = -5Ax^2
These represent the only contributions to the x2x^2 term in the final expanded polynomial.
3
Formulate an equation for the coefficient
6−5A=−196 - 5A = -19
The sum of the partial x2x^2 coefficients must equal the total x2x^2 coefficient given in the problem.
4
Solve the linear equation for AA
−5A=−25→A=5-5A = -25 \rightarrow A = 5
Isolating the variable AA provides the final answer.

Key Concept

Multiplying Polynomials
Question 497Question →

A military field generator consumes diesel fuel at a rate of 3.253.25 gallons per hour. The generator's fuel tank initially contains 50.450.4 gallons of fuel. If the generator runs continuously for 8.48.4 hours, how many gallons of fuel remain in the tank?

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Answer: 23.1

Answer

23.1
To find the remaining fuel, you first need to determine the total amount used. Multiplying the hourly rate of 3.253.25 gallons by 8.48.4 hours gives 27.327.3 gallons consumed. Subtracting this from the initial 50.450.4 gallons (50.4−27.350.4 - 27.3) leaves exactly 23.123.1 gallons.

Step-by-Step Solution

1
Calculate the total amount of fuel consumed by the generator during the run time.
3.25×8.4=27.33.25 \times 8.4 = 27.3 gallons
The total fuel consumed is found by multiplying the hourly consumption rate by the total number of hours the generator operates.
2
Calculate the remaining fuel by subtracting the consumed fuel from the initial amount.
50.4−27.3=23.150.4 - 27.3 = 23.1 gallons
The fuel left in the tank is the difference between the starting volume and the volume that was burned.

Key Concept

Solving multi-step practical arithmetic problems involving decimal multiplication and decimal subtraction.
Estimated Time:1m 0s
Question 498Question →

An industrial pump dispenses 3.453.45 liters of a chemical per cycle. A tank initially contains 150.8150.8 liters of the chemical. If the pump runs for 1414 cycles to remove the chemical from the tank, and then a technician manually adds 5.255.25 liters back into the tank, how many liters of chemical remain in the tank?

Show answer & explanation

Answer: 107.75

Answer

107.75
The final volume is accurately found by multiplying the removal rate by the number of cycles to determine the total removed amount, subtracting that from the initial volume, and finally adding the manually returned amount while maintaining proper decimal alignment.

Step-by-Step Solution

1
Calculate the total volume of chemical removed by the pump.
14×3.45=48.314 \times 3.45 = 48.3
The pump runs for 14 cycles, removing 3.45 liters each time, so multiplication is required to find the total removal.
2
Subtract the removed volume from the initial tank volume.
150.8−48.3=102.5150.8 - 48.3 = 102.5
Removing the chemical decreases the total volume available in the tank.
3
Add the volume of the chemical manually poured back into the tank.
102.5+5.25=107.75102.5 + 5.25 = 107.75
Adding chemical increases the total volume to its final amount.

Key Concept

Solving multi-step practical problems involving the multiplication, subtraction, and addition of decimals.
Estimated Time:1m 0s
Question 499Question →

A sample of mineral oil has a density of 0.8 g/cm30.8\text{ g/cm}^3 and a volume of 50 cm350\text{ cm}^3. What is the mass of the oil sample in grams?

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Answer: 40

Answer

40 g
The mass of a substance is determined by multiplying its density by its volume: Mass=Density×Volume=0.8 g/cm3×50 cm3=40 g\text{Mass} = \text{Density} \times \text{Volume} = 0.8\text{ g/cm}^3 \times 50\text{ cm}^3 = 40\text{ g}.

Step-by-Step Solution

1
State the formula for calculating mass from density and volume
Mass=Density×Volume\text{Mass} = \text{Density} \times \text{Volume}
Density represents mass per unit volume (Density=MassVolume\text{Density} = \frac{\text{Mass}}{\text{Volume}}); rearranging this relationship isolates mass.
2
Substitute the given values into the equation and compute the result
Mass=0.8 g/cm3×50 cm3=40 g\text{Mass} = 0.8\text{ g/cm}^3 \times 50\text{ cm}^3 = 40\text{ g}
Multiplying the density (0.8 g/cm30.8\text{ g/cm}^3) by the total volume (50 cm350\text{ cm}^3) yields the total mass in grams.

Key Concept

The relationship between mass, volume, and density as physical properties of matter
Estimated Time:45s
Question 500Question →

A 12 V12\text{ V} direct-current car battery is connected to a circuit powering a single headlight with a resistance of 4 Ω4\,\Omega. What is the electric current, in amperes, flowing through the headlight?

Show answer & explanation

Answer: 3

Answer

The electric current flowing through the headlight is 3 amperes.
According to Ohm's law, electric current (II) equals voltage (VV) divided by resistance (RR). Dividing a voltage of 12 V12\text{ V} by a resistance of 4 Ω4\,\Omega yields an electric current of 3 A3\text{ A}.

Step-by-Step Solution

1
Identify the relationship between voltage, current, and resistance using Ohm's law.
V=I×RV = I \times R, which rearranges to I=VRI = \frac{V}{R}.
Ohm's law governs the relationship between electric potential difference, current flow, and resistance in a DC circuit.
2
Substitute the given values into the formula and solve for current.
I=12 V4 Ω=3 AI = \frac{12\text{ V}}{4\,\Omega} = 3\text{ A}
Dividing the electromotive force (voltage) by the total circuit resistance yields the resulting electric current.

Key Concept

Ohm's Law (V=IRV = IR)
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