Number Theory and Operations

159 questions

Question 121Question →

Calculate the value of each decimal expression below. Arrange the results in ascending order (from smallest to largest).

Drag items to arrange them in the correct order

Show answer & explanation

Answer

The correct order from smallest to largest is: 1.5×21.5 \times 2, followed by 1.2+2.41.2 + 2.4, then 8.4÷28.4 \div 2, and finally 5.8−1.35.8 - 1.3.
Evaluating each mathematical expression individually yields 4.5, 3.6, 4.2, and 3.0 respectively. Arranging these numerical results in ascending order gives 3.0, 3.6, 4.2, and 4.5. This directly maps to the expressions: 1.5×21.5 \times 2, then 1.2+2.41.2 + 2.4, then 8.4÷28.4 \div 2, and finally 5.8−1.35.8 - 1.3.

Step-by-Step Solution

1
Calculate the value of the first expression.
5.8−1.3=4.55.8 - 1.3 = 4.5
To determine the numerical value for comparison.
2
Calculate the value of the second expression.
1.2+2.4=3.61.2 + 2.4 = 3.6
To determine the numerical value for comparison.
3
Calculate the value of the third expression.
8.4÷2=4.28.4 \div 2 = 4.2
To determine the numerical value for comparison.
4
Calculate the value of the fourth expression.
1.5×2=3.01.5 \times 2 = 3.0
To determine the numerical value for comparison.
5
Compare the four calculated values and order them from smallest to largest.
3.0<3.6<4.2<4.53.0 < 3.6 < 4.2 < 4.5
To establish the final ascending sequence required by the question.

Key Concept

Performing basic operations (addition, subtraction, multiplication, division) with decimals and comparing their magnitudes.
Estimated Time:45s
Question 122Question →

A sporting goods store stocks basketballs and footballs in a ratio of 3:43:4. After receiving a new shipment of 1010 additional basketballs, the ratio of basketballs to footballs changes to 5:65:6. How many footballs are currently in stock?

Show answer & explanation

Answer: 120

Answer

There are 120 footballs currently in stock.
By scaling the initial ratio (3:43:4) to 9:129:12 and the new ratio (5:65:6) to 10:1210:12, we can see that the 1010 added basketballs represent exactly 11 part (10−9=110 - 9 = 1). Since the footballs represent 1212 parts in this scaled system, there are 12×10=12012 \times 10 = 120 footballs in stock.

Step-by-Step Solution

1
Identify the quantity that remains unchanged.
The number of footballs does not change when the new shipment of basketballs arrives.
This provides an anchor point to compare the before and after ratios.
2
Find a common multiple for the football ratio parts.
The initial ratio has 44 parts for footballs and the new ratio has 66 parts. The least common multiple (LCM) of 44 and 66 is 1212.
Creating a common denominator for the unchanging item allows direct comparison of the changed item's parts.
3
Scale both ratios so the football parts equal 1212.
Initial ratio: Multiply 3:43:4 by 33 to get 9:129:12. New ratio: Multiply 5:65:6 by 22 to get 10:1210:12.
This standardizes the 'size' of one part across both ratios.
4
Determine the change in basketball parts.
The scaled basketball parts increased from 99 to 1010, a difference of exactly 11 part.
This 11-part increase corresponds directly to the physical items added.
5
Calculate the actual number of footballs.
Since 11 part equals the 1010 basketballs added, the 1212 parts for footballs equal 12×10=12012 \times 10 = 120 footballs.
This yields the final answer by multiplying the scaled parts by the unit value.

Key Concept

Scaling Ratios and Proportions

Alternative Method

Using algebra, let the initial basketballs be 3x3x and footballs be 4x4x. After adding 1010 basketballs, the new ratio yields the equation 3x+104x=56\frac{3x + 10}{4x} = \frac{5}{6}. Cross-multiplying gives 6(3x+10)=5(4x)6(3x + 10) = 5(4x), which simplifies to 18x+60=20x18x + 60 = 20x. Solving for xx gives 2x=602x = 60, so x=30x = 30. The number of footballs is 4x=4(30)=1204x = 4(30) = 120.
Estimated Time:1m 0s
Question 123Question →

A supply convoy is distributing medical kits and rations to various outposts in a ratio of 2:72:7. If a particular outpost receives 5656 rations, how many medical kits should they receive?

Show answer & explanation

Answer: 16; 16 kits; 16 medical kits; sixteen

Answer

16
The correct amount is found by maintaining the ratio of 22 medical kits for every 77 rations. Since 5656 is 88 times as large as 77 (56÷7=856 \div 7 = 8), the number of medical kits must also be 88 times as large as 22. Multiplying the kit ratio component (22) by this scale factor (88) gives 1616 medical kits.

Step-by-Step Solution

1
Identify the given ratio and the known quantity.
Ratio of medical kits to rations is 2:72:7. The known quantity is 5656 rations.
Extracting the correct values and their relationship is required to set up the proportion.
2
Set up a proportion.
27=x56\frac{2}{7} = \frac{x}{56}
The ratio of kits to rations (2/72/7) must equal the ratio of actual kits (xx) to actual rations (5656).
3
Solve for the unknown value xx.
x=2×567=16x = \frac{2 \times 56}{7} = 16
Multiplying both sides by 5656 isolates xx, revealing the required number of medical kits.

Key Concept

Solving direct proportions using a scale factor or cross-multiplication

Alternative Method

Find the scale factor by dividing the actual number of rations by the ratio number for rations: 56÷7=856 \div 7 = 8. Then multiply the ratio number for medical kits by this scale factor: 2×8=162 \times 8 = 16.
Estimated Time:45s
Question 124Question →

A communications technician is configuring signal transponders. The synchronization cycle for each transponder is determined by the Least Common Multiple (LCM) of its two input frequencies (measured in Hz). Arrange the following pairs of input frequencies in ascending order based on their resulting synchronization cycle (smallest LCM to largest LCM).

Drag items to arrange them in the correct order

Show answer & explanation

Answer

The correct order from smallest to largest LCM is: 12 Hz and 18 Hz (LCM=36), 16 Hz and 24 Hz (LCM=48), 10 Hz and 25 Hz (LCM=50), 8 Hz and 14 Hz (LCM=56), followed by 15 Hz and 20 Hz (LCM=60).
The correct sequence is determined by finding the LCM of each frequency pair and listing them in ascending order. The calculated LCMs are 36, 48, 50, 56, and 60 respectively.

Step-by-Step Solution

1
Calculate the Least Common Multiple (LCM) for the first pair, 12 Hz12\text{ Hz} and 18 Hz18\text{ Hz}.
The LCM of 1212 and 1818 is 3636.
The multiples of 1818 are 18,36,5418, 36, 54. Since 3636 is divisible by 1212 (12×3=3612 \times 3 = 36), it is the lowest common multiple.
2
Calculate the LCM for 16 Hz16\text{ Hz} and 24 Hz24\text{ Hz}.
The LCM of 1616 and 2424 is 4848.
The multiples of 2424 are 24,4824, 48. Since 4848 is divisible by 1616 (16×3=4816 \times 3 = 48), it is the lowest common multiple.
3
Calculate the LCM for 10 Hz10\text{ Hz} and 25 Hz25\text{ Hz}.
The LCM of 1010 and 2525 is 5050.
The multiples of 2525 are 25,5025, 50. Since 5050 is divisible by 1010 (10×5=5010 \times 5 = 50), it is the lowest common multiple.
4
Calculate the LCM for 8 Hz8\text{ Hz} and 14 Hz14\text{ Hz}.
The LCM of 88 and 1414 is 5656.
Using prime factorizations: 8=238 = 2^3 and 14=2×714 = 2 \times 7. The LCM takes the highest powers: 23×7=8×7=562^3 \times 7 = 8 \times 7 = 56.
5
Calculate the LCM for 15 Hz15\text{ Hz} and 20 Hz20\text{ Hz}.
The LCM of 1515 and 2020 is 6060.
Using prime factorizations: 15=3×515 = 3 \times 5 and 20=22×520 = 2^2 \times 5. The LCM takes the highest powers: 22×3×5=602^2 \times 3 \times 5 = 60.
6
Arrange the pairs in ascending order based on their calculated LCMs.
36<48<50<56<6036 < 48 < 50 < 56 < 60
The stem requires ordering the frequencies from the smallest resulting synchronization cycle (smallest LCM) to the largest.

Key Concept

Calculating the Least Common Multiple (LCM) to synchronize multiple periodic events.
Question 125Question →

An experimental particle travels a distance of 4.5×1054.5 \times 10^5 meters in 5.0×10−35.0 \times 10^{-3} seconds. What is the average speed of the particle in meters per second, expressed in proper scientific notation?

Show answer & explanation

Answer: 9.0×1079.0 \times 10^7

Answer

The correct speed is 9.0×1079.0 \times 10^7 meters per second.
To divide numbers in scientific notation, divide the coefficients and subtract the exponents. Dividing 4.54.5 by 5.05.0 yields 0.90.9. Subtracting the exponent −3-3 from 55 yields 88 (since 5−(−3)=5+3=85 - (-3) = 5 + 3 = 8). This gives an intermediate result of 0.9×1080.9 \times 10^8. To convert this into proper scientific notation, the coefficient must be between 11 and 1010. Moving the decimal point one place to the right converts 0.90.9 to 9.09.0, which requires decreasing the exponent by 11, resulting in the final correct answer of 9.0×1079.0 \times 10^7.

Step-by-Step Solution

1
Divide the coefficients given in the problem: 4.5÷5.04.5 \div 5.0.
0.90.9
When dividing numbers in scientific notation, the coefficients are divided separately from the powers of 10.
2
Divide the powers of 10 by subtracting the denominator's exponent from the numerator's exponent: 105÷10−310^5 \div 10^{-3}.
105−(−3)=10810^{5 - (-3)} = 10^8
According to the laws of exponents, division of like bases requires subtracting the exponent of the divisor from the exponent of the dividend.
3
Combine the newly calculated coefficient and power of 10.
0.9×1080.9 \times 10^8
This represents the mathematical result before applying proper formatting rules.
4
Normalize the answer by moving the decimal point one place to the right to make the coefficient between 1 and 10, and subtract 1 from the exponent to balance the shift.
9.0×1079.0 \times 10^7
Proper scientific notation requires the coefficient to be greater than or equal to 1 and less than 10.

Key Concept

Scientific Notation Division and Normalization
Question 126Question →

A logistics coordinator is packing identical emergency relief kits. They have 180180 bottles of water, 252252 energy bars, and 324324 bandages. If every kit must contain the exact same combination of supplies with no items left over, what is the greatest number of kits that can be assembled?

Show answer & explanation

Answer: 36

Answer

The greatest number of kits that can be assembled is 36.
The scenario describes dividing three sets of items into identical groups with no remainder, which means finding the Greatest Common Factor (GCF). Breaking down the numbers into prime factors yields: 180=22×32×5180 = 2^2 \times 3^2 \times 5, 252=22×32×7252 = 2^2 \times 3^2 \times 7, and 324=22×34324 = 2^2 \times 3^4. The factors shared by all three are 222^2 and 323^2. Multiplying these together (4×94 \times 9) gives the GCF of 3636. Therefore, a maximum of 3636 kits can be made, each containing exactly 55 water bottles, 77 energy bars, and 99 bandages.

Step-by-Step Solution

1
Identify the mathematical operation required by the scenario.
We need to find the Greatest Common Factor (GCF) of 180, 252, and 324.
The problem asks for the maximum number of identical kits that can be made by dividing all supplies without any leftovers, which aligns with the definition of the GCF.
2
Determine the prime factorization for each quantity.
180=22×32×5180 = 2^2 \times 3^2 \times 5
252=22×32×7252 = 2^2 \times 3^2 \times 7
324=22×34324 = 2^2 \times 3^4
Prime factorization is a reliable method to find all common prime factors among multiple large numbers.
3
Identify the common prime factors and their lowest exponents.
The common prime bases are 2 and 3. Their lowest exponents across all factorizations are 222^2 and 323^2.
The GCF is the product of the lowest power of each prime factor that appears in all of the numbers.
4
Calculate the final GCF by multiplying the common prime factors.
22×32=4×9=362^2 \times 3^2 = 4 \times 9 = 36
Multiplying the lowest common prime factors gives the greatest numerical value that divides evenly into all three supply quantities.

Key Concept

Greatest Common Factor (GCF) via Prime Factorization

Alternative Method

Instead of prime factorization, you can check the factors of the common difference. The difference between the quantities is 7272 (252−180=72252 - 180 = 72 and 324−252=72324 - 252 = 72). The factors of 7272 are 72,36,24,18,12,9,8,6,4,3,2,172, 36, 24, 18, 12, 9, 8, 6, 4, 3, 2, 1. Checking these against 180180 from largest to smallest, 7272 does not divide 180180, but 3636 does (180÷36=5180 \div 36 = 5). Since 3636 divides all three numbers, it is the GCF.
Estimated Time:1m 30s
Question 127Question →

A tactical transport vehicle's fuel efficiency is evaluated under two conditions. On paved roads, the ratio of miles driven to gallons of fuel consumed is 15:115:1. In off-road conditions, the vehicle's fuel efficiency decreases by 20%20\%. How many gallons of fuel are required to drive 60 miles60\text{ miles} in off-road conditions?

Show answer & explanation

Answer: 55

Answer

The correct amount of fuel required is 55 gallons.
The original fuel efficiency is 15 miles per gallon. A 20% decrease reduces this rate by 3 mpg (0.20 × 15), resulting in a new off-road efficiency of 12 mpg. To find the required fuel for a 60-mile trip, divide the total distance by the new unit rate: 60 / 12 = 5 gallons.

Step-by-Step Solution

1
Identify the original fuel efficiency from the given ratio.
The ratio 15:115:1 means the vehicle gets 15 miles per gallon15\text{ miles per gallon} (mpg) on paved roads.
Converting the ratio into a unit rate makes it easier to apply the percentage change.
2
Calculate the off-road fuel efficiency by applying the 20%20\% decrease.
15−(0.20×15)=15−3=12 mpg15 - (0.20 \times 15) = 15 - 3 = 12\text{ mpg}.
The problem states the efficiency decreases by 20%20\% in off-road conditions.
3
Set up a proportion to find the gallons required for the 60-mile60\text{-mile} trip.
12 miles1 gallon=60 milesx gallons\frac{12\text{ miles}}{1\text{ gallon}} = \frac{60\text{ miles}}{x\text{ gallons}}
Fuel consumption is a direct proportion between miles driven and gallons used at a constant rate.
4
Solve for xx.
12x=60  ⟹  x=5 gallons12x = 60 \implies x = 5\text{ gallons}.
Isolating the variable gives the final required amount of fuel.

Key Concept

Applying percentage changes to unit rates and setting up proportions to solve for an unknown quantity.

Alternative Method

Calculate the fuel needed for paved roads first (60/15=4 gallons60 / 15 = 4\text{ gallons}). Recognize that since the new efficiency is 80%80\% (or 45\frac{4}{5}) of the original, the fuel needed will be the inverse ratio (54\frac{5}{4}) of the original fuel amount. Multiply 4 gallons×54=5 gallons4\text{ gallons} \times \frac{5}{4} = 5\text{ gallons}.
Estimated Time:1m 0s
Question 128Question →

A rectangular microchip has a length of 8.0×10−38.0 \times 10^{-3} meters and a width of 4.5×10−34.5 \times 10^{-3} meters. Calculate the area of the microchip in square meters and express the result in proper scientific notation as a×10na \times 10^n (where 1≤a<101 \le a < 10). What is the value of the coefficient aa?

Show answer & explanation

Answer: 3.6

Answer

The coefficient aa is 3.6.
The correct answer is derived by multiplying the coefficients (8.0 × 4.5 = 36), adding the exponents (-3 + -3 = -6), and normalizing the preliminary result of 36 × 10^-6 by moving the decimal left by one place. This creates a proper coefficient of 3.6 and changes the exponent to -5.

Step-by-Step Solution

1
Set up the multiplication for area
Area = (8.0×10−3)×(4.5×10−3)(8.0 \times 10^{-3}) \times (4.5 \times 10^{-3})
The area of a rectangle is found by multiplying its length by its width.
2
Multiply the coefficients
8.0×4.5=368.0 \times 4.5 = 36
When multiplying terms in scientific notation, the numerical coefficients are multiplied together.
3
Multiply the powers of 10
10−3×10−3=10−610^{-3} \times 10^{-3} = 10^{-6}
When multiplying identical bases, their exponents are added: −3+(−3)=−6-3 + (-3) = -6.
4
Combine into preliminary result
36×10−636 \times 10^{-6}
Bring the multiplied coefficient and combined power of 10 together.
5
Normalize to proper scientific notation
3.6×10−53.6 \times 10^{-5}
Proper scientific notation requires the coefficient aa to satisfy 1≤a<101 \le a < 10. Moving the decimal one place left on 36 increases the exponent by 1 (−6+1=−5-6 + 1 = -5).
6
Extract the coefficient aa
3.6
The question specifically asks for the value of the coefficient aa in the final a×10na \times 10^n format.

Key Concept

Multiplying and Normalizing Values in Scientific Notation
Question 129Question →

A plumber has a copper pipe that is 14.514.5 inches long. She cuts off a piece that is 3.753.75 inches long. What is the length of the remaining pipe in inches?

Show answer & explanation

Answer: 10.75

Answer

10.75
Subtracting the cut piece (3.753.75 inches) from the total length (14.514.5 inches) gives the remaining length. Aligning the decimals properly as 14.50−3.7514.50 - 3.75 results in exactly 10.7510.75.

Step-by-Step Solution

1
Identify the operation needed
Subtraction: 14.5−3.7514.5 - 3.75
Cutting a piece off means reducing the total length of the pipe.
2
Align the decimals for subtraction
14.50−3.7514.50 - 3.75
To subtract decimals correctly, align the place values by lining up the decimal points. Add a placeholder zero to 14.514.5 to make it 14.5014.50.
3
Perform the subtraction
10.7510.75
Subtracting 3.753.75 from 14.5014.50 yields 10.7510.75.

Key Concept

Decimal Subtraction and Alignment
Estimated Time:45s
Question 130Question →

Determine the final value of each arithmetic expression below. What is the correct sequence when the expressions are arranged from smallest to largest result?

Drag items to arrange them in the correct order

Show answer & explanation

Answer

The correct sequence from smallest to largest is: 0.18+0.420.18 + 0.42, 3.5÷53.5 \div 5, 2.1−1.32.1 - 1.3, and 0.15×60.15 \times 6.
To arrange the sequence properly, first calculate their values: 0.18+0.42=0.60.18 + 0.42 = 0.6, 3.5÷5=0.73.5 \div 5 = 0.7, 2.1−1.3=0.82.1 - 1.3 = 0.8, and 0.15×6=0.90.15 \times 6 = 0.9. By comparing these results side by side, the accurate ascending order is 0.60.6, 0.70.7, 0.80.8, and 0.90.9.

Step-by-Step Solution

1
Calculate the sum for the fourth expression.
0.18+0.42=0.600.18 + 0.42 = 0.60, which is 0.60.6.
Adding the hundredths and tenths places properly yields 0.60.6.
2
Calculate the quotient for the third expression.
3.5÷5=0.73.5 \div 5 = 0.7.
Since 35÷5=735 \div 5 = 7, dividing 3.53.5 by 55 gives 0.70.7.
3
Calculate the difference for the first expression.
2.1−1.3=0.82.1 - 1.3 = 0.8.
Borrowing from the ones place allows subtracting 1.31.3 from 2.12.1 to get 0.80.8.
4
Calculate the product for the second expression.
0.15×6=0.900.15 \times 6 = 0.90, which is 0.90.9.
Multiplying 1515 by 66 gives 9090. Since the original factors have a total of two decimal places, the result is 0.900.90.
5
Order the evaluated results from smallest to largest.
0.6<0.7<0.8<0.90.6 < 0.7 < 0.8 < 0.9.
Comparing the tenths digit of each calculated value provides the final arrangement.

Key Concept

Performing basic arithmetic operations with decimals and comparing their magnitudes.
Question 131Question →

An integer kk is defined as the Least Common Multiple (LCM) of 1212 and 2828. What is the Greatest Common Factor (GCF) of kk and 4040?

Show answer & explanation

Answer: 4

Answer

The Greatest Common Factor of kk and 4040 is 4.
The problem requires two distinct mathematical steps. First, calculate the Least Common Multiple of 1212 and 2828. Using prime factorizations (12=22×312 = 2^2 \times 3 and 28=22×728 = 2^2 \times 7), the LCM is the product of the highest powers of all prime factors: 22×3×7=842^2 \times 3 \times 7 = 84. Therefore, k=84k = 84. The second step asks for the Greatest Common Factor of kk (8484) and 4040. The prime factorization of 4040 is 23×52^3 \times 5. The only shared prime factor between 8484 and 4040 is 22, and the lowest power they share is 222^2. Thus, the GCF is 44.

Step-by-Step Solution

1
Find the prime factorizations of 12 and 28.
12=22×312 = 2^2 \times 3 and 28=22×728 = 2^2 \times 7.
Prime factorization is the most reliable method for finding the Least Common Multiple.
2
Calculate kk, which is the LCM of 12 and 28.
k=22×3×7=4×21=84k = 2^2 \times 3 \times 7 = 4 \times 21 = 84.
The LCM is found by multiplying the highest power of every prime factor present in either number.
3
Find the prime factorization of 40.
40=23×540 = 2^3 \times 5.
This is needed to compare against the prime factors of kk (8484) to find the Greatest Common Factor.
4
Calculate the GCF of 84 and 40.
Comparing 8484 (22×3×72^2 \times 3 \times 7) and 4040 (23×52^3 \times 5), the only shared prime base is 2. The lowest exponent for this base is 2. Thus, the GCF is 22=42^2 = 4.
The GCF is the product of the lowest powers of all common prime factors shared by both integers.

Key Concept

Applying prime factorization to sequentially determine Least Common Multiples (LCM) and Greatest Common Factors (GCF).
Question 132Question →

An industrial bakery has a large container holding 103810\frac{3}{8} gallons of vegetable oil. On Monday morning, a baker uses 3123\frac{1}{2} gallons for a batch of muffins. In the afternoon, they use an additional 2342\frac{3}{4} gallons for bread dough. How many gallons of vegetable oil remain in the container? (Enter your answer as a decimal.)

Show answer & explanation

Answer: 4.125

Answer

4.125
Converting all fractions to a common denominator of 8 yields 103810\frac{3}{8} total, 3483\frac{4}{8} used first, and 2682\frac{6}{8} used second. Total used is 6286\frac{2}{8}. Subtracting this from 103810\frac{3}{8} leaves 4184\frac{1}{8}. Converting 18\frac{1}{8} to a decimal yields 0.125, making the final answer 4.125.

Step-by-Step Solution

1
Find a common denominator for all the fractions involved.
The common denominator for 8, 2, and 4 is 8.
Fractions must have the same denominator before they can be added or subtracted.
2
Convert the amounts of oil used into mixed numbers with the common denominator of 8.
312=3483\frac{1}{2} = 3\frac{4}{8} and 234=2682\frac{3}{4} = 2\frac{6}{8}.
This prepares the values for addition.
3
Add the amounts used together to find the total amount of oil removed.
348+268=5108=6283\frac{4}{8} + 2\frac{6}{8} = 5\frac{10}{8} = 6\frac{2}{8}
We must consolidate the used portions before subtracting from the total.
4
Subtract the total oil used from the original amount in the container.
1038−628=41810\frac{3}{8} - 6\frac{2}{8} = 4\frac{1}{8}
Subtracting the total used gives the remaining oil.
5
Convert the final mixed number to a decimal format.
418=4+(1÷8)=4.1254\frac{1}{8} = 4 + (1 \div 8) = 4.125
The question explicitly requires the answer to be entered as a decimal.

Key Concept

Adding and subtracting mixed numbers with unlike denominators
Question 133Question →

A biomedical researcher is cataloging the diameters of four microscopic specimens. To properly calibrate the imaging equipment, arrange the specimens in descending order based on their diameter, from the largest to the smallest.

Drag items to arrange them in the correct order

Show answer & explanation

Answer

The correct descending order from largest to smallest is Specimen Beta, Specimen Delta, Specimen Gamma, and Specimen Alpha.
By converting all measurements into standard scientific notation (a×10na \times 10^n), their magnitudes can be compared directly. Specimen Beta has the largest exponent (−5-5). The remaining three specimens all reduce to an exponent of −6-6. Ordering those three by their coefficients (9.09.0, 8.58.5, and 6.56.5) yields the final sequence.

Step-by-Step Solution

1
Convert Specimen Beta from standard decimal form to scientific notation.
0.0000720.000072 meters becomes 7.2×10−57.2 \times 10^{-5} meters.
A uniform mathematical format is necessary to accurately compare the magnitudes of all specimens.
2
Normalize the coefficient for Specimen Gamma.
850×10−8850 \times 10^{-8} becomes 8.5×10−68.5 \times 10^{-6}.
Proper scientific notation requires the coefficient to be greater than or equal to 1 and less than 10. Moving the decimal two places left increases the exponent by 2.
3
Normalize the coefficient for Specimen Delta.
0.9×10−50.9 \times 10^{-5} becomes 9.0×10−69.0 \times 10^{-6}.
Moving the decimal one place right to create a valid coefficient decreases the exponent by 1.
4
Compare the exponents first, then the coefficients to determine the descending order.
7.2×10−5>9.0×10−6>8.5×10−6>6.5×10−67.2 \times 10^{-5} > 9.0 \times 10^{-6} > 8.5 \times 10^{-6} > 6.5 \times 10^{-6}.
A larger exponent (−5-5 vs −6-6) dictates a larger overall number. For values sharing the identical −6-6 exponent, the descending order is determined directly by their coefficients (9.0>8.5>6.59.0 > 8.5 > 6.5).

Key Concept

Normalizing Coefficients and Comparing Magnitudes in Scientific Notation
Estimated Time:1m 30s
Question 134Question →

A mechanic is draining old oil from a vehicle into a waste oil catch pan that has a maximum capacity of 1515 quarts. The catch pan already contains 4234\frac{2}{3} quarts of oil from a previous job. If the vehicle's engine holds 7347\frac{3}{4} quarts of oil, and all of it is drained into the catch pan, how much more room, in quarts, is left in the catch pan?

Show answer & explanation

Answer: 27122\frac{7}{12}

Answer

The correct answer is 27122\frac{7}{12}.
To find the remaining capacity, first add the two amounts of oil using a common denominator of 12 (4812+7912=111712=125124\frac{8}{12} + 7\frac{9}{12} = 11\frac{17}{12} = 12\frac{5}{12} quarts). Then, subtract this total from the pan's capacity of 15. By borrowing, 15 becomes 14121214\frac{12}{12}. Subtracting 1251212\frac{5}{12} leaves 27122\frac{7}{12} quarts.

Step-by-Step Solution

1
Determine the total amount of oil that will be in the catch pan by adding the existing oil and the vehicle's oil.
423+7344\frac{2}{3} + 7\frac{3}{4}
The pan's occupied space is the sum of what was already there and what is being added.
2
Find a common denominator to add the fractions.
The least common multiple of 3 and 4 is 12. Convert the fractions: 4812+79124\frac{8}{12} + 7\frac{9}{12}.
Fractions must have the same denominator before they can be added.
3
Add the whole numbers and the numerators, then simplify.
4+7=114 + 7 = 11 and 812+912=1712\frac{8}{12} + \frac{9}{12} = \frac{17}{12}. Since 1712=1512\frac{17}{12} = 1\frac{5}{12}, the total is 11+1512=1251211 + 1\frac{5}{12} = 12\frac{5}{12} quarts.
Combines the mixed numbers to find the total volume of oil.
4
Subtract the total volume of oil from the catch pan's maximum capacity.
15−1251215 - 12\frac{5}{12}
The remaining room is the difference between the total capacity and the occupied space.
5
Borrow 1 from the whole number 15 to perform the subtraction.
Rewrite 1515 as 14121214\frac{12}{12}. Subtract: 141212−12512=(14−12)+(1212−512)=271214\frac{12}{12} - 12\frac{5}{12} = (14 - 12) + (\frac{12}{12} - \frac{5}{12}) = 2\frac{7}{12} quarts.
Borrowing allows subtraction of the fractional part.

Key Concept

Adding mixed numbers with unlike denominators and subtracting mixed numbers from whole numbers by borrowing.
Question 135Question →

Given x=−4x = -4 and y=3y = 3, what is the exact value of the expression 3∣x−y∣−∣y2−x2∣3|x - y| - |y^2 - x^2|?

Show answer & explanation

Answer: 14

Answer

14
By correctly substituting the variables, following the order of operations, and applying the definition of absolute value, the expression simplifies to 3(7)−73(7) - 7, which evaluates precisely to 1414.

Step-by-Step Solution

1
Substitute the given values for xx and yy into the expression.
3∣−4−3∣−∣(3)2−(−4)2∣3|-4 - 3| - |(3)^2 - (-4)^2|
Variable substitution is the first step in evaluating an algebraic expression.
2
Simplify the expression inside the first absolute value bars.
∣−4−3∣=∣−7∣|-4 - 3| = |-7|
Absolute value bars act as grouping symbols, so operations inside them must be performed first.
3
Evaluate the exponents inside the second absolute value bars.
∣(3)2−(−4)2∣=∣9−16∣|(3)^2 - (-4)^2| = |9 - 16|
Following the order of operations, exponents are evaluated before subtraction.
4
Simplify the expression inside the second absolute value bars.
∣9−16∣=∣−7∣|9 - 16| = |-7|
Complete the subtraction inside the grouping symbols.
5
Apply the absolute value function to both simplified terms.
3(7)−73(7) - 7
The absolute value of any non-zero real number is its positive counterpart: ∣−7∣=7|-7| = 7.
6
Perform the final multiplication and subtraction.
21−7=1421 - 7 = 14
Multiplication is performed before subtraction according to the standard order of operations.

Key Concept

Evaluating algebraic expressions involving absolute value, exponents, and signed numbers.
Estimated Time:1m 30s
Question 136Question →

What is the value of the following expression?

23−14×112+58 \frac{2}{3} - \frac{1}{4} \times 1\frac{1}{2} + \frac{5}{8}
Show answer & explanation

Answer: 1112\frac{11}{12}

Answer

The correct value of the expression is 1112\frac{11}{12}.
The correct answer is found by rigorously applying the order of operations. The multiplication 14×112\frac{1}{4} \times 1\frac{1}{2} must be done first. After converting 1121\frac{1}{2} to 32\frac{3}{2}, the product is 38\frac{3}{8}. Substituting this back gives 23−38+58\frac{2}{3} - \frac{3}{8} + \frac{5}{8}. By combining the terms with eighths, we get −38+58=28-\frac{3}{8} + \frac{5}{8} = \frac{2}{8}, or 14\frac{1}{4}. Adding this to the initial term requires a common denominator of 12: 812+312=1112\frac{8}{12} + \frac{3}{12} = \frac{11}{12}.

Step-by-Step Solution

1
Convert the mixed number to an improper fraction.
112=321\frac{1}{2} = \frac{3}{2}
Fraction multiplication requires all terms to be expressed as proper or improper fractions.
2
Perform the multiplication operation.
14×32=38\frac{1}{4} \times \frac{3}{2} = \frac{3}{8}
According to the order of operations (PEMDAS), multiplication must be performed before addition and subtraction.
3
Substitute the multiplication result back into the expression.
23−38+58\frac{2}{3} - \frac{3}{8} + \frac{5}{8}
This updates the expression for the remaining addition and subtraction operations.
4
Combine the fractions that already share a common denominator.
−38+58=28-\frac{3}{8} + \frac{5}{8} = \frac{2}{8}, which simplifies to 14\frac{1}{4}.
Grouping terms with the same denominator makes the calculation faster and simpler.
5
Find a common denominator for the remaining terms and add.
23+14=812+312=1112\frac{2}{3} + \frac{1}{4} = \frac{8}{12} + \frac{3}{12} = \frac{11}{12}
Fractions must have a common denominator (in this case, 12) before their numerators can be added.

Key Concept

Order of Operations with Fractions
Estimated Time:1m 0s
Question 137Question →

A portable generator's fuel tank holds 8148\frac{1}{4} gallons of diesel. If the generator consumes fuel at a rate of 1231\frac{2}{3} gallons per hour, how many gallons of fuel remain in the tank after exactly 22 hours of continuous operation?

Show answer & explanation

Answer: 411124\frac{11}{12}

Answer

The correct answer is 411124\frac{11}{12} gallons.
The correct answer accurately calculates the total fuel used by multiplying the hourly consumption rate by the operating time (123×2=3131\frac{2}{3} \times 2 = 3\frac{1}{3}). It then correctly subtracts this total from the initial tank capacity by finding a common denominator and borrowing appropriately (814−313=8312−3412=71512−3412=411128\frac{1}{4} - 3\frac{1}{3} = 8\frac{3}{12} - 3\frac{4}{12} = 7\frac{15}{12} - 3\frac{4}{12} = 4\frac{11}{12}).

Step-by-Step Solution

1
Calculate the total amount of fuel consumed in 2 hours.
2×123=2×53=103=3132 \times 1\frac{2}{3} = 2 \times \frac{5}{3} = \frac{10}{3} = 3\frac{1}{3} gallons
Total consumption is the hourly rate multiplied by the number of hours operated.
2
Set up the subtraction to find the remaining fuel.
814−3138\frac{1}{4} - 3\frac{1}{3}
Remaining fuel is the initial capacity minus the total consumed fuel.
3
Find a common denominator to subtract the mixed numbers.
The least common multiple of 44 and 33 is 1212. The expression becomes 8312−34128\frac{3}{12} - 3\frac{4}{12}.
Fractions must have the same denominator before they can be added or subtracted.
4
Borrow from the whole number to subtract the fractions.
83128\frac{3}{12} becomes 715127\frac{15}{12}. Then, 71512−3412=411127\frac{15}{12} - 3\frac{4}{12} = 4\frac{11}{12} gallons.
Since 312\frac{3}{12} is less than 412\frac{4}{12}, one whole unit must be converted into twelfths (1212\frac{12}{12}) and added to the fraction.

Key Concept

Fraction Operations
Question 138Question →

A hiker plans to complete a trail that is 153415\frac{3}{4} miles long. If she hikes at a consistent average speed of 3123\frac{1}{2} miles per hour, how many hours will it take her to complete the entire trail?

Show answer & explanation

Answer: 4.5

Answer

4.5
The correct answer is found by converting the total distance (153415\frac{3}{4}) and the speed (3123\frac{1}{2}) into improper fractions (634\frac{63}{4} and 72\frac{7}{2}), and then dividing the distance by the speed. This translates to 634×27\frac{63}{4} \times \frac{2}{7}, which cross-simplifies perfectly to 92\frac{9}{2} or 4.54.5 hours.

Step-by-Step Solution

1
Convert the mixed numbers into improper fractions.
1534=63415\frac{3}{4} = \frac{63}{4} and 312=723\frac{1}{2} = \frac{7}{2}
Fraction arithmetic requires mixed numbers to be in improper fraction form before dividing.
2
Set up the division equation to solve for time.
Time = 634÷72\frac{63}{4} \div \frac{7}{2}
Time is calculated by dividing total distance by the average speed.
3
Change the division to multiplication by using the reciprocal of the divisor.
634×27\frac{63}{4} \times \frac{2}{7}
Dividing by a fraction is mathematically equivalent to multiplying by its reciprocal.
4
Multiply the fractions and simplify the result.
63×24×7=12628=92=4.5\frac{63 \times 2}{4 \times 7} = \frac{126}{28} = \frac{9}{2} = 4.5
Simplifying the fraction yields the exact number of hours.

Key Concept

Dividing mixed numbers by converting to improper fractions and multiplying by the reciprocal.
Estimated Time:1m 0s
Question 139Question →

If y=−3y = -3, which of the following represents all possible values for xx in the equation −2−2∣x−y∣=−16-2 - 2|x - y| = -16?

Show answer & explanation

Answer: 44 and −10-10

Answer

The possible values for xx are 44 and −10-10.
The correct answer accurately substitutes the negative value, isolates the absolute value term to yield ∣x+3∣=7|x + 3| = 7, and evaluates both the positive and negative branches to find the two valid solutions for xx.

Step-by-Step Solution

1
Substitute the value y=−3y = -3 into the original equation.
−2−2∣x−(−3)∣=−16⇒−2−2∣x+3∣=−16-2 - 2|x - (-3)| = -16 \Rightarrow -2 - 2|x + 3| = -16
To reduce the equation to a single variable so it can be solved.
2
Begin isolating the absolute value expression by adding 22 to both sides.
−2∣x+3∣=−16+2⇒−2∣x+3∣=−14-2|x + 3| = -16 + 2 \Rightarrow -2|x + 3| = -14
To undo the constant subtraction outside the absolute value, following reverse order of operations.
3
Divide both sides of the equation by −2-2.
∣x+3∣=7|x + 3| = 7
To completely isolate the absolute value expression.
4
Set up two separate equations for the positive and negative pathways.
x+3=7x + 3 = 7 and x+3=−7x + 3 = -7
The expression inside the absolute value can evaluate to either 77 or −7-7 and still have an absolute distance of 77 from zero.
5
Solve both resulting linear equations for xx.
x=4x = 4 and x=−10x = -10
To find all possible values that satisfy the original equation.

Key Concept

Solving linear absolute value equations requires accurately substituting variables, strictly following the order of operations to isolate the absolute value, and creating two distinct pathways (positive and negative) to find all solutions.
Estimated Time:1m 30s
Question 140Question →

A plumber is connecting three sections of PVC pipe to bridge a gap that is 121412\frac{1}{4} feet wide. The first section of pipe measures 4234\frac{2}{3} feet in length, and the second section measures 3343\frac{3}{4} feet. Assuming there is no overlap between the connected sections, what must be the length of the third section of pipe to exactly bridge the gap?

Show answer & explanation

Answer: 3563\frac{5}{6} feet

Answer

The third section of pipe must be 3563\frac{5}{6} feet long.
The correct answer accurately adds the two pipe lengths by finding a common denominator of 12, resulting in 85128\frac{5}{12}. It then subtracts this sum from the total gap width of 1231212\frac{3}{12} by properly borrowing from the whole number to get 111512−8512=3101211\frac{15}{12} - 8\frac{5}{12} = 3\frac{10}{12}, which simplifies to 3563\frac{5}{6}.

Step-by-Step Solution

1
Find the combined length of the first two pipe sections.
423+3344\frac{2}{3} + 3\frac{3}{4}
To determine how much of the gap has already been covered.
2
Convert the fractions to a common denominator and add.
4812+3912=717124\frac{8}{12} + 3\frac{9}{12} = 7\frac{17}{12}
The least common multiple of 3 and 4 is 12.
3
Simplify the improper fraction.
71712=7+1512=85127\frac{17}{12} = 7 + 1\frac{5}{12} = 8\frac{5}{12} feet
Converting to a proper mixed number makes the final subtraction step accurate.
4
Subtract the combined length from the total gap width.
1214−8512=12312−851212\frac{1}{4} - 8\frac{5}{12} = 12\frac{3}{12} - 8\frac{5}{12}
The remaining distance requires subtracting the covered distance from the total.
5
Borrow from the whole number to perform the subtraction.
111512−8512=31012=35611\frac{15}{12} - 8\frac{5}{12} = 3\frac{10}{12} = 3\frac{5}{6} feet
Since 312\frac{3}{12} is smaller than 512\frac{5}{12}, you must borrow 1 whole (or 1212\frac{12}{12}) from 12.

Key Concept

Fraction Operations with Mixed Numbers
PreviousPage 7 / 8Next
Number Theory and Operations Practice Questions — Armed Services Vocational Aptitude Battery (ASVAB) — Page 7 | Examkin