Number Theory and Operations

159 questions

Question 101Question →

A naval shipyard allocates its weekly steel supply for submarine repair, surface ship repair, and new construction in a ratio of 3:4:53:4:5. If the surface ship repair division receives 240240 tons of steel, what is the total amount of steel allocated to all three divisions combined?

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Answer: 720

Answer

The total amount of steel allocated to all three divisions is 720 tons.
The ratio of steel for submarine repair, surface ship repair, and new construction is 3:4:53:4:5, which means there are 1212 total parts (3+4+53+4+5). We are given that surface ship repair, the middle term representing 44 parts of the ratio, receives 240240 tons. To find the value of a single part, divide 240240 by 44, yielding 6060 tons. Finally, multiply this unit rate by the 1212 total parts to find the total steel allocation: 60×12=72060 \times 12 = 720 tons.

Step-by-Step Solution

1
Identify the number of ratio parts assigned to surface ship repair and calculate the total number of parts.
Surface ship repair = 4 parts. Total parts = 3 + 4 + 5 = 12 parts.
To find the value of a single part, we must correctly match the given amount to its corresponding ratio value.
2
Calculate the amount of steel that corresponds to one ratio part.
240 tons / 4 parts = 60 tons per part.
Finding this unit rate allows us to scale up to the total amount.
3
Multiply the unit rate by the total number of parts.
60 tons/part * 12 parts = 720 tons.
The question asks for the total amount of steel allocated to all three divisions combined.

Key Concept

Solving multi-part ratio problems by finding a unit rate

Alternative Method

You can set up a direct proportion: 4 parts / 240 tons = 12 total parts / x tons. Cross-multiplying gives 4x = 2880, so dividing both sides by 4 yields x = 720.
Estimated Time:1m 0s
Question 102Question →

A mechanical engineer is determining the load factor for a support beam. The calculation requires evaluating the equation below.

Load Factor=(558−234)÷(113×38)\text{Load Factor} = \left( 5 \frac{5}{8} - 2 \frac{3}{4} \right) \div \left( 1 \frac{1}{3} \times \frac{3}{8} \right)

What is the final load factor? Express your answer as an exact decimal.

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Answer: 5.75

Answer

The final load factor is exactly 5.75.
The expression evaluates to exactly 5.75. This is found by first converting all mixed numbers to improper fractions, calculating the values inside the parentheses (238\frac{23}{8} and 12\frac{1}{2} respectively), and then performing fraction division by multiplying by the reciprocal (238×2=234=5.75\frac{23}{8} \times 2 = \frac{23}{4} = 5.75).

Step-by-Step Solution

1
Convert the mixed numbers in the expression to improper fractions.
558=4585 \frac{5}{8} = \frac{45}{8}, 234=1142 \frac{3}{4} = \frac{11}{4}, and 113=431 \frac{1}{3} = \frac{4}{3}.
Fraction multiplication and division require working with improper fractions rather than mixed numbers.
2
Perform the subtraction inside the first set of parentheses: 458−114\frac{45}{8} - \frac{11}{4}.
Convert 114\frac{11}{4} to 228\frac{22}{8}. Then, 458−228=238\frac{45}{8} - \frac{22}{8} = \frac{23}{8}.
To subtract fractions, they must have a common denominator. The lowest common denominator for 8 and 4 is 8.
3
Perform the multiplication inside the second set of parentheses: 43×38\frac{4}{3} \times \frac{3}{8}.
Multiply the numerators and denominators: 4×33×8=1224\frac{4 \times 3}{3 \times 8} = \frac{12}{24}. This simplifies to 12\frac{1}{2}.
Following the order of operations (PEMDAS), operations inside parentheses must be evaluated first.
4
Divide the result of the first parentheses by the result of the second parentheses.
238÷12=238×21=468\frac{23}{8} \div \frac{1}{2} = \frac{23}{8} \times \frac{2}{1} = \frac{46}{8}.
Dividing by a fraction is mathematically equivalent to multiplying by its reciprocal.
5
Simplify the final fraction and convert it to a decimal format.
468=234=534\frac{46}{8} = \frac{23}{4} = 5 \frac{3}{4}. As a decimal, 534=5.755 \frac{3}{4} = 5.75.
The question specifically requests the final load factor expressed as a decimal.

Key Concept

Compound Fraction Operations and Order of Operations
Question 103Question →

Arrange the following values from least to greatest.

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Answer

The correct sequence from least to greatest is: 620620, 8,5008,500, 1.2×1041.2 \times 10^4, 3.0×1053.0 \times 10^5.
By converting all values to standard form, it is clear that 620620 is the smallest, followed by 8,5008,500, then 12,00012,000 (which is 1.2×1041.2 \times 10^4), and finally 300,000300,000 (which is 3.0×1053.0 \times 10^5).

Step-by-Step Solution

1
Convert all values to standard numerical form to easily compare their sizes.
The values become: 12,00012,000 (from item 1), 620620 (from item 2), 300,000300,000 (from item 3), and 8,5008,500 (from item 4).
Translating scientific notation into standard form allows for direct visual comparison of digit lengths and magnitudes.
2
Group and compare the numbers by their total number of digits.
620620 has three digits, 8,5008,500 has four digits, 12,00012,000 has five digits, and 300,000300,000 has six digits.
For whole positive numbers, a value with fewer digits is always smaller than a value with more digits.
3
Order the values sequentially starting from the smallest.
The final order is 620620 < 8,5008,500 < 12,00012,000 < 300,000300,000.
This establishes the ascending sequence requested by the question.

Key Concept

Comparing Magnitudes in Standard and Scientific Notation

Alternative Method

Instead of using standard form, you can convert all numbers to scientific notation: 6.2×1026.2 \times 10^2, 8.5×1038.5 \times 10^3, 1.2×1041.2 \times 10^4, 3.0×1053.0 \times 10^5. Because the exponents (2,3,4,52, 3, 4, 5) are already in ascending order, you can immediately determine the correct sequence without looking at the coefficients.
Estimated Time:45s
Question 104Question →

A cybersecurity team analyzes network traffic and categorizes detected threats into low, medium, and high severity in a ratio of 9:5:29:5:2. If the team logged exactly 145145 medium severity threats during a shift, what was the total number of threats logged across all three categories?

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Answer: 464

Answer

464
The correct answer is found by first determining the value of a single ratio part. Since 55 parts represent 145145 medium threats, one part equals 2929 threats. Multiplying this base unit by the total number of parts (1616) gives the total of 464464 threats.

Step-by-Step Solution

1
Determine the total number of parts in the ratio.
9+5+2=169 + 5 + 2 = 16 parts
To find the total amount of threats, we first need to know how many total parts make up the complete ratio.
2
Find the numerical value of a single part.
145÷5=29145 \div 5 = 29 threats per part
We know that 55 parts equal 145145 medium threats. Dividing the count by the parts gives the baseline value of one part.
3
Calculate the total number of threats.
29×16=46429 \times 16 = 464 threats
Multiplying the value of one part by the total number of parts yields the total count across all categories.

Key Concept

Solving Part-to-Whole Ratio Problems
Question 105Question →

A student is required to identify a calculation that yields a value greater than zero. Which of the following arithmetic expressions produces a positive integer result?

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Answer: (−3)×(−4)−10(-3) \times (-4) - 10

Answer

The expression (−3)×(−4)−10(-3) \times (-4) - 10 produces a positive integer.
The expression (−3)×(−4)−10(-3) \times (-4) - 10 evaluates to a positive integer because the product of −3-3 and −4-4 is a positive 1212, and subtracting 1010 from 1212 leaves 22.

Step-by-Step Solution

1
Evaluate the first expression: −5+(−2)-5 + (-2).
−5+(−2)=−7-5 + (-2) = -7.
Adding a negative integer to a negative integer results in a smaller negative integer.
2
Evaluate the second expression: 4−3×24 - 3 \times 2.
4−6=−24 - 6 = -2.
Following the order of operations (PEMDAS), multiplication is performed before subtraction.
3
Evaluate the third expression: −∣−8∣+5-|-8| + 5.
−8+5=−3-8 + 5 = -3.
The absolute value of −8-8 is positive 88. The negative sign outside makes it −8-8. Adding 55 results in a negative integer.
4
Evaluate the fourth expression: (−3)×(−4)−10(-3) \times (-4) - 10.
12−10=212 - 10 = 2.
Multiplying two negative integers yields a positive integer (1212). Subtracting 1010 from 1212 leaves a positive integer.

Key Concept

Integer operations combining sign rules, absolute value, and the order of operations.
Estimated Time:50s
Question 106Question →

What is the value of the following expression?

8.4−2.4×1.5+4.5÷0.58.4 - 2.4 \times 1.5 + 4.5 \div 0.5
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Answer: 13.8

Answer

13.8
Applying the order of operations correctly requires first evaluating the multiplication (2.4×1.5=3.62.4 \times 1.5 = 3.6) and the division (4.5÷0.5=94.5 \div 0.5 = 9). Substituting these values back simplifies the equation to 8.4−3.6+98.4 - 3.6 + 9. Processing the remaining subtraction and addition from left to right yields 4.8+9=13.84.8 + 9 = 13.8.

Step-by-Step Solution

1
Evaluate the multiplication part of the expression.
2.4×1.5=3.62.4 \times 1.5 = 3.6
According to the order of operations, multiplication must be performed before addition or subtraction.
2
Evaluate the division part of the expression.
4.5÷0.5=94.5 \div 0.5 = 9
Division shares the same precedence as multiplication and must also be evaluated before addition and subtraction.
3
Substitute the results back into the original expression.
8.4−3.6+98.4 - 3.6 + 9
This simplifies the expression so that only addition and subtraction remain.
4
Evaluate the remaining addition and subtraction from left to right.
8.4−3.6=4.88.4 - 3.6 = 4.8, and 4.8+9=13.84.8 + 9 = 13.8
Addition and subtraction have equal precedence and are solved strictly from left to right.

Key Concept

Order of Operations with Decimals
Question 107Question →

A specialized aerospace alloy is manufactured by combining titanium and aluminum in a ratio of 7:47:4 by weight. If a batch of this alloy contains 140 kilograms140\text{ kilograms} of titanium, what is the total weight of the batch?

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Answer: 220 kg220\text{ kg}

Answer

The total weight of the batch is 220 kg220\text{ kg}.
The given ratio indicates the alloy consists of 77 parts titanium and 44 parts aluminum, making 1111 parts in total. Because the 77 parts of titanium weigh 140 kg140\text{ kg}, each single part weighs 20 kg20\text{ kg} (140÷7140 \div 7). Multiplying the 1111 total parts by 20 kg20\text{ kg} per part results in a total weight of 220 kg220\text{ kg}.

Step-by-Step Solution

1
Determine the weight of a single ratio part based on the known titanium content.
140 kg÷7 parts=20 kg per part140\text{ kg} \div 7\text{ parts} = 20\text{ kg per part}
Since the ratio of titanium to aluminum is 7:47:4, the 140 kg140\text{ kg} corresponds exactly to the 77 parts of titanium.
2
Calculate the total number of parts in the alloy mixture.
7 parts (titanium)+4 parts (aluminum)=11 total parts7\text{ parts (titanium)} + 4\text{ parts (aluminum)} = 11\text{ total parts}
The total weight is composed of both the titanium and the aluminum parts combined.
3
Multiply the total number of parts by the weight of a single part.
11 parts×20 kg per part=220 kg11\text{ parts} \times 20\text{ kg per part} = 220\text{ kg}
This yields the combined weight of the entire batch.

Key Concept

Solving Part-to-Whole Ratio Problems
Estimated Time:1m 0s
Question 108Question →

What is the value of the expression 12−2∣−4+1∣12 - 2|-4 + 1|?

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Answer: 6

Answer

6
The expression is evaluated by first simplifying the terms inside the absolute value to get |-3|, which equals positive 3. Multiplying this by the coefficient 2 gives 6. Finally, subtracting 6 from 12 yields the correct answer of 6.

Step-by-Step Solution

1
Simplify the expression inside the absolute value bars.
−4+1=−3-4 + 1 = -3
According to the order of operations, operations inside absolute value bars (which act as grouping symbols) must be performed first.
2
Evaluate the absolute value of the result.
∣−3∣=3|-3| = 3
The absolute value of a number represents its distance from zero, which is always positive.
3
Multiply the result by the coefficient outside the absolute value.
2×3=62 \times 3 = 6
Multiplication must be performed before subtraction according to the order of operations (PEMDAS).
4
Subtract the product from the initial value.
12−6=612 - 6 = 6
This completes the evaluation of the expression to find the final numerical value.

Key Concept

Absolute Value and Order of Operations
Question 109Question →

Arrange the following fractions and mixed numbers in ascending order (from smallest to largest).

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Answer

The correct ascending order is 78\frac{7}{8}, 1141 \frac{1}{4}, 32\frac{3}{2}, and 1341 \frac{3}{4}.
The proper fraction 78\frac{7}{8} is the only value less than 1, placing it first. Converting 32\frac{3}{2} to 1121 \frac{1}{2} (or 1.51.5) allows easy comparison with 1141 \frac{1}{4} (1.25) and 1341 \frac{3}{4} (1.75), confirming the correct ascending sequence.

Step-by-Step Solution

1
Identify values less than 1.
78\frac{7}{8} is the only proper fraction (less than 1), making it the smallest.
Proper fractions are always less than mixed numbers or improper fractions.
2
Convert the improper fraction to a mixed number to make comparison easier.
32=112\frac{3}{2} = 1 \frac{1}{2}.
Matching the format of the other numbers allows for a direct comparison of the fractional parts.
3
Find a common denominator for the fractional parts of the values greater than 1 (1141 \frac{1}{4}, 1121 \frac{1}{2}, and 1341 \frac{3}{4}).
The common denominator is 4. 1121 \frac{1}{2} becomes 1241 \frac{2}{4}.
Common denominators allow you to directly compare the numerators.
4
Order the mixed numbers by their fractional parts.
1141 \frac{1}{4} is smaller than 1241 \frac{2}{4} (which is 32\frac{3}{2}), and 1241 \frac{2}{4} is smaller than 1341 \frac{3}{4}.
Since the whole numbers are identical, the fractions determine the order.

Key Concept

Ordering mixed numbers and improper fractions
Question 110Question →

A botanist has 120120 tulip bulbs, 168168 daffodil bulbs, and 216216 crocus bulbs. She wants to plant them in separate rows such that each row contains only one type of flower, and every row has the exact same number of bulbs. What is the greatest number of bulbs she can plant in a single row?

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Answer: 24

Answer

24
The greatest number of bulbs per row must perfectly divide the total count of each flower type without remainders. Therefore, we calculate the Greatest Common Factor (GCF) of 120, 168, and 216. The prime factorizations reveal the common factors are 232^3 and 313^1, which multiply to 24.

Step-by-Step Solution

1
Identify the mathematical operation required by the scenario.
The problem asks for the greatest number that divides 120, 168, and 216 evenly. This means finding the Greatest Common Factor (GCF).
Each row must have the same number of bulbs and only one flower type, meaning the row size must be a common divisor of all three total quantities.
2
Find the prime factorization of 120, 168, and 216.
120=23×3×5120 = 2^3 \times 3 \times 5, 168=23×3×7168 = 2^3 \times 3 \times 7, and 216=23×33216 = 2^3 \times 3^3.
Prime factorization is a systematic method to determine the common factors of multiple large numbers.
3
Identify the common prime factors and select their lowest powers.
The common prime factors are 2 and 3. Their lowest powers across the three numbers are 232^3 and 313^1.
The GCF is formed by multiplying the lowest powers of all prime factors that appear in every number's factorization.
4
Calculate the GCF.
23×3=8×3=242^3 \times 3 = 8 \times 3 = 24.
Multiplying the selected prime factors yields the greatest possible number of bulbs per row.

Key Concept

Greatest Common Factor (GCF)
Question 111Question →

Evaluate the following mathematical expressions involving decimals. What is the correct sequence of these expressions when ordered from least to greatest value?

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Answer

The correct order from least to greatest is: 0.15×40−14.4÷1.20.15 \times 40 - 14.4 \div 1.2, followed by 10.5−3.2×2.510.5 - 3.2 \times 2.5, then (4.2−1.8)÷0.6+0.5(4.2 - 1.8) \div 0.6 + 0.5, and finally 2.4×0.5+1.8÷0.32.4 \times 0.5 + 1.8 \div 0.3.
Evaluating each expression using the correct order of operations yields final decimal values of 7.27.2, 2.52.5, −6.0-6.0, and 4.54.5. Arranging these values numerically from least to greatest provides the correct structural sequence.

Step-by-Step Solution

1
Evaluate the first expression: 2.4×0.5+1.8÷0.32.4 \times 0.5 + 1.8 \div 0.3.
1.2+6=7.21.2 + 6 = 7.2
According to the order of operations, multiplication and division are performed left-to-right before addition.
2
Evaluate the second expression: 10.5−3.2×2.510.5 - 3.2 \times 2.5.
10.5−8.0=2.510.5 - 8.0 = 2.5
Multiplication must be performed before subtraction.
3
Evaluate the third expression: 0.15×40−14.4÷1.20.15 \times 40 - 14.4 \div 1.2.
6.0−12=−6.06.0 - 12 = -6.0
Perform multiplication and division first. Then subtract the larger value from the smaller value, resulting in a negative number.
4
Evaluate the fourth expression: (4.2−1.8)÷0.6+0.5(4.2 - 1.8) \div 0.6 + 0.5.
2.4÷0.6+0.5=4+0.5=4.52.4 \div 0.6 + 0.5 = 4 + 0.5 = 4.5
Operations inside parentheses take highest priority, followed by division, and finally addition.
5
Order the evaluated results from least to greatest.
−6.0<2.5<4.5<7.2-6.0 < 2.5 < 4.5 < 7.2
Arranging the numerical values based on their algebraic magnitude provides the final sequence.

Key Concept

Order of Operations with Decimals

Alternative Method

Convert all terminating decimals to fractions (e.g., 0.5=120.5 = \frac{1}{2}, 0.3=3100.3 = \frac{3}{10}) before performing the operations to avoid decimal placement and alignment errors.
Estimated Time:1m 30s
Question 112Question →

What is the value of the following expression?

∣−4−∣−9∣∣|-4 - |-9||

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Answer: 13

Answer

13
The correct answer is found by first evaluating the innermost absolute value, ∣−9∣=9|-9| = 9. Substituting this value back into the expression gives ∣−4−9∣|-4 - 9|. Simplifying the subtraction inside yields ∣−13∣|-13|. Finally, the absolute value of −13-13 is 1313.

Step-by-Step Solution

1
Evaluate the inner absolute value.
∣−9∣=9|-9| = 9
According to the order of operations, we must simplify the expression from the inside out. The absolute value of a negative number is its positive counterpart.
2
Substitute and simplify the remaining expression.
∣−4−9∣=∣−13∣|-4 - 9| = |-13|
Replacing ∣−9∣|-9| with 99 gives the subtraction −4−9-4 - 9, which simplifies to −13-13.
3
Evaluate the outer absolute value.
∣−13∣=13|-13| = 13
The absolute value represents the distance from zero on the number line, which is always non-negative.

Key Concept

Absolute Value
Question 113Question →

A commercial bakery prepares a special bread dough using flour, water, and sourdough starter in a ratio of 11:6:311:6:3 by weight. If a single batch uses 4242 pounds of water, what is the total weight of the dough for this batch, in pounds?

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Answer: 140; 140 pounds; 140 lbs; 140 lb

Answer

140
Since the water represents 66 parts of the ratio and weighs 4242 pounds, each part weighs exactly 77 pounds (42÷6=742 \div 6 = 7). The entire batch of dough is composed of 2020 total parts (1111 for flour + 66 for water + 33 for starter). Multiplying the 2020 total parts by the 77 pounds per part results in a total batch weight of 140140 pounds.

Step-by-Step Solution

1
Find the value of one part in the ratio.
42÷6=742 \div 6 = 7 pounds per part.
Water corresponds to 66 parts of the 11:6:311:6:3 ratio, and its total weight is 4242 pounds.
2
Calculate the total number of parts in the entire dough mixture.
11+6+3=2011 + 6 + 3 = 20 total parts.
The total weight is the sum of the parts for flour, water, and starter.
3
Multiply the total number of parts by the weight of a single part.
20×7=14020 \times 7 = 140 pounds.
Scaling the 2020 total parts by the 77 pounds per part gives the total weight of the batch.

Key Concept

Solving proportions by finding the unit rate of a single part and multiplying it by the total number of parts.
Question 114Question →

A civil engineering project requires a specific concrete mixture consisting of cement, sand, and gravel in a ratio of 2:3:62:3:6 by weight. If a batch of this concrete mixture weighs a total of 6,600 lbs6,600\text{ lbs}, how many more pounds of gravel are used than cement?

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Answer: 2,4002,400

Answer

The concrete mixture requires 2,4002,400 more pounds of gravel than cement.
The entire mixture consists of 1111 equal parts (22 cement +3+ 3 sand +6+ 6 gravel). Since the total mixture weighs 6,600 lbs6,600\text{ lbs}, one part weighs 600 lbs600\text{ lbs} (6,600÷116,600 \div 11). The difference between the amount of gravel (66 parts) and cement (22 parts) is 44 parts. Multiplying this difference by the weight of one part yields 4×600=2,400 lbs4 \times 600 = 2,400\text{ lbs}.

Step-by-Step Solution

1
Find the total number of parts in the ratio.
2+3+6=11 parts2 + 3 + 6 = 11\text{ parts}.
The total given weight of the concrete mixture must be distributed across all the ratio parts combined.
2
Calculate the weight of a single proportional part.
6,600÷11=600 lbs6,600 \div 11 = 600\text{ lbs}.
Dividing the total mixture weight by the total number of parts determines the exact value of one unit.
3
Determine the difference in parts between the gravel and the cement.
6−2=4 parts6 - 2 = 4\text{ parts}.
The question asks 'how many more pounds' of gravel are used than cement, which corresponds to the difference in their ratio shares.
4
Calculate the final difference in weight.
4×600=2,400 lbs4 \times 600 = 2,400\text{ lbs}.
Multiplying the part difference by the weight per part gives the final amount.

Key Concept

Solving part-to-whole ratio scenarios and calculating the difference between specific components.
Estimated Time:1m 0s
Question 115Question →

The prime factorizations of two integers, XX and YY, are given below:

X=23×32×5X = 2^3 \times 3^2 \times 5
Y=22×33Y = 2^2 \times 3^3

Based on this information, what is the greatest common factor (GCF) of XX and YY?

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Answer: 3636

Answer

The greatest common factor is 3636.
To determine the greatest common factor (GCF) from prime factorizations, we must identify the prime bases shared by both numbers and raise each to its lowest given exponent. The shared bases for XX and YY are 22 and 33. Taking the lowest exponent for each gives 222^2 and 323^2. Their product, 4×94 \times 9, equals 3636.

Step-by-Step Solution

1
Identify the common prime bases in both factorizations.
The prime bases present in both XX and YY are 22 and 33. The prime base 55 is only in XX.
The greatest common factor (GCF) only includes prime factors that are shared by all given numbers.
2
Determine the lowest exponent for each common prime base.
For base 22, the exponents are 33 and 22, so the lowest is 22. For base 33, the exponents are 22 and 33, so the lowest is 22.
To find the greatest common factor, we must use the smallest available power of each common prime to ensure it divides both numbers perfectly.
3
Multiply the resulting prime powers to calculate the GCF.
22×32=4×9=362^2 \times 3^2 = 4 \times 9 = 36.
The product of these prime powers yields the greatest integer that divides both XX and YY without a remainder.

Key Concept

Calculating the greatest common factor (GCF) using prime factorization by finding the lowest powers of all common prime bases.
Question 116Question →

A military motor pool maintains a fleet of tactical trucks, transport vans, and passenger cars in a ratio of 8:5:38:5:3. If there are exactly 112112 total vehicles in this fleet, how many transport vans does the motor pool maintain?

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Answer: 35

Answer

The motor pool maintains 35 transport vans.
The problem outlines a part-to-part-to-part ratio of 8:5:38:5:3 and a total quantity of 112112. To solve this, first add the parts of the ratio together (8+5+3=168 + 5 + 3 = 16). Next, divide the total quantity by the total ratio parts (112÷16=7112 \div 16 = 7) to determine that each 'part' represents 77 actual vehicles. Since the ratio for transport vans is the middle number (55), multiply 55 by 77 to correctly get 3535 transport vans.

Step-by-Step Solution

1
Determine the total number of parts in the given ratio.
8+5+3=168 + 5 + 3 = 16 parts
Since the total number of vehicles in the fleet is given, we must find the total sum of the ratio parts to determine the size of a single part.
2
Calculate the exact value of a single ratio part.
112÷16=7112 \div 16 = 7 vehicles per part
Dividing the total quantity of vehicles by the total number of ratio parts gives the multiplier for the ratio.
3
Find the number of transport vans.
5×7=355 \times 7 = 35 transport vans
The ratio value specifically assigned to transport vans is 55. Multiplying this by the value of one part gives the final count.

Key Concept

Solving part-to-whole ratio problems by establishing the total parts before finding specific component quantities.
Estimated Time:1m 0s
Question 117Question →

A supply clerk is organizing copper wire. A spool initially contains 154515\frac{4}{5} meters of wire. If a technician uses 6126\frac{1}{2} meters of wire from the spool, how many meters of wire remain? Express your answer as a decimal.

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Answer: 9.3

Answer

9.3
The initial length of the wire is 154515\frac{4}{5} meters and the used portion is 6126\frac{1}{2} meters. By converting these to decimals, you get 15.815.8 meters and 6.56.5 meters. Subtracting the used portion from the initial portion yields 15.8−6.5=9.315.8 - 6.5 = 9.3 meters. Alternatively, using a common denominator of 10 gives 15810−6510=931015\frac{8}{10} - 6\frac{5}{10} = 9\frac{3}{10}, which also equals 9.3.

Step-by-Step Solution

1
Convert the mixed numbers to decimals or find a common denominator.
1545=15.815\frac{4}{5} = 15.8 and 612=6.56\frac{1}{2} = 6.5
Numbers must be in a uniform format to perform subtraction easily.
2
Subtract the length of wire used from the initial length.
15.8−6.5=9.315.8 - 6.5 = 9.3
The remaining length is the difference between the starting amount and the used amount.

Key Concept

Fraction Operations
Estimated Time:45s
Question 118Question →

Arrange the following pairs of integers in ascending order based on the value of their Greatest Common Factor (GCF).

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Answer

The correct ascending order based on the Greatest Common Factor (GCF) is: 3232 and 4040 (GCF = 8), 3636 and 4848 (GCF = 12), 4242 and 5656 (GCF = 14), 4545 and 6060 (GCF = 15).
By evaluating the Greatest Common Factor for each pair, we find that the GCF of 3232 and 4040 is 88; the GCF of 3636 and 4848 is 1212; the GCF of 4242 and 5656 is 1414; and the GCF of 4545 and 6060 is 1515. The correct ascending order is 88, 1212, 1414, 1515.

Step-by-Step Solution

1
Find the GCF for 4545 and 6060.
The GCF is 1515.
The factors of 4545 are 1,3,5,9,15,451, 3, 5, 9, 15, 45. The factors of 6060 include 1,2,3,4,5,6,10,12,15,20,30,601, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60. The largest shared factor is 1515.
2
Find the GCF for 3232 and 4040.
The GCF is 88.
The largest number that divides exactly into both 3232 and 4040 is 88.
3
Find the GCF for 4242 and 5656.
The GCF is 1414.
The largest number that divides exactly into both 4242 and 5656 is 1414 (42=14×342 = 14 \times 3, 56=14×456 = 14 \times 4).
4
Find the GCF for 3636 and 4848.
The GCF is 1212.
The largest number that divides exactly into both 3636 and 4848 is 1212.
5
Order the pairs based on the calculated GCFs.
The sequence from smallest to largest GCF is 88, 1212, 1414, 1515.
Arranging the values in ascending order determines the correct sequence.

Key Concept

Calculating the Greatest Common Factor (GCF) of pairs of integers.

Alternative Method

You can also use prime factorization for each number to find the GCF by multiplying the lowest powers of all common prime factors between the pairs.
Estimated Time:1m 30s
Question 119Question →

In a piece of heavy machinery, two interlocking gears are rotating together. The drive gear has 2828 teeth, and the driven gear has 4242 teeth. At a certain moment, a marked tooth on the drive gear aligns exactly with a marked tooth on the driven gear. How many teeth must pass the alignment point before these two specific marked teeth align with each other again?

Show answer & explanation

Answer: 8484

Answer

The gears will align again after 8484 teeth pass the alignment point.
To find the moment when two rotating cycles synchronize, the Least Common Multiple (LCM) of their cycle lengths (the number of teeth) must be determined. By finding the prime factorizations (28=22×728 = 2^2 \times 7 and 42=2×3×742 = 2 \times 3 \times 7) and multiplying the highest powers of all unique prime factors present (22×3×72^2 \times 3 \times 7), the LCM is calculated as 8484. Thus, exactly 8484 teeth must pass for the marked teeth to realign.

Step-by-Step Solution

1
Identify the mathematical concept required to solve the synchronization problem.
The problem asks for the next time repeating cycles coincide, which requires finding the Least Common Multiple (LCM) of 2828 and 4242.
The LCM determines the smallest positive integer that is a multiple of both numbers, representing the first point where both gear cycles overlap.
2
Find the prime factorization of the number of teeth on each gear.
For the drive gear: 28=22×728 = 2^2 \times 7. For the driven gear: 42=2×3×742 = 2 \times 3 \times 7.
Prime factorization breaks down each number into its core primes, allowing for an accurate calculation of the LCM.
3
Calculate the LCM using the identified prime factors.
LCM = 22×3×7=4×3×7=842^2 \times 3 \times 7 = 4 \times 3 \times 7 = 84.
The LCM is calculated by taking the highest power of each prime factor that appears in any of the original factorizations.

Key Concept

Factors, Multiples, and Primes
Question 120Question →

What is the sum of all distinct prime factors of the integer 546546?

Show answer & explanation

Answer: 25

Answer

25
The integer 546546 factors completely into the prime numbers 22, 33, 77, and 1313. Since the question asks for the sum of all distinct prime factors, adding these together yields 2+3+7+13=252 + 3 + 7 + 13 = 25.

Step-by-Step Solution

1
Find the prime factorization of 546546 by continuously dividing by the smallest possible prime numbers.
546=2×273=2×3×91=2×3×7×13546 = 2 \times 273 = 2 \times 3 \times 91 = 2 \times 3 \times 7 \times 13
To identify all prime factors, we must break the number down into its foundational prime components.
2
Identify the distinct prime factors from the factorization.
The distinct prime factors are 22, 33, 77, and 1313.
The question specifically asks for the sum of the 'distinct' prime factors.
3
Calculate the sum of these distinct prime factors.
2+3+7+13=252 + 3 + 7 + 13 = 25
Adding the identified distinct prime factors yields the final requested value.

Key Concept

Prime Factorization and Properties of Integers
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