Question

Difficulty: MediumExpansion Cards and Power Supplies

A field technician is assembling a custom audio/video workstation. The system components have the following peak power requirements:

- Processor (CPU): 125 W125\text{ W}
- Dedicated Graphics Card (GPU): 285 W285\text{ W}
- PCIe Video Capture Card: 30 W30\text{ W}
- Motherboard, RAM, and cooling system: 70 W70\text{ W}
- Storage drives: 30 W30\text{ W}

To ensure stable operation and longevity, company policy specifies that the total power draw of all components must not exceed 80%80\% of the power supply unit's (PSU) rated continuous capacity.

What is the minimum rated capacity, in Watts (W\text{W}), required for the power supply unit?

Answer: 675 W

Answer

The minimum rated capacity required for the power supply unit is 675 W675\text{ W}.
The total system power consumption is calculated by summing the requirements of all individual hardware components (125 W+285 W+30 W+70 W+30 W=540 W125\text{ W} + 285\text{ W} + 30\text{ W} + 70\text{ W} + 30\text{ W} = 540\text{ W}). To ensure the system power draw does not exceed 80%80\% of the PSU rating, the total draw is divided by 0.800.80, resulting in 5400.80=675 W\frac{540}{0.80} = 675\text{ W}.

Step-by-Step Solution

1
Calculate total peak power requirement of all workstation components.
125 W+285 W+30 W+70 W+30 W=540 W125\text{ W} + 285\text{ W} + 30\text{ W} + 70\text{ W} + 30\text{ W} = 540\text{ W} total power draw.
Before sizing a PSU, all component TDPs and peak power demands must be combined.
2
Calculate the minimum required PSU continuous wattage rating given the 80%80\% load limit.
540 W0.80=675 W\frac{540\text{ W}}{0.80} = 675\text{ W}.
Dividing the expected load by 0.800.80 ensures the power supply operates within its recommended continuous duty cycle without overloading.

Key Concept

Power supply sizing calculations including peak load headroom and maximum load percentages
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