Question

Difficulty: HardIPv4 Addressing and Subnetting

A network administrator is troubleshooting connectivity on an enterprise server host configured with the IP address 10.205.75.142/2110.205.75.142/21. To establish proper firewall routing rules, the administrator needs to identify the complete range of usable host IP addresses within this specific subnet. Which of the following represents the correct usable host IP address range for this subnetwork segment?

  1. 10.205.72.110.205.72.1 to 10.205.79.25410.205.79.254Answer
  2. B
    10.205.72.010.205.72.0 to 10.205.79.25510.205.79.255
  3. C
    10.205.75.110.205.75.1 to 10.205.75.25410.205.75.254
  4. D
    10.205.64.110.205.64.1 to 10.205.79.25410.205.79.254

Answer

The usable host range for the 10.205.75.142/2110.205.75.142/21 subnet is 10.205.72.110.205.72.1 to 10.205.79.25410.205.79.254.
The CIDR notation /21/21 indicates that the first 21 bits represent the network prefix, corresponding to a subnet mask of 255.255.248.0255.255.248.0. In the third octet, subnets increment by multiples of 88 (256248=8256 - 248 = 8). For an IP address with 7575 in the third octet, the network boundary starts at 7272 (9×8=729 \times 8 = 72), making the network address 10.205.72.010.205.72.0 and the broadcast address 10.205.79.25510.205.79.255. Excluding the network and broadcast addresses yields the usable range of 10.205.72.110.205.72.1 through 10.205.79.25410.205.79.254.

Step-by-Step Solution

1
Determine the subnet mask and third-octet block size for a /21 CIDR prefix.
A /21 prefix leaves 11 host bits (3221=1132 - 21 = 11). The subnet mask is 255.255.248.0255.255.248.0. The third octet increment (block size) is calculated as 256248=8256 - 248 = 8.
The CIDR prefix defines the boundary between the network portion and host portion of the IP address.
2
Find the network address by calculating the nearest lower multiple of the block size (8) for the third octet (75).
Multiples of 8 in the third octet are 0,8,16,24,32,40,48,56,64,72,800, 8, 16, 24, 32, 40, 48, 56, 64, 72, 80. Since 75 falls between 72 and 80, the network ID is 10.205.72.010.205.72.0.
The network ID is the first IP address of the subnet segment.
3
Determine the broadcast address for the subnet segment.
The next subnet begins at 10.205.80.010.205.80.0, making the broadcast address of the current segment 10.205.79.25510.205.79.255.
The broadcast address is the last address in the subnet block immediately preceding the start of the next block.
4
Calculate the usable host IP address range by subtracting network and broadcast addresses.
First usable host IP: 10.205.72.110.205.72.1. Last usable host IP: 10.205.79.25410.205.79.254.
Usable host addresses consist of all IP addresses between the network address and the broadcast address.

Key Concept

Calculating CIDR Subnet Boundaries and Usable Host Ranges for Non-Byte-Aligned Prefixes
Rate this question